Why is $cos pi x$ needed in $sumlimits_n=-infty^infty g(n)=frac12ioint_=inftyfraccos pi xsin pi xg(x),mathrm dx$? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Find $I:=limlimits_Rto inftyintlimits_-R^R fracx sin(3x)x ^2+4dx$ using residuesContour Integration $frac1sin z cos z$Computing $sumlimits_n=1^inftyfracsin nn$ with residuesIs there a way to compute $int_0^infty fraccos (qt) J_1 (qr)1+q^2 , mathrmd q$ provided that $0<t<r$?Why this :$sumlimits_n=1^inftyfrac1nsin n$ is not harmonic series and is convergent?Evaluating $int_-infty^infty fracxsin(kx)x^2+a^2 ,mathrm dx$ using complex analysisSumming a trigonometric series, $sumlimits_n=1^infty fracsin nxn$Why is $sumlimits_n=N+1^infty frac 12^n! < sumlimits_n=(N+1)!^infty frac 12^n = frac12^(N+1)!-1$Complex integral $oint_=1 fracz^2sin^3 z cos z dz$Generalizing $sumlimits_mgeq1sumlimits_ngeq1frac(-1)^nn^3sin(n/m^2k)=frac112zeta(6k)-fracpi^212zeta(2k)$
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Why is $cos pi x$ needed in $sumlimits_n=-infty^infty g(n)=frac12ioint_=inftyfraccos pi xsin pi xg(x),mathrm dx$?
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Find $I:=limlimits_Rto inftyintlimits_-R^R fracx sin(3x)x ^2+4dx$ using residuesContour Integration $frac1sin z cos z$Computing $sumlimits_n=1^inftyfracsin nn$ with residuesIs there a way to compute $int_0^infty fraccos (qt) J_1 (qr)1+q^2 , mathrmd q$ provided that $0<t<r$?Why this :$sumlimits_n=1^inftyfrac1nsin n$ is not harmonic series and is convergent?Evaluating $int_-infty^infty fracxsin(kx)x^2+a^2 ,mathrm dx$ using complex analysisSumming a trigonometric series, $sumlimits_n=1^infty fracsin nxn$Why is $sumlimits_n=N+1^infty frac 12^n! < sumlimits_n=(N+1)!^infty frac 12^n = frac12^(N+1)!-1$Complex integral $oint_=1 fracz^2sin^3 z cos z dz$Generalizing $sumlimits_mgeq1sumlimits_ngeq1frac(-1)^nn^3sin(n/m^2k)=frac112zeta(6k)-fracpi^212zeta(2k)$
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I am trying to prove this sum formula:$$sum_n=-infty^infty g(n)=frac12ioint_=inftyfraccos pi xsin pi xg(x),mathrm dx.$$I do not understand why $cos pi x$ is needed here. This is because poles of $sin pi x$ are at $x=0,pm 1,pm 2,cdots$
Any help will be highly appreciated.
sequences-and-series complex-analysis contour-integration
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show 7 more comments
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I am trying to prove this sum formula:$$sum_n=-infty^infty g(n)=frac12ioint_=inftyfraccos pi xsin pi xg(x),mathrm dx.$$I do not understand why $cos pi x$ is needed here. This is because poles of $sin pi x$ are at $x=0,pm 1,pm 2,cdots$
Any help will be highly appreciated.
sequences-and-series complex-analysis contour-integration
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What are you integrating over?
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– greelious
Dec 6 '18 at 2:38
4
$begingroup$
Up to issue how should one take the limit, one has $$frac1sinpi x = sumlimits_k=-infty^infty frac1(x-k)(sin(pi x)') = sumlimits_k=-infty^infty frac(-1)^kpi(x-k)$$ The $cos(pi x)$ factor is there to get rid of the $(-1)^k$ factor in the residues.
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– achille hui
Dec 6 '18 at 3:01
1
$begingroup$
@user302797 Using unicode to replace correct mathJAX markup is not acceptable. As the system won't know how to replace the unicode on different rendering engine and expression may not scale/style properly.
$endgroup$
– achille hui
Dec 6 '18 at 3:15
1
$begingroup$
It is better to use MathJax to encode mathematical characters. It is true that most browsers can render unicode, however, if the characters are encoded using MathJax, MathJax can manage effects like styling and sizing better.
