Integrals involving Dirichlet kernel and sinc function Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Help evaluating or upper-bounding integral $int_-infty^infty fracaboperatornamesinc^2(cx)a+boperatornamesinc^2(cx);dx$Integrating sinc / gaussian function with 2nd order polynomials as argumentsIntegral involving $operatornamesinc$ and exponentialCalculate $int_-T^T operatornamesincbig(tau-lambdabig) operatornamesincbig(tau-nubig)dtau$.Fourier transform of a product of two rect functionsImpossible definite integral!evaluate a Fraunhofer diffraction integralDefinite integral $int_y^infty$ involving two Meijer's G functionIntegral involving 2-dimensional Gaussian functionFourier transform of the convolution of a Dirac comb with the product of a complex exponential function and a rect function

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Integrals involving Dirichlet kernel and sinc function



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Help evaluating or upper-bounding integral $int_-infty^infty fracaboperatornamesinc^2(cx)a+boperatornamesinc^2(cx);dx$Integrating sinc / gaussian function with 2nd order polynomials as argumentsIntegral involving $operatornamesinc$ and exponentialCalculate $int_-T^T operatornamesincbig(tau-lambdabig) operatornamesincbig(tau-nubig)dtau$.Fourier transform of a product of two rect functionsImpossible definite integral!evaluate a Fraunhofer diffraction integralDefinite integral $int_y^infty$ involving two Meijer's G functionIntegral involving 2-dimensional Gaussian functionFourier transform of the convolution of a Dirac comb with the product of a complex exponential function and a rect function










0












$begingroup$


I am looking to evaluate the following definite integral involving Dirichlet kernel and sinc function with phase.
beginequationI(d) = int_-infty^infty fracsin[N(k^"-k^')]sin(k^"-k^') fracsin(c(k^"-k^'))c(k^"-k^') fracsin(Nk^')sin(k^') fracsin(ck^')ck^' exp(ik^'d+iphi(k^')) rect Big(frack^'k_0Big) dk^' endequation



Seems to be difficult due to Dirichlet kernel. Thank you in advance.










share|cite|improve this question











$endgroup$











  • $begingroup$
    No, the Dirichlet kernel cancel and with $int_-infty^infty$ instead of $int_0^k_0$ it would have a closed form.
    $endgroup$
    – reuns
    Mar 25 at 22:13











  • $begingroup$
    Kindly explain how they cancel? btw, I corrected for missing constant in the sinc argument.
    $endgroup$
    – user16409
    Mar 25 at 22:52










  • $begingroup$
    With your $c$ they don't anymore. Why would you want to evaluate $int_0^k_0$ ? With $int_-infty^infty$ it still has a closed form
    $endgroup$
    – reuns
    Mar 25 at 22:54











  • $begingroup$
    $int_0^k_0$ ? --> I have optical low pass filter that limits spatial frequencies.
    $endgroup$
    – user16409
    Mar 25 at 23:06















0












$begingroup$


I am looking to evaluate the following definite integral involving Dirichlet kernel and sinc function with phase.
beginequationI(d) = int_-infty^infty fracsin[N(k^"-k^')]sin(k^"-k^') fracsin(c(k^"-k^'))c(k^"-k^') fracsin(Nk^')sin(k^') fracsin(ck^')ck^' exp(ik^'d+iphi(k^')) rect Big(frack^'k_0Big) dk^' endequation



Seems to be difficult due to Dirichlet kernel. Thank you in advance.










share|cite|improve this question











$endgroup$











  • $begingroup$
    No, the Dirichlet kernel cancel and with $int_-infty^infty$ instead of $int_0^k_0$ it would have a closed form.
    $endgroup$
    – reuns
    Mar 25 at 22:13











  • $begingroup$
    Kindly explain how they cancel? btw, I corrected for missing constant in the sinc argument.
    $endgroup$
    – user16409
    Mar 25 at 22:52










  • $begingroup$
    With your $c$ they don't anymore. Why would you want to evaluate $int_0^k_0$ ? With $int_-infty^infty$ it still has a closed form
    $endgroup$
    – reuns
    Mar 25 at 22:54











  • $begingroup$
    $int_0^k_0$ ? --> I have optical low pass filter that limits spatial frequencies.
    $endgroup$
    – user16409
    Mar 25 at 23:06













