Question on elementary Linear Algebra product Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Linear Algebra - Finding the matrix for the transformationMonotonicity of $log det R(d_i, d_j)$Maximizing the smallest eigenvalue of a linear combination of matricesReflection Matrix linear algebraDo four dimensional vectors have a cross product property?Show that $A^TA=I=AA^T$ imposes $frac12n(n+1)$ conditions on the elements of $A$.Linear algebra: Proving uniqueness and existence of a functionSet of linear algebra questionsSimplifying a dot and cross product expressionHow to apply the Cauchy-Schwartz inequality on the following inner product?
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Question on elementary Linear Algebra product
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Linear Algebra - Finding the matrix for the transformationMonotonicity of $log det R(d_i, d_j)$Maximizing the smallest eigenvalue of a linear combination of matricesReflection Matrix linear algebraDo four dimensional vectors have a cross product property?Show that $A^TA=I=AA^T$ imposes $frac12n(n+1)$ conditions on the elements of $A$.Linear algebra: Proving uniqueness and existence of a functionSet of linear algebra questionsSimplifying a dot and cross product expressionHow to apply the Cauchy-Schwartz inequality on the following inner product?
$begingroup$
I came across this in a problem:
$$fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1mathbfumathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu$$
Then, in order to simplify this, I thought the following:
begingather
fracmathbfumathbfv^TmathbfA^-1+mathbfucolorredleft(mathbfv^TmathbfA^-1mathbfuright)mathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1colorredleft(mathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1left(1+colorredmathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
mathbfumathbfv^TmathbfA^-1
endgather
I figured that this could be done because of associativity and as the terms in $colorredtextred$ result in a scalar, it could be 'moved around'. Is this correct? If yes, does this always hold or are there any conditions on the vectors and matrices involved?
matrices vectors
$endgroup$
add a comment |
$begingroup$
I came across this in a problem:
$$fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1mathbfumathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu$$
Then, in order to simplify this, I thought the following:
begingather
fracmathbfumathbfv^TmathbfA^-1+mathbfucolorredleft(mathbfv^TmathbfA^-1mathbfuright)mathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1colorredleft(mathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1left(1+colorredmathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
mathbfumathbfv^TmathbfA^-1
endgather
I figured that this could be done because of associativity and as the terms in $colorredtextred$ result in a scalar, it could be 'moved around'. Is this correct? If yes, does this always hold or are there any conditions on the vectors and matrices involved?
matrices vectors
$endgroup$
4
$begingroup$
Correct, and it always holds (as long as $A$ is invertible of course).
$endgroup$
– amsmath
Mar 26 at 6:21
$begingroup$
@amsmath great, thx!
$endgroup$
– bertozzijr
Mar 26 at 7:34
add a comment |
$begingroup$
I came across this in a problem:
$$fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1mathbfumathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu$$
Then, in order to simplify this, I thought the following:
begingather
fracmathbfumathbfv^TmathbfA^-1+mathbfucolorredleft(mathbfv^TmathbfA^-1mathbfuright)mathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1colorredleft(mathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1left(1+colorredmathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
mathbfumathbfv^TmathbfA^-1
endgather
I figured that this could be done because of associativity and as the terms in $colorredtextred$ result in a scalar, it could be 'moved around'. Is this correct? If yes, does this always hold or are there any conditions on the vectors and matrices involved?
matrices vectors
$endgroup$
I came across this in a problem:
$$fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1mathbfumathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu$$
Then, in order to simplify this, I thought the following:
begingather
fracmathbfumathbfv^TmathbfA^-1+mathbfucolorredleft(mathbfv^TmathbfA^-1mathbfuright)mathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1colorredleft(mathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1left(1+colorredmathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
mathbfumathbfv^TmathbfA^-1
endgather
I figured that this could be done because of associativity and as the terms in $colorredtextred$ result in a scalar, it could be 'moved around'. Is this correct? If yes, does this always hold or are there any conditions on the vectors and matrices involved?
matrices vectors
matrices vectors
asked Mar 26 at 6:16
bertozzijrbertozzijr
6331720
6331720
4
$begingroup$
Correct, and it always holds (as long as $A$ is invertible of course).
$endgroup$
– amsmath
Mar 26 at 6:21
$begingroup$
@amsmath great, thx!
$endgroup$
– bertozzijr
Mar 26 at 7:34
add a comment |
4
$begingroup$
Correct, and it always holds (as long as $A$ is invertible of course).
$endgroup$
– amsmath
Mar 26 at 6:21
$begingroup$
@amsmath great, thx!
$endgroup$
– bertozzijr
Mar 26 at 7:34
4
4
$begingroup$
Correct, and it always holds (as long as $A$ is invertible of course).
$endgroup$
– amsmath
Mar 26 at 6:21
$begingroup$
Correct, and it always holds (as long as $A$ is invertible of course).
$endgroup$
– amsmath
Mar 26 at 6:21
$begingroup$
@amsmath great, thx!
$endgroup$
– bertozzijr
Mar 26 at 7:34
$begingroup$
@amsmath great, thx!
$endgroup$
– bertozzijr
Mar 26 at 7:34
add a comment |
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4
$begingroup$
Correct, and it always holds (as long as $A$ is invertible of course).
$endgroup$
– amsmath
Mar 26 at 6:21
$begingroup$
@amsmath great, thx!
$endgroup$
– bertozzijr
Mar 26 at 7:34