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How to divide by decimal quickly?
How to easily divide numbers in scientific notationProve divisibility for general equation of sucessionHow to divide by 12 quickly?How to divide a number by $2$ numbers?What is $underbrace555cdots555_1000 texttimes textmod 7$ without a calculatorDoes zero divide zeroLong Division of Proper Polynomialspolynomial long division minus of a minus clarificationHow many times can I divide a number by anotherFinding out the remainder of $frac11^text10-1100$ using modulus
$begingroup$
My friend asked me to help solve a problem in which she cannot use a calculator.
$$
requireenclose
beginarrayr
32.45 encloselongdiv253.11 \[-3pt]
endarray
$$
What is the best method to approach this in an exam situation - i.e. relatively quickly?
Thanks for your help.
divisibility
asked Mar 11 at 8:49
alicookalicook
111
New contributor
alicook is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
My friend asked me to help solve a problem in which she cannot use a calculator.
$$
requireenclose
beginarrayr
32.45 encloselongdiv253.11 \[-3pt]
endarray
$$
What is the best method to approach this in an exam situation - i.e. relatively quickly?
Thanks for your help.
divisibility
asked Mar 11 at 8:49
alicookalicook
111
New contributor
alicook is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
You can just focus on finding $$ requireenclose beginarrayr 3245 encloselongdiv25311,\ endarray $$ since $frac253.1132.45 =frac253113245$. By the way, is the exam multiple choice? And what type of answer does it want (decimal form, or remainder?)?
$endgroup$
– Minus One-Twelfth
Mar 11 at 9:00
$begingroup$
That is true. No, it is not multiple choice. With the answer in decimal form.
$endgroup$
– alicook
Mar 11 at 9:06
$begingroup$
This link might be helpful: mathlearners.com/vedic-mathematics/…
$endgroup$
– Paras Khosla
Mar 11 at 9:15
1
$begingroup$
+1 for figuring out how to display a long division using MathJax
$endgroup$
– bubba
Mar 11 at 9:20
add a comment |
$begingroup$
My friend asked me to help solve a problem in which she cannot use a calculator.
$$
requireenclose
beginarrayr
32.45 encloselongdiv253.11 \[-3pt]
endarray
$$
What is the best method to approach this in an exam situation - i.e. relatively quickly?
Thanks for your help.
divisibility
asked Mar 11 at 8:49
alicookalicook
111
New contributor
alicook is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
My friend asked me to help solve a problem in which she cannot use a calculator.
$$
requireenclose
beginarrayr
32.45 encloselongdiv253.11 \[-3pt]
endarray
$$
What is the best method to approach this in an exam situation - i.e. relatively quickly?
Thanks for your help.
divisibility
divisibility
asked Mar 11 at 8:49
alicookalicook
111
New contributor
alicook is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 11 at 8:49
alicookalicook
111
New contributor
alicook is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 11 at 8:49
alicookalicook
111
New contributor
alicook is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 11 at 8:49
alicookalicook
111
asked Mar 11 at 8:49
alicookalicook
111
111
New contributor
alicook is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
alicook is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
alicook is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
You can just focus on finding $$ requireenclose beginarrayr 3245 encloselongdiv25311,\ endarray $$ since $frac253.1132.45 =frac253113245$. By the way, is the exam multiple choice? And what type of answer does it want (decimal form, or remainder?)?
$endgroup$
– Minus One-Twelfth
Mar 11 at 9:00
$begingroup$
That is true. No, it is not multiple choice. With the answer in decimal form.
$endgroup$
– alicook
Mar 11 at 9:06
$begingroup$
This link might be helpful: mathlearners.com/vedic-mathematics/…
$endgroup$
– Paras Khosla
Mar 11 at 9:15
1
$begingroup$
+1 for figuring out how to display a long division using MathJax
$endgroup$
– bubba
Mar 11 at 9:20
add a comment |
$begingroup$
You can just focus on finding $$ requireenclose beginarrayr 3245 encloselongdiv25311,\ endarray $$ since $frac253.1132.45 =frac253113245$. By the way, is the exam multiple choice? And what type of answer does it want (decimal form, or remainder?)?
