Variation of Jensen's inequality Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Jensen's inequalityTotal variation distance for probability measuresI need help understanding proofs of Gibbs' Inequality using Jensen's Inequality.Is a convex combination of conditional probabilities the conditional probability of a convex combination of unconditional probabilities?probability measure on $sigma$-algebraUsing Jensen's inequality to prove another inequality?Question about convex set of probabilitiesJensen's inequality applied to Liapunov's CLT conditionFrom additivity of the measure, couldn't we prove the $sigma -$additivity?Generalize Jensen's Integral Inequality to the product of two functions
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Variation of Jensen's inequality
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Jensen's inequalityTotal variation distance for probability measuresI need help understanding proofs of Gibbs' Inequality using Jensen's Inequality.Is a convex combination of conditional probabilities the conditional probability of a convex combination of unconditional probabilities?probability measure on $sigma$-algebraUsing Jensen's inequality to prove another inequality?Question about convex set of probabilitiesJensen's inequality applied to Liapunov's CLT conditionFrom additivity of the measure, couldn't we prove the $sigma -$additivity?Generalize Jensen's Integral Inequality to the product of two functions
$begingroup$
I have a more general question: can we always say that, given a convex function $g$ and some $h$ s.t. $sum_xinmathcalXh(x)=1$, $AsubsetmathcalX$ $$sum_xin A g(x)h(x)geq gleft(sum_xin A xh(x)right)$$
even if we do not sum on all the $x$? Why does it hold? I have seen it done a few times (practical question), like here:
$$sum_xin A left(fracP(x)Q(x)right)^ccdotfrac1P(A) P(x) geq sum_xin A left(fracP(x)Q(x)cdotfrac1P(A) P(x)right)^c$$
where $cgeq 0$ and $P,Q$ are probability measures on $mathcalX$. Is it correct? Can you give me some hints on the proof? Sorry if it is silly but I just can't see it!
probability measure-theory jensen-inequality
$endgroup$
add a comment |
$begingroup$
I have a more general question: can we always say that, given a convex function $g$ and some $h$ s.t. $sum_xinmathcalXh(x)=1$, $AsubsetmathcalX$ $$sum_xin A g(x)h(x)geq gleft(sum_xin A xh(x)right)$$
even if we do not sum on all the $x$? Why does it hold? I have seen it done a few times (practical question), like here:
$$sum_xin A left(fracP(x)Q(x)right)^ccdotfrac1P(A) P(x) geq sum_xin A left(fracP(x)Q(x)cdotfrac1P(A) P(x)right)^c$$
where $cgeq 0$ and $P,Q$ are probability measures on $mathcalX$. Is it correct? Can you give me some hints on the proof? Sorry if it is silly but I just can't see it!
probability measure-theory jensen-inequality
$endgroup$
$begingroup$
True if $g(0)=0$ but not otherwise.
$endgroup$
– Kavi Rama Murthy
Mar 26 at 9:03
$begingroup$
@KaviRamaMurthy thanks! Why not otherwise? How does it work with $log$?
$endgroup$
– user1868607
Mar 26 at 9:15
$begingroup$
@user1868607 If $h(x)geq0$, it's just Jensen, otherwise, It's wrong, I think.
$endgroup$
– Michael Rozenberg
Mar 26 at 10:02
add a comment |
$begingroup$
I have a more general question: can we always say that, given a convex function $g$ and some $h$ s.t. $sum_xinmathcalXh(x)=1$, $AsubsetmathcalX$ $$sum_xin A g(x)h(x)geq gleft(sum_xin A xh(x)right)$$
even if we do not sum on all the $x$? Why does it hold? I have seen it done a few times (practical question), like here:
$$sum_xin A left(fracP(x)Q(x)right)^ccdotfrac1P(A) P(x) geq sum_xin A left(fracP(x)Q(x)cdotfrac1P(A) P(x)right)^c$$
where $cgeq 0$ and $P,Q$ are probability measures on $mathcalX$. Is it correct? Can you give me some hints on the proof? Sorry if it is silly but I just can't see it!
probability measure-theory jensen-inequality
$endgroup$
I have a more general question: can we always say that, given a convex function $g$ and some $h$ s.t. $sum_xinmathcalXh(x)=1$, $AsubsetmathcalX$ $$sum_xin A g(x)h(x)geq gleft(sum_xin A xh(x)right)$$
even if we do not sum on all the $x$? Why does it hold? I have seen it done a few times (practical question), like here:
$$sum_xin A left(fracP(x)Q(x)right)^ccdotfrac1P(A) P(x) geq sum_xin A left(fracP(x)Q(x)cdotfrac1P(A) P(x)right)^c$$
where $cgeq 0$ and $P,Q$ are probability measures on $mathcalX$. Is it correct? Can you give me some hints on the proof? Sorry if it is silly but I just can't see it!
probability measure-theory jensen-inequality
probability measure-theory jensen-inequality
asked Mar 26 at 8:54
user1868607user1868607
3211210
3211210
$begingroup$
True if $g(0)=0$ but not otherwise.
$endgroup$
– Kavi Rama Murthy
Mar 26 at 9:03
$begingroup$
@KaviRamaMurthy thanks! Why not otherwise? How does it work with $log$?
$endgroup$
– user1868607
Mar 26 at 9:15
$begingroup$
@user1868607 If $h(x)geq0$, it's just Jensen, otherwise, It's wrong, I think.
$endgroup$
– Michael Rozenberg
Mar 26 at 10:02
add a comment |
$begingroup$
True if $g(0)=0$ but not otherwise.
$endgroup$
– Kavi Rama Murthy
Mar 26 at 9:03
$begingroup$
@KaviRamaMurthy thanks! Why not otherwise? How does it work with $log$?
$endgroup$
– user1868607
Mar 26 at 9:15
$begingroup$
@user1868607 If $h(x)geq0$, it's just Jensen, otherwise, It's wrong, I think.
$endgroup$
– Michael Rozenberg
Mar 26 at 10:02
$begingroup$
True if $g(0)=0$ but not otherwise.
$endgroup$
– Kavi Rama Murthy
Mar 26 at 9:03
$begingroup$
True if $g(0)=0$ but not otherwise.
$endgroup$
– Kavi Rama Murthy
Mar 26 at 9:03
$begingroup$
@KaviRamaMurthy thanks! Why not otherwise? How does it work with $log$?
$endgroup$
– user1868607
Mar 26 at 9:15
$begingroup$
@KaviRamaMurthy thanks! Why not otherwise? How does it work with $log$?
$endgroup$
– user1868607
Mar 26 at 9:15
$begingroup$
@user1868607 If $h(x)geq0$, it's just Jensen, otherwise, It's wrong, I think.
$endgroup$
– Michael Rozenberg
Mar 26 at 10:02
$begingroup$
@user1868607 If $h(x)geq0$, it's just Jensen, otherwise, It's wrong, I think.
$endgroup$
– Michael Rozenberg
Mar 26 at 10:02
add a comment |
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$begingroup$
True if $g(0)=0$ but not otherwise.
$endgroup$
– Kavi Rama Murthy
Mar 26 at 9:03
$begingroup$
@KaviRamaMurthy thanks! Why not otherwise? How does it work with $log$?
$endgroup$
– user1868607
Mar 26 at 9:15
$begingroup$
@user1868607 If $h(x)geq0$, it's just Jensen, otherwise, It's wrong, I think.
$endgroup$
– Michael Rozenberg
Mar 26 at 10:02