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Find displacement vector AB, given A is point (-3,5,7) and B is (-5,-4,9)

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0

$begingroup$

I am unsure if I answered this questions correctly.

If A is a point with coordinates (-3,5,7) and point B has coordinates (-5,-4,9) then find displacement vector AB.

I got (-8,1,16), is this correct if not, what is the correct answer and how do you do it?

matrices vectors

share|cite|improve this question

edited Mar 11 at 18:29

KReiser

9,87121435

asked Mar 11 at 9:48

SamSam

305

New contributor

Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I'm not sure of the names, but isn't "displacement" $;AB;$ the same as the vector $;vecAB;$ ? If this is the case, then $;vecAB=B-A=(-2,-9,2);$ ...
  $endgroup$
  – DonAntonio
  Mar 11 at 9:51
  
  

  
  
  
  


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  Yes, you are correct about that. I see. I don't what happened there, pretty simple question :)
  $endgroup$
  – Sam
  Mar 11 at 9:54
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
  $endgroup$
  – KReiser
  Mar 11 at 18:30
  

  
  
  
  

add a comment | 

0

$begingroup$

I am unsure if I answered this questions correctly.

If A is a point with coordinates (-3,5,7) and point B has coordinates (-5,-4,9) then find displacement vector AB.

I got (-8,1,16), is this correct if not, what is the correct answer and how do you do it?

matrices vectors

share|cite|improve this question

edited Mar 11 at 18:29

KReiser

9,87121435

asked Mar 11 at 9:48

SamSam

305

New contributor

Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I'm not sure of the names, but isn't "displacement" $;AB;$ the same as the vector $;vecAB;$ ? If this is the case, then $;vecAB=B-A=(-2,-9,2);$ ...
  $endgroup$
  – DonAntonio
  Mar 11 at 9:51
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yes, you are correct about that. I see. I don't what happened there, pretty simple question :)
  $endgroup$
  – Sam
  Mar 11 at 9:54
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Please do not apply the algebraic-geometry tag to elementary problems involving algebra and geometry, as per the tag description.
  $endgroup$
  – KReiser
  Mar 11 at 18:30
  

  
  
  
  

add a comment | 

$begingroup$

I am unsure if I answered this questions correctly.

If A is a point with coordinates (-3,5,7) and point B has coordinates (-5,-4,9) then find displacement vector AB.

I got (-8,1,16), is this correct if not, what is the correct answer and how do you do it?

matrices vectors

share|cite|improve this question

edited Mar 11 at 18:29

KReiser

9,87121435

asked Mar 11 at 9:48

SamSam

305

New contributor

Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

share|cite|improve this question

edited Mar 11 at 18:29

KReiser

9,87121435

asked Mar 11 at 9:48

SamSam

305

New contributor

Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|cite|improve this question

edited Mar 11 at 18:29

KReiser

9,87121435

asked Mar 11 at 9:48

SamSam

305

New contributor

Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited Mar 11 at 18:29

KReiser

9,87121435

edited Mar 11 at 18:29

KReiser

9,87121435

asked Mar 11 at 9:48

SamSam

305

New contributor

Sam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked Mar 11 at 9:48

SamSam

305

1 Answer
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1

$begingroup$

The coordinates of point $A$ has first component $-3$, and the coordinates of $B$ has first component $-5$. That means that to get from $A$ to $B$, you have to change the first component by $-2$. Thus the first coordinate of the displacement vector is $-2$.

Do the same for the two other components, and you have your answer. Remember to always go the same way (from $A$ to $B$), and you'll be fine.

share|cite|improve this answer

answered Mar 11 at 9:54

ArthurArthur

118k7117200

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thank, the explanation was very helpful.
  $endgroup$
  – Sam
  Mar 11 at 9:55
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @Sam In almost every single case in school math, the formula you learn for something is only of secondary importance to what's actually going on, but people often only really learn the formula. This opens up lots of possibilities for mistakes like adding when you should subtract, or subtracting in the wrong order. Going back to the basics of what you are ultimately after helps avoid such mistakes (although no method is foolproof).
  $endgroup$
  – Arthur
  Mar 11 at 9:58
  
  

  
  
  
  

add a comment | 

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1

$begingroup$

The coordinates of point $A$ has first component $-3$, and the coordinates of $B$ has first component $-5$. That means that to get from $A$ to $B$, you have to change the first component by $-2$. Thus the first coordinate of the displacement vector is $-2$.

Do the same for the two other components, and you have your answer. Remember to always go the same way (from $A$ to $B$), and you'll be fine.

share|cite|improve this answer

answered Mar 11 at 9:54

ArthurArthur

118k7117200

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thank, the explanation was very helpful.
  $endgroup$
  – Sam
  Mar 11 at 9:55
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @Sam In almost every single case in school math, the formula you learn for something is only of secondary importance to what's actually going on, but people often only really learn the formula. This opens up lots of possibilities for mistakes like adding when you should subtract, or subtracting in the wrong order. Going back to the basics of what you are ultimately after helps avoid such mistakes (although no method is foolproof).
  $endgroup$
  – Arthur
  Mar 11 at 9:58
  
  

  
  
  
  

add a comment | 

1

$begingroup$

The coordinates of point $A$ has first component $-3$, and the coordinates of $B$ has first component $-5$. That means that to get from $A$ to $B$, you have to change the first component by $-2$. Thus the first coordinate of the displacement vector is $-2$.

Do the same for the two other components, and you have your answer. Remember to always go the same way (from $A$ to $B$), and you'll be fine.

share|cite|improve this answer

answered Mar 11 at 9:54

ArthurArthur

118k7117200

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thank, the explanation was very helpful.
  $endgroup$
  – Sam
  Mar 11 at 9:55
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @Sam In almost every single case in school math, the formula you learn for something is only of secondary importance to what's actually going on, but people often only really learn the formula. This opens up lots of possibilities for mistakes like adding when you should subtract, or subtracting in the wrong order. Going back to the basics of what you are ultimately after helps avoid such mistakes (although no method is foolproof).
  $endgroup$
  – Arthur
  Mar 11 at 9:58
  
  

  
  
  
  

add a comment | 

$begingroup$

The coordinates of point $A$ has first component $-3$, and the coordinates of $B$ has first component $-5$. That means that to get from $A$ to $B$, you have to change the first component by $-2$. Thus the first coordinate of the displacement vector is $-2$.

Do the same for the two other components, and you have your answer. Remember to always go the same way (from $A$ to $B$), and you'll be fine.

share|cite|improve this answer

answered Mar 11 at 9:54

ArthurArthur

118k7117200

$endgroup$

share|cite|improve this answer

answered Mar 11 at 9:54

ArthurArthur

118k7117200

answered Mar 11 at 9:54

ArthurArthur

118k7117200

answered Mar 11 at 9:54

ArthurArthur

118k7117200