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What does do double vertical bars with numerical parameters on the right hand side mean?
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)What do vertical bars with an index mean?Meaning of double vertical bars in context: “let $q$ be a prime divisor of $n$ with $q^s|| n$.”What does double vertical lines $|$ mean in number theory?For a function $q(t,x,y)$, what does $q^*$, $q_x^*$ mean?Double vertical barswhat does this derivative notation mean in General Relativity?What does subtraction on linear tranforms mean?What do the two (double) vertical bars mean in this equation?What does Kx mean in this equation? [in Carnap or Russell and Whitehead's logical notation]What does an equal sign mean in a parenthesis?
$begingroup$
In the following equation, $$large R(Y) = lambda left| frac x^top Y right|^2_2$$ What do the double bars with range $2$ to $2$ on the right hand side mean? I need to work with this equation, but I don't understand what it is doing. Note, $x$ and $Y$ are both matrices, and $lambda$ is just a constant.
notation
edited Mar 26 at 9:00
Rócherz
3,0263823
asked Mar 26 at 8:38
AdamAdam
82
$endgroup$
add a comment |
$begingroup$
In the following equation, $$large R(Y) = lambda left| frac x^top Y right|^2_2$$ What do the double bars with range $2$ to $2$ on the right hand side mean? I need to work with this equation, but I don't understand what it is doing. Note, $x$ and $Y$ are both matrices, and $lambda$ is just a constant.
notation
edited Mar 26 at 9:00
Rócherz
3,0263823
asked Mar 26 at 8:38
AdamAdam
82
$endgroup$
$begingroup$
Welcome to SE. Don’t forget to accept the post below if you feel it helps.
$endgroup$
– Richard Ambler
Mar 26 at 9:05
add a comment |
$begingroup$
In the following equation, $$large R(Y) = lambda left| frac x^top Y right|^2_2$$ What do the double bars with range $2$ to $2$ on the right hand side mean? I need to work with this equation, but I don't understand what it is doing. Note, $x$ and $Y$ are both matrices, and $lambda$ is just a constant.
notation
edited Mar 26 at 9:00
Rócherz
3,0263823
asked Mar 26 at 8:38
AdamAdam
82
$endgroup$
In the following equation, $$large R(Y) = lambda left| frac x^top Y right|^2_2$$ What do the double bars with range $2$ to $2$ on the right hand side mean? I need to work with this equation, but I don't understand what it is doing. Note, $x$ and $Y$ are both matrices, and $lambda$ is just a constant.
notation
notation
edited Mar 26 at 9:00
Rócherz
3,0263823
asked Mar 26 at 8:38
AdamAdam
82
edited Mar 26 at 9:00
Rócherz
3,0263823
asked Mar 26 at 8:38
AdamAdam
82
edited Mar 26 at 9:00
Rócherz
3,0263823
edited Mar 26 at 9:00
Rócherz
3,0263823
edited Mar 26 at 9:00
Rócherz
3,0263823
3,0263823
asked Mar 26 at 8:38
AdamAdam
82
asked Mar 26 at 8:38
AdamAdam
82
asked Mar 26 at 8:38
AdamAdam
82
82
$begingroup$
Welcome to SE. Don’t forget to accept the post below if you feel it helps.
$endgroup$
– Richard Ambler
Mar 26 at 9:05
add a comment |
$begingroup$
Welcome to SE. Don’t forget to accept the post below if you feel it helps.
$endgroup$
– Richard Ambler
Mar 26 at 9:05
$begingroup$
Welcome to SE. Don’t forget to accept the post below if you feel it helps.
$endgroup$
– Richard Ambler
Mar 26 at 9:05
$begingroup$
Welcome to SE. Don’t forget to accept the post below if you feel it helps.
$endgroup$
– Richard Ambler
Mar 26 at 9:05
add a comment |
1 Answer
1
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$begingroup$
In the notation
$$left|xright|_colorblue2^colorred2$$
- the top (red) $colorred2$ simply means squaring, as in $x^2$;
- the bottom (blue) $colorblue2$ refers to the fact that it's the "2-norm", the standard Euclidean norm.