$endgroup$
– robjohn♦
Dec 6 '18 at 5:29
1
$begingroup$
Note that inlargepiπ: $largepiπ$, the first is italic, which is in keeping with the other characters rendered in MathJax, like $abc$. Roman characters are usually used for operator names like $sin(x)$ and $log(x)$. See this meta question
$endgroup$
– robjohn♦
Dec 6 '18 at 5:35
|
show 7 more comments
$begingroup$
I am trying to prove this sum formula:$$sum_n=-infty^infty g(n)=frac12ioint_=inftyfraccos pi xsin pi xg(x),mathrm dx.$$I do not understand why $cos pi x$ is needed here. This is because poles of $sin pi x$ are at $x=0,pm 1,pm 2,cdots$
Any help will be highly appreciated.
sequences-and-series complex-analysis contour-integration
$endgroup$
I am trying to prove this sum formula:$$sum_n=-infty^infty g(n)=frac12ioint_=inftyfraccos pi xsin pi xg(x),mathrm dx.$$I do not understand why $cos pi x$ is needed here. This is because poles of $sin pi x$ are at $x=0,pm 1,pm 2,cdots$
Any help will be highly appreciated.
sequences-and-series complex-analysis contour-integration
sequences-and-series complex-analysis contour-integration
edited Mar 26 at 6:26
J. M. is a poor mathematician
61.3k5152291
61.3k5152291
asked Dec 6 '18 at 2:30
Hazoor ImranHazoor Imran
161
161
$begingroup$
What are you integrating over?
$endgroup$
– greelious
Dec 6 '18 at 2:38
4
$begingroup$
Up to issue how should one take the limit, one has $$frac1sinpi x = sumlimits_k=-infty^infty frac1(x-k)(sin(pi x)') = sumlimits_k=-infty^infty frac(-1)^kpi(x-k)$$ The $cos(pi x)$ factor is there to get rid of the $(-1)^k$ factor in the residues.
$endgroup$
– achille hui
Dec 6 '18 at 3:01
1
$begingroup$
@user302797 Using unicode to replace correct mathJAX markup is not acceptable. As the system won't know how to replace the unicode on different rendering engine and expression may not scale/style properly.
$endgroup$
– achille hui
Dec 6 '18 at 3:15
1
$begingroup$
It is better to use MathJax to encode mathematical characters. It is true that most browsers can render unicode, however, if the characters are encoded using MathJax, MathJax can manage effects like styling and sizing better.
$endgroup$
– robjohn♦
Dec 6 '18 at 5:29
1
$begingroup$
Note that inlargepiπ: $largepiπ$, the first is italic, which is in keeping with the other characters rendered in MathJax, like $abc$. Roman characters are usually used for operator names like $sin(x)$ and $log(x)$. See this meta question
$endgroup$
– robjohn♦
Dec 6 '18 at 5:35
|
show 7 more comments
$begingroup$
What are you integrating over?
$endgroup$
– greelious
Dec 6 '18 at 2:38
4
$begingroup$
Up to issue how should one take the limit, one has $$frac1sinpi x = sumlimits_k=-infty^infty frac1(x-k)(sin(pi x)') = sumlimits_k=-infty^infty frac(-1)^kpi(x-k)$$ The $cos(pi x)$ factor is there to get rid of the $(-1)^k$ factor in the residues.
$endgroup$
– achille hui
Dec 6 '18 at 3:01
1
$begingroup$
@user302797 Using unicode to replace correct mathJAX markup is not acceptable. As the system won't know how to replace the unicode on different rendering engine and expression may not scale/style properly.
$endgroup$
– achille hui
Dec 6 '18 at 3:15
1
$begingroup$
It is better to use MathJax to encode mathematical characters. It is true that most browsers can render unicode, however, if the characters are encoded using MathJax, MathJax can manage effects like styling and sizing better.
$endgroup$
– robjohn♦
Dec 6 '18 at 5:29
1
$begingroup$
Note that inlargepiπ: $largepiπ$, the first is italic, which is in keeping with the other characters rendered in MathJax, like $abc$. Roman characters are usually used for operator names like $sin(x)$ and $log(x)$. See this meta question
$endgroup$
– robjohn♦
Dec 6 '18 at 5:35
$begingroup$
What are you integrating over?
