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Confusion about tensor fields taking values in vector fields rather than functions
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)A question about Killing vector and Riemann curvature tensorA question about a definition of Ricci curvatureShow isometry of flow on a compact Riemannian manifold where the vector field is KillingUsing index notation to write $d^2=0$ in terms of a torsion free connection.connection laplacian on general vector bundlesBasic question: Riemannian Curvature is nondegenerateHow to derive the Riemann Curvature Tensor?Curvature tensor for a manifold with torsionWhat comes after the curvature tensor in “higher derivatives”?Relation between the Curvature of a Connection and the Curvature of the Induced Connection on the Frame Bundle
$begingroup$
I'm beginning with tensorial calculus and I have some questions. Let $(M,g)$ a riemannian manifold with $nabla$ his Levi Civita connection. The curvature tensor $R$ is defined as
beginalign*
R : mathfrakX(M) times mathfrakX(M) times mathfrakX(M) &to mathfrakX(M)\
(X,Y,Z) &mapsto R(X,Y)Z
endalign*
where
$$R(X,Y)Z = nabla_X nabla_Y Z - nabla_Y nabla_X Z - nabla_[X,Y]Z.$$
In all books of differential geometry, they said that $R$ is a $(1,3)$ tensor but I don't know why, because a $(1,3)$ tensor is a multilinear map
$$Omega^1(M) times mathfrakX(M) times mathfrakX(M)timesmathfrakX(M) to C^infty(M).$$
I think that I don't understand any concept or because for example, let $X in mathfrakX(M)$, then $nabla X : TM to TM$, $(nabla X)(v_p) = nabla_v_pX$, is a $(1,1)$ tensor field and I don't know why.
$textbfRemark$: $Omega^1(M)$ is the set of all 1-forms, $alpha : M to TM^*$.
differential-geometry tensors
$endgroup$
add a comment |
$begingroup$
I'm beginning with tensorial calculus and I have some questions. Let $(M,g)$ a riemannian manifold with $nabla$ his Levi Civita connection. The curvature tensor $R$ is defined as
beginalign*
R : mathfrakX(M) times mathfrakX(M) times mathfrakX(M) &to mathfrakX(M)\
(X,Y,Z) &mapsto R(X,Y)Z
endalign*
where
$$R(X,Y)Z = nabla_X nabla_Y Z - nabla_Y nabla_X Z - nabla_[X,Y]Z.$$
In all books of differential geometry, they said that $R$ is a $(1,3)$ tensor but I don't know why, because a $(1,3)$ tensor is a multilinear map
$$Omega^1(M) times mathfrakX(M) times mathfrakX(M)timesmathfrakX(M) to C^infty(M).$$
I think that I don't understand any concept or because for example, let $X in mathfrakX(M)$, then $nabla X : TM to TM$, $(nabla X)(v_p) = nabla_v_pX$, is a $(1,1)$ tensor field and I don't know why.
$textbfRemark$: $Omega^1(M)$ is the set of all 1-forms, $alpha : M to TM^*$.
differential-geometry tensors
$endgroup$
add a comment |
$begingroup$
I'm beginning with tensorial calculus and I have some questions. Let $(M,g)$ a riemannian manifold with $nabla$ his Levi Civita connection. The curvature tensor $R$ is defined as
beginalign*
R : mathfrakX(M) times mathfrakX(M) times mathfrakX(M) &to mathfrakX(M)\
(X,Y,Z) &mapsto R(X,Y)Z
endalign*
where
$$R(X,Y)Z = nabla_X nabla_Y Z - nabla_Y nabla_X Z - nabla_[X,Y]Z.$$
In all books of differential geometry, they said that $R$ is a $(1,3)$ tensor but I don't know why, because a $(1,3)$ tensor is a multilinear map
$$Omega^1(M) times mathfrakX(M) times mathfrakX(M)timesmathfrakX(M) to C^infty(M).$$
I think that I don't understand any concept or because for example, let $X in mathfrakX(M)$, then $nabla X : TM to TM$, $(nabla X)(v_p) = nabla_v_pX$, is a $(1,1)$ tensor field and I don't know why.
$textbfRemark$: $Omega^1(M)$ is the set of all 1-forms, $alpha : M to TM^*$.
differential-geometry tensors
$endgroup$
I'm beginning with tensorial calculus and I have some questions. Let $(M,g)$ a riemannian manifold with $nabla$ his Levi Civita connection. The curvature tensor $R$ is defined as
beginalign*
R : mathfrakX(M) times mathfrakX(M) times mathfrakX(M) &to mathfrakX(M)\
(X,Y,Z) &mapsto R(X,Y)Z
endalign*
where
$$R(X,Y)Z = nabla_X nabla_Y Z - nabla_Y nabla_X Z - nabla_[X,Y]Z.$$
In all books of differential geometry, they said that $R$ is a $(1,3)$ tensor but I don't know why, because a $(1,3)$ tensor is a multilinear map
$$Omega^1(M) times mathfrakX(M) times mathfrakX(M)timesmathfrakX(M) to C^infty(M).$$
I think that I don't understand any concept or because for example, let $X in mathfrakX(M)$, then $nabla X : TM to TM$, $(nabla X)(v_p) = nabla_v_pX$, is a $(1,1)$ tensor field and I don't know why.
