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How does this notation using theta mean a line or linear function?
Why does Andrew Ng use the form h(x) = Theta subscript 0 + Theta subscript 1 x instead of the more common slope-intercept form?Functions with subscripts?Deriving cost function using MLE :Why use log function?Cost Function of Neural Network (Forward Propagation)Meaning of symbols after the bar in probability notationProbabilistic Interpretation of Linear Regression: Why is the hypothesis function considered the mean of random variable y?(ML) Gradient Descent Step Simplication Question for Linear regressionwhy is the least square cost function for linear regression convexWhat does the semi colon in $(x(i),y(i));i=1,…,m$ mean?Why does Andrew Ng use the form h(x) = Theta subscript 0 + Theta subscript 1 x instead of the more common slope-intercept form?Derivation of partial derivative of cost function with respect to weights in backpropagation algorithm
$begingroup$
Question:
How does this notation using theta mean a line(ar function)?
Explanation:
I'm taking Andrew Ng's Machine Learning course on Coursera. He often uses math notation without explaining it. He says...
We're going to represent h as follows. And we will write this as
h (subscript theta) (x) equals theta (subscript one) plus theta (subscript one) of x. (see first green line of right of image below)
"h" above means hypothesis in machine learning but would commonly be called a function in math.
What I am really confused by and hoping for help understanding is ...
what does "theta (subscript one) plus theta (subscript one) of x" mean?
how does it represent a line or linear function?
I don't yet understand the correlation.
notation machine-learning
asked Sep 1 '18 at 17:54
Axle MaxAxle Max
297
$endgroup$
add a comment |
$begingroup$
Question:
How does this notation using theta mean a line(ar function)?
Explanation:
I'm taking Andrew Ng's Machine Learning course on Coursera. He often uses math notation without explaining it. He says...
We're going to represent h as follows. And we will write this as
h (subscript theta) (x) equals theta (subscript one) plus theta (subscript one) of x. (see first green line of right of image below)
"h" above means hypothesis in machine learning but would commonly be called a function in math.
What I am really confused by and hoping for help understanding is ...
what does "theta (subscript one) plus theta (subscript one) of x" mean?
how does it represent a line or linear function?
I don't yet understand the correlation.
notation machine-learning
asked Sep 1 '18 at 17:54
Axle MaxAxle Max
297
$endgroup$
add a comment |
$begingroup$
Question:
How does this notation using theta mean a line(ar function)?
Explanation:
I'm taking Andrew Ng's Machine Learning course on Coursera. He often uses math notation without explaining it. He says...
We're going to represent h as follows. And we will write this as
h (subscript theta) (x) equals theta (subscript one) plus theta (subscript one) of x. (see first green line of right of image below)
"h" above means hypothesis in machine learning but would commonly be called a function in math.
What I am really confused by and hoping for help understanding is ...
what does "theta (subscript one) plus theta (subscript one) of x" mean?
how does it represent a line or linear function?
I don't yet understand the correlation.
notation machine-learning
asked Sep 1 '18 at 17:54
Axle MaxAxle Max
297
$endgroup$
Question:
How does this notation using theta mean a line(ar function)?
Explanation:
I'm taking Andrew Ng's Machine Learning course on Coursera. He often uses math notation without explaining it. He says...
We're going to represent h as follows. And we will write this as
h (subscript theta) (x) equals theta (subscript one) plus theta (subscript one) of x. (see first green line of right of image below)
"h" above means hypothesis in machine learning but would commonly be called a function in math.
What I am really confused by and hoping for help understanding is ...
what does "theta (subscript one) plus theta (subscript one) of x" mean?
how does it represent a line or linear function?
I don't yet understand the correlation.
notation machine-learning
notation machine-learning
asked Sep 1 '18 at 17:54
Axle MaxAxle Max
297
asked Sep 1 '18 at 17:54
Axle MaxAxle Max
297
asked Sep 1 '18 at 17:54
Axle MaxAxle Max
297
asked Sep 1 '18 at 17:54
Axle MaxAxle Max
297
asked Sep 1 '18 at 17:54
Axle MaxAxle Max
297
297
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
A more popular form of a straight line would be $$y=mx+c$$
Here $theta_0$ corresponds to $c$ which is the intercept.
and $theta_1$ corresponds to $m$ which is the gradient.
answered Sep 1 '18 at 17:57
Siong Thye GohSiong Thye Goh
103k1468119
$endgroup$
$begingroup$
Wow! It took me a while to understand your answer but it's really elegant. Thank you. So c is the intercept because when x = 0, y = c. and m is the gradient because m determines the slope. Cool.
$endgroup$
– Axle Max
Sep 2 '18 at 7:20
$begingroup$
2 more questions: 1. Is theta used here for a reason? Or is it a convention of some kind? 2. Is the use of Theta here a reference to the polar coordinate system or is it just coincidence?
$endgroup$
– Axle Max
Sep 2 '18 at 7:22
2
$begingroup$
it is just a symbol, it is not relevant to polar coordinate. another common notation is $beta$ for this setting. They are parameters that we have to estimate in this setting.
$endgroup$
– Siong Thye Goh
Sep 2 '18 at 11:42
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
A more popular form of a straight line would be $$y=mx+c$$
Here $theta_0$ corresponds to $c$ which is the intercept.
and $theta_1$ corresponds to $m$ which is the gradient.
answered Sep 1 '18 at 17:57
Siong Thye GohSiong Thye Goh
103k1468119
$endgroup$
$begingroup$
Wow! It took me a while to understand your answer but it's really elegant. Thank you. So c is the intercept because when x = 0, y = c. and m is the gradient because m determines the slope. Cool.
