I need help in this statistics problem. Can somebody help?Motivation behind standard deviation?Calculating mean and standard deviation of very large sample sizesBeginning statistics, simple confidence interval problemProbability distribution; what is probability that i wont spend more than 75% of the customers2 simple statistics questions regarding probability and means.Percentage greater than 2 standard deviations from the meanHow to determine notable change in a sequence of numbers?Statistics Hypothesis Testing + binomial table problemSolving formulas involving multiple means and standard deviationsCould someone explain this results section from a study? (very elementary question)
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I need help in this statistics problem. Can somebody help?
Motivation behind standard deviation?Calculating mean and standard deviation of very large sample sizesBeginning statistics, simple confidence interval problemProbability distribution; what is probability that i wont spend more than 75% of the customers2 simple statistics questions regarding probability and means.Percentage greater than 2 standard deviations from the meanHow to determine notable change in a sequence of numbers?Statistics Hypothesis Testing + binomial table problemSolving formulas involving multiple means and standard deviationsCould someone explain this results section from a study? (very elementary question)
$begingroup$
So I have this raw data for a case study:
Note: 1 stands for average weight and 2 for overweight.
I need to calculate the following:
- What is the mean expected time spent for the average-weight
patients? What is the mean expected time spent for the overweight
patients? - What is the difference in means between the groups? By approximately
how many standard deviations do the means differ?
I have already solved the first one and the first part of the 2nd question. However how do I answer the 2nd part of the 2nd question?(the standard deviations part)
Answers:
1) Average weight mean = 31.36; overweight mean = 24.74
2) Difference = 6.62; they differ by 0.68 standard deviations
statistics standard-deviation means
$endgroup$
add a comment |
$begingroup$
So I have this raw data for a case study:
Note: 1 stands for average weight and 2 for overweight.
I need to calculate the following:
- What is the mean expected time spent for the average-weight
patients? What is the mean expected time spent for the overweight
patients? - What is the difference in means between the groups? By approximately
how many standard deviations do the means differ?
I have already solved the first one and the first part of the 2nd question. However how do I answer the 2nd part of the 2nd question?(the standard deviations part)
Answers:
1) Average weight mean = 31.36; overweight mean = 24.74
2) Difference = 6.62; they differ by 0.68 standard deviations
statistics standard-deviation means
$endgroup$
2
$begingroup$
There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
$endgroup$
– Paul Sinclair
Mar 22 at 3:11
$begingroup$
I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
$endgroup$
– RaphX
Mar 22 at 6:55
$begingroup$
Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
$endgroup$
– Paul Sinclair
Mar 22 at 12:59
$begingroup$
That is possible.
$endgroup$
– RaphX
Mar 22 at 13:29
add a comment |
$begingroup$
So I have this raw data for a case study:
Note: 1 stands for average weight and 2 for overweight.
I need to calculate the following:
- What is the mean expected time spent for the average-weight
patients? What is the mean expected time spent for the overweight
patients? - What is the difference in means between the groups? By approximately
how many standard deviations do the means differ?
I have already solved the first one and the first part of the 2nd question. However how do I answer the 2nd part of the 2nd question?(the standard deviations part)
Answers:
1) Average weight mean = 31.36; overweight mean = 24.74
2) Difference = 6.62; they differ by 0.68 standard deviations
statistics standard-deviation means
$endgroup$
So I have this raw data for a case study:
Note: 1 stands for average weight and 2 for overweight.
I need to calculate the following:
- What is the mean expected time spent for the average-weight
patients? What is the mean expected time spent for the overweight
patients? - What is the difference in means between the groups? By approximately
how many standard deviations do the means differ?
I have already solved the first one and the first part of the 2nd question. However how do I answer the 2nd part of the 2nd question?(the standard deviations part)
Answers:
1) Average weight mean = 31.36; overweight mean = 24.74
2) Difference = 6.62; they differ by 0.68 standard deviations
statistics standard-deviation means
statistics standard-deviation means
edited Mar 22 at 3:08
Paul Sinclair
20.7k21543
20.7k21543
asked Mar 21 at 18:02
RaphXRaphX
167
167
2
$begingroup$
There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
$endgroup$
– Paul Sinclair
Mar 22 at 3:11
$begingroup$
I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
$endgroup$
– RaphX
Mar 22 at 6:55
$begingroup$
Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
$endgroup$
– Paul Sinclair
Mar 22 at 12:59
$begingroup$
That is possible.
$endgroup$
– RaphX
Mar 22 at 13:29
add a comment |
2
$begingroup$
There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
$endgroup$
– Paul Sinclair
Mar 22 at 3:11
$begingroup$
I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
$endgroup$
– RaphX
Mar 22 at 6:55
$begingroup$
Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
$endgroup$
– Paul Sinclair
Mar 22 at 12:59
$begingroup$
That is possible.
$endgroup$
– RaphX
Mar 22 at 13:29
2
2
$begingroup$
There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
$endgroup$
– Paul Sinclair
Mar 22 at 3:11
$begingroup$
There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
$endgroup$
– Paul Sinclair
Mar 22 at 3:11
$begingroup$
I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
$endgroup$
– RaphX
Mar 22 at 6:55
$begingroup$
I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
$endgroup$
– RaphX
Mar 22 at 6:55
$begingroup$
Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
$endgroup$
– Paul Sinclair
Mar 22 at 12:59
$begingroup$
Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
$endgroup$
– Paul Sinclair
Mar 22 at 12:59
$begingroup$
That is possible.
$endgroup$
– RaphX
Mar 22 at 13:29
$begingroup$
That is possible.
$endgroup$
– RaphX
Mar 22 at 13:29
add a comment |
0
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2
$begingroup$
There is a formula for standard deviation in your textbook. Apply it to the whole sample - not just group 1 or 2. How many times the standard deviation is the difference?
$endgroup$
– Paul Sinclair
Mar 22 at 3:11
$begingroup$
I got the standard deviation of the whole sample as 10.238. Dividing the difference between the means by this gives me 0.65. Is this how you wanted me to solve? If it is can you explain how this corresponds to the answer? .
$endgroup$
– RaphX
Mar 22 at 6:55
$begingroup$
Obviously they used a different standard deviation. I don't know if your formula was std dev for the full population (where you divide by $n$) or for a sample (where you divide by $n-1$), nor which would be appropriate here since I don't know the source nor use of this data, but that is too small to explain the difference. My guess is that they used the std dev of either just the "1" entries or of just the "2" entries. But I don't see a justification for using either instead of the full population.
$endgroup$
– Paul Sinclair
Mar 22 at 12:59
$begingroup$
That is possible.
$endgroup$
– RaphX
Mar 22 at 13:29