$endgroup$
– Minus One-Twelfth
Mar 11 at 9:00
$begingroup$
That is true. No, it is not multiple choice. With the answer in decimal form.
$endgroup$
– alicook
Mar 11 at 9:06
$begingroup$
This link might be helpful: mathlearners.com/vedic-mathematics/…
$endgroup$
– Paras Khosla
Mar 11 at 9:15
1
$begingroup$
+1 for figuring out how to display a long division using MathJax
$endgroup$
– bubba
Mar 11 at 9:20
$begingroup$
You can just focus on finding $$ requireenclose beginarrayr 3245 encloselongdiv25311,\ endarray $$ since $frac253.1132.45 =frac253113245$. By the way, is the exam multiple choice? And what type of answer does it want (decimal form, or remainder?)?
$endgroup$
– Minus One-Twelfth
Mar 11 at 9:00
$begingroup$
You can just focus on finding $$ requireenclose beginarrayr 3245 encloselongdiv25311,\ endarray $$ since $frac253.1132.45 =frac253113245$. By the way, is the exam multiple choice? And what type of answer does it want (decimal form, or remainder?)?
$endgroup$
– Minus One-Twelfth
Mar 11 at 9:00
$begingroup$
That is true. No, it is not multiple choice. With the answer in decimal form.
$endgroup$
– alicook
Mar 11 at 9:06
$begingroup$
That is true. No, it is not multiple choice. With the answer in decimal form.
$endgroup$
– alicook
Mar 11 at 9:06
$begingroup$
This link might be helpful: mathlearners.com/vedic-mathematics/…
$endgroup$
– Paras Khosla
Mar 11 at 9:15
$begingroup$
This link might be helpful: mathlearners.com/vedic-mathematics/…
$endgroup$
– Paras Khosla
Mar 11 at 9:15
1
1
$begingroup$
+1 for figuring out how to display a long division using MathJax
$endgroup$
– bubba
Mar 11 at 9:20
$begingroup$
+1 for figuring out how to display a long division using MathJax
$endgroup$
– bubba
Mar 11 at 9:20
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
May be
$$32.45=frac3245100=frac5 times 11 times 59100$$
$$253.11=frac25311100=frac3 times 11 times 13 times 59100$$ could help to get
$$frac32.45253.11=frac 539$$
$$frac253.1132.45=frac 395=frac 7810=7.8$$
answered Mar 11 at 9:37
Claude LeiboviciClaude Leibovici
124k1157135
$endgroup$
$begingroup$
It was quite a good idea to factorise the numbers.
$endgroup$
– Henrik
Mar 11 at 9:42
$begingroup$
@Henrik. I suppose that this was the goal of the problem. Dividing by $5$ or by $11$ is simple mentally; by $13$, they used to teach it at my time (looooong time ago !).
$endgroup$
– Claude Leibovici
Mar 11 at 9:45
$begingroup$
That's great but how do you get to the factorisation? What is the thought process behind - if I can ask that? Do you just start with 5 or 10 usually? I can see as soon as you start doing that - it simplifies quickly.
$endgroup$
– alicook
Mar 11 at 9:51
$begingroup$
@alicook. Multiple both numbers by $100$ to kake them whole numbers; this does not change the ratio. Now, have a look at en.wikipedia.org/wiki/Divisibility_rule and use mental calculation.
$endgroup$
– Claude Leibovici
Mar 11 at 9:58
add a comment |
Your Answer
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1 Answer
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votes
$begingroup$
May be
$$32.45=frac3245100=frac5 times 11 times 59100$$
$$253.11=frac25311100=frac3 times 11 times 13 times 59100$$ could help to get
$$frac32.45253.11=frac 539$$
$$frac253.1132.45=frac 395=frac 7810=7.8$$
answered Mar 11 at 9:37
Claude LeiboviciClaude Leibovici
124k1157135
$endgroup$
$begingroup$
It was quite a good idea to factorise the numbers.
