How many ways we can draw 2 similar cards of the same rankCounting how many hands of cards use all four suitsCombination - How many different waysHow many different flush hands can you have that consist only of hearts, diamonds or spades?How many ways to draw consecutive fibonacci numbers from deck of cardsHow many cards of a single suit must be present in any set of n cards?Poker Combinations: How many ways can you get 4 of the same suit in a hand of 5 cards?How to solve card related combination problemHow many different hands of 7 cards…How many ways are there to choose from a deck of cards?A poker hand contains five cards. Find the probability that a poker hand can be…
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How many ways we can draw 2 similar cards of the same rank
Counting how many hands of cards use all four suitsCombination - How many different waysHow many different flush hands can you have that consist only of hearts, diamonds or spades?How many ways to draw consecutive fibonacci numbers from deck of cardsHow many cards of a single suit must be present in any set of n cards?Poker Combinations: How many ways can you get 4 of the same suit in a hand of 5 cards?How to solve card related combination problemHow many different hands of 7 cards…How many ways are there to choose from a deck of cards?A poker hand contains five cards. Find the probability that a poker hand can be…
$begingroup$
How many ways we can draw 2 similar cards with the same face value from the deck of 36 cards?
Deck has 4 suits and 9 cards in each suit
combinatorics
New contributor
$endgroup$
|
show 1 more comment
$begingroup$
How many ways we can draw 2 similar cards with the same face value from the deck of 36 cards?
Deck has 4 suits and 9 cards in each suit
combinatorics
New contributor
$endgroup$
$begingroup$
Some of us on the site are not familiar with cards; can you please define "similar" and "rank"? I assume you mean draw 2 cards with the same face value for the moment.
$endgroup$
– ItsJustVennDiagramsBro
Mar 10 at 21:10
$begingroup$
Yes, exactly - 2 cards with a same face value
$endgroup$
– Leocete
Mar 10 at 21:12
$begingroup$
And a deck of $36$ cards? That deck is not the standard 52-card deck so some additional clarification is necessary. I assume that this is something like a standard german deck where there are $4$ suits, and nine cards in each suit?
$endgroup$
– JMoravitz
Mar 10 at 21:21
$begingroup$
@JMoravitz Yes, 4 suits, 9 cards in each suit
$endgroup$
– Leocete
Mar 10 at 21:23
$begingroup$
Additionally, you will need to clarify what exactly you are wishing to count. Are you considering order relevant so that something like $Aclubsuit, Aheartsuit$ is considered a different outcome than $Aheartsuit,Aclubsuit$? Or are these considered to be the same since the set of cards in the hand are the same?
$endgroup$
– JMoravitz
Mar 10 at 21:24
|
show 1 more comment
$begingroup$
How many ways we can draw 2 similar cards with the same face value from the deck of 36 cards?
Deck has 4 suits and 9 cards in each suit
combinatorics
New contributor
$endgroup$
How many ways we can draw 2 similar cards with the same face value from the deck of 36 cards?
Deck has 4 suits and 9 cards in each suit
combinatorics
combinatorics
New contributor
New contributor
edited Mar 10 at 21:24
Leocete
New contributor
asked Mar 10 at 21:08
LeoceteLeocete
32
32
New contributor
New contributor
$begingroup$
Some of us on the site are not familiar with cards; can you please define "similar" and "rank"? I assume you mean draw 2 cards with the same face value for the moment.
$endgroup$
– ItsJustVennDiagramsBro
Mar 10 at 21:10
$begingroup$
Yes, exactly - 2 cards with a same face value
$endgroup$
– Leocete
Mar 10 at 21:12
$begingroup$
And a deck of $36$ cards? That deck is not the standard 52-card deck so some additional clarification is necessary. I assume that this is something like a standard german deck where there are $4$ suits, and nine cards in each suit?
$endgroup$
– JMoravitz
Mar 10 at 21:21
$begingroup$
@JMoravitz Yes, 4 suits, 9 cards in each suit
$endgroup$
– Leocete
Mar 10 at 21:23
$begingroup$
Additionally, you will need to clarify what exactly you are wishing to count. Are you considering order relevant so that something like $Aclubsuit, Aheartsuit$ is considered a different outcome than $Aheartsuit,Aclubsuit$? Or are these considered to be the same since the set of cards in the hand are the same?
$endgroup$
– JMoravitz
Mar 10 at 21:24
|
show 1 more comment
$begingroup$
Some of us on the site are not familiar with cards; can you please define "similar" and "rank"? I assume you mean draw 2 cards with the same face value for the moment.
