Span of two vectorsShowing vectors span a vector space by definitionHow do I determine the intersection of span A and span B?span between vector and set of vectorsSuppose that $v_1,v_2,v_3,v_4$ spans $V$. Prove that the list $v_1 - v_2, v_2 - v_3, v_3-v_4,v_4$ also spans $V$.Is showing that if two vectors in $mathbbR^n$ are linearly independent, then they span $mathbbR^n$?Prove linear independence of two general set of vectorsHelp with proof of two spanning sets of the same spacelinear algebra span of four unknown vectors.Span of two vectors - confusionWhich rows of vectors are linearly dependent or linearly independent?
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Span of two vectors
Showing vectors span a vector space by definitionHow do I determine the intersection of span A and span B?span between vector and set of vectorsSuppose that $v_1,v_2,v_3,v_4$ spans $V$. Prove that the list $v_1 - v_2, v_2 - v_3, v_3-v_4,v_4$ also spans $V$.Is showing that if two vectors in $mathbbR^n$ are linearly independent, then they span $mathbbR^n$?Prove linear independence of two general set of vectorsHelp with proof of two spanning sets of the same spacelinear algebra span of four unknown vectors.Span of two vectors - confusionWhich rows of vectors are linearly dependent or linearly independent?
$begingroup$
Let $v_1 = (1, 1, -1)$ and $v_2 = (-3, 2, -2)$. Which of the following vectors are in $mathrmspan,v_1, v_2$?
(i) $(4, -1, 1)$
(ii) $(7, -3, 3)$
(iii) $(11, -4, 4)$
I tried to solve for the $c_1,c_2$ but I am really confused and only have 1 answer left, can someone please help???
linear-algebra
$endgroup$
add a comment |
$begingroup$
Let $v_1 = (1, 1, -1)$ and $v_2 = (-3, 2, -2)$. Which of the following vectors are in $mathrmspan,v_1, v_2$?
(i) $(4, -1, 1)$
(ii) $(7, -3, 3)$
(iii) $(11, -4, 4)$
I tried to solve for the $c_1,c_2$ but I am really confused and only have 1 answer left, can someone please help???
linear-algebra
$endgroup$
5
$begingroup$
You have three equations with two unknowns. Do you see these equations? If so, solve for the unknowns using two of the equations. And then plug those values into the third equation. If the answer is consistent, then the vector is in the span. If it is not, then the vector is not in the span.
$endgroup$
– NicNic8
Mar 21 at 18:03
$begingroup$
I don't know what you mean by equations. I created a matrix and tried to solve for c1 and c2
$endgroup$
– McA
Mar 21 at 18:08
$begingroup$
Perhaps, then, you’d care to show us exactly what you mean by “I tried to solve for the $c_1$, $c_2$...”
$endgroup$
– amd
Mar 21 at 18:10
$begingroup$
that's the thing, I checked other solutions and they had v3 but I don't
$endgroup$
– McA
Mar 21 at 18:22
add a comment |
$begingroup$
Let $v_1 = (1, 1, -1)$ and $v_2 = (-3, 2, -2)$. Which of the following vectors are in $mathrmspan,v_1, v_2$?
(i) $(4, -1, 1)$
(ii) $(7, -3, 3)$
(iii) $(11, -4, 4)$
I tried to solve for the $c_1,c_2$ but I am really confused and only have 1 answer left, can someone please help???
linear-algebra
$endgroup$
Let $v_1 = (1, 1, -1)$ and $v_2 = (-3, 2, -2)$. Which of the following vectors are in $mathrmspan,v_1, v_2$?
(i) $(4, -1, 1)$
(ii) $(7, -3, 3)$
(iii) $(11, -4, 4)$
I tried to solve for the $c_1,c_2$ but I am really confused and only have 1 answer left, can someone please help???
linear-algebra
linear-algebra
edited Mar 21 at 18:04
Brian
1,268216
1,268216
asked Mar 21 at 17:59
McAMcA
1
1
5
$begingroup$
You have three equations with two unknowns. Do you see these equations? If so, solve for the unknowns using two of the equations. And then plug those values into the third equation. If the answer is consistent, then the vector is in the span. If it is not, then the vector is not in the span.
$endgroup$
– NicNic8
Mar 21 at 18:03
$begingroup$
I don't know what you mean by equations. I created a matrix and tried to solve for c1 and c2
$endgroup$
– McA
Mar 21 at 18:08
$begingroup$
Perhaps, then, you’d care to show us exactly what you mean by “I tried to solve for the $c_1$, $c_2$...”
$endgroup$
– amd
Mar 21 at 18:10
$begingroup$
that's the thing, I checked other solutions and they had v3 but I don't
$endgroup$
– McA
Mar 21 at 18:22
add a comment |
5
$begingroup$
You have three equations with two unknowns. Do you see these equations? If so, solve for the unknowns using two of the equations. And then plug those values into the third equation. If the answer is consistent, then the vector is in the span. If it is not, then the vector is not in the span.
$endgroup$
– NicNic8
Mar 21 at 18:03
$begingroup$
I don't know what you mean by equations. I created a matrix and tried to solve for c1 and c2
$endgroup$
– McA
Mar 21 at 18:08
$begingroup$
Perhaps, then, you’d care to show us exactly what you mean by “I tried to solve for the $c_1$, $c_2$...”
$endgroup$
– amd
Mar 21 at 18:10
$begingroup$
that's the thing, I checked other solutions and they had v3 but I don't
$endgroup$
– McA
Mar 21 at 18:22
5
5
$begingroup$
You have three equations with two unknowns. Do you see these equations? If so, solve for the unknowns using two of the equations. And then plug those values into the third equation. If the answer is consistent, then the vector is in the span. If it is not, then the vector is not in the span.