$endgroup$
– Henrik
Mar 11 at 9:42
$begingroup$
@Henrik. I suppose that this was the goal of the problem. Dividing by $5$ or by $11$ is simple mentally; by $13$, they used to teach it at my time (looooong time ago !).
$endgroup$
– Claude Leibovici
Mar 11 at 9:45
$begingroup$
That's great but how do you get to the factorisation? What is the thought process behind - if I can ask that? Do you just start with 5 or 10 usually? I can see as soon as you start doing that - it simplifies quickly.
$endgroup$
– alicook
Mar 11 at 9:51
$begingroup$
@alicook. Multiple both numbers by $100$ to kake them whole numbers; this does not change the ratio. Now, have a look at en.wikipedia.org/wiki/Divisibility_rule and use mental calculation.
$endgroup$
– Claude Leibovici
Mar 11 at 9:58
add a comment |
$begingroup$
May be
$$32.45=frac3245100=frac5 times 11 times 59100$$
$$253.11=frac25311100=frac3 times 11 times 13 times 59100$$ could help to get
$$frac32.45253.11=frac 539$$
$$frac253.1132.45=frac 395=frac 7810=7.8$$
answered Mar 11 at 9:37
Claude LeiboviciClaude Leibovici
124k1157135
$endgroup$
$begingroup$
It was quite a good idea to factorise the numbers.
$endgroup$
– Henrik
Mar 11 at 9:42
$begingroup$
@Henrik. I suppose that this was the goal of the problem. Dividing by $5$ or by $11$ is simple mentally; by $13$, they used to teach it at my time (looooong time ago !).
$endgroup$
– Claude Leibovici
Mar 11 at 9:45
$begingroup$
That's great but how do you get to the factorisation? What is the thought process behind - if I can ask that? Do you just start with 5 or 10 usually? I can see as soon as you start doing that - it simplifies quickly.
$endgroup$
– alicook
Mar 11 at 9:51
$begingroup$
@alicook. Multiple both numbers by $100$ to kake them whole numbers; this does not change the ratio. Now, have a look at en.wikipedia.org/wiki/Divisibility_rule and use mental calculation.
$endgroup$
– Claude Leibovici
Mar 11 at 9:58
add a comment |
$begingroup$
May be
$$32.45=frac3245100=frac5 times 11 times 59100$$
$$253.11=frac25311100=frac3 times 11 times 13 times 59100$$ could help to get
$$frac32.45253.11=frac 539$$
$$frac253.1132.45=frac 395=frac 7810=7.8$$
answered Mar 11 at 9:37
Claude LeiboviciClaude Leibovici
124k1157135
$endgroup$
May be
$$32.45=frac3245100=frac5 times 11 times 59100$$
$$253.11=frac25311100=frac3 times 11 times 13 times 59100$$ could help to get
$$frac32.45253.11=frac 539$$
$$frac253.1132.45=frac 395=frac 7810=7.8$$
answered Mar 11 at 9:37
Claude LeiboviciClaude Leibovici
124k1157135
answered Mar 11 at 9:37
Claude LeiboviciClaude Leibovici
124k1157135
answered Mar 11 at 9:37
Claude LeiboviciClaude Leibovici
124k1157135
answered Mar 11 at 9:37
Claude LeiboviciClaude Leibovici
124k1157135
124k1157135
$begingroup$
It was quite a good idea to factorise the numbers.
$endgroup$
– Henrik
Mar 11 at 9:42
$begingroup$
@Henrik. I suppose that this was the goal of the problem. Dividing by $5$ or by $11$ is simple mentally; by $13$, they used to teach it at my time (looooong time ago !).
$endgroup$
– Claude Leibovici
Mar 11 at 9:45
$begingroup$
That's great but how do you get to the factorisation? What is the thought process behind - if I can ask that? Do you just start with 5 or 10 usually? I can see as soon as you start doing that - it simplifies quickly.
