Confusion about tensor fields taking values in vector fields rather than functions Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)A question about Killing vector and Riemann curvature tensorA question about a definition of Ricci curvatureShow isometry of flow on a compact Riemannian manifold where the vector field is KillingUsing index notation to write $d^2=0$ in terms of a torsion free connection.connection laplacian on general vector bundlesBasic question: Riemannian Curvature is nondegenerateHow to derive the Riemann Curvature Tensor?Curvature tensor for a manifold with torsionWhat comes after the curvature tensor in “higher derivatives”?Relation between the Curvature of a Connection and the Curvature of the Induced Connection on the Frame Bundle

If A makes B more likely then B makes A more likely"

Simulating Exploding Dice

Using "nakedly" instead of "with nothing on"

Slither Like a Snake

Passing functions in C++

New Order #5: where Fibonacci and Beatty meet at Wythoff

Two different pronunciation of "понял"

What did Darwin mean by 'squib' here?

Limit for e and 1/e

How does modal jazz use chord progressions?

What is the electric potential inside a point charge?

Why is there no army of Iron-Mans in the MCU?

How can players take actions together that are impossible otherwise?

Why use gamma over alpha radiation?

Direct Experience of Meditation

How to market an anarchic city as a tourism spot to people living in civilized areas?

I'm having difficulty getting my players to do stuff in a sandbox campaign

Why don't the Weasley twins use magic outside of school if the Trace can only find the location of spells cast?

Statistical model of ligand substitution

What was the last x86 CPU that did not have the x87 floating-point unit built in?

Estimate capacitor parameters

Who can trigger ship-wide alerts in Star Trek?

Is it possible to ask for a hotel room without minibar/extra services?

Replacing HDD with SSD; what about non-APFS/APFS?



Confusion about tensor fields taking values in vector fields rather than functions



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)A question about Killing vector and Riemann curvature tensorA question about a definition of Ricci curvatureShow isometry of flow on a compact Riemannian manifold where the vector field is KillingUsing index notation to write $d^2=0$ in terms of a torsion free connection.connection laplacian on general vector bundlesBasic question: Riemannian Curvature is nondegenerateHow to derive the Riemann Curvature Tensor?Curvature tensor for a manifold with torsionWhat comes after the curvature tensor in “higher derivatives”?Relation between the Curvature of a Connection and the Curvature of the Induced Connection on the Frame Bundle










0












$begingroup$


I'm beginning with tensorial calculus and I have some questions. Let $(M,g)$ a riemannian manifold with $nabla$ his Levi Civita connection. The curvature tensor $R$ is defined as



beginalign*
R : mathfrakX(M) times mathfrakX(M) times mathfrakX(M) &to mathfrakX(M)\
(X,Y,Z) &mapsto R(X,Y)Z
endalign*



where



$$R(X,Y)Z = nabla_X nabla_Y Z - nabla_Y nabla_X Z - nabla_[X,Y]Z.$$



In all books of differential geometry, they said that $R$ is a $(1,3)$ tensor but I don't know why, because a $(1,3)$ tensor is a multilinear map



$$Omega^1(M) times mathfrakX(M) times mathfrakX(M)timesmathfrakX(M) to C^infty(M).$$



I think that I don't understand any concept or because for example, let $X in mathfrakX(M)$, then $nabla X : TM to TM$, $(nabla X)(v_p) = nabla_v_pX$, is a $(1,1)$ tensor field and I don't know why.



$textbfRemark$: $Omega^1(M)$ is the set of all 1-forms, $alpha : M to TM^*$.










share|cite|improve this question











$endgroup$
















    0












    $begingroup$


    I'm beginning with tensorial calculus and I have some questions. Let $(M,g)$ a riemannian manifold with $nabla$ his Levi Civita connection. The curvature tensor $R$ is defined as



    beginalign*
    R : mathfrakX(M) times mathfrakX(M) times mathfrakX(M) &to mathfrakX(M)\
    (X,Y,Z) &mapsto R(X,Y)Z
    endalign*



    where



    $$R(X,Y)Z = nabla_X nabla_Y Z - nabla_Y nabla_X Z - nabla_[X,Y]Z.$$



    In all books of differential geometry, they said that $R$ is a $(1,3)$ tensor but I don't know why, because a $(1,3)$ tensor is a multilinear map



    $$Omega^1(M) times mathfrakX(M) times mathfrakX(M)timesmathfrakX(M) to C^infty(M).$$



    I think that I don't understand any concept or because for example, let $X in mathfrakX(M)$, then $nabla X : TM to TM$, $(nabla X)(v_p) = nabla_v_pX$, is a $(1,1)$ tensor field and I don't know why.