$endgroup$
– NicNic8
Mar 21 at 18:03
$begingroup$
You have three equations with two unknowns. Do you see these equations? If so, solve for the unknowns using two of the equations. And then plug those values into the third equation. If the answer is consistent, then the vector is in the span. If it is not, then the vector is not in the span.
$endgroup$
– NicNic8
Mar 21 at 18:03
$begingroup$
I don't know what you mean by equations. I created a matrix and tried to solve for c1 and c2
$endgroup$
– McA
Mar 21 at 18:08
$begingroup$
I don't know what you mean by equations. I created a matrix and tried to solve for c1 and c2
$endgroup$
– McA
Mar 21 at 18:08
$begingroup$
Perhaps, then, you’d care to show us exactly what you mean by “I tried to solve for the $c_1$, $c_2$...”
$endgroup$
– amd
Mar 21 at 18:10
$begingroup$
Perhaps, then, you’d care to show us exactly what you mean by “I tried to solve for the $c_1$, $c_2$...”
$endgroup$
– amd
Mar 21 at 18:10
$begingroup$
that's the thing, I checked other solutions and they had v3 but I don't
$endgroup$
– McA
Mar 21 at 18:22
$begingroup$
that's the thing, I checked other solutions and they had v3 but I don't
$endgroup$
– McA
Mar 21 at 18:22
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Calculate $v_1-v_2$, $v_1-2c_2$ and $2v_1-3c_2$.
In case you've found that vector (i) and vector (ii) are in the span, save some work by observing that vector (iii) is the sum of both.
$endgroup$
$begingroup$
thanks a lot!!!
$endgroup$
– McA
Mar 21 at 18:51
add a comment |
$begingroup$
We can somewhat 'simplify' the basis vectors by noting that the span of $v_1,v_2$ is also the span of $dfrac2v_1-v_25,dfrac3v_1+v_25equiv(1,0,0),(0,1,-1)$. Now it's easy to see which vectors lie in the span.
$endgroup$
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Calculate $v_1-v_2$, $v_1-2c_2$ and $2v_1-3c_2$.
In case you've found that vector (i) and vector (ii) are in the span, save some work by observing that vector (iii) is the sum of both.
$endgroup$
$begingroup$
thanks a lot!!!
$endgroup$
– McA
Mar 21 at 18:51
add a comment |
$begingroup$
Calculate $v_1-v_2$, $v_1-2c_2$ and $2v_1-3c_2$.
In case you've found that vector (i) and vector (ii) are in the span, save some work by observing that vector (iii) is the sum of both.
$endgroup$
$begingroup$
thanks a lot!!!
$endgroup$
– McA
Mar 21 at 18:51
add a comment |
$begingroup$
Calculate $v_1-v_2$, $v_1-2c_2$ and $2v_1-3c_2$.
In case you've found that vector (i) and vector (ii) are in the span, save some work by observing that vector (iii) is the sum of both.
$endgroup$
Calculate $v_1-v_2$, $v_1-2c_2$ and $2v_1-3c_2$.
In case you've found that vector (i) and vector (ii) are in the span, save some work by observing that vector (iii) is the sum of both.
answered Mar 21 at 18:42
Michael HoppeMichael Hoppe
11.3k31837
11.3k31837
$begingroup$
thanks a lot!!!
$endgroup$
– McA
Mar 21 at 18:51
add a comment |
$begingroup$
thanks a lot!!!
$endgroup$
– McA
Mar 21 at 18:51
$begingroup$
thanks a lot!!!
$endgroup$
– McA
Mar 21 at 18:51
$begingroup$
thanks a lot!!!
$endgroup$
– McA
Mar 21 at 18:51
add a comment |
$begingroup$
We can somewhat 'simplify' the basis vectors by noting that the span of $v_1,v_2$ is also the span of $dfrac2v_1-v_25,dfrac3v_1+v_25equiv(1,0,0),(0,1,-1)$. Now it's easy to see which vectors lie in the span.
$endgroup$
add a comment |
$begingroup$
We can somewhat 'simplify' the basis vectors by noting that the span of $v_1,v_2$ is also the span of $dfrac2v_1-v_25,dfrac3v_1+v_25equiv(1,0,0),(0,1,-1)$. Now it's easy to see which vectors lie in the span.
$endgroup$
add a comment |
$begingroup$
We can somewhat 'simplify' the basis vectors by noting that the span of $v_1,v_2$ is also the span of $dfrac2v_1-v_25,dfrac3v_1+v_25equiv(1,0,0),(0,1,-1)$. Now it's easy to see which vectors lie in the span.
$endgroup$
We can somewhat 'simplify' the basis vectors by noting that the span of $v_1,v_2$ is also the span of $dfrac2v_1-v_25,dfrac3v_1+v_25equiv(1,0,0),(0,1,-1)$. Now it's easy to see which vectors lie in the span.
answered Mar 21 at 18:52
Shubham JohriShubham Johri
5,500818
5,500818
add a comment |
add a comment |
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5
$begingroup$
You have three equations with two unknowns. Do you see these equations? If so, solve for the unknowns using two of the equations. And then plug those values into the third equation. If the answer is consistent, then the vector is in the span. If it is not, then the vector is not in the span.
$endgroup$
– NicNic8
Mar 21 at 18:03
$begingroup$
I don't know what you mean by equations. I created a matrix and tried to solve for c1 and c2
$endgroup$
– McA
Mar 21 at 18:08
$begingroup$
Perhaps, then, you’d care to show us exactly what you mean by “I tried to solve for the $c_1$, $c_2$...”
$endgroup$
– amd
Mar 21 at 18:10
$begingroup$
that's the thing, I checked other solutions and they had v3 but I don't
$endgroup$
– McA
Mar 21 at 18:22