See here for the more general $p$-norm, of which this is a special case:
$$left| x right| _p = left( |x_1|^p + |x_2|^p + dotsb + |x_n|^p right) ^1/p$$
answered Mar 26 at 8:47
StackTDStackTD
24.3k2254
$endgroup$
$begingroup$
Thank you so much! I was so lost as to what that was supposed to mean!
$endgroup$
– Adam
Mar 26 at 8:52
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
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active
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votes
$begingroup$
In the notation
$$left|xright|_colorblue2^colorred2$$
- the top (red) $colorred2$ simply means squaring, as in $x^2$;
- the bottom (blue) $colorblue2$ refers to the fact that it's the "2-norm", the standard Euclidean norm.
See here for the more general $p$-norm, of which this is a special case:
$$left| x right| _p = left( |x_1|^p + |x_2|^p + dotsb + |x_n|^p right) ^1/p$$
answered Mar 26 at 8:47
StackTDStackTD
24.3k2254
$endgroup$
$begingroup$
Thank you so much! I was so lost as to what that was supposed to mean!
$endgroup$
– Adam
Mar 26 at 8:52
add a comment |
$begingroup$
In the notation
$$left|xright|_colorblue2^colorred2$$
- the top (red) $colorred2$ simply means squaring, as in $x^2$;
- the bottom (blue) $colorblue2$ refers to the fact that it's the "2-norm", the standard Euclidean norm.
See here for the more general $p$-norm, of which this is a special case:
$$left| x right| _p = left( |x_1|^p + |x_2|^p + dotsb + |x_n|^p right) ^1/p$$
answered Mar 26 at 8:47
StackTDStackTD
24.3k2254
$endgroup$
$begingroup$
Thank you so much! I was so lost as to what that was supposed to mean!
$endgroup$
– Adam
Mar 26 at 8:52
add a comment |
$begingroup$
In the notation
$$left|xright|_colorblue2^colorred2$$
- the top (red) $colorred2$ simply means squaring, as in $x^2$;
- the bottom (blue) $colorblue2$ refers to the fact that it's the "2-norm", the standard Euclidean norm.
See here for the more general $p$-norm, of which this is a special case:
$$left| x right| _p = left( |x_1|^p + |x_2|^p + dotsb + |x_n|^p right) ^1/p$$
answered Mar 26 at 8:47
StackTDStackTD
24.3k2254
$endgroup$
In the notation
$$left|xright|_colorblue2^colorred2$$
- the top (red) $colorred2$ simply means squaring, as in $x^2$;
- the bottom (blue) $colorblue2$ refers to the fact that it's the "2-norm", the standard Euclidean norm.
See here for the more general $p$-norm, of which this is a special case:
$$left| x right| _p = left( |x_1|^p + |x_2|^p + dotsb + |x_n|^p right) ^1/p$$
answered Mar 26 at 8:47
StackTDStackTD
24.3k2254
answered Mar 26 at 8:47
StackTDStackTD
24.3k2254
answered Mar 26 at 8:47
StackTDStackTD
24.3k2254
answered Mar 26 at 8:47
StackTDStackTD
24.3k2254
24.3k2254
$begingroup$
Thank you so much! I was so lost as to what that was supposed to mean!
$endgroup$
– Adam
Mar 26 at 8:52
add a comment |
$begingroup$
Thank you so much! I was so lost as to what that was supposed to mean!
$endgroup$
– Adam
Mar 26 at 8:52
$begingroup$
Thank you so much! I was so lost as to what that was supposed to mean!
$endgroup$
– Adam
Mar 26 at 8:52
$begingroup$
Thank you so much! I was so lost as to what that was supposed to mean!
$endgroup$
– Adam
Mar 26 at 8:52
add a comment |
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