Argument list too long when zipping large list of certain files in a folder The 2019 Stack Overflow Developer Survey Results Are InSolving “mv: Argument list too long”?How to print a range of IP addresses with Linux seq commandbash: /usr/bin/perl: Argument list too long/usr/bin/awk: Argument list too longArgument list too long with just 5000 filesAWK Using a Variable in an Equality Expressionbash array with variable in the nameReplace a long string with the sed command: Argument list too long errorAdd text to each value while looping thru and printing them in a array?Moving random files using shuf and mv - Argument list too long
Why was M87 targeted for the Event Horizon Telescope instead of Sagittarius A*?
What do hard-Brexiteers want with respect to the Irish border?
Does HR tell a hiring manager about salary negotiations?
Kerning for subscripts of sigma?
How do you keep chess fun when your opponent constantly beats you?
Cooking pasta in a water boiler
How much of the clove should I use when using big garlic heads?
How did passengers keep warm on sail ships?
A word that means fill it to the required quantity
Is one supposed to eat the zero'ah (shank bone) from the Seder plate?
I am an eight letter word. What am I?
"as much details as you can remember"
Keeping a retro style to sci-fi spaceships?
What do these terms in Caesar's Gallic wars mean?
writing variables above the numbers in tikz picture
How to support a colleague who finds meetings extremely tiring?
Why can't devices on different VLANs, but on the same subnet, communicate?
How come people say “Would of”?
Why “相同意思的词” is called “同义词” instead of "同意词"？
Falsification in Math vs Science
How do I free up internal storage if I don't have any apps downloaded?
How do PCB vias affect signal quality?
Deal with toxic manager when you can't quit
How to charge AirPods to keep battery healthy?
Argument list too long when zipping large list of certain files in a folder
The 2019 Stack Overflow Developer Survey Results Are InSolving “mv: Argument list too long”?How to print a range of IP addresses with Linux seq commandbash: /usr/bin/perl: Argument list too long/usr/bin/awk: Argument list too longArgument list too long with just 5000 filesAWK Using a Variable in an Equality Expressionbash array with variable in the nameReplace a long string with the sed command: Argument list too long errorAdd text to each value while looping thru and printing them in a array?Moving random files using shuf and mv - Argument list too long
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command but met with "Argument list too long" error.
declare -a arr=()
fixed=5
for i in `seq 10 1 200`; do
for j in `seq $((i+fixed)) 1 200`; do
arr+=("$i_$j.xxx")
done
done
new_arr=$(printf ",%s" "$arr[@]")
new_arr=$new_arr:1
zip all_data.zip $new_arr
bash
asked Mar 24 at 3:54
ZackZack
234
add a comment |
I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command but met with "Argument list too long" error.
declare -a arr=()
fixed=5
for i in `seq 10 1 200`; do
for j in `seq $((i+fixed)) 1 200`; do
arr+=("$i_$j.xxx")
done
done
new_arr=$(printf ",%s" "$arr[@]")
new_arr=$new_arr:1
zip all_data.zip $new_arr
bash
asked Mar 24 at 3:54
ZackZack
234
As an alternative: you can create an empty zip file at the beginning and add a file to that zip file, instead of making an array first and adding them all at once. Might save you a loop, unless you have need for the array for other reasons...
– Henno Brandsma
Mar 24 at 13:51
add a comment |
I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command but met with "Argument list too long" error.
declare -a arr=()
fixed=5
for i in `seq 10 1 200`; do
for j in `seq $((i+fixed)) 1 200`; do
arr+=("$i_$j.xxx")
done
done
new_arr=$(printf ",%s" "$arr[@]")
new_arr=$new_arr:1
zip all_data.zip $new_arr
bash
asked Mar 24 at 3:54
ZackZack
234
I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command but met with "Argument list too long" error.
declare -a arr=()
fixed=5
for i in `seq 10 1 200`; do
for j in `seq $((i+fixed)) 1 200`; do
arr+=("$i_$j.xxx")
done
done
new_arr=$(printf ",%s" "$arr[@]")
new_arr=$new_arr:1
zip all_data.zip $new_arr
bash
bash
asked Mar 24 at 3:54
ZackZack
234
asked Mar 24 at 3:54
ZackZack
234
edited Mar 24 at 3:59
Zack
asked Mar 24 at 3:54
ZackZack
234
asked Mar 24 at 3:54
ZackZack
234
asked Mar 24 at 3:54
ZackZack
234
234
As an alternative: you can create an empty zip file at the beginning and add a file to that zip file, instead of making an array first and adding them all at once. Might save you a loop, unless you have need for the array for other reasons...