$endgroup$
– ItsJustVennDiagramsBro
Mar 10 at 21:10
$begingroup$
Yes, exactly - 2 cards with a same face value
$endgroup$
– Leocete
Mar 10 at 21:12
$begingroup$
And a deck of $36$ cards? That deck is not the standard 52-card deck so some additional clarification is necessary. I assume that this is something like a standard german deck where there are $4$ suits, and nine cards in each suit?
$endgroup$
– JMoravitz
Mar 10 at 21:21
$begingroup$
@JMoravitz Yes, 4 suits, 9 cards in each suit
$endgroup$
– Leocete
Mar 10 at 21:23
$begingroup$
Additionally, you will need to clarify what exactly you are wishing to count. Are you considering order relevant so that something like $Aclubsuit, Aheartsuit$ is considered a different outcome than $Aheartsuit,Aclubsuit$? Or are these considered to be the same since the set of cards in the hand are the same?
$endgroup$
– JMoravitz
Mar 10 at 21:24
$begingroup$
Some of us on the site are not familiar with cards; can you please define "similar" and "rank"? I assume you mean draw 2 cards with the same face value for the moment.
$endgroup$
– ItsJustVennDiagramsBro
Mar 10 at 21:10
$begingroup$
Some of us on the site are not familiar with cards; can you please define "similar" and "rank"? I assume you mean draw 2 cards with the same face value for the moment.
$endgroup$
– ItsJustVennDiagramsBro
Mar 10 at 21:10
$begingroup$
Yes, exactly - 2 cards with a same face value
$endgroup$
– Leocete
Mar 10 at 21:12
$begingroup$
Yes, exactly - 2 cards with a same face value
$endgroup$
– Leocete
Mar 10 at 21:12
$begingroup$
And a deck of $36$ cards? That deck is not the standard 52-card deck so some additional clarification is necessary. I assume that this is something like a standard german deck where there are $4$ suits, and nine cards in each suit?
$endgroup$
– JMoravitz
Mar 10 at 21:21
$begingroup$
And a deck of $36$ cards? That deck is not the standard 52-card deck so some additional clarification is necessary. I assume that this is something like a standard german deck where there are $4$ suits, and nine cards in each suit?
$endgroup$
– JMoravitz
Mar 10 at 21:21
$begingroup$
@JMoravitz Yes, 4 suits, 9 cards in each suit
$endgroup$
– Leocete
Mar 10 at 21:23
$begingroup$
@JMoravitz Yes, 4 suits, 9 cards in each suit
$endgroup$
– Leocete
Mar 10 at 21:23
$begingroup$
Additionally, you will need to clarify what exactly you are wishing to count. Are you considering order relevant so that something like $Aclubsuit, Aheartsuit$ is considered a different outcome than $Aheartsuit,Aclubsuit$? Or are these considered to be the same since the set of cards in the hand are the same?
$endgroup$
– JMoravitz
Mar 10 at 21:24
$begingroup$
Additionally, you will need to clarify what exactly you are wishing to count. Are you considering order relevant so that something like $Aclubsuit, Aheartsuit$ is considered a different outcome than $Aheartsuit,Aclubsuit$? Or are these considered to be the same since the set of cards in the hand are the same?
$endgroup$
– JMoravitz
Mar 10 at 21:24
|
show 1 more comment
1 Answer
1
active
oldest
votes
$begingroup$
If I remember correctly there are 4 cards of 9 possible values in the deck.
Assuming the order of two cards being irrelevant the number in question is:
$$
9binom42=54.
$$
If the order matters the number should be multiplied by $2!=2$.
$endgroup$
$begingroup$
Additional clarification needs to be made by the OP or your answer needs a qualifier stating that your answer assumes that order of cards is irrelevant
$endgroup$
– JMoravitz
Mar 10 at 21:23
$begingroup$
@JMoravitz I have started my answer with an assumption about the deck composition. This assumption seems to be correct.
$endgroup$
– user
Mar 10 at 21:26
$begingroup$
the assumption about the deck composition is not what I was referring to. The currently unstated assumption (which was only just now clarified by the OP) that the order of drawing the cards is irrelevant is what I was referring to. In some problems it is common to consider $Aclubsuit,Aheartsuit$ to be a "different" result than $Aheartsuit,Aclubsuit$. In the first scenario you drew a club first. That is a decidedly different outcome than drawing a heart first in several games. If the OP stated that order of cards mattered, then your answer would have been incorrect.
