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How to find the dual of max flow using bounding?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Difficulties in Writing the Dual of a Primal ProgramDuality. Is this the correct Dual to this Primal L.P.?Integer linear programming, energy constrained max-flow problem, column generationDual problem to max flow with leaking and minimal flowWhat is the significance of an infeasible solution to a network flow problem?Obtaining the Lagrangian dual by relaxationWrite down the dual LP and show that $y$ is a feasible solution to the dual LP.Dual Of Integer Network FormulationDeriving the dual of the minimum cost flow problem.Dual of a linear program.










0












$begingroup$


I am learning about dual programs in a grad class, but the lectures are lacking. I had to teach myself the bounding method and I understand it, but I'm not sure how to apply it to the Max-flow problem. We did not go over how we obtained the dual in much detail during lecture.



Here is the concept I am trying to use:



To find the dual of
$$max_x c^Tx\
texts.t. Axleq b\
-Ixleq 0
$$

where $I$ is the identity matrix, note that for any $y,z geq 0$ and feasible solution the following must hold:
$$y^T(Ax-b)+z^T(-Ix)leq 0.$$
After some manipulation,
$$(A^Ty-Iz)x leq b^Ty$$
which yields the dual
$$min_y b^Ty\
texts.t. A^Ty-Iz = c\
ygeq 0.$$

We can then eliminate $z$ and get the constraint $A^Txgeq c$.



From my understanding, this works because we can relate $c$ to the coefficient on $x$ in the linear combination of constraints. However, the objective function in Max-flow only deals with flow out of the source and the flow conservation and capacity constraints deal with all flows in the network. Can this method still be applied to find the dual, or is there another method I need to learn?



Here is the Max-flow problem as a LP:
$$max sum_v:(s,v)in E f(s,v)\
texts.t. sum_u:(u,v)in E f(u,v) - sum_w:(v,w)in E f(v,w) = 0, forall vin V - s,t\
f(u,v)leq c(u,v), forall (u,v)in E\
f(u,v)geq 0, forall (u,v)in E.$$










share|cite|improve this question









$endgroup$
















    0












    $begingroup$


    I am learning about dual programs in a grad class, but the lectures are lacking. I had to teach myself the bounding method and I understand it, but I'm not sure how to apply it to the Max-flow problem. We did not go over how we obtained the dual in much detail during lecture.



    Here is the concept I am trying to use:



    To find the dual of
    $$max_x c^Tx\
    texts.t. Axleq b\
    -Ixleq 0
    $$

    where $I$ is the identity matrix, note that for any $y,z geq 0$ and feasible solution the following must hold:
    $$y^T(Ax-b)+z^T(-Ix)leq 0.$$
    After some manipulation,
    $$(A^Ty-Iz)x leq b^Ty$$
    which yields the dual
    $$min_y b^Ty\
    texts.t. A^Ty-Iz = c\
    ygeq 0.$$

    We can then eliminate $z$ and get the constraint $A^Txgeq c$.



    From my understanding, this works because we can relate $c$ to the coefficient on $x$ in the linear combination of constraints. However, the objective function in Max-flow only deals with flow out of the source and the flow conservation and capacity constraints deal with all flows in the network. Can this method still be applied to find the dual, or is there another method I need to learn?



    Here is the Max-flow problem as a LP:
    $$max sum_v:(s,v)in E f(s,v)\
    texts.t. sum_u:(u,v)in E f(u,v) - sum_w:(v,w)in E f(v,w) = 0, forall vin V - s,t\
    f(u,v)leq c(u,v), forall (u,v)in E\
    f(u,v)geq 0, forall (u,v)in E.$$










    share|cite|improve this question









    $endgroup$














      0












      0








      0





      $begingroup$


      I am learning about dual programs in a grad class, but the lectures are lacking. I had to teach myself the bounding method and I understand it, but I'm not sure how to apply it to the Max-flow problem. We did not go over how we obtained the dual in much detail during lecture.



      Here is the concept I am trying to use:



      To find the dual of
      $$max_x c^Tx\
      texts.t. Axleq b\
      -Ixleq 0
      $$

      where $I$ is the identity matrix, note that for any $y,z geq 0$ and feasible solution the following must hold:
      $$y^T(Ax-b)+z^T(-Ix)leq 0.$$
      After some manipulation,
      $$(A^Ty-Iz)x leq b^Ty$$
      which yields the dual
      $$min_y b^Ty\
      texts.t. A^Ty-Iz = c\
      ygeq 0.$$

      We can then eliminate $z$ and get the constraint $A^Txgeq c$.



      From my understanding, this works because we can relate $c$ to the coefficient on $x$ in the linear combination of constraints. However, the objective function in Max-flow only deals with flow out of the source and the flow conservation and capacity constraints deal with all flows in the network. Can this method still be applied to find the dual, or is there another method I need to learn?



      Here is the Max-flow problem as a LP:
      $$max sum_v:(s,v)in E f(s,v)\
      texts.t. sum_u:(u,v)in E f(u,v) - sum_w:(v,w)in E f(v,w) = 0, forall vin V - s,t\
      f(u,v)leq c(u,v), forall (u,v)in E\
      f(u,v)geq 0, forall (u,v)in E.$$










      share|cite|improve this question









      $endgroup$




      I am learning about dual programs in a grad class, but the lectures are lacking. I had to teach myself the bounding method and I understand it, but I'm not sure how to apply it to the Max-flow problem. We did not go over how we obtained the dual in much detail during lecture.



      Here is the concept I am trying to use:



      To find the dual of
      $$max_x c^Tx\
      texts.t. Axleq b\
      -Ixleq 0
      $$

      where $I$ is the identity matrix, note that for any $y,z geq 0$ and feasible solution the following must hold:
      $$y^T(Ax-b)+z^T(-Ix)leq 0.$$
      After some manipulation,
      $$(A^Ty-Iz)x leq b^Ty$$
      which yields the dual
      $$min_y b^Ty\
      texts.t. A^Ty-Iz = c\
      ygeq 0.$$

      We can then eliminate $z$ and get the constraint $A^Txgeq c$.



      From my understanding, this works because we can relate $c$ to the coefficient on $x$ in the linear combination of constraints. However, the objective function in Max-flow only deals with flow out of the source and the flow conservation and capacity constraints deal with all flows in the network. Can this method still be applied to find the dual, or is there another method I need to learn?



      Here is the Max-flow problem as a LP:
      $$max sum_v:(s,v)in E f(s,v)\
      texts.t. sum_u:(u,v)in E f(u,v) - sum_w:(v,w)in E f(v,w) = 0, forall vin V - s,t\
      f(u,v)leq c(u,v), forall (u,v)in E\
      f(u,v)geq 0, forall (u,v)in E.$$







      linear-programming duality-theorems






      share|cite|improve this question













      share|cite|improve this question











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