– Henno Brandsma
Mar 24 at 13:51
add a comment |
As an alternative: you can create an empty zip file at the beginning and add a file to that zip file, instead of making an array first and adding them all at once. Might save you a loop, unless you have need for the array for other reasons...
– Henno Brandsma
Mar 24 at 13:51
As an alternative: you can create an empty zip file at the beginning and add a file to that zip file, instead of making an array first and adding them all at once. Might save you a loop, unless you have need for the array for other reasons...
– Henno Brandsma
Mar 24 at 13:51
As an alternative: you can create an empty zip file at the beginning and add a file to that zip file, instead of making an array first and adding them all at once. Might save you a loop, unless you have need for the array for other reasons...
– Henno Brandsma
Mar 24 at 13:51
add a comment |
1 Answer
1
active
oldest
votes
extract from man zip ( linux version )
zip -@ foo
will store the files listed one per line on stdin in foo.zip.
example from the same man page
find . -name "*.[ch]" -print | zip source -@
So steps will be :
build a list off all files to be archive , format must one file name by line
run
zipcommandcat BIG_FILENAME_LIST.txt | zip thebigziparchive -@
answered Mar 24 at 4:16
EchoMike444EchoMike444
1,0506
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "106"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f508247%2fargument-list-too-long-when-zipping-large-list-of-certain-files-in-a-folder%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
extract from man zip ( linux version )
zip -@ foo
will store the files listed one per line on stdin in foo.zip.
example from the same man page
find . -name "*.[ch]" -print | zip source -@
So steps will be :
build a list off all files to be archive , format must one file name by line
run
zipcommandcat BIG_FILENAME_LIST.txt | zip thebigziparchive -@
answered Mar 24 at 4:16
EchoMike444EchoMike444
1,0506
add a comment |
extract from man zip ( linux version )
zip -@ foo
will store the files listed one per line on stdin in foo.zip.
example from the same man page
find . -name "*.[ch]" -print | zip source -@
So steps will be :
build a list off all files to be archive , format must one file name by line
run
zipcommandcat BIG_FILENAME_LIST.txt | zip thebigziparchive -@
answered Mar 24 at 4:16
EchoMike444EchoMike444
1,0506
add a comment |
extract from man zip ( linux version )
zip -@ foo
will store the files listed one per line on stdin in foo.zip.
example from the same man page
find . -name "*.[ch]" -print | zip source -@
So steps will be :
build a list off all files to be archive , format must one file name by line
run
zipcommandcat BIG_FILENAME_LIST.txt | zip thebigziparchive -@
answered Mar 24 at 4:16
EchoMike444EchoMike444
1,0506
extract from man zip ( linux version )
zip -@ foo
will store the files listed one per line on stdin in foo.zip.
example from the same man page
find . -name "*.[ch]" -print | zip source -@
So steps will be :
build a list off all files to be archive , format must one file name by line
run
zipcommandcat BIG_FILENAME_LIST.txt | zip thebigziparchive -@
answered Mar 24 at 4:16
EchoMike444EchoMike444
1,0506
answered Mar 24 at 4:16
EchoMike444EchoMike444
1,0506
answered Mar 24 at 4:16
EchoMike444EchoMike444
1,0506
answered Mar 24 at 4:16
EchoMike444EchoMike444
1,0506
1,0506
add a comment |
add a comment |
Thanks for contributing an answer to Unix & Linux Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f508247%2fargument-list-too-long-when-zipping-large-list-of-certain-files-in-a-folder%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
As an alternative: you can create an empty zip file at the beginning and add a file to that zip file, instead of making an array first and adding them all at once. Might save you a loop, unless you have need for the array for other reasons...
– Henno Brandsma
Mar 24 at 13:51