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Is $a^4 + b^4 + c^4$ a spherical harmonic?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Relationship between Surface Area and VolumeSpherical Harmonic Expansion On Non Unit SphereSpherical Harmonic integrationWeak problem formulation for PDE and boundary conditionsShow that $ int_S^2 (xy)^2, dS = frac4pi15$Meaning of cross terms in multivariable Taylor expansionSpherical Harmonic IdentitySpherical Harmonic DerivativeEvaluating the Surface Integral on a Sphere for a scalar function (integral is involved in PDE)Laplacian as limit of Integral Identity










0












$begingroup$


I am trying to construct Harmonic polynomials on the sphere. What about the examples:



  • $f = x^2 + y^2 + z^2$

  • $g = x^4 + y^4 + z^4$

We have that $nabla^2 f neq 0$ by compuing the second derivative of each coordinate separately:



$$
left(
fracpartial^2partial x^2 +
fracpartial^2partial y^2 +
fracpartial^2partial z^2
right) (x^4 + y^4 + z^4) = 12(x^2 + y^2 + z^2) neq 0
$$

We have a decomposition $L^2(S^2) = bigoplus H_d $ with $H_d = textharmonic polynomials in x,y,z text of degree d $. I am pretty sure the two functions I have constructed are in $L^2$.



$$ int_S^2 |f|^2 < 9 int_S^2 1, dS = 9 times (4pi) $$
and a similar story for $g$. How can I get an expansion of $f$ and $g$ in terms of harmonic polynomials? Are there terms of lower degree missing?










share|cite|improve this question











$endgroup$
















    0












    $begingroup$


    I am trying to construct Harmonic polynomials on the sphere. What about the examples:



    • $f = x^2 + y^2 + z^2$

    • $g = x^4 + y^4 + z^4$

    We have that $nabla^2 f neq 0$ by compuing the second derivative of each coordinate separately:



    $$
    left(
    fracpartial^2partial x^2 +
    fracpartial^2partial y^2 +
    fracpartial^2partial z^2
    right) (x^4 + y^4 + z^4) = 12(x^2 + y^2 + z^2) neq 0
    $$

    We have a decomposition $L^2(S^2) = bigoplus H_d $ with $H_d = textharmonic polynomials in x,y,z text of degree d $. I am pretty sure the two functions I have constructed are in $L^2$.



    $$ int_S^2 |f|^2 < 9 int_S^2 1, dS = 9 times (4pi) $$
    and a similar story for $g$. How can I get an expansion of $f$ and $g$ in terms of harmonic polynomials? Are there terms of lower degree missing?










    share|cite|improve this question











    $endgroup$














      0












      0








      0





      $begingroup$


      I am trying to construct Harmonic polynomials on the sphere. What about the examples:



      • $f = x^2 + y^2 + z^2$

      • $g = x^4 + y^4 + z^4$

      We have that $nabla^2 f neq 0$ by compuing the second derivative of each coordinate separately:



      $$
      left(
      fracpartial^2partial x^2 +
      fracpartial^2partial y^2 +
      fracpartial^2partial z^2
      right) (x^4 + y^4 + z^4) = 12(x^2 + y^2 + z^2) neq 0
      $$

      We have a decomposition $L^2(S^2) = bigoplus H_d $ with $H_d = textharmonic polynomials in x,y,z text of degree d $. I am pretty sure the two functions I have constructed are in $L^2$.



      $$ int_S^2 |f|^2 < 9 int_S^2 1, dS = 9 times (4pi) $$
      and a similar story for $g$. How can I get an expansion of $f$ and $g$ in terms of harmonic polynomials? Are there terms of lower degree missing?










      share|cite|improve this question











      $endgroup$




      I am trying to construct Harmonic polynomials on the sphere. What about the examples:



      • $f = x^2 + y^2 + z^2$

      • $g = x^4 + y^4 + z^4$

      We have that $nabla^2 f neq 0$ by compuing the second derivative of each coordinate separately:



      $$
      left(
      fracpartial^2partial x^2 +
      fracpartial^2partial y^2 +
      fracpartial^2partial z^2
      right) (x^4 + y^4 + z^4) = 12(x^2 + y^2 + z^2) neq 0
      $$

      We have a decomposition $L^2(S^2) = bigoplus H_d $ with $H_d = textharmonic polynomials in x,y,z text of degree d $. I am pretty sure the two functions I have constructed are in $L^2$.



      $$ int_S^2 |f|^2 < 9 int_S^2 1, dS = 9 times (4pi) $$
      and a similar story for $g$. How can I get an expansion of $f$ and $g$ in terms of harmonic polynomials? Are there terms of lower degree missing?







