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Show that $sup_x_1, dots, x_n in mathscrX|mathscrF(x_1, dots, x_n)|=S(mathscrA, n)$



The 2019 Stack Overflow Developer Survey Results Are InShow that the posterior density of ($mu$, $tau$) is equal to $f(mu, tau | x_1, …, x_n) = f(mu| tau, x_1,…,x_n)f(tau|x_1,…x_n)$Show that $T$ is a sufficient statistic.How to calculate the probability that $X_n$ is not the largest observation in the sample?Is it correct to say $textmax(x_1,x_2,dots,x_n)=lim_p to infty fracx_1^p+x_2^p+dots+x_n^px_1^p-1+x_2^p-1+dots+x_n^p-1$Show that X_1,…,X_n are independent.What is the expectation of norm of $[X_1,ldots, X_n]$ where $X_i$ are indpendent complex Gaussian random variablesFind expectation of $fracX_1 + cdots + X_mX_1 + cdots + X_n$ when $X_1,ldots,X_n$ are i.i.dDerive the maximum likelihood equation when only $I[X_1>5], I[X_2 > 5], … , I[X_n > 5]$ are observed.$X_1, X_2, cdots, X_n$ : i.i.d. $sim textBernoulli(p)$. Then $barx$ is an unbiased estimator of $p$.distribution of $sum_i=1^n (X_i-X_n+i)^2$ where $X_1,X_2,dots,X_2n$ are iid $N(mu,sigma^2)$










1












$begingroup$


Show that $$sup_x_1, dots, x_n in mathscrX|mathscrF(x_1, dots, x_n)|=S(mathscrA, n)$$
where $S(mathscrA, n)$ denotes the n-th shattering number of the class
$$mathscrA=A_f: f in mathscrF$$
where
$$A_f = x in mathscrX: f(x) = 1$$



I don't quite understand how to approach this problem. Any help will be highly appreciated.










share|cite|improve this question









$endgroup$











  • $begingroup$
    What does $|mathscrF(x_1,dots, x_n)|$ stand for?
    $endgroup$
    – stochasticboy321
    Mar 24 at 22:57










  • $begingroup$
    Having thought a little - I'm guessing $mathscrF(x)$ is the set $(f(x_1), dots, f(x_n) ), f in mathscrF,$ and the $f$ are $0,1$-valued. In addition, you define the shattering number in the set-inclusion sense. If this is the case, argue pointwise - fix a set of inputs $X = x_1, dots, x_n$, and consider the map $varphi: mathscrA(X) to mathscrF(X), (A_f cap X) mapsto (f(x_1), dots, f(x_n) ).$ Argue that this is a bijection (this is almost trivial), to get that for any $X$, $mathscrA(X)$ and $mathscrF(X)$ are of equal size. The conclusion then follows.
    $endgroup$
    – stochasticboy321
    Mar 24 at 23:37
















1












$begingroup$


Show that $$sup_x_1, dots, x_n in mathscrX|mathscrF(x_1, dots, x_n)|=S(mathscrA, n)$$
where $S(mathscrA, n)$ denotes the n-th shattering number of the class
$$mathscrA=A_f: f in mathscrF$$
where
$$A_f = x in mathscrX: f(x) = 1$$



I don't quite understand how to approach this problem. Any help will be highly appreciated.










share|cite|improve this question









$endgroup$











  • $begingroup$
    What does $|mathscrF(x_1,dots, x_n)|$ stand for?
    $endgroup$
    – stochasticboy321
    Mar 24 at 22:57










  • $begingroup$
    Having thought a little - I'm guessing $mathscrF(x)$ is the set $(f(x_1), dots, f(x_n) ), f in mathscrF,$ and the $f$ are $0,1$-valued. In addition, you define the shattering number in the set-inclusion sense. If this is the case, argue pointwise - fix a set of inputs $X = x_1, dots, x_n$, and consider the map $varphi: mathscrA(X) to mathscrF(X), (A_f cap X) mapsto (f(x_1), dots, f(x_n) ).$ Argue that this is a bijection (this is almost trivial), to get that for any $X$, $mathscrA(X)$ and $mathscrF(X)$ are of equal size. The conclusion then follows.
    $endgroup$
    – stochasticboy321
    Mar 24 at 23:37