$endgroup$
– alicook
Mar 11 at 9:51
$begingroup$
@alicook. Multiple both numbers by $100$ to kake them whole numbers; this does not change the ratio. Now, have a look at en.wikipedia.org/wiki/Divisibility_rule and use mental calculation.
$endgroup$
– Claude Leibovici
Mar 11 at 9:58
add a comment |
$begingroup$
It was quite a good idea to factorise the numbers.
$endgroup$
– Henrik
Mar 11 at 9:42
$begingroup$
@Henrik. I suppose that this was the goal of the problem. Dividing by $5$ or by $11$ is simple mentally; by $13$, they used to teach it at my time (looooong time ago !).
$endgroup$
– Claude Leibovici
Mar 11 at 9:45
$begingroup$
That's great but how do you get to the factorisation? What is the thought process behind - if I can ask that? Do you just start with 5 or 10 usually? I can see as soon as you start doing that - it simplifies quickly.
$endgroup$
– alicook
Mar 11 at 9:51
$begingroup$
@alicook. Multiple both numbers by $100$ to kake them whole numbers; this does not change the ratio. Now, have a look at en.wikipedia.org/wiki/Divisibility_rule and use mental calculation.
$endgroup$
– Claude Leibovici
Mar 11 at 9:58
$begingroup$
It was quite a good idea to factorise the numbers.
$endgroup$
– Henrik
Mar 11 at 9:42
$begingroup$
It was quite a good idea to factorise the numbers.
$endgroup$
– Henrik
Mar 11 at 9:42
$begingroup$
@Henrik. I suppose that this was the goal of the problem. Dividing by $5$ or by $11$ is simple mentally; by $13$, they used to teach it at my time (looooong time ago !).
$endgroup$
– Claude Leibovici
Mar 11 at 9:45
$begingroup$
@Henrik. I suppose that this was the goal of the problem. Dividing by $5$ or by $11$ is simple mentally; by $13$, they used to teach it at my time (looooong time ago !).
$endgroup$
– Claude Leibovici
Mar 11 at 9:45
$begingroup$
That's great but how do you get to the factorisation? What is the thought process behind - if I can ask that? Do you just start with 5 or 10 usually? I can see as soon as you start doing that - it simplifies quickly.
$endgroup$
– alicook
Mar 11 at 9:51
$begingroup$
That's great but how do you get to the factorisation? What is the thought process behind - if I can ask that? Do you just start with 5 or 10 usually? I can see as soon as you start doing that - it simplifies quickly.
$endgroup$
– alicook
Mar 11 at 9:51
$begingroup$
@alicook. Multiple both numbers by $100$ to kake them whole numbers; this does not change the ratio. Now, have a look at en.wikipedia.org/wiki/Divisibility_rule and use mental calculation.
$endgroup$
– Claude Leibovici
Mar 11 at 9:58
$begingroup$
@alicook. Multiple both numbers by $100$ to kake them whole numbers; this does not change the ratio. Now, have a look at en.wikipedia.org/wiki/Divisibility_rule and use mental calculation.
$endgroup$
– Claude Leibovici
Mar 11 at 9:58
add a comment |
alicook is a new contributor. Be nice, and check out our Code of Conduct.
alicook is a new contributor. Be nice, and check out our Code of Conduct.
alicook is a new contributor. Be nice, and check out our Code of Conduct.
alicook is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
You can just focus on finding $$ requireenclose beginarrayr 3245 encloselongdiv25311,\ endarray $$ since $frac253.1132.45 =frac253113245$. By the way, is the exam multiple choice? And what type of answer does it want (decimal form, or remainder?)?
$endgroup$
– Minus One-Twelfth
Mar 11 at 9:00
$begingroup$
That is true. No, it is not multiple choice. With the answer in decimal form.
$endgroup$
– alicook
Mar 11 at 9:06
$begingroup$
This link might be helpful: mathlearners.com/vedic-mathematics/…
$endgroup$
– Paras Khosla
Mar 11 at 9:15
1
$begingroup$
+1 for figuring out how to display a long division using MathJax
$endgroup$
– bubba
Mar 11 at 9:20