$endgroup$
– greelious
Dec 6 '18 at 2:38
$begingroup$
What are you integrating over?
$endgroup$
– greelious
Dec 6 '18 at 2:38
4
4
$begingroup$
Up to issue how should one take the limit, one has $$frac1sinpi x = sumlimits_k=-infty^infty frac1(x-k)(sin(pi x)') = sumlimits_k=-infty^infty frac(-1)^kpi(x-k)$$ The $cos(pi x)$ factor is there to get rid of the $(-1)^k$ factor in the residues.
$endgroup$
– achille hui
Dec 6 '18 at 3:01
$begingroup$
Up to issue how should one take the limit, one has $$frac1sinpi x = sumlimits_k=-infty^infty frac1(x-k)(sin(pi x)') = sumlimits_k=-infty^infty frac(-1)^kpi(x-k)$$ The $cos(pi x)$ factor is there to get rid of the $(-1)^k$ factor in the residues.
$endgroup$
– achille hui
Dec 6 '18 at 3:01
1
1
$begingroup$
@user302797 Using unicode to replace correct mathJAX markup is not acceptable. As the system won't know how to replace the unicode on different rendering engine and expression may not scale/style properly.
$endgroup$
– achille hui
Dec 6 '18 at 3:15
$begingroup$
@user302797 Using unicode to replace correct mathJAX markup is not acceptable. As the system won't know how to replace the unicode on different rendering engine and expression may not scale/style properly.
$endgroup$
– achille hui
Dec 6 '18 at 3:15
1
1
$begingroup$
It is better to use MathJax to encode mathematical characters. It is true that most browsers can render unicode, however, if the characters are encoded using MathJax, MathJax can manage effects like styling and sizing better.
$endgroup$
– robjohn♦
Dec 6 '18 at 5:29
$begingroup$
It is better to use MathJax to encode mathematical characters. It is true that most browsers can render unicode, however, if the characters are encoded using MathJax, MathJax can manage effects like styling and sizing better.
$endgroup$
– robjohn♦
Dec 6 '18 at 5:29
1
1
$begingroup$
Note that in
largepiπ: $largepiπ$, the first is italic, which is in keeping with the other characters rendered in MathJax, like $abc$. Roman characters are usually used for operator names like $sin(x)$ and $log(x)$. See this meta question$endgroup$
– robjohn♦
Dec 6 '18 at 5:35
$begingroup$
Note that in
largepiπ: $largepiπ$, the first is italic, which is in keeping with the other characters rendered in MathJax, like $abc$. Roman characters are usually used for operator names like $sin(x)$ and $log(x)$. See this meta question$endgroup$
– robjohn♦
Dec 6 '18 at 5:35
|
show 7 more comments
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$begingroup$
What are you integrating over?
$endgroup$
– greelious
Dec 6 '18 at 2:38
4
$begingroup$
Up to issue how should one take the limit, one has $$frac1sinpi x = sumlimits_k=-infty^infty frac1(x-k)(sin(pi x)') = sumlimits_k=-infty^infty frac(-1)^kpi(x-k)$$ The $cos(pi x)$ factor is there to get rid of the $(-1)^k$ factor in the residues.
$endgroup$
– achille hui
Dec 6 '18 at 3:01
1
$begingroup$
@user302797 Using unicode to replace correct mathJAX markup is not acceptable. As the system won't know how to replace the unicode on different rendering engine and expression may not scale/style properly.
$endgroup$
– achille hui
Dec 6 '18 at 3:15
1
$begingroup$
It is better to use MathJax to encode mathematical characters. It is true that most browsers can render unicode, however, if the characters are encoded using MathJax, MathJax can manage effects like styling and sizing better.
$endgroup$
– robjohn♦
Dec 6 '18 at 5:29
1
$begingroup$
Note that in
largepiπ: $largepiπ$, the first is italic, which is in keeping with the other characters rendered in MathJax, like $abc$. Roman characters are usually used for operator names like $sin(x)$ and $log(x)$. See this meta question$endgroup$
– robjohn♦
Dec 6 '18 at 5:35