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Question on elementary Linear Algebra product



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Linear Algebra - Finding the matrix for the transformationMonotonicity of $log det R(d_i, d_j)$Maximizing the smallest eigenvalue of a linear combination of matricesReflection Matrix linear algebraDo four dimensional vectors have a cross product property?Show that $A^TA=I=AA^T$ imposes $frac12n(n+1)$ conditions on the elements of $A$.Linear algebra: Proving uniqueness and existence of a functionSet of linear algebra questionsSimplifying a dot and cross product expressionHow to apply the Cauchy-Schwartz inequality on the following inner product?










4












$begingroup$


I came across this in a problem:



$$fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1mathbfumathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu$$



Then, in order to simplify this, I thought the following:



begingather
fracmathbfumathbfv^TmathbfA^-1+mathbfucolorredleft(mathbfv^TmathbfA^-1mathbfuright)mathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1colorredleft(mathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1left(1+colorredmathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
mathbfumathbfv^TmathbfA^-1
endgather



I figured that this could be done because of associativity and as the terms in $colorredtextred$ result in a scalar, it could be 'moved around'. Is this correct? If yes, does this always hold or are there any conditions on the vectors and matrices involved?










share|cite|improve this question









$endgroup$







  • 4




    $begingroup$
    Correct, and it always holds (as long as $A$ is invertible of course).
    $endgroup$
    – amsmath
    Mar 26 at 6:21










  • $begingroup$
    @amsmath great, thx!
    $endgroup$
    – bertozzijr
    Mar 26 at 7:34















4












$begingroup$


I came across this in a problem:



$$fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1mathbfumathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu$$



Then, in order to simplify this, I thought the following:



begingather
fracmathbfumathbfv^TmathbfA^-1+mathbfucolorredleft(mathbfv^TmathbfA^-1mathbfuright)mathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1colorredleft(mathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1left(1+colorredmathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
mathbfumathbfv^TmathbfA^-1
endgather



I figured that this could be done because of associativity and as the terms in $colorredtextred$ result in a scalar, it could be 'moved around'. Is this correct? If yes, does this always hold or are there any conditions on the vectors and matrices involved?










share|cite|improve this question









$endgroup$







  • 4




    $begingroup$
    Correct, and it always holds (as long as $A$ is invertible of course).
    $endgroup$
    – amsmath
    Mar 26 at 6:21










  • $begingroup$
    @amsmath great, thx!
    $endgroup$
    – bertozzijr
    Mar 26 at 7:34













4












4








4





$begingroup$


I came across this in a problem:



$$fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1mathbfumathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu$$



Then, in order to simplify this, I thought the following:



begingather
fracmathbfumathbfv^TmathbfA^-1+mathbfucolorredleft(mathbfv^TmathbfA^-1mathbfuright)mathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1colorredleft(mathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1left(1+colorredmathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
mathbfumathbfv^TmathbfA^-1
endgather



I figured that this could be done because of associativity and as the terms in $colorredtextred$ result in a scalar, it could be 'moved around'. Is this correct? If yes, does this always hold or are there any conditions on the vectors and matrices involved?










share|cite|improve this question









$endgroup$




I came across this in a problem:



$$fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1mathbfumathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu$$



Then, in order to simplify this, I thought the following:



begingather
fracmathbfumathbfv^TmathbfA^-1+mathbfucolorredleft(mathbfv^TmathbfA^-1mathbfuright)mathbfv^TmathbfA^-11+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1+mathbfumathbfv^TmathbfA^-1colorredleft(mathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
fracmathbfumathbfv^TmathbfA^-1left(1+colorredmathbfv^TmathbfA^-1mathbfuright)1+mathbfv^TmathbfA^-1mathbfu\
mathbfumathbfv^TmathbfA^-1
endgather



I figured that this could be done because of associativity and as the terms in $colorredtextred$ result in a scalar, it could be 'moved around'. Is this correct? If yes, does this always hold or are there any conditions on the vectors and matrices involved?







matrices vectors






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 26 at 6:16









bertozzijrbertozzijr

6331720




6331720







  • 4




    $begingroup$
    Correct, and it always holds (as long as $A$ is invertible of course).
    $endgroup$
    – amsmath
    Mar 26 at 6:21










  • $begingroup$
    @amsmath great, thx!
    $endgroup$
    – bertozzijr
    Mar 26 at 7:34












  • 4




    $begingroup$
    Correct, and it always holds (as long as $A$ is invertible of course).
    $endgroup$
    – amsmath
    Mar 26 at 6:21










  • $begingroup$
    @amsmath great, thx!
    $endgroup$
    – bertozzijr
    Mar 26 at 7:34







4




4




$begingroup$
Correct, and it always holds (as long as $A$ is invertible of course).
$endgroup$
– amsmath
Mar 26 at 6:21




$begingroup$
Correct, and it always holds (as long as $A$ is invertible of course).
$endgroup$
– amsmath
Mar 26 at 6:21












$begingroup$
@amsmath great, thx!
$endgroup$
– bertozzijr
Mar 26 at 7:34




$begingroup$
@amsmath great, thx!
$endgroup$
– bertozzijr
Mar 26 at 7:34










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