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I need help in this statistics problem. Can somebody help?


Motivation behind standard deviation?Calculating mean and standard deviation of very large sample sizesBeginning statistics, simple confidence interval problemProbability distribution; what is probability that i wont spend more than 75% of the customers2 simple statistics questions regarding probability and means.Percentage greater than 2 standard deviations from the meanHow to determine notable change in a sequence of numbers?Statistics Hypothesis Testing + binomial table problemSolving formulas involving multiple means and standard deviationsCould someone explain this results section from a study? (very elementary question)













0












$begingroup$


So I have this raw data for a case study:
enter image description here




Note: 1 stands for average weight and 2 for overweight.




I need to calculate the following:



  1. What is the mean expected time spent for the average-weight
    patients? What is the mean expected time spent for the overweight
    patients?

  2. What is the difference in means between the groups? By approximately
    how many standard deviations do the means differ?

I have already solved the first one and the first part of the 2nd question. However how do I answer the 2nd part of the 2nd question?(the standard deviations part)




Answers:



1) Average weight mean = 31.36; overweight mean = 24.74



2) Difference = 6.62; they differ by 0.68 standard deviations











share|cite|improve this question











$endgroup$







  • 2




    $begingroup$
    There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
    $endgroup$
    – Paul Sinclair
    Mar 22 at 3:11










  • $begingroup$
    I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
    $endgroup$
    – RaphX
    Mar 22 at 6:55











  • $begingroup$
    Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
    $endgroup$
    – Paul Sinclair
    Mar 22 at 12:59










  • $begingroup$
    That is possible.
    $endgroup$
    – RaphX
    Mar 22 at 13:29















0












$begingroup$


So I have this raw data for a case study:
enter image description here




Note: 1 stands for average weight and 2 for overweight.




I need to calculate the following:



  1. What is the mean expected time spent for the average-weight
    patients? What is the mean expected time spent for the overweight
    patients?

  2. What is the difference in means between the groups? By approximately
    how many standard deviations do the means differ?

I have already solved the first one and the first part of the 2nd question. However how do I answer the 2nd part of the 2nd question?(the standard deviations part)




Answers:



1) Average weight mean = 31.36; overweight mean = 24.74



2) Difference = 6.62; they differ by 0.68 standard deviations











share|cite|improve this question











$endgroup$







  • 2




    $begingroup$
    There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
    $endgroup$
    – Paul Sinclair
    Mar 22 at 3:11










  • $begingroup$
    I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
    $endgroup$
    – RaphX
    Mar 22 at 6:55











  • $begingroup$
    Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
    $endgroup$
    – Paul Sinclair
    Mar 22 at 12:59










  • $begingroup$
    That is possible.
    $endgroup$
    – RaphX
    Mar 22 at 13:29













0












0








0





$begingroup$


So I have this raw data for a case study:
enter image description here




Note: 1 stands for average weight and 2 for overweight.




I need to calculate the following:



  1. What is the mean expected time spent for the average-weight
    patients? What is the mean expected time spent for the overweight
    patients?

  2. What is the difference in means between the groups? By approximately
    how many standard deviations do the means differ?

I have already solved the first one and the first part of the 2nd question. However how do I answer the 2nd part of the 2nd question?(the standard deviations part)




Answers:



1) Average weight mean = 31.36; overweight mean = 24.74



2) Difference = 6.62; they differ by 0.68 standard deviations











share|cite|improve this question











$endgroup$




So I have this raw data for a case study:
enter image description here




Note: 1 stands for average weight and 2 for overweight.




I need to calculate the following:



  1. What is the mean expected time spent for the average-weight
    patients? What is the mean expected time spent for the overweight
    patients?

  2. What is the difference in means between the groups? By approximately
    how many standard deviations do the means differ?

I have already solved the first one and the first part of the 2nd question. However how do I answer the 2nd part of the 2nd question?(the standard deviations part)




Answers:



1) Average weight mean = 31.36; overweight mean = 24.74



2) Difference = 6.62; they differ by 0.68 standard deviations








statistics standard-deviation means






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 22 at 3:08









Paul Sinclair

20.7k21543




20.7k21543










asked Mar 21 at 18:02









RaphXRaphX

167




167







  • 2




    $begingroup$
    There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
    $endgroup$
    – Paul Sinclair
    Mar 22 at 3:11










  • $begingroup$
    I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
    $endgroup$
    – RaphX
    Mar 22 at 6:55











  • $begingroup$
    Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
    $endgroup$
    – Paul Sinclair
    Mar 22 at 12:59










  • $begingroup$
    That is possible.
    $endgroup$
    – RaphX
    Mar 22 at 13:29












  • 2




    $begingroup$
    There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
    $endgroup$
    – Paul Sinclair
    Mar 22 at 3:11










  • $begingroup$
    I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
    $endgroup$
    – RaphX
    Mar 22 at 6:55











  • $begingroup$
    Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
    $endgroup$
    – Paul Sinclair
    Mar 22 at 12:59










  • $begingroup$
    That is possible.
    $endgroup$
    – RaphX
    Mar 22 at 13:29







2




2




$begingroup$
There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
$endgroup$
– Paul Sinclair
Mar 22 at 3:11




$begingroup$
There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
$endgroup$
– Paul Sinclair
Mar 22 at 3:11












$begingroup$
I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
$endgroup$
– RaphX
Mar 22 at 6:55





$begingroup$
I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
$endgroup$
– RaphX
Mar 22 at 6:55













$begingroup$
Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
$endgroup$
– Paul Sinclair
Mar 22 at 12:59




$begingroup$
Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
$endgroup$
– Paul Sinclair
Mar 22 at 12:59












$begingroup$
That is possible.
$endgroup$
– RaphX
Mar 22 at 13:29




$begingroup$
That is possible.
$endgroup$
– RaphX
Mar 22 at 13:29










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