A problem on epsilon and delta in the proof of L'Hospital's RuleWhat is the Least Upper bound on $delta$ in the $epsilon-delta$ definition of limit?Darboux Integrability epsilon-delta proofProof on showing F(x,y) is continuous by $epsilon - delta$ definitionepsilon delta approach to a problemDoubt in epsilon-delta limit proof (more specifically, the inequalities)Question about proof using epsilon delta for limitsDependence and Independence of $epsilon$ and $delta$Proving the limit of trigonometric function using epsilon delta definition.Epsilon-delta definitions, inequality strict / non-strict?Epsilon-delta derivative proof of $x^n$
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A problem on epsilon and delta in the proof of L'Hospital's Rule
What is the Least Upper bound on $delta$ in the $epsilon-delta$ definition of limit?Darboux Integrability epsilon-delta proofProof on showing F(x,y) is continuous by $epsilon - delta$ definitionepsilon delta approach to a problemDoubt in epsilon-delta limit proof (more specifically, the inequalities)Question about proof using epsilon delta for limitsDependence and Independence of $epsilon$ and $delta$Proving the limit of trigonometric function using epsilon delta definition.Epsilon-delta definitions, inequality strict / non-strict?Epsilon-delta derivative proof of $x^n$
$begingroup$
I'm following the proof of L'Hospital's Rule from a text but have trouble understanding this part regarding epsilon-delta.
Assume $Lgt 0$ and $epsilon gt 0$ is given and $delta in (0,1)$. What we have is
$$(L-epsilon)(1-delta)-deltalt fracf(alpha)g(alpha)lt(L+epsilon)+delta$$
If we take $delta=operatornamemin1,epsilon,epsilon/($ then
$$L-2epsilonle fracf(alpha)g(alpha)le L+2epsilon$$
I can't get the first inequality above. Also, shouldn't we get a strict inequality on the right side? I've tried some manipulations but all have been unsuccessful in getting that. How can I show this part?
real-analysis analysis
$endgroup$
add a comment |
$begingroup$
I'm following the proof of L'Hospital's Rule from a text but have trouble understanding this part regarding epsilon-delta.
Assume $Lgt 0$ and $epsilon gt 0$ is given and $delta in (0,1)$. What we have is
$$(L-epsilon)(1-delta)-deltalt fracf(alpha)g(alpha)lt(L+epsilon)+delta$$
If we take $delta=operatornamemin1,epsilon,epsilon/($ then
$$L-2epsilonle fracf(alpha)g(alpha)le L+2epsilon$$
I can't get the first inequality above. Also, shouldn't we get a strict inequality on the right side? I've tried some manipulations but all have been unsuccessful in getting that. How can I show this part?
real-analysis analysis
$endgroup$
add a comment |
$begingroup$
I'm following the proof of L'Hospital's Rule from a text but have trouble understanding this part regarding epsilon-delta.
Assume $Lgt 0$ and $epsilon gt 0$ is given and $delta in (0,1)$. What we have is
$$(L-epsilon)(1-delta)-deltalt fracf(alpha)g(alpha)lt(L+epsilon)+delta$$
If we take $delta=operatornamemin1,epsilon,epsilon/($ then
$$L-2epsilonle fracf(alpha)g(alpha)le L+2epsilon$$
I can't get the first inequality above. Also, shouldn't we get a strict inequality on the right side? I've tried some manipulations but all have been unsuccessful in getting that. How can I show this part?
real-analysis analysis
$endgroup$
I'm following the proof of L'Hospital's Rule from a text but have trouble understanding this part regarding epsilon-delta.
Assume $Lgt 0$ and $epsilon gt 0$ is given and $delta in (0,1)$. What we have is
$$(L-epsilon)(1-delta)-deltalt fracf(alpha)g(alpha)lt(L+epsilon)+delta$$
If we take $delta=operatornamemin1,epsilon,epsilon/($ then
$$L-2epsilonle fracf(alpha)g(alpha)le L+2epsilon$$
I can't get the first inequality above. Also, shouldn't we get a strict inequality on the right side? I've tried some manipulations but all have been unsuccessful in getting that. How can I show this part?
real-analysis analysis
real-analysis analysis
edited Mar 14 at 7:13
Winfield Chen
484
484
asked Mar 13 '15 at 0:23
takecaretakecare
2,34021537
2,34021537
add a comment |
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