    $textbfRemark$: $Omega^1(M)$ is the set of all 1-forms, $alpha : M to TM^*$.










    share|cite|improve this question











    $endgroup$














      0












      0








      0





      $begingroup$


      I'm beginning with tensorial calculus and I have some questions. Let $(M,g)$ a riemannian manifold with $nabla$ his Levi Civita connection. The curvature tensor $R$ is defined as



      beginalign*
      R : mathfrakX(M) times mathfrakX(M) times mathfrakX(M) &to mathfrakX(M)\
      (X,Y,Z) &mapsto R(X,Y)Z
      endalign*



      where



      $$R(X,Y)Z = nabla_X nabla_Y Z - nabla_Y nabla_X Z - nabla_[X,Y]Z.$$



      In all books of differential geometry, they said that $R$ is a $(1,3)$ tensor but I don't know why, because a $(1,3)$ tensor is a multilinear map



      $$Omega^1(M) times mathfrakX(M) times mathfrakX(M)timesmathfrakX(M) to C^infty(M).$$



      I think that I don't understand any concept or because for example, let $X in mathfrakX(M)$, then $nabla X : TM to TM$, $(nabla X)(v_p) = nabla_v_pX$, is a $(1,1)$ tensor field and I don't know why.



      $textbfRemark$: $Omega^1(M)$ is the set of all 1-forms, $alpha : M to TM^*$.










      share|cite|improve this question











      $endgroup$




      I'm beginning with tensorial calculus and I have some questions. Let $(M,g)$ a riemannian manifold with $nabla$ his Levi Civita connection. The curvature tensor $R$ is defined as



      beginalign*
      R : mathfrakX(M) times mathfrakX(M) times mathfrakX(M) &to mathfrakX(M)\
      (X,Y,Z) &mapsto R(X,Y)Z
      endalign*



      where



      $$R(X,Y)Z = nabla_X nabla_Y Z - nabla_Y nabla_X Z - nabla_[X,Y]Z.$$



      In all books of differential geometry, they said that $R$ is a $(1,3)$ tensor but I don't know why, because a $(1,3)$ tensor is a multilinear map



      $$Omega^1(M) times mathfrakX(M) times mathfrakX(M)timesmathfrakX(M) to C^infty(M).$$



      I think that I don't understand any concept or because for example, let $X in mathfrakX(M)$, then $nabla X : TM to TM$, $(nabla X)(v_p) = nabla_v_pX$, is a $(1,1)$ tensor field and I don't know why.



      $textbfRemark$: $Omega^1(M)$ is the set of all 1-forms, $alpha : M to TM^*$.







      differential-geometry tensors






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 25 at 19:19









      Michael Albanese

      64.8k1599315




      64.8k1599315










      asked Mar 25 at 18:58









      hal97hal97

      907




      907




















          1 Answer
          1






          active

          oldest

          votes


















          2












          $begingroup$

          A $(p, q)$-tensor field on a smooth manifold $M$ is a $C^infty(M)$-multilinear map $T : Omega^1(M)^ptimesmathfrakX(M)^q to C^infty(M)$.



          Given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to mathfrakX(M)$, there is an associated $(p + 1, q)$-tensor field $T : Omega^1(M)^p+1timesmathfrakX(M)^q to C^infty(M)$ defined by



          $$T(beta, alpha^1, dots, alpha^p, X_1, dots, X_q) := beta(S(alpha^1, dots, alpha^p, X_1, dots, X_q)).$$



          Likewise, given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to Omega^1(M)$, there is an associated $(p, q + 1)$-tensor field $T : Omega^1(M)^ptimesmathfrakX(M)^q+1 to C^infty(M)$ defined by



          $$T(alpha^1, dots, alpha^p, Y, X_1, dots, X_q) := (S(alpha^1, dots, alpha^p, X_1, dots, X_q))(Y).$$






          share|cite|improve this answer









          $endgroup$













            Your Answer








            StackExchange.ready(function()
            var channelOptions =
            tags: "".split(" "),
            id: "69"
            ;
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function()
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled)
            StackExchange.using("snippets", function()
            createEditor();
            );

            else
            createEditor();

            );

            function createEditor()
            StackExchange.prepareEditor(
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader:
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            ,
            noCode: true, onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            );



            );













            draft saved

            draft discarded


















            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3162188%2fconfusion-about-tensor-fields-taking-values-in-vector-fields-rather-than-functio%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2












            $begingroup$

            A $(p, q)$-tensor field on a smooth manifold $M$ is a $C^infty(M)$-multilinear map $T : Omega^1(M)^ptimesmathfrakX(M)^q to C^infty(M)$.



            Given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to mathfrakX(M)$, there is an associated $(p + 1, q)$-tensor field $T : Omega^1(M)^p+1timesmathfrakX(M)^q to C^infty(M)$ defined by



            $$T(beta, alpha^1, dots, alpha^p, X_1, dots, X_q) := beta(S(alpha^1, dots, alpha^p, X_1, dots, X_q)).$$



            Likewise, given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to Omega^1(M)$, there is an associated $(p, q + 1)$-tensor field $T : Omega^1(M)^ptimesmathfrakX(M)^q+1 to C^infty(M)$ defined by



            $$T(alpha^1, dots, alpha^p, Y, X_1, dots, X_q) := (S(alpha^1, dots, alpha^p, X_1, dots, X_q))(Y).$$






            share|cite|improve this answer









            $endgroup$

















              2












              $begingroup$

              A $(p, q)$-tensor field on a smooth manifold $M$ is a $C^infty(M)$-multilinear map $T : Omega^1(M)^ptimesmathfrakX(M)^q to C^infty(M)$.



