Probability of picking animal from pond The 2019 Stack Overflow Developer Survey Results Are InRandomly picking increasing numbers in $ 1, dots, n$Probability Question: Picking Balls From An Urnprobability of getting the same permutation after swappingProbability with replacementProbability that $x^2+y^2 leq 1$ for uniformly distributed random variables.Setting up probability problem picking marbles uniformly from two bagsHow to compute the conditional probability?Why total probability is the sum of conditional probabilities?Conditional Probability (The cookie Poroblem)Discrete Conditional Probability: Determine Pr(A | B) for bit strings
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Probability of picking animal from pond
The 2019 Stack Overflow Developer Survey Results Are InRandomly picking increasing numbers in $ 1, dots, n$Probability Question: Picking Balls From An Urnprobability of getting the same permutation after swappingProbability with replacementProbability that $x^2+y^2 leq 1$ for uniformly distributed random variables.Setting up probability problem picking marbles uniformly from two bagsHow to compute the conditional probability?Why total probability is the sum of conditional probabilities?Conditional Probability (The cookie Poroblem)Discrete Conditional Probability: Determine Pr(A | B) for bit strings
$begingroup$
A bit confused by this problem.
Joe and Marcy have two distinguishable ponds. Initially, each of the ponds contains four ducks and five geese. Joe first picks a bird uniformly at random from the left pond and moves it to the right pond. Then, Marcy picks a bird uniformly at random from the right pond. What is the probability that Marcy picks a duck?
Do we work with conditional probabilities for this problem where we have to calculate the probabilities that Marcy picks a duck given Joe picks a ducks vs when he picks a goose?
probability
asked Mar 24 at 7:29
RobinRobin
625
$endgroup$
add a comment |
$begingroup$
A bit confused by this problem.
Joe and Marcy have two distinguishable ponds. Initially, each of the ponds contains four ducks and five geese. Joe first picks a bird uniformly at random from the left pond and moves it to the right pond. Then, Marcy picks a bird uniformly at random from the right pond. What is the probability that Marcy picks a duck?
Do we work with conditional probabilities for this problem where we have to calculate the probabilities that Marcy picks a duck given Joe picks a ducks vs when he picks a goose?
probability
asked Mar 24 at 7:29
RobinRobin
625
$endgroup$
add a comment |
$begingroup$
A bit confused by this problem.
Joe and Marcy have two distinguishable ponds. Initially, each of the ponds contains four ducks and five geese. Joe first picks a bird uniformly at random from the left pond and moves it to the right pond. Then, Marcy picks a bird uniformly at random from the right pond. What is the probability that Marcy picks a duck?
Do we work with conditional probabilities for this problem where we have to calculate the probabilities that Marcy picks a duck given Joe picks a ducks vs when he picks a goose?
probability
asked Mar 24 at 7:29
RobinRobin
625
$endgroup$
A bit confused by this problem.
Joe and Marcy have two distinguishable ponds. Initially, each of the ponds contains four ducks and five geese. Joe first picks a bird uniformly at random from the left pond and moves it to the right pond. Then, Marcy picks a bird uniformly at random from the right pond. What is the probability that Marcy picks a duck?
Do we work with conditional probabilities for this problem where we have to calculate the probabilities that Marcy picks a duck given Joe picks a ducks vs when he picks a goose?
probability
probability
asked Mar 24 at 7:29
RobinRobin
625
asked Mar 24 at 7:29
RobinRobin
625
asked Mar 24 at 7:29
RobinRobin
625
asked Mar 24 at 7:29
RobinRobin
625
asked Mar 24 at 7:29
RobinRobin
625
625
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Yes you need conditional probabilities.The second event
Marcy picks a duck is dependent on first event ,which bird was transferred earlier by Joe. (duck or goose). So
$P(Marcy picks duck)=P(Joe picks goose and Marcy picks duck)+P(Joe picks duck and Marcy picks duck)=P(Marcy picks duck | Joe picks goose) . P(Joe picks goose) + P(Marcy picks duck | Joe picks duck) . P(Joe picks duck).
=5/9*4/10 +4/9*5/10$
answered Mar 24 at 7:45
TojrahTojrah
4036
$endgroup$
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Yes you need conditional probabilities.The second event
Marcy picks a duck is dependent on first event ,which bird was transferred earlier by Joe. (duck or goose). So
$P(Marcy picks duck)=P(Joe picks goose and Marcy picks duck)+P(Joe picks duck and Marcy picks duck)=P(Marcy picks duck | Joe picks goose) . P(Joe picks goose) + P(Marcy picks duck | Joe picks duck) . P(Joe picks duck).
=5/9*4/10 +4/9*5/10$
answered Mar 24 at 7:45
TojrahTojrah
4036
$endgroup$
add a comment |
$begingroup$
Yes you need conditional probabilities.The second event
Marcy picks a duck is dependent on first event ,which bird was transferred earlier by Joe. (duck or goose). So
$P(Marcy picks duck)=P(Joe picks goose and Marcy picks duck)+P(Joe picks duck and Marcy picks duck)=P(Marcy picks duck | Joe picks goose) . P(Joe picks goose) + P(Marcy picks duck | Joe picks duck) . P(Joe picks duck).
=5/9*4/10 +4/9*5/10$
answered Mar 24 at 7:45
TojrahTojrah
4036
$endgroup$
add a comment |
$begingroup$
Yes you need conditional probabilities.The second event
Marcy picks a duck is dependent on first event ,which bird was transferred earlier by Joe. (duck or goose). So
$P(Marcy picks duck)=P(Joe picks goose and Marcy picks duck)+P(Joe picks duck and Marcy picks duck)=P(Marcy picks duck | Joe picks goose) . P(Joe picks goose) + P(Marcy picks duck | Joe picks duck) . P(Joe picks duck).
=5/9*4/10 +4/9*5/10$
answered Mar 24 at 7:45
TojrahTojrah
4036
$endgroup$
Yes you need conditional probabilities.The second event
Marcy picks a duck is dependent on first event ,which bird was transferred earlier by Joe. (duck or goose). So
$P(Marcy picks duck)=P(Joe picks goose and Marcy picks duck)+P(Joe picks duck and Marcy picks duck)=P(Marcy picks duck | Joe picks goose) . P(Joe picks goose) + P(Marcy picks duck | Joe picks duck) . P(Joe picks duck).
=5/9*4/10 +4/9*5/10$
answered Mar 24 at 7:45
TojrahTojrah
4036
answered Mar 24 at 7:45
TojrahTojrah
4036
answered Mar 24 at 7:45
TojrahTojrah
4036
answered Mar 24 at 7:45
TojrahTojrah
4036
4036
add a comment |
add a comment |
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