How to get the Standard Deviation based on the sample Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Sample Standard Deviation vs. Population Standard DeviationHow to calculate signifiance on an A/B test on revenuestandard deviation of binned sampleEstimate standard deviation of sampleCalculating the sample standard deviationsample standard deviation given population standard deviationHow to get the population standard deviation from a sample standard deviatoinProblem with Sample Standard DeviationSample or Poulation standard deviationEstimating the standard deviation based on sample

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How to get the Standard Deviation based on the sample



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Sample Standard Deviation vs. Population Standard DeviationHow to calculate signifiance on an A/B test on revenuestandard deviation of binned sampleEstimate standard deviation of sampleCalculating the sample standard deviationsample standard deviation given population standard deviationHow to get the population standard deviation from a sample standard deviatoinProblem with Sample Standard DeviationSample or Poulation standard deviationEstimating the standard deviation based on sample










0












$begingroup$


The situation is I have 96 sets of paper, 22 questions categorized into 5 categories.Every options consisting marks of 0,1,2,3,4.



| | 0 | 1 | 2 | 3 | 4 |
|-----|-----|-----|-----|-----|-----|
| A | 5 | 42 | 71 | 116 | 150 |
| B | 7 | 43 | 94 | 136 | 104 |
| C | 0 | 47 | 118 | 175 | 140 |
| D | 0 | 13 | 40 | 123 | 112 |
| E | 0 | 148 | 183 | 175 | 70 |

Category A consists of 4 questions
Category B consists of 4 questions
Category C consists of 5 questions
Category D consists of 3 questions
Category E consists of 6 questions


For A:




Total: $(5*0)+(42*1)+(71*2)+(116*3)+(150*4) = 1132$



Avg: $(1132/96$ sets)$/4$ questions $= 2.94$



STDEV: ?











share|cite|improve this question











$endgroup$
















    0












    $begingroup$


    The situation is I have 96 sets of paper, 22 questions categorized into 5 categories.Every options consisting marks of 0,1,2,3,4.



    | | 0 | 1 | 2 | 3 | 4 |
    |-----|-----|-----|-----|-----|-----|
    | A | 5 | 42 | 71 | 116 | 150 |
    | B | 7 | 43 | 94 | 136 | 104 |
    | C | 0 | 47 | 118 | 175 | 140 |
    | D | 0 | 13 | 40 | 123 | 112 |
    | E | 0 | 148 | 183 | 175 | 70 |

    Category A consists of 4 questions
    Category B consists of 4 questions
    Category C consists of 5 questions
    Category D consists of 3 questions
    Category E consists of 6 questions


    For A:




    Total: $(5*0)+(42*1)+(71*2)+(116*3)+(150*4) = 1132$



    Avg: $(1132/96$ sets)$/4$ questions $= 2.94$



    STDEV: ?











    share|cite|improve this question











    $endgroup$














      0












      0








      0





      $begingroup$


      The situation is I have 96 sets of paper, 22 questions categorized into 5 categories.Every options consisting marks of 0,1,2,3,4.



      | | 0 | 1 | 2 | 3 | 4 |
      |-----|-----|-----|-----|-----|-----|
      | A | 5 | 42 | 71 | 116 | 150 |
      | B | 7 | 43 | 94 | 136 | 104 |
      | C | 0 | 47 | 118 | 175 | 140 |
      | D | 0 | 13 | 40 | 123 | 112 |
      | E | 0 | 148 | 183 | 175 | 70 |

      Category A consists of 4 questions
      Category B consists of 4 questions
      Category C consists of 5 questions
      Category D consists of 3 questions
      Category E consists of 6 questions


      For A:




      Total: $(5*0)+(42*1)+(71*2)+(116*3)+(150*4) = 1132$



      Avg: $(1132/96$ sets)$/4$ questions $= 2.94$



      STDEV: ?











      share|cite|improve this question











      $endgroup$




      The situation is I have 96 sets of paper, 22 questions categorized into 5 categories.Every options consisting marks of 0,1,2,3,4.



      | | 0 | 1 | 2 | 3 | 4 |
      |-----|-----|-----|-----|-----|-----|
      | A | 5 | 42 | 71 | 116 | 150 |
      | B | 7 | 43 | 94 | 136 | 104 |
      | C | 0 | 47 | 118 | 175 | 140 |
      | D | 0 | 13 | 40 | 123 | 112 |
      | E | 0 | 148 | 183 | 175 | 70 |

      Category A consists of 4 questions
      Category B consists of 4 questions
      Category C consists of 5 questions
      Category D consists of 3 questions
      Category E consists of 6 questions


      For A:




      Total: $(5*0)+(42*1)+(71*2)+(116*3)+(150*4) = 1132$



      Avg: $(1132/96$ sets)$/4$ questions $= 2.94$



      STDEV: ?








      analysis statistics standard-deviation






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 26 at 9:55









      YuiTo Cheng

      2,43841037




      2,43841037










      asked Mar 26 at 9:52









      1myb1myb

      1011




      1011




















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