What does the following complex equation signifies? The 2019 Stack Overflow Developer Survey Results Are InConvert in terms of complex numbers, the line whose equation is $2x-y=3$Every line or circle in $mathbbC$ are solution sets to the equation…how to write eqn of line in complex formShow that $left|dfracz-a1-bar a zright|=r$ represents a circleA simple complex rational function.$a barzz+ bbarz + barbz+c=0$ - What curve it represents in the complex plane?Solving an equation then Representing that function of complex variables on a circleFor what complex numbers w does the equation exp(z)=w have solutions?Show that the locus of points $z$ in the complex plane satisfying an equation of the type $Azbarz+Bz+barBbarz+c=0$, in which both $A$ and…Analytically find roots of equation with anti-symmetric, complex coefficients.
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What does the following complex equation signifies?
The 2019 Stack Overflow Developer Survey Results Are InConvert in terms of complex numbers, the line whose equation is $2x-y=3$Every line or circle in $mathbbC$ are solution sets to the equation…how to write eqn of line in complex formShow that $left|dfracz-a1-bar a zright|=r$ represents a circleA simple complex rational function.$a barzz+ bbarz + barbz+c=0$ - What curve it represents in the complex plane?Solving an equation then Representing that function of complex variables on a circleFor what complex numbers w does the equation exp(z)=w have solutions?Show that the locus of points $z$ in the complex plane satisfying an equation of the type $Azbarz+Bz+barBbarz+c=0$, in which both $A$ and…Analytically find roots of equation with anti-symmetric, complex coefficients.
$begingroup$
The set of complex numbers z satisfying the equation
$(3 + 7i)z + (10 − 2i)barz + 100 = 0$
represents what?
Here is my approach
$(3 + 7i)(x+iy) + (10 − 2i)(x-iy) + 100 = 0$
$13x-9y+5ix-7iy+100=0$
$x(13+5i)+y(-9-7i)+100=0$
Though there are no squared terms hence it can't be any second degree curve like circle, straight line then what is it?
complex-analysis
asked Mar 24 at 7:55
Vineet KumarVineet Kumar
11
$endgroup$
add a comment |
$begingroup$
The set of complex numbers z satisfying the equation
$(3 + 7i)z + (10 − 2i)barz + 100 = 0$
represents what?
Here is my approach
$(3 + 7i)(x+iy) + (10 − 2i)(x-iy) + 100 = 0$
$13x-9y+5ix-7iy+100=0$
$x(13+5i)+y(-9-7i)+100=0$
Though there are no squared terms hence it can't be any second degree curve like circle, straight line then what is it?
complex-analysis
asked Mar 24 at 7:55
Vineet KumarVineet Kumar
11
$endgroup$
$begingroup$
A point$$?
$endgroup$
– Lord Shark the Unknown
Mar 24 at 7:58
add a comment |
$begingroup$
The set of complex numbers z satisfying the equation
$(3 + 7i)z + (10 − 2i)barz + 100 = 0$
represents what?
Here is my approach
$(3 + 7i)(x+iy) + (10 − 2i)(x-iy) + 100 = 0$
$13x-9y+5ix-7iy+100=0$
$x(13+5i)+y(-9-7i)+100=0$
Though there are no squared terms hence it can't be any second degree curve like circle, straight line then what is it?
complex-analysis
asked Mar 24 at 7:55
Vineet KumarVineet Kumar
11
$endgroup$
The set of complex numbers z satisfying the equation
$(3 + 7i)z + (10 − 2i)barz + 100 = 0$
represents what?
Here is my approach
$(3 + 7i)(x+iy) + (10 − 2i)(x-iy) + 100 = 0$
$13x-9y+5ix-7iy+100=0$
$x(13+5i)+y(-9-7i)+100=0$
Though there are no squared terms hence it can't be any second degree curve like circle, straight line then what is it?
complex-analysis
complex-analysis
asked Mar 24 at 7:55
Vineet KumarVineet Kumar
11
asked Mar 24 at 7:55
Vineet KumarVineet Kumar
11
edited Mar 24 at 8:25
Vineet Kumar
asked Mar 24 at 7:55
Vineet KumarVineet Kumar
11
asked Mar 24 at 7:55
Vineet KumarVineet Kumar
11
asked Mar 24 at 7:55
Vineet KumarVineet Kumar
11
11
$begingroup$
A point$$?
$endgroup$
– Lord Shark the Unknown
Mar 24 at 7:58
add a comment |
$begingroup$
A point$$?
$endgroup$
– Lord Shark the Unknown
Mar 24 at 7:58
$begingroup$
A point$$?
$endgroup$
– Lord Shark the Unknown
Mar 24 at 7:58
$begingroup$
A point$$?
$endgroup$
– Lord Shark the Unknown
Mar 24 at 7:58
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Welcome to MSE!
Hint: From $13x−9y+5ix−7iy+100=0$ you get $13x-9y+100=0$ (real part) and $5x-7y=0$ (imaginary part).
answered Mar 24 at 7:58
WuestenfuxWuestenfux
5,5131513
$endgroup$
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Welcome to MSE!
Hint: From $13x−9y+5ix−7iy+100=0$ you get $13x-9y+100=0$ (real part) and $5x-7y=0$ (imaginary part).
answered Mar 24 at 7:58
WuestenfuxWuestenfux
5,5131513
$endgroup$
add a comment |
$begingroup$
Welcome to MSE!
Hint: From $13x−9y+5ix−7iy+100=0$ you get $13x-9y+100=0$ (real part) and $5x-7y=0$ (imaginary part).
answered Mar 24 at 7:58
WuestenfuxWuestenfux
5,5131513
$endgroup$
add a comment |
$begingroup$
Welcome to MSE!
Hint: From $13x−9y+5ix−7iy+100=0$ you get $13x-9y+100=0$ (real part) and $5x-7y=0$ (imaginary part).
answered Mar 24 at 7:58
WuestenfuxWuestenfux
5,5131513
$endgroup$
Welcome to MSE!
Hint: From $13x−9y+5ix−7iy+100=0$ you get $13x-9y+100=0$ (real part) and $5x-7y=0$ (imaginary part).
answered Mar 24 at 7:58
WuestenfuxWuestenfux
5,5131513
answered Mar 24 at 7:58
WuestenfuxWuestenfux
5,5131513
answered Mar 24 at 7:58
WuestenfuxWuestenfux
5,5131513
answered Mar 24 at 7:58
WuestenfuxWuestenfux
5,5131513
5,5131513
add a comment |
add a comment |
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$begingroup$
A point$$?
$endgroup$
– Lord Shark the Unknown
Mar 24 at 7:58