      multivariable-calculus polynomials hilbert-spaces spherical-harmonics






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 25 at 23:15









      Benjamin

      643419




      643419










      asked Mar 25 at 19:03









      cactus314cactus314

      15.5k42269




      15.5k42269




















          1 Answer
          1






          active

          oldest

          votes


















          1












          $begingroup$

          You can decompose a function on $mathbbS^2$ into spherical harmonics, not into harmonic polynomials. They are related, but they are not the same. Spherical harmonics satisfy the equation
          $$ Delta_mathbbS^2 Y^m_l(theta, phi) = -l(l+1) Y^m_l (theta, phi)$$
          which means that functions $f(x,y,z) = r^l Y^m_l(theta,phi)$ are harmonic functions. Such functions also happen to be polynomials, so they are called harmonic polynomials. However, if you multiply a spherical harmonic with wrong power of $r$, you don't get a harmonic polynomial.



          If you want to write your functions into spherical harmonic, you need to separate their radial and spherical part. In case of $f$ it's simple
          $$ f(x,y,z) = r^2 = sqrt4pi, r^2 Y^0_0(theta, phi)$$
          You can see that it involves a spherical harmonic with $l=0$ multiplied by $r^2$. The power of $r$ doesn't match, so no wonder you don't get a harmonic polynomial, $Delta f neq 0$.



          With $g$ you have
          beginalign g(x,y,z) &= r^4 (sin^4theta cos^4phi + sin^4thetasin^4phi + cos^4theta) = \
          &= r^4 left(sin^4theta Big(frac18 e^4iphi + frac34 + frac18 e^-4iphiBig) + cos^4thetaright) = \
          &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac34 sin^4theta + cos^4thetaright) = \
          &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac74 cos^4theta - frac32 cos^2theta +frac34right) = \
          &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac4sqrtpi15 Y^0_4(theta,phi) +frac6sqrtpi5Y^0_0(theta,phi)right)endalign

          Again, you have spherical harmonic with index $l=0$ not matching the power of $r$, so you don't get a harmonic polynomial, and $Delta g neq 0$.






          share|cite|improve this answer











          $endgroup$













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            1












            $begingroup$

            You can decompose a function on $mathbbS^2$ into spherical harmonics, not into harmonic polynomials. They are related, but they are not the same. Spherical harmonics satisfy the equation
            $$ Delta_mathbbS^2 Y^m_l(theta, phi) = -l(l+1) Y^m_l (theta, phi)$$
            which means that functions $f(x,y,z) = r^l Y^m_l(theta,phi)$ are harmonic functions. Such functions also happen to be polynomials, so they are called harmonic polynomials. However, if you multiply a spherical harmonic with wrong power of $r$, you don't get a harmonic polynomial.



            If you want to write your functions into spherical harmonic, you need to separate their radial and spherical part. In case of $f$ it's simple
            $$ f(x,y,z) = r^2 = sqrt4pi, r^2 Y^0_0(theta, phi)$$
            You can see that it involves a spherical harmonic with $l=0$ multiplied by $r^2$. The power of $r$ doesn't match, so no wonder you don't get a harmonic polynomial, $Delta f neq 0$.



            With $g$ you have
            beginalign g(x,y,z) &= r^4 (sin^4theta cos^4phi + sin^4thetasin^4phi + cos^4theta) = \
            &= r^4 left(sin^4theta Big(frac18 e^4iphi + frac34 + frac18 e^-4iphiBig) + cos^4thetaright) = \
            &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac34 sin^4theta + cos^4thetaright) = \
            &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac74 cos^4theta - frac32 cos^2theta +frac34right) = \
            &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac4sqrtpi15 Y^0_4(theta,phi) +frac6sqrtpi5Y^0_0(theta,phi)right)endalign

            Again, you have spherical harmonic with index $l=0$ not matching the power of $r$, so you don't get a harmonic polynomial, and $Delta g neq 0$.






            share|cite|improve this answer











            $endgroup$

















              1












              $begingroup$

              You can decompose a function on $mathbbS^2$ into spherical harmonics, not into harmonic polynomials. They are related, but they are not the same. Spherical harmonics satisfy the equation
              $$ Delta_mathbbS^2 Y^m_l(theta, phi) = -l(l+1) Y^m_l (theta, phi)$$
              which means that functions $f(x,y,z) = r^l Y^m_l(theta,phi)$ are harmonic functions. Such functions also happen to be polynomials, so they are called harmonic polynomials. However, if you multiply a spherical harmonic with wrong power of $r$, you don't get a harmonic polynomial.



              If you want to write your functions into spherical harmonic, you need to separate their radial and spherical part. In case of $f$ it's simple
              $$ f(x,y,z) = r^2 = sqrt4pi, r^2 Y^0_0(theta, phi)$$
              You can see that it involves a spherical harmonic with $l=0$ multiplied by $r^2$. The power of $r$ doesn't match, so no wonder you don't get a harmonic polynomial, $Delta f neq 0$.