$textbfRemark$: $Omega^1(M)$ is the set of all 1-forms, $alpha : M to TM^*$.
differential-geometry tensors
differential-geometry tensors
edited Mar 25 at 19:19
Michael Albanese
64.8k1599315
64.8k1599315
asked Mar 25 at 18:58
hal97hal97
907
907
add a comment |
add a comment |
1 Answer
1
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$begingroup$
A $(p, q)$-tensor field on a smooth manifold $M$ is a $C^infty(M)$-multilinear map $T : Omega^1(M)^ptimesmathfrakX(M)^q to C^infty(M)$.
Given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to mathfrakX(M)$, there is an associated $(p + 1, q)$-tensor field $T : Omega^1(M)^p+1timesmathfrakX(M)^q to C^infty(M)$ defined by
$$T(beta, alpha^1, dots, alpha^p, X_1, dots, X_q) := beta(S(alpha^1, dots, alpha^p, X_1, dots, X_q)).$$
Likewise, given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to Omega^1(M)$, there is an associated $(p, q + 1)$-tensor field $T : Omega^1(M)^ptimesmathfrakX(M)^q+1 to C^infty(M)$ defined by
$$T(alpha^1, dots, alpha^p, Y, X_1, dots, X_q) := (S(alpha^1, dots, alpha^p, X_1, dots, X_q))(Y).$$
$endgroup$
add a comment |
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1 Answer
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1 Answer
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active
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votes
$begingroup$
A $(p, q)$-tensor field on a smooth manifold $M$ is a $C^infty(M)$-multilinear map $T : Omega^1(M)^ptimesmathfrakX(M)^q to C^infty(M)$.
Given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to mathfrakX(M)$, there is an associated $(p + 1, q)$-tensor field $T : Omega^1(M)^p+1timesmathfrakX(M)^q to C^infty(M)$ defined by
$$T(beta, alpha^1, dots, alpha^p, X_1, dots, X_q) := beta(S(alpha^1, dots, alpha^p, X_1, dots, X_q)).$$
Likewise, given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to Omega^1(M)$, there is an associated $(p, q + 1)$-tensor field $T : Omega^1(M)^ptimesmathfrakX(M)^q+1 to C^infty(M)$ defined by
$$T(alpha^1, dots, alpha^p, Y, X_1, dots, X_q) := (S(alpha^1, dots, alpha^p, X_1, dots, X_q))(Y).$$
$endgroup$
add a comment |
$begingroup$
A $(p, q)$-tensor field on a smooth manifold $M$ is a $C^infty(M)$-multilinear map $T : Omega^1(M)^ptimesmathfrakX(M)^q to C^infty(M)$.
Given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to mathfrakX(M)$, there is an associated $(p + 1, q)$-tensor field $T : Omega^1(M)^p+1timesmathfrakX(M)^q to C^infty(M)$ defined by
$$T(beta, alpha^1, dots, alpha^p, X_1, dots, X_q) := beta(S(alpha^1, dots, alpha^p, X_1, dots, X_q)).$$
Likewise, given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to Omega^1(M)$, there is an associated $(p, q + 1)$-tensor field $T : Omega^1(M)^ptimesmathfrakX(M)^q+1 to C^infty(M)$ defined by
$$T(alpha^1, dots, alpha^p, Y, X_1, dots, X_q) := (S(alpha^1, dots, alpha^p, X_1, dots, X_q))(Y).$$
$endgroup$
add a comment |
$begingroup$
A $(p, q)$-tensor field on a smooth manifold $M$ is a $C^infty(M)$-multilinear map $T : Omega^1(M)^ptimesmathfrakX(M)^q to C^infty(M)$.
Given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to mathfrakX(M)$, there is an associated $(p + 1, q)$-tensor field $T : Omega^1(M)^p+1timesmathfrakX(M)^q to C^infty(M)$ defined by
$$T(beta, alpha^1, dots, alpha^p, X_1, dots, X_q) := beta(S(alpha^1, dots, alpha^p, X_1, dots, X_q)).$$
Likewise, given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to Omega^1(M)$, there is an associated $(p, q + 1)$-tensor field $T : Omega^1(M)^ptimesmathfrakX(M)^q+1 to C^infty(M)$ defined by
$$T(alpha^1, dots, alpha^p, Y, X_1, dots, X_q) := (S(alpha^1, dots, alpha^p, X_1, dots, X_q))(Y).$$
$endgroup$
A $(p, q)$-tensor field on a smooth manifold $M$ is a $C^infty(M)$-multilinear map $T : Omega^1(M)^ptimesmathfrakX(M)^q to C^infty(M)$.
Given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to mathfrakX(M)$, there is an associated $(p + 1, q)$-tensor field $T : Omega^1(M)^p+1timesmathfrakX(M)^q to C^infty(M)$ defined by
$$T(beta, alpha^1, dots, alpha^p, X_1, dots, X_q) := beta(S(alpha^1, dots, alpha^p, X_1, dots, X_q)).$$
Likewise, given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to Omega^1(M)$, there is an associated $(p, q + 1)$-tensor field $T : Omega^1(M)^ptimesmathfrakX(M)^q+1 to C^infty(M)$ defined by
$$T(alpha^1, dots, alpha^p, Y, X_1, dots, X_q) := (S(alpha^1, dots, alpha^p, X_1, dots, X_q))(Y).$$
answered Mar 25 at 19:19
Michael AlbaneseMichael Albanese
64.8k1599315
64.8k1599315
add a comment |
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