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Translating a sentence into a predicate formula


Express statements using symbolic logicWhat does 'any' mean in predicate calculusWould including the outside quantifier make more sense/be logically correct?Translating English to QuantifiersTranslating English to symbolic logicOrder of statements in implicationTranslating this nested quantifier to english (negation of nested quantifiers)How do I translate sentences from English to predicate logic?Nested Quantifiers (And vs Implies)Need someone to check if I am reading nested quantifiers correctly













0












$begingroup$


Problem 3.40. (a) Translate the following sentence into a predicate formula:



There is a student who has e-mailed at most n other people in the class,
besides possibly himself.



The domain of discourse should be the set of students in the class; in addition, the only predicates that you may use are



  • equality,

  • E.x; y/, meaning that “x has sent e-mail to y.”

(b) Explain how you would use your predicate formula (or some variant of it) to
express the following two sentences.



  1. There is a student who has emailed at least n other people in the class, besides possibly himself.

  2. There is a student who has emailed exactly n other people in the class, besides possibly himself.









share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    Do you know quantifiers ? Like e.g. $exists x$
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:18










  • $begingroup$
    How are you asked to mange the "n" ? Do you know "numerical" quantifiers ? if not, Try with the simple cases : $n=1$ and $n=2$.
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:30











  • $begingroup$
    How we have to read "besides possibly himself" ? That we have to exclude himself from counting, I think...
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:31















0












$begingroup$


Problem 3.40. (a) Translate the following sentence into a predicate formula:



There is a student who has e-mailed at most n other people in the class,
besides possibly himself.



The domain of discourse should be the set of students in the class; in addition, the only predicates that you may use are



  • equality,

  • E.x; y/, meaning that “x has sent e-mail to y.”

(b) Explain how you would use your predicate formula (or some variant of it) to
express the following two sentences.



  1. There is a student who has emailed at least n other people in the class, besides possibly himself.

  2. There is a student who has emailed exactly n other people in the class, besides possibly himself.









share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    Do you know quantifiers ? Like e.g. $exists x$
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:18










  • $begingroup$
    How are you asked to mange the "n" ? Do you know "numerical" quantifiers ? if not, Try with the simple cases : $n=1$ and $n=2$.
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:30











  • $begingroup$
    How we have to read "besides possibly himself" ? That we have to exclude himself from counting, I think...
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:31













0












0








0





$begingroup$


Problem 3.40. (a) Translate the following sentence into a predicate formula:



There is a student who has e-mailed at most n other people in the class,
besides possibly himself.



The domain of discourse should be the set of students in the class; in addition, the only predicates that you may use are



  • equality,

  • E.x; y/, meaning that “x has sent e-mail to y.”

(b) Explain how you would use your predicate formula (or some variant of it) to
express the following two sentences.



  1. There is a student who has emailed at least n other people in the class, besides possibly himself.

  2. There is a student who has emailed exactly n other people in the class, besides possibly himself.









share|cite|improve this question











$endgroup$




Problem 3.40. (a) Translate the following sentence into a predicate formula:



There is a student who has e-mailed at most n other people in the class,
besides possibly himself.



The domain of discourse should be the set of students in the class; in addition, the only predicates that you may use are



  • equality,

  • E.x; y/, meaning that “x has sent e-mail to y.”

(b) Explain how you would use your predicate formula (or some variant of it) to
express the following two sentences.



  1. There is a student who has emailed at least n other people in the class, besides possibly himself.

  2. There is a student who has emailed exactly n other people in the class, besides possibly himself.






discrete-mathematics






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 23 at 16:25









N. F. Taussig

44.8k103358




44.8k103358










asked Jan 23 at 16:16









Jinlin LIJinlin LI

1




1







  • 1




    $begingroup$
    Do you know quantifiers ? Like e.g. $exists x$
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:18










  • $begingroup$
    How are you asked to mange the "n" ? Do you know "numerical" quantifiers ? if not, Try with the simple cases : $n=1$ and $n=2$.
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:30











  • $begingroup$
    How we have to read "besides possibly himself" ? That we have to exclude himself from counting, I think...
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:31












  • 1




    $begingroup$
    Do you know quantifiers ? Like e.g. $exists x$
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:18










  • $begingroup$
    How are you asked to mange the "n" ? Do you know "numerical" quantifiers ? if not, Try with the simple cases : $n=1$ and $n=2$.
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:30











  • $begingroup$
    How we have to read "besides possibly himself" ? That we have to exclude himself from counting, I think...
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 23 at 16:31







1




1




$begingroup$
Do you know quantifiers ? Like e.g. $exists x$
$endgroup$
– Mauro ALLEGRANZA
Jan 23 at 16:18




$begingroup$
Do you know quantifiers ? Like e.g. $exists x$
$endgroup$
– Mauro ALLEGRANZA
Jan 23 at 16:18












$begingroup$
How are you asked to mange the "n" ? Do you know "numerical" quantifiers ? if not, Try with the simple cases : $n=1$ and $n=2$.
$endgroup$
– Mauro ALLEGRANZA
Jan 23 at 16:30