              With $g$ you have
              beginalign g(x,y,z) &= r^4 (sin^4theta cos^4phi + sin^4thetasin^4phi + cos^4theta) = \
              &= r^4 left(sin^4theta Big(frac18 e^4iphi + frac34 + frac18 e^-4iphiBig) + cos^4thetaright) = \
              &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac34 sin^4theta + cos^4thetaright) = \
              &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac74 cos^4theta - frac32 cos^2theta +frac34right) = \
              &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac4sqrtpi15 Y^0_4(theta,phi) +frac6sqrtpi5Y^0_0(theta,phi)right)endalign

              Again, you have spherical harmonic with index $l=0$ not matching the power of $r$, so you don't get a harmonic polynomial, and $Delta g neq 0$.






              share|cite|improve this answer











              $endgroup$















                1












                1








                1





                $begingroup$

                You can decompose a function on $mathbbS^2$ into spherical harmonics, not into harmonic polynomials. They are related, but they are not the same. Spherical harmonics satisfy the equation
                $$ Delta_mathbbS^2 Y^m_l(theta, phi) = -l(l+1) Y^m_l (theta, phi)$$
                which means that functions $f(x,y,z) = r^l Y^m_l(theta,phi)$ are harmonic functions. Such functions also happen to be polynomials, so they are called harmonic polynomials. However, if you multiply a spherical harmonic with wrong power of $r$, you don't get a harmonic polynomial.



                If you want to write your functions into spherical harmonic, you need to separate their radial and spherical part. In case of $f$ it's simple
                $$ f(x,y,z) = r^2 = sqrt4pi, r^2 Y^0_0(theta, phi)$$
                You can see that it involves a spherical harmonic with $l=0$ multiplied by $r^2$. The power of $r$ doesn't match, so no wonder you don't get a harmonic polynomial, $Delta f neq 0$.



                With $g$ you have
                beginalign g(x,y,z) &= r^4 (sin^4theta cos^4phi + sin^4thetasin^4phi + cos^4theta) = \
                &= r^4 left(sin^4theta Big(frac18 e^4iphi + frac34 + frac18 e^-4iphiBig) + cos^4thetaright) = \
                &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac34 sin^4theta + cos^4thetaright) = \
                &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac74 cos^4theta - frac32 cos^2theta +frac34right) = \
                &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac4sqrtpi15 Y^0_4(theta,phi) +frac6sqrtpi5Y^0_0(theta,phi)right)endalign

                Again, you have spherical harmonic with index $l=0$ not matching the power of $r$, so you don't get a harmonic polynomial, and $Delta g neq 0$.






                share|cite|improve this answer











                $endgroup$



                You can decompose a function on $mathbbS^2$ into spherical harmonics, not into harmonic polynomials. They are related, but they are not the same. Spherical harmonics satisfy the equation
                $$ Delta_mathbbS^2 Y^m_l(theta, phi) = -l(l+1) Y^m_l (theta, phi)$$
                which means that functions $f(x,y,z) = r^l Y^m_l(theta,phi)$ are harmonic functions. Such functions also happen to be polynomials, so they are called harmonic polynomials. However, if you multiply a spherical harmonic with wrong power of $r$, you don't get a harmonic polynomial.



                If you want to write your functions into spherical harmonic, you need to separate their radial and spherical part. In case of $f$ it's simple
                $$ f(x,y,z) = r^2 = sqrt4pi, r^2 Y^0_0(theta, phi)$$
                You can see that it involves a spherical harmonic with $l=0$ multiplied by $r^2$. The power of $r$ doesn't match, so no wonder you don't get a harmonic polynomial, $Delta f neq 0$.



                With $g$ you have
                beginalign g(x,y,z) &= r^4 (sin^4theta cos^4phi + sin^4thetasin^4phi + cos^4theta) = \
                &= r^4 left(sin^4theta Big(frac18 e^4iphi + frac34 + frac18 e^-4iphiBig) + cos^4thetaright) = \
                &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac34 sin^4theta + cos^4thetaright) = \
                &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac74 cos^4theta - frac32 cos^2theta +frac34right) = \
                &= r^4 left(sqrtfrac8pi315Y^4_4(theta,phi) + sqrtfrac8pi315Y^-4_4(theta,phi)+ frac4sqrtpi15 Y^0_4(theta,phi) +frac6sqrtpi5Y^0_0(theta,phi)right)endalign

                Again, you have spherical harmonic with index $l=0$ not matching the power of $r$, so you don't get a harmonic polynomial, and $Delta g neq 0$.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Mar 25 at 21:47

























                answered Mar 25 at 21:10









                Adam LatosińskiAdam Latosiński

                6518




                6518



























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