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Bifurcation with two parameters



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)researching hopf bifurcationRelationship between Turing bifurcation, saddle-node bifurcation, and Hopf bifurcation?Does this type of bifurcation exist?Hopf bifurcation and limit cycle2D Bifurcation ClassificationPitchfork Bifurcation - subcritical and supercritical?Hopf bifurcation and limit cycles: problem in understandingHow can I classify the type of a bifurcation that doesn't seem to change the state of the equilibrium points?Supercritical and subcritical Hopf bifurcationBifurcation in a linear system with 2 equations and 1parameter










1












$begingroup$


Question:



Consider the system



beginalign
fracdxdt & = y \
fracdydt & = -(x^2+mu)y - (x^2+nu)x
endalign



Conduct Hopf analysis at the parameter values where Hopf bifurcations occur.




Attempt:



When we only have one parameter, I understand that a bifurcation occurs at the parameter value where the critical point(s) change stability. However, what is the definition of a bifurcation point when there are two or more parameter values?



In this particular example, I see that the critical points are at $(0,0)$ and $(pm sqrt-nu,0)$, where the latter only exists when $nu<0$.



Going from $nu>0$ to $nu<0$, the critical point $(0,0)$ goes from being stable to unstable, and we also gain two extra critical points - so is it right to say that we have a bifurcation at $nu=0$?










share|cite|improve this question









$endgroup$











  • $begingroup$
    Bifurcation points are like borderline between the regions of systems on parameter plane (or space) with qualitatively the same behaviour. If you are studying bifurcations of equilibria of planar systems, local bifurcations only happen when you pass through a non-hyperbolic equilibrium: i.e., its linearization has eigenvalues $lambda$ with $Relambda = 0$. So, yeah, $nu = 0$ belongs to a set of bifurcation points: it follows both from change in qualitative picture (number of equilibria is different depending on point in the neighbourhood) and from non-hyperbolicity of equilibrium.
    $endgroup$
    – Evgeny
    Mar 26 at 10:09















1












$begingroup$


Question:



Consider the system



beginalign
fracdxdt & = y \
fracdydt & = -(x^2+mu)y - (x^2+nu)x
endalign



Conduct Hopf analysis at the parameter values where Hopf bifurcations occur.




Attempt:



When we only have one parameter, I understand that a bifurcation occurs at the parameter value where the critical point(s) change stability. However, what is the definition of a bifurcation point when there are two or more parameter values?



In this particular example, I see that the critical points are at $(0,0)$ and $(pm sqrt-nu,0)$, where the latter only exists when $nu<0$.



Going from $nu>0$ to $nu<0$, the critical point $(0,0)$ goes from being stable to unstable, and we also gain two extra critical points - so is it right to say that we have a bifurcation at $nu=0$?










share|cite|improve this question









$endgroup$











  • $begingroup$
    Bifurcation points are like borderline between the regions of systems on parameter plane (or space) with qualitatively the same behaviour. If you are studying bifurcations of equilibria of planar systems, local bifurcations only happen when you pass through a non-hyperbolic equilibrium: i.e., its linearization has eigenvalues $lambda$ with $Relambda = 0$. So, yeah, $nu = 0$ belongs to a set of bifurcation points: it follows both from change in qualitative picture (number of equilibria is different depending on point in the neighbourhood) and from non-hyperbolicity of equilibrium.
    $endgroup$
    – Evgeny
    Mar 26 at 10:09













1












1








1





$begingroup$


Question:



Consider the system



beginalign
fracdxdt & = y \
fracdydt & = -(x^2+mu)y - (x^2+nu)x
endalign



Conduct Hopf analysis at the parameter values where Hopf bifurcations occur.




Attempt:



When we only have one parameter, I understand that a bifurcation occurs at the parameter value where the critical point(s) change stability. However, what is the definition of a bifurcation point when there are two or more parameter values?



In this particular example, I see that the critical points are at $(0,0)$ and $(pm sqrt-nu,0)$, where the latter only exists when $nu<0$.



Going from $nu>0$ to $nu<0$, the critical point $(0,0)$ goes from being stable to unstable, and we also gain two extra critical points - so is it right to say that we have a bifurcation at $nu=0$?










share|cite|improve this question









$endgroup$




Question:



Consider the system



beginalign
fracdxdt & = y \
fracdydt & = -(x^2+mu)y - (x^2+nu)x
endalign



Conduct Hopf analysis at the parameter values where Hopf bifurcations occur.




Attempt:



When we only have one parameter, I understand that a bifurcation occurs at the parameter value where the critical point(s) change stability. However, what is the definition of a bifurcation point when there are two or more parameter values?



In this particular example, I see that the critical points are at $(0,0)$ and $(pm sqrt-nu,0)$, where the latter only exists when $nu<0$.



Going from $nu>0$ to $nu<0$, the critical point $(0,0)$ goes from being stable to unstable, and we also gain two extra critical points - so is it right to say that we have a bifurcation at $nu=0$?







ordinary-differential-equations dynamical-systems bifurcation






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 25 at 21:06









glowstonetreesglowstonetrees

2,390418




2,390418











  • $begingroup$
    Bifurcation points are like borderline between the regions of systems on parameter plane (or space) with qualitatively the same behaviour. If you are studying bifurcations of equilibria of planar systems, local bifurcations only happen when you pass through a non-hyperbolic equilibrium: i.e., its linearization has eigenvalues $lambda$ with $Relambda = 0$. So, yeah, $nu = 0$ belongs to a set of bifurcation points: it follows both from change in qualitative picture (number of equilibria is different depending on point in the neighbourhood) and from non-hyperbolicity of equilibrium.
    $endgroup$
    – Evgeny
    Mar 26 at 10:09
















  • $begingroup$
    Bifurcation points are like borderline between the regions of systems on parameter plane (or space) with qualitatively the same behaviour. If you are studying bifurcations of equilibria of planar systems, local bifurcations only happen when you pass through a non-hyperbolic equilibrium: i.e., its linearization has eigenvalues $lambda$ with $Relambda = 0$. So, yeah, $nu = 0$ belongs to a set of bifurcation points: it follows both from change in qualitative picture (number of equilibria is different depending on point in the neighbourhood) and from non-hyperbolicity of equilibrium.
    $endgroup$
    – Evgeny
    Mar 26 at 10:09















$begingroup$
Bifurcation points are like borderline between the regions of systems on parameter plane (or space) with qualitatively the same behaviour. If you are studying bifurcations of equilibria of planar systems, local bifurcations only happen when you pass through a non-hyperbolic equilibrium: i.e., its linearization has eigenvalues $lambda$ with $Relambda = 0$. So, yeah, $nu = 0$ belongs to a set of bifurcation points: it follows both from change in qualitative picture (number of equilibria is different depending on point in the neighbourhood) and from non-hyperbolicity of equilibrium.
$endgroup$
– Evgeny
Mar 26 at 10:09




$begingroup$
Bifurcation points are like borderline between the regions of systems on parameter plane (or space) with qualitatively the same behaviour. If you are studying bifurcations of equilibria of planar systems, local bifurcations only happen when you pass through a non-hyperbolic equilibrium: i.e., its linearization has eigenvalues $lambda$ with $Relambda = 0$. So, yeah, $nu = 0$ belongs to a set of bifurcation points: it follows both from change in qualitative picture (number of equilibria is different depending on point in the neighbourhood) and from non-hyperbolicity of equilibrium.
$endgroup$
– Evgeny
Mar 26 at 10:09










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