$endgroup$
– Axle Max
Sep 2 '18 at 7:20
$begingroup$
2 more questions: 1. Is theta used here for a reason? Or is it a convention of some kind? 2. Is the use of Theta here a reference to the polar coordinate system or is it just coincidence?
$endgroup$
– Axle Max
Sep 2 '18 at 7:22
2
$begingroup$
it is just a symbol, it is not relevant to polar coordinate. another common notation is $beta$ for this setting. They are parameters that we have to estimate in this setting.
$endgroup$
– Siong Thye Goh
Sep 2 '18 at 11:42
add a comment |
$begingroup$
A more popular form of a straight line would be $$y=mx+c$$
Here $theta_0$ corresponds to $c$ which is the intercept.
and $theta_1$ corresponds to $m$ which is the gradient.
answered Sep 1 '18 at 17:57
Siong Thye GohSiong Thye Goh
103k1468119
$endgroup$
$begingroup$
Wow! It took me a while to understand your answer but it's really elegant. Thank you. So c is the intercept because when x = 0, y = c. and m is the gradient because m determines the slope. Cool.
$endgroup$
– Axle Max
Sep 2 '18 at 7:20
$begingroup$
2 more questions: 1. Is theta used here for a reason? Or is it a convention of some kind? 2. Is the use of Theta here a reference to the polar coordinate system or is it just coincidence?
$endgroup$
– Axle Max
Sep 2 '18 at 7:22
2
$begingroup$
it is just a symbol, it is not relevant to polar coordinate. another common notation is $beta$ for this setting. They are parameters that we have to estimate in this setting.
$endgroup$
– Siong Thye Goh
Sep 2 '18 at 11:42
add a comment |
$begingroup$
A more popular form of a straight line would be $$y=mx+c$$
Here $theta_0$ corresponds to $c$ which is the intercept.
and $theta_1$ corresponds to $m$ which is the gradient.
answered Sep 1 '18 at 17:57
Siong Thye GohSiong Thye Goh
103k1468119
$endgroup$
A more popular form of a straight line would be $$y=mx+c$$
Here $theta_0$ corresponds to $c$ which is the intercept.
and $theta_1$ corresponds to $m$ which is the gradient.
answered Sep 1 '18 at 17:57
Siong Thye GohSiong Thye Goh
103k1468119
answered Sep 1 '18 at 17:57
Siong Thye GohSiong Thye Goh
103k1468119
answered Sep 1 '18 at 17:57
Siong Thye GohSiong Thye Goh
103k1468119
answered Sep 1 '18 at 17:57
Siong Thye GohSiong Thye Goh
103k1468119
103k1468119
$begingroup$
Wow! It took me a while to understand your answer but it's really elegant. Thank you. So c is the intercept because when x = 0, y = c. and m is the gradient because m determines the slope. Cool.
$endgroup$
– Axle Max
Sep 2 '18 at 7:20
$begingroup$
2 more questions: 1. Is theta used here for a reason? Or is it a convention of some kind? 2. Is the use of Theta here a reference to the polar coordinate system or is it just coincidence?
$endgroup$
– Axle Max
Sep 2 '18 at 7:22
2
$begingroup$
it is just a symbol, it is not relevant to polar coordinate. another common notation is $beta$ for this setting. They are parameters that we have to estimate in this setting.
$endgroup$
– Siong Thye Goh
Sep 2 '18 at 11:42
add a comment |
$begingroup$
Wow! It took me a while to understand your answer but it's really elegant. Thank you. So c is the intercept because when x = 0, y = c. and m is the gradient because m determines the slope. Cool.
$endgroup$
– Axle Max
Sep 2 '18 at 7:20
$begingroup$
2 more questions: 1. Is theta used here for a reason? Or is it a convention of some kind? 2. Is the use of Theta here a reference to the polar coordinate system or is it just coincidence?
$endgroup$
– Axle Max
Sep 2 '18 at 7:22
2
$begingroup$
it is just a symbol, it is not relevant to polar coordinate. another common notation is $beta$ for this setting. They are parameters that we have to estimate in this setting.
$endgroup$
– Siong Thye Goh
Sep 2 '18 at 11:42
$begingroup$
Wow! It took me a while to understand your answer but it's really elegant. Thank you. So c is the intercept because when x = 0, y = c. and m is the gradient because m determines the slope. Cool.
$endgroup$
– Axle Max
Sep 2 '18 at 7:20
$begingroup$
Wow! It took me a while to understand your answer but it's really elegant. Thank you. So c is the intercept because when x = 0, y = c. and m is the gradient because m determines the slope. Cool.
$endgroup$
– Axle Max
Sep 2 '18 at 7:20
$begingroup$
2 more questions: 1. Is theta used here for a reason? Or is it a convention of some kind? 2. Is the use of Theta here a reference to the polar coordinate system or is it just coincidence?
$endgroup$
– Axle Max
Sep 2 '18 at 7:22
$begingroup$
2 more questions: 1. Is theta used here for a reason? Or is it a convention of some kind? 2. Is the use of Theta here a reference to the polar coordinate system or is it just coincidence?
$endgroup$
– Axle Max
Sep 2 '18 at 7:22
2
2
$begingroup$
it is just a symbol, it is not relevant to polar coordinate. another common notation is $beta$ for this setting. They are parameters that we have to estimate in this setting.
$endgroup$
– Siong Thye Goh
Sep 2 '18 at 11:42
$begingroup$
it is just a symbol, it is not relevant to polar coordinate. another common notation is $beta$ for this setting. They are parameters that we have to estimate in this setting.
$endgroup$
– Siong Thye Goh
Sep 2 '18 at 11:42
add a comment |
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