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Househbolder transformation identity matrix dimensions
Least-squares solution to a transformation between coordinate frames“Averaging” transformation matrices?Using Least Squares to calculate a matrix in an equation.Least squares with matrix solution with constraintsHow to expand the matrix in Matlab (forming $A$ matrix in least square problem)Minimize $|AXBd -c |^2$, enforcing $X$ to be a diagonal block matrixMinimizing a transformation describing the configuration of a rigid body with respect to its verticesProper way to use projection matrix equationAre there any cases where Modified Gram-Schmidt is more reliable than Householder for QR decomposition?Solve Matrix Least Squares (Frobenius Norm) Problem with Lower Triangular Matrix Constraint
$begingroup$
When performing a householder transformation and generating an elementary reflector matrix of the form:
$$H = I - 2dfracvv^Tv^Tv$$
How do we know the dimensions of the identity matrix?
least-squares
$endgroup$
add a comment |
$begingroup$
When performing a householder transformation and generating an elementary reflector matrix of the form:
$$H = I - 2dfracvv^Tv^Tv$$
How do we know the dimensions of the identity matrix?
least-squares
$endgroup$
add a comment |
$begingroup$
When performing a householder transformation and generating an elementary reflector matrix of the form:
$$H = I - 2dfracvv^Tv^Tv$$
How do we know the dimensions of the identity matrix?
least-squares
$endgroup$
When performing a householder transformation and generating an elementary reflector matrix of the form:
$$H = I - 2dfracvv^Tv^Tv$$
How do we know the dimensions of the identity matrix?
least-squares
least-squares
asked Mar 10 at 21:02
ParadoxParadox
205110
205110
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add a comment |
1 Answer
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$begingroup$
Let $nin mathbb N$ such that $v in mathbb R^n$. Then $vv^t in mathbb R^ntimes n$ and we therefore need $I in mathbb R^ntimes n$ for the difference to make sense.
$endgroup$
add a comment |
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1 Answer
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1 Answer
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$begingroup$
Let $nin mathbb N$ such that $v in mathbb R^n$. Then $vv^t in mathbb R^ntimes n$ and we therefore need $I in mathbb R^ntimes n$ for the difference to make sense.
$endgroup$
add a comment |
$begingroup$
Let $nin mathbb N$ such that $v in mathbb R^n$. Then $vv^t in mathbb R^ntimes n$ and we therefore need $I in mathbb R^ntimes n$ for the difference to make sense.
$endgroup$
add a comment |
$begingroup$
Let $nin mathbb N$ such that $v in mathbb R^n$. Then $vv^t in mathbb R^ntimes n$ and we therefore need $I in mathbb R^ntimes n$ for the difference to make sense.
$endgroup$
Let $nin mathbb N$ such that $v in mathbb R^n$. Then $vv^t in mathbb R^ntimes n$ and we therefore need $I in mathbb R^ntimes n$ for the difference to make sense.
answered Mar 10 at 21:13
flawrflawr
11.7k32546
11.7k32546
add a comment |
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