              Given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to mathfrakX(M)$, there is an associated $(p + 1, q)$-tensor field $T : Omega^1(M)^p+1timesmathfrakX(M)^q to C^infty(M)$ defined by



              $$T(beta, alpha^1, dots, alpha^p, X_1, dots, X_q) := beta(S(alpha^1, dots, alpha^p, X_1, dots, X_q)).$$



              Likewise, given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to Omega^1(M)$, there is an associated $(p, q + 1)$-tensor field $T : Omega^1(M)^ptimesmathfrakX(M)^q+1 to C^infty(M)$ defined by



              $$T(alpha^1, dots, alpha^p, Y, X_1, dots, X_q) := (S(alpha^1, dots, alpha^p, X_1, dots, X_q))(Y).$$






              share|cite|improve this answer









              $endgroup$















                2












                2








                2





                $begingroup$

                A $(p, q)$-tensor field on a smooth manifold $M$ is a $C^infty(M)$-multilinear map $T : Omega^1(M)^ptimesmathfrakX(M)^q to C^infty(M)$.



                Given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to mathfrakX(M)$, there is an associated $(p + 1, q)$-tensor field $T : Omega^1(M)^p+1timesmathfrakX(M)^q to C^infty(M)$ defined by



                $$T(beta, alpha^1, dots, alpha^p, X_1, dots, X_q) := beta(S(alpha^1, dots, alpha^p, X_1, dots, X_q)).$$



                Likewise, given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to Omega^1(M)$, there is an associated $(p, q + 1)$-tensor field $T : Omega^1(M)^ptimesmathfrakX(M)^q+1 to C^infty(M)$ defined by



                $$T(alpha^1, dots, alpha^p, Y, X_1, dots, X_q) := (S(alpha^1, dots, alpha^p, X_1, dots, X_q))(Y).$$






                share|cite|improve this answer









                $endgroup$



                A $(p, q)$-tensor field on a smooth manifold $M$ is a $C^infty(M)$-multilinear map $T : Omega^1(M)^ptimesmathfrakX(M)^q to C^infty(M)$.



                Given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to mathfrakX(M)$, there is an associated $(p + 1, q)$-tensor field $T : Omega^1(M)^p+1timesmathfrakX(M)^q to C^infty(M)$ defined by



                $$T(beta, alpha^1, dots, alpha^p, X_1, dots, X_q) := beta(S(alpha^1, dots, alpha^p, X_1, dots, X_q)).$$



                Likewise, given a $C^infty(M)$-multilinear map $S : Omega^1(M)^ptimesmathfrakX(M)^q to Omega^1(M)$, there is an associated $(p, q + 1)$-tensor field $T : Omega^1(M)^ptimesmathfrakX(M)^q+1 to C^infty(M)$ defined by



                $$T(alpha^1, dots, alpha^p, Y, X_1, dots, X_q) := (S(alpha^1, dots, alpha^p, X_1, dots, X_q))(Y).$$







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Mar 25 at 19:19









                Michael AlbaneseMichael Albanese

                64.8k1599315




                64.8k1599315



























                    draft saved

                    draft discarded
















































                    Thanks for contributing an answer to Mathematics Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid


                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.

                    Use MathJax to format equations. MathJax reference.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function ()
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3162188%2fconfusion-about-tensor-fields-taking-values-in-vector-fields-rather-than-functio%23new-answer', 'question_page');

                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    Lowndes Grove History Architecture References Navigation menu32°48′6″N 79°57′58″W / 32.80167°N 79.96611°W / 32.80167; -79.9661132°48′6″N 79°57′58″W / 32.80167°N 79.96611°W / 32.80167; -79.9661178002500"National Register Information System"Historic houses of South Carolina"Lowndes Grove""+32° 48' 6.00", −79° 57' 58.00""Lowndes Grove, Charleston County (260 St. Margaret St., Charleston)""Lowndes Grove"The Charleston ExpositionIt Happened in South Carolina"Lowndes Grove (House), Saint Margaret Street & Sixth Avenue, Charleston, Charleston County, SC(Photographs)"Plantations of the Carolina Low Countrye

                    random experiment with two different functions on unit interval Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Random variable and probability space notionsRandom Walk with EdgesFinding functions where the increase over a random interval is Poisson distributedNumber of days until dayCan an observed event in fact be of zero probability?Unit random processmodels of coins and uniform distributionHow to get the number of successes given $n$ trials , probability $P$ and a random variable $X$Absorbing Markov chain in a computer. Is “almost every” turned into always convergence in computer executions?Stopped random walk is not uniformly integrable

                    How should I support this large drywall patch? Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?How do I cover large gaps in drywall?How do I keep drywall around a patch from crumbling?Can I glue a second layer of drywall?How to patch long strip on drywall?Large drywall patch: how to avoid bulging seams?Drywall Mesh Patch vs. Bulge? To remove or not to remove?How to fix this drywall job?Prep drywall before backsplashWhat's the best way to fix this horrible drywall patch job?Drywall patching using 3M Patch Plus Primer