$endgroup$
– JMoravitz
Mar 10 at 21:28
$begingroup$
@JMoravitz I have expanded the answer to cover both scenario.
$endgroup$
– user
Mar 10 at 21:55
add a comment |
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1 Answer
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1 Answer
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oldest
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$begingroup$
If I remember correctly there are 4 cards of 9 possible values in the deck.
Assuming the order of two cards being irrelevant the number in question is:
$$
9binom42=54.
$$
If the order matters the number should be multiplied by $2!=2$.
$endgroup$
$begingroup$
Additional clarification needs to be made by the OP or your answer needs a qualifier stating that your answer assumes that order of cards is irrelevant
$endgroup$
– JMoravitz
Mar 10 at 21:23
$begingroup$
@JMoravitz I have started my answer with an assumption about the deck composition. This assumption seems to be correct.
$endgroup$
– user
Mar 10 at 21:26
$begingroup$
the assumption about the deck composition is not what I was referring to. The currently unstated assumption (which was only just now clarified by the OP) that the order of drawing the cards is irrelevant is what I was referring to. In some problems it is common to consider $Aclubsuit,Aheartsuit$ to be a "different" result than $Aheartsuit,Aclubsuit$. In the first scenario you drew a club first. That is a decidedly different outcome than drawing a heart first in several games. If the OP stated that order of cards mattered, then your answer would have been incorrect.
$endgroup$
– JMoravitz
Mar 10 at 21:28
$begingroup$
@JMoravitz I have expanded the answer to cover both scenario.
$endgroup$
– user
Mar 10 at 21:55
add a comment |
$begingroup$
If I remember correctly there are 4 cards of 9 possible values in the deck.
Assuming the order of two cards being irrelevant the number in question is:
$$
9binom42=54.
$$
If the order matters the number should be multiplied by $2!=2$.
$endgroup$
$begingroup$
Additional clarification needs to be made by the OP or your answer needs a qualifier stating that your answer assumes that order of cards is irrelevant
$endgroup$
– JMoravitz
Mar 10 at 21:23
$begingroup$
@JMoravitz I have started my answer with an assumption about the deck composition. This assumption seems to be correct.
$endgroup$
– user
Mar 10 at 21:26
$begingroup$
the assumption about the deck composition is not what I was referring to. The currently unstated assumption (which was only just now clarified by the OP) that the order of drawing the cards is irrelevant is what I was referring to. In some problems it is common to consider $Aclubsuit,Aheartsuit$ to be a "different" result than $Aheartsuit,Aclubsuit$. In the first scenario you drew a club first. That is a decidedly different outcome than drawing a heart first in several games. If the OP stated that order of cards mattered, then your answer would have been incorrect.
$endgroup$
– JMoravitz
Mar 10 at 21:28
$begingroup$
@JMoravitz I have expanded the answer to cover both scenario.
$endgroup$
– user
Mar 10 at 21:55
add a comment |
$begingroup$
If I remember correctly there are 4 cards of 9 possible values in the deck.
Assuming the order of two cards being irrelevant the number in question is:
$$
9binom42=54.
$$
If the order matters the number should be multiplied by $2!=2$.
$endgroup$
If I remember correctly there are 4 cards of 9 possible values in the deck.
Assuming the order of two cards being irrelevant the number in question is:
$$
9binom42=54.
$$
If the order matters the number should be multiplied by $2!=2$.
edited Mar 10 at 21:54
answered Mar 10 at 21:21
useruser
5,31511030
5,31511030
$begingroup$
Additional clarification needs to be made by the OP or your answer needs a qualifier stating that your answer assumes that order of cards is irrelevant
$endgroup$
– JMoravitz
Mar 10 at 21:23
$begingroup$
@JMoravitz I have started my answer with an assumption about the deck composition. This assumption seems to be correct.
$endgroup$
– user
Mar 10 at 21:26
$begingroup$
the assumption about the deck composition is not what I was referring to. The currently unstated assumption (which was only just now clarified by the OP) that the order of drawing the cards is irrelevant is what I was referring to. In some problems it is common to consider $Aclubsuit,Aheartsuit$ to be a "different" result than $Aheartsuit,Aclubsuit$. In the first scenario you drew a club first. That is a decidedly different outcome than drawing a heart first in several games. If the OP stated that order of cards mattered, then your answer would have been incorrect.
$endgroup$
– JMoravitz
Mar 10 at 21:28
$begingroup$
@JMoravitz I have expanded the answer to cover both scenario.