$begingroup$
How are you asked to mange the "n" ? Do you know "numerical" quantifiers ? if not, Try with the simple cases : $n=1$ and $n=2$.
$endgroup$
– Mauro ALLEGRANZA
Jan 23 at 16:30













$begingroup$
How we have to read "besides possibly himself" ? That we have to exclude himself from counting, I think...
$endgroup$
– Mauro ALLEGRANZA
Jan 23 at 16:31




$begingroup$
How we have to read "besides possibly himself" ? That we have to exclude himself from counting, I think...
$endgroup$
– Mauro ALLEGRANZA
Jan 23 at 16:31










1 Answer
1






active

oldest

votes


















0












$begingroup$

Solution to part (a):
$
exists s Big((forall u ^neg E(s, u) ) land big( exists xexists y (xne y land y ne s land x ne s) land (E(s, x) lor E(s,y)) land forall z ((z ne x lor zne y lor z ne s) implies ^neg E(s,z))big) Big)
$




  • $(forall u ^neg E(s, u) )$ stands for the case that s does not send any one an email.


  • $ E(s, x) lor E(s,y)$ stands for 2 people


  • $forall z ((z ne x lor zne y lor z ne s) implies ^neg E(s,z))$ stands for at most 2 people





share|cite|improve this answer









$endgroup$












  • $begingroup$
    @MauroALLEGRANZA Sir, may you check whether this solution is correct?
    $endgroup$
    – 王文军 or Wenjun Wang
    Mar 14 at 7:59










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1 Answer
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active

oldest

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0












$begingroup$

Solution to part (a):
$
exists s Big((forall u ^neg E(s, u) ) land big( exists xexists y (xne y land y ne s land x ne s) land (E(s, x) lor E(s,y)) land forall z ((z ne x lor zne y lor z ne s) implies ^neg E(s,z))big) Big)
$




  • $(forall u ^neg E(s, u) )$ stands for the case that s does not send any one an email.


  • $ E(s, x) lor E(s,y)$ stands for 2 people


  • $forall z ((z ne x lor zne y lor z ne s) implies ^neg E(s,z))$ stands for at most 2 people





share|cite|improve this answer









$endgroup$












  • $begingroup$
    @MauroALLEGRANZA Sir, may you check whether this solution is correct?
    $endgroup$
    – 王文军 or Wenjun Wang
    Mar 14 at 7:59















0












$begingroup$

Solution to part (a):
$
exists s Big((forall u ^neg E(s, u) ) land big( exists xexists y (xne y land y ne s land x ne s) land (E(s, x) lor E(s,y)) land forall z ((z ne x lor zne y lor z ne s) implies ^neg E(s,z))big) Big)
$




  • $(forall u ^neg E(s, u) )$ stands for the case that s does not send any one an email.


  • $ E(s, x) lor E(s,y)$ stands for 2 people


  • $forall z ((z ne x lor zne y lor z ne s) implies ^neg E(s,z))$ stands for at most 2 people





share|cite|improve this answer









$endgroup$












  • $begingroup$
    @MauroALLEGRANZA Sir, may you check whether this solution is correct?
    $endgroup$
    – 王文军 or Wenjun Wang
    Mar 14 at 7:59













0












0








0





$begingroup$

Solution to part (a):
$
exists s Big((forall u ^neg E(s, u) ) land big( exists xexists y (xne y land y ne s land x ne s) land (E(s, x) lor E(s,y)) land forall z ((z ne x lor zne y lor z ne s) implies ^neg E(s,z))big) Big)
$




  • $(forall u ^neg E(s, u) )$ stands for the case that s does not send any one an email.


  • $ E(s, x) lor E(s,y)$ stands for 2 people


  • $forall z ((z ne x lor zne y lor z ne s) implies ^neg E(s,z))$ stands for at most 2 people





share|cite|improve this answer









$endgroup$



Solution to part (a):
$
exists s Big((forall u ^neg E(s, u) ) land big( exists xexists y (xne y land y ne s land x ne s) land (E(s, x) lor E(s,y)) land forall z ((z ne x lor zne y lor z ne s) implies ^neg E(s,z))big) Big)
$




  • $(forall u ^neg E(s, u) )$ stands for the case that s does not send any one an email.


  • $ E(s, x) lor E(s,y)$ stands for 2 people


  • $forall z ((z ne x lor zne y lor z ne s) implies ^neg E(s,z))$ stands for at most 2 people






share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Mar 14 at 7:48









王文军 or Wenjun Wang王文军 or Wenjun Wang

514




514











  • $begingroup$
    @MauroALLEGRANZA Sir, may you check whether this solution is correct?
    $endgroup$
    – 王文军 or Wenjun Wang
    Mar 14 at 7:59
















  • $begingroup$
    @MauroALLEGRANZA Sir, may you check whether this solution is correct?
    $endgroup$
    – 王文军 or Wenjun Wang
    Mar 14 at 7:59















$begingroup$
@MauroALLEGRANZA Sir, may you check whether this solution is correct?
$endgroup$
– 王文军 or Wenjun Wang
Mar 14 at 7:59




$begingroup$
@MauroALLEGRANZA Sir, may you check whether this solution is correct?
$endgroup$
– 王文军 or Wenjun Wang
Mar 14 at 7:59

















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