1












1








1


1



$begingroup$


Show that $$sup_x_1, dots, x_n in mathscrX|mathscrF(x_1, dots, x_n)|=S(mathscrA, n)$$
where $S(mathscrA, n)$ denotes the n-th shattering number of the class
$$mathscrA=A_f: f in mathscrF$$
where
$$A_f = x in mathscrX: f(x) = 1$$



I don't quite understand how to approach this problem. Any help will be highly appreciated.










share|cite|improve this question









$endgroup$




Show that $$sup_x_1, dots, x_n in mathscrX|mathscrF(x_1, dots, x_n)|=S(mathscrA, n)$$
where $S(mathscrA, n)$ denotes the n-th shattering number of the class
$$mathscrA=A_f: f in mathscrF$$
where
$$A_f = x in mathscrX: f(x) = 1$$



I don't quite understand how to approach this problem. Any help will be highly appreciated.







statistics machine-learning






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 24 at 7:32









acrob4t1acrob4t1

41




41











  • $begingroup$
    What does $|mathscrF(x_1,dots, x_n)|$ stand for?
    $endgroup$
    – stochasticboy321
    Mar 24 at 22:57










  • $begingroup$
    Having thought a little - I'm guessing $mathscrF(x)$ is the set $(f(x_1), dots, f(x_n) ), f in mathscrF,$ and the $f$ are $0,1$-valued. In addition, you define the shattering number in the set-inclusion sense. If this is the case, argue pointwise - fix a set of inputs $X = x_1, dots, x_n$, and consider the map $varphi: mathscrA(X) to mathscrF(X), (A_f cap X) mapsto (f(x_1), dots, f(x_n) ).$ Argue that this is a bijection (this is almost trivial), to get that for any $X$, $mathscrA(X)$ and $mathscrF(X)$ are of equal size. The conclusion then follows.
    $endgroup$
    – stochasticboy321
    Mar 24 at 23:37

















  • $begingroup$
    What does $|mathscrF(x_1,dots, x_n)|$ stand for?
    $endgroup$
    – stochasticboy321
    Mar 24 at 22:57










  • $begingroup$
    Having thought a little - I'm guessing $mathscrF(x)$ is the set $(f(x_1), dots, f(x_n) ), f in mathscrF,$ and the $f$ are $0,1$-valued. In addition, you define the shattering number in the set-inclusion sense. If this is the case, argue pointwise - fix a set of inputs $X = x_1, dots, x_n$, and consider the map $varphi: mathscrA(X) to mathscrF(X), (A_f cap X) mapsto (f(x_1), dots, f(x_n) ).$ Argue that this is a bijection (this is almost trivial), to get that for any $X$, $mathscrA(X)$ and $mathscrF(X)$ are of equal size. The conclusion then follows.
    $endgroup$
    – stochasticboy321
    Mar 24 at 23:37
















$begingroup$
What does $|mathscrF(x_1,dots, x_n)|$ stand for?
$endgroup$
– stochasticboy321
Mar 24 at 22:57




$begingroup$
What does $|mathscrF(x_1,dots, x_n)|$ stand for?
$endgroup$
– stochasticboy321
Mar 24 at 22:57












$begingroup$
Having thought a little - I'm guessing $mathscrF(x)$ is the set $(f(x_1), dots, f(x_n) ), f in mathscrF,$ and the $f$ are $0,1$-valued. In addition, you define the shattering number in the set-inclusion sense. If this is the case, argue pointwise - fix a set of inputs $X = x_1, dots, x_n$, and consider the map $varphi: mathscrA(X) to mathscrF(X), (A_f cap X) mapsto (f(x_1), dots, f(x_n) ).$ Argue that this is a bijection (this is almost trivial), to get that for any $X$, $mathscrA(X)$ and $mathscrF(X)$ are of equal size. The conclusion then follows.
$endgroup$
– stochasticboy321
Mar 24 at 23:37





$begingroup$
Having thought a little - I'm guessing $mathscrF(x)$ is the set $(f(x_1), dots, f(x_n) ), f in mathscrF,$ and the $f$ are $0,1$-valued. In addition, you define the shattering number in the set-inclusion sense. If this is the case, argue pointwise - fix a set of inputs $X = x_1, dots, x_n$, and consider the map $varphi: mathscrA(X) to mathscrF(X), (A_f cap X) mapsto (f(x_1), dots, f(x_n) ).$ Argue that this is a bijection (this is almost trivial), to get that for any $X$, $mathscrA(X)$ and $mathscrF(X)$ are of equal size. The conclusion then follows.
$endgroup$
– stochasticboy321
Mar 24 at 23:37











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