$endgroup$
– user
Mar 10 at 21:55
add a comment |
$begingroup$
Additional clarification needs to be made by the OP or your answer needs a qualifier stating that your answer assumes that order of cards is irrelevant
$endgroup$
– JMoravitz
Mar 10 at 21:23
$begingroup$
@JMoravitz I have started my answer with an assumption about the deck composition. This assumption seems to be correct.
$endgroup$
– user
Mar 10 at 21:26
$begingroup$
the assumption about the deck composition is not what I was referring to. The currently unstated assumption (which was only just now clarified by the OP) that the order of drawing the cards is irrelevant is what I was referring to. In some problems it is common to consider $Aclubsuit,Aheartsuit$ to be a "different" result than $Aheartsuit,Aclubsuit$. In the first scenario you drew a club first. That is a decidedly different outcome than drawing a heart first in several games. If the OP stated that order of cards mattered, then your answer would have been incorrect.
$endgroup$
– JMoravitz
Mar 10 at 21:28
$begingroup$
@JMoravitz I have expanded the answer to cover both scenario.
$endgroup$
– user
Mar 10 at 21:55
$begingroup$
Additional clarification needs to be made by the OP or your answer needs a qualifier stating that your answer assumes that order of cards is irrelevant
$endgroup$
– JMoravitz
Mar 10 at 21:23
$begingroup$
Additional clarification needs to be made by the OP or your answer needs a qualifier stating that your answer assumes that order of cards is irrelevant
$endgroup$
– JMoravitz
Mar 10 at 21:23
$begingroup$
@JMoravitz I have started my answer with an assumption about the deck composition. This assumption seems to be correct.
$endgroup$
– user
Mar 10 at 21:26
$begingroup$
@JMoravitz I have started my answer with an assumption about the deck composition. This assumption seems to be correct.
$endgroup$
– user
Mar 10 at 21:26
$begingroup$
the assumption about the deck composition is not what I was referring to. The currently unstated assumption (which was only just now clarified by the OP) that the order of drawing the cards is irrelevant is what I was referring to. In some problems it is common to consider $Aclubsuit,Aheartsuit$ to be a "different" result than $Aheartsuit,Aclubsuit$. In the first scenario you drew a club first. That is a decidedly different outcome than drawing a heart first in several games. If the OP stated that order of cards mattered, then your answer would have been incorrect.
$endgroup$
– JMoravitz
Mar 10 at 21:28
$begingroup$
the assumption about the deck composition is not what I was referring to. The currently unstated assumption (which was only just now clarified by the OP) that the order of drawing the cards is irrelevant is what I was referring to. In some problems it is common to consider $Aclubsuit,Aheartsuit$ to be a "different" result than $Aheartsuit,Aclubsuit$. In the first scenario you drew a club first. That is a decidedly different outcome than drawing a heart first in several games. If the OP stated that order of cards mattered, then your answer would have been incorrect.
$endgroup$
– JMoravitz
Mar 10 at 21:28
$begingroup$
@JMoravitz I have expanded the answer to cover both scenario.
$endgroup$
– user
Mar 10 at 21:55
$begingroup$
@JMoravitz I have expanded the answer to cover both scenario.
$endgroup$
– user
Mar 10 at 21:55
add a comment |
Leocete is a new contributor. Be nice, and check out our Code of Conduct.
Leocete is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Some of us on the site are not familiar with cards; can you please define "similar" and "rank"? I assume you mean draw 2 cards with the same face value for the moment.
$endgroup$
– ItsJustVennDiagramsBro
Mar 10 at 21:10
$begingroup$
Yes, exactly - 2 cards with a same face value
$endgroup$
– Leocete
Mar 10 at 21:12
$begingroup$
And a deck of $36$ cards? That deck is not the standard 52-card deck so some additional clarification is necessary. I assume that this is something like a standard german deck where there are $4$ suits, and nine cards in each suit?
$endgroup$
– JMoravitz
Mar 10 at 21:21
$begingroup$
@JMoravitz Yes, 4 suits, 9 cards in each suit
$endgroup$
– Leocete
Mar 10 at 21:23
$begingroup$
Additionally, you will need to clarify what exactly you are wishing to count. Are you considering order relevant so that something like $Aclubsuit, Aheartsuit$ is considered a different outcome than $Aheartsuit,Aclubsuit$? Or are these considered to be the same since the set of cards in the hand are the same?
$endgroup$
– JMoravitz
Mar 10 at 21:24