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A line with a parametric vector equation
Finding a vector equation for a trajectoryHelp with finding range and equation of a position vector (projectile)Unit vector of an angle in plane polar coordinatesFinding an orthogonal basis w.r.t an inner productContinuity of matrix product with respect to matrix norm?Finding diagonal matrices with complex entriesVector Proof of Diagonals of a RhombusMatrix proof on the zero matrixVector Identities Question - concerning cross and dot productVector equation for a cone
$begingroup$
I am struggling with this question. Any help would be greatly appreciated
matrices vectors
New contributor
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add a comment |
$begingroup$
I am struggling with this question. Any help would be greatly appreciated
matrices vectors
New contributor
$endgroup$
$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30
add a comment |
$begingroup$
I am struggling with this question. Any help would be greatly appreciated
matrices vectors
New contributor
$endgroup$
I am struggling with this question. Any help would be greatly appreciated
matrices vectors
matrices vectors
New contributor
New contributor
edited Mar 11 at 18:30
KReiser
9,87121435
9,87121435
New contributor
asked Mar 11 at 10:12
SamSam
305
305
New contributor
New contributor
$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30
add a comment |
$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30
$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30
$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Do you know how a parametric equation works?
Hint
What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?
Once you have this value of $t$, what is the value of the second coordinate?
$endgroup$
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
add a comment |
$begingroup$
If $x_1=-8$, then we have $t=-2$.
Can you take it from here ?
$endgroup$
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Do you know how a parametric equation works?
Hint
What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?
Once you have this value of $t$, what is the value of the second coordinate?
$endgroup$
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
add a comment |
$begingroup$
Do you know how a parametric equation works?
Hint
What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?
Once you have this value of $t$, what is the value of the second coordinate?
$endgroup$
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
add a comment |
$begingroup$
Do you know how a parametric equation works?
Hint
What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?
Once you have this value of $t$, what is the value of the second coordinate?
$endgroup$
Do you know how a parametric equation works?
Hint
What does the value of (the parameter) $t$ have to be for the first coordinate to be $-8$?
Once you have this value of $t$, what is the value of the second coordinate?
answered Mar 11 at 10:16
StackTDStackTD
23.6k2154
23.6k2154
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
add a comment |
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
$begingroup$
I believe $t$ has to be -2?
$endgroup$
– Sam
Mar 11 at 10:26
1
1
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Correct, and then you know all the other coordinates as well.
$endgroup$
– StackTD
Mar 11 at 10:27
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Therefore the answer is $19$?
$endgroup$
– Sam
Mar 11 at 10:29
1
1
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
$begingroup$
Yes, that's right :-).
$endgroup$
– StackTD
Mar 11 at 10:30
add a comment |
$begingroup$
If $x_1=-8$, then we have $t=-2$.
Can you take it from here ?
$endgroup$
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
add a comment |
$begingroup$
If $x_1=-8$, then we have $t=-2$.
Can you take it from here ?
$endgroup$
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
add a comment |
$begingroup$
If $x_1=-8$, then we have $t=-2$.
Can you take it from here ?
$endgroup$
If $x_1=-8$, then we have $t=-2$.
Can you take it from here ?
answered Mar 11 at 10:16
FredFred
48.3k1849
48.3k1849
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
add a comment |
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
so $x2=9+-2*-5=19$?
$endgroup$
– Sam
Mar 11 at 10:29
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
$begingroup$
Yes, we have $x_2=19.$
$endgroup$
– Fred
Mar 11 at 10:33
add a comment |
Sam is a new contributor. Be nice, and check out our Code of Conduct.
Sam is a new contributor. Be nice, and check out our Code of Conduct.
Sam is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
$endgroup$
– KReiser
Mar 11 at 18:30