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1

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question:There are two trees that are spaced 30 meters apart. The height of one of them is 12 meters and the other is 28 meters. The two trees should be kept by two wires so that both wires are connected to a point on the ground with a nail and the other head they reach the end of both trees. Where to knock down the nail to get the least wire.

my try:

assume that, $$ Z=T_1+T_2 $$ $$28^2+ x^2=T_1^2$$ $$12^2+(30-x)^2=T_2^2$$

by this way: $$Z=sqrt28^2+x^2 +sqrt12^2+(30-x)^2$$

and for the maximum $Z$ we have:$$fracddxZ$$

The final answer is $x=9$.

if my solution is true does it different if I say:

$28^2+left(30-xright)^2=T_1^2$

$12^2+x^2=T_2^2$
and ...

optimization

share|cite|improve this question

edited Mar 21 at 18:51

black rose

asked Mar 21 at 18:41

black roseblack rose

62

$endgroup$

add a comment | 

1

$begingroup$

question:There are two trees that are spaced 30 meters apart. The height of one of them is 12 meters and the other is 28 meters. The two trees should be kept by two wires so that both wires are connected to a point on the ground with a nail and the other head they reach the end of both trees. Where to knock down the nail to get the least wire.

my try:

assume that, $$ Z=T_1+T_2 $$ $$28^2+ x^2=T_1^2$$ $$12^2+(30-x)^2=T_2^2$$

by this way: $$Z=sqrt28^2+x^2 +sqrt12^2+(30-x)^2$$

and for the maximum $Z$ we have:$$fracddxZ$$

The final answer is $x=9$.

if my solution is true does it different if I say:

$28^2+left(30-xright)^2=T_1^2$

$12^2+x^2=T_2^2$
and ...

optimization

share|cite|improve this question

edited Mar 21 at 18:51

black rose

asked Mar 21 at 18:41

black roseblack rose

62

$endgroup$

add a comment | 

$begingroup$

question:There are two trees that are spaced 30 meters apart. The height of one of them is 12 meters and the other is 28 meters. The two trees should be kept by two wires so that both wires are connected to a point on the ground with a nail and the other head they reach the end of both trees. Where to knock down the nail to get the least wire.

my try:

assume that, $$ Z=T_1+T_2 $$ $$28^2+ x^2=T_1^2$$ $$12^2+(30-x)^2=T_2^2$$

by this way: $$Z=sqrt28^2+x^2 +sqrt12^2+(30-x)^2$$

and for the maximum $Z$ we have:$$fracddxZ$$

The final answer is $x=9$.

if my solution is true does it different if I say:

$28^2+left(30-xright)^2=T_1^2$

$12^2+x^2=T_2^2$
and ...

optimization

share|cite|improve this question

edited Mar 21 at 18:51

black rose

asked Mar 21 at 18:41

black roseblack rose

62

$endgroup$

share|cite|improve this question

edited Mar 21 at 18:51

black rose

asked Mar 21 at 18:41

black roseblack rose

62

share|cite|improve this question

edited Mar 21 at 18:51

black rose

asked Mar 21 at 18:41

black roseblack rose

62

asked Mar 21 at 18:41

black roseblack rose

62

asked Mar 21 at 18:41

black roseblack rose

62