0












0








0





$begingroup$


I am looking to evaluate the following definite integral involving Dirichlet kernel and sinc function with phase.
beginequationI(d) = int_-infty^infty fracsin[N(k^"-k^')]sin(k^"-k^') fracsin(c(k^"-k^'))c(k^"-k^') fracsin(Nk^')sin(k^') fracsin(ck^')ck^' exp(ik^'d+iphi(k^')) rect Big(frack^'k_0Big) dk^' endequation



Seems to be difficult due to Dirichlet kernel. Thank you in advance.










share|cite|improve this question











$endgroup$




I am looking to evaluate the following definite integral involving Dirichlet kernel and sinc function with phase.
beginequationI(d) = int_-infty^infty fracsin[N(k^"-k^')]sin(k^"-k^') fracsin(c(k^"-k^'))c(k^"-k^') fracsin(Nk^')sin(k^') fracsin(ck^')ck^' exp(ik^'d+iphi(k^')) rect Big(frack^'k_0Big) dk^' endequation



Seems to be difficult due to Dirichlet kernel. Thank you in advance.







definite-integrals convolution






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 28 at 9:25







user16409

















asked Mar 25 at 21:02









user16409user16409

85111




85111











  • $begingroup$
    No, the Dirichlet kernel cancel and with $int_-infty^infty$ instead of $int_0^k_0$ it would have a closed form.
    $endgroup$
    – reuns
    Mar 25 at 22:13











  • $begingroup$
    Kindly explain how they cancel? btw, I corrected for missing constant in the sinc argument.
    $endgroup$
    – user16409
    Mar 25 at 22:52










  • $begingroup$
    With your $c$ they don't anymore. Why would you want to evaluate $int_0^k_0$ ? With $int_-infty^infty$ it still has a closed form
    $endgroup$
    – reuns
    Mar 25 at 22:54











  • $begingroup$
    $int_0^k_0$ ? --> I have optical low pass filter that limits spatial frequencies.
    $endgroup$
    – user16409
    Mar 25 at 23:06
















  • $begingroup$
    No, the Dirichlet kernel cancel and with $int_-infty^infty$ instead of $int_0^k_0$ it would have a closed form.
    $endgroup$
    – reuns
    Mar 25 at 22:13











  • $begingroup$
    Kindly explain how they cancel? btw, I corrected for missing constant in the sinc argument.
    $endgroup$
    – user16409
    Mar 25 at 22:52










  • $begingroup$
    With your $c$ they don't anymore. Why would you want to evaluate $int_0^k_0$ ? With $int_-infty^infty$ it still has a closed form
    $endgroup$
    – reuns
    Mar 25 at 22:54











  • $begingroup$
    $int_0^k_0$ ? --> I have optical low pass filter that limits spatial frequencies.
    $endgroup$
    – user16409
    Mar 25 at 23:06















$begingroup$
No, the Dirichlet kernel cancel and with $int_-infty^infty$ instead of $int_0^k_0$ it would have a closed form.
$endgroup$
– reuns
Mar 25 at 22:13





$begingroup$
No, the Dirichlet kernel cancel and with $int_-infty^infty$ instead of $int_0^k_0$ it would have a closed form.
$endgroup$
– reuns
Mar 25 at 22:13













$begingroup$
Kindly explain how they cancel? btw, I corrected for missing constant in the sinc argument.
$endgroup$
– user16409
Mar 25 at 22:52




$begingroup$
Kindly explain how they cancel? btw, I corrected for missing constant in the sinc argument.
$endgroup$
– user16409
Mar 25 at 22:52












$begingroup$
With your $c$ they don't anymore. Why would you want to evaluate $int_0^k_0$ ? With $int_-infty^infty$ it still has a closed form
$endgroup$
– reuns
Mar 25 at 22:54





$begingroup$
With your $c$ they don't anymore. Why would you want to evaluate $int_0^k_0$ ? With $int_-infty^infty$ it still has a closed form
$endgroup$
– reuns
Mar 25 at 22:54













$begingroup$
$int_0^k_0$ ? --> I have optical low pass filter that limits spatial frequencies.
$endgroup$
– user16409
Mar 25 at 23:06




$begingroup$
$int_0^k_0$ ? --> I have optical low pass filter that limits spatial frequencies.
$endgroup$
– user16409
Mar 25 at 23:06










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