Complex dynamical system: check stability of point numericallyIdentification of (Centers of) Cycles in a Discrete Time Dynamical SystemHelp on designing a dynamical systemCompute stable/unstable/center manifold for nonlinear system of ODEsEigenvalues for a 2nd Order Ode$2$-dim dynamical system IVPRange of parameter values for a stability of a fixed point for this 2d mapStability of a nonhomogeneous system of differential equationsHow to find equilibria of a system of ODEsHow to find stable and unstable manifolds for nonlinear ode?rate of Convergence for a dynamical system

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Complex dynamical system: check stability of point numerically


Identification of (Centers of) Cycles in a Discrete Time Dynamical SystemHelp on designing a dynamical systemCompute stable/unstable/center manifold for nonlinear system of ODEsEigenvalues for a 2nd Order Ode$2$-dim dynamical system IVPRange of parameter values for a stability of a fixed point for this 2d mapStability of a nonhomogeneous system of differential equationsHow to find equilibria of a system of ODEsHow to find stable and unstable manifolds for nonlinear ode?rate of Convergence for a dynamical system













1












$begingroup$


Given a dynamical system described by the equations (for i=1,...,N)
$$fracd y_idt = P_i - by_i + K underseti neq jsum_i=1^N sin(x_i-x_j)$$
$$fracd x_idt = y_i$$
Say that I have found a stable point in the $R^2n$ dimensional space $((x_1,y_1),(x_2,y_2),...,(x_n,y_n))$ such that $fracdx_idt = fracdy_idt=0$ for all $i =1,...,N$.



How do I check numerically, if this point is stable or unstable? (Preferably without checking the eigenvalues of the jacobian matrix)










share|cite|improve this question









$endgroup$











  • $begingroup$
    You could test if it is a local minimum of the energy function $$sum_ifrac12y_i^2-P_ix_i+Ksum_j< icos(x_i-x_j),$$ if you know a derivative-free method to do that.
    $endgroup$
    – LutzL
    Mar 11 at 12:08










  • $begingroup$
    What's wrong with checking eigenvalues numerically? You can find analytical expression for derivatives using any symbolic engine, plug in equilibrium coordinates and find eigenvalues quite reliably. Another crudest way to check stability is just to pick a random point quite close to the equilibrium and integrate trajectory for a moderate amount of time. If it is a saddle, most likely you won't pick a point from its stable manifold and trajectory abruptly goes somewhere else, not to the equilibrium. P.S. Kuramoto with an inertia? :)
    $endgroup$
    – Evgeny
    Mar 11 at 12:29










  • $begingroup$
    Will that work? Picking a 'random' point nearby in 2n dimensional space? Wouldn't it by chance be a direction which exhibits 'directional' stability while others are unstable? And yes! It is indeed Kuramoto with inertia :-)
    $endgroup$
    – Fabric
    2 days ago















1












$begingroup$


Given a dynamical system described by the equations (for i=1,...,N)
$$fracd y_idt = P_i - by_i + K underseti neq jsum_i=1^N sin(x_i-x_j)$$
$$fracd x_idt = y_i$$
Say that I have found a stable point in the $R^2n$ dimensional space $((x_1,y_1),(x_2,y_2),...,(x_n,y_n))$ such that $fracdx_idt = fracdy_idt=0$ for all $i =1,...,N$.



How do I check numerically, if this point is stable or unstable? (Preferably without checking the eigenvalues of the jacobian matrix)










share|cite|improve this question









$endgroup$











  • $begingroup$
    You could test if it is a local minimum of the energy function $$sum_ifrac12y_i^2-P_ix_i+Ksum_j< icos(x_i-x_j),$$ if you know a derivative-free method to do that.
    $endgroup$
    – LutzL
    Mar 11 at 12:08










  • $begingroup$
    What's wrong with checking eigenvalues numerically? You can find analytical expression for derivatives using any symbolic engine, plug in equilibrium coordinates and find eigenvalues quite reliably. Another crudest way to check stability is just to pick a random point quite close to the equilibrium and integrate trajectory for a moderate amount of time. If it is a saddle, most likely you won't pick a point from its stable manifold and trajectory abruptly goes somewhere else, not to the equilibrium. P.S. Kuramoto with an inertia? :)
    $endgroup$
    – Evgeny
    Mar 11 at 12:29










  • $begingroup$
    Will that work? Picking a 'random' point nearby in 2n dimensional space? Wouldn't it by chance be a direction which exhibits 'directional' stability while others are unstable? And yes! It is indeed Kuramoto with inertia :-)
    $endgroup$
    – Fabric
    2 days ago













1












1








1





$begingroup$


Given a dynamical system described by the equations (for i=1,...,N)
$$fracd y_idt = P_i - by_i + K underseti neq jsum_i=1^N sin(x_i-x_j)$$
$$fracd x_idt = y_i$$
Say that I have found a stable point in the $R^2n$ dimensional space $((x_1,y_1),(x_2,y_2),...,(x_n,y_n))$ such that $fracdx_idt = fracdy_idt=0$ for all $i =1,...,N$.



How do I check numerically, if this point is stable or unstable? (Preferably without checking the eigenvalues of the jacobian matrix)










share|cite|improve this question









$endgroup$




Given a dynamical system described by the equations (for i=1,...,N)
$$fracd y_idt = P_i - by_i + K underseti neq jsum_i=1^N sin(x_i-x_j)$$
$$fracd x_idt = y_i$$
Say that I have found a stable point in the $R^2n$ dimensional space $((x_1,y_1),(x_2,y_2),...,(x_n,y_n))$ such that $fracdx_idt = fracdy_idt=0$ for all $i =1,...,N$.



How do I check numerically, if this point is stable or unstable? (Preferably without checking the eigenvalues of the jacobian matrix)







numerical-methods dynamical-systems stability-theory






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 11 at 11:38









FabricFabric

478




478











  • $begingroup$
    You could test if it is a local minimum of the energy function $$sum_ifrac12y_i^2-P_ix_i+Ksum_j< icos(x_i-x_j),$$ if you know a derivative-free method to do that.
    $endgroup$
    – LutzL
    Mar 11 at 12:08










  • $begingroup$
    What's wrong with checking eigenvalues numerically? You can find analytical expression for derivatives using any symbolic engine, plug in equilibrium coordinates and find eigenvalues quite reliably. Another crudest way to check stability is just to pick a random point quite close to the equilibrium and integrate trajectory for a moderate amount of time. If it is a saddle, most likely you won't pick a point from its stable manifold and trajectory abruptly goes somewhere else, not to the equilibrium. P.S. Kuramoto with an inertia? :)
    $endgroup$
    – Evgeny
    Mar 11 at 12:29










  • $begingroup$
    Will that work? Picking a 'random' point nearby in 2n dimensional space? Wouldn't it by chance be a direction which exhibits 'directional' stability while others are unstable? And yes! It is indeed Kuramoto with inertia :-)
    $endgroup$
    – Fabric
    2 days ago
















  • $begingroup$
    You could test if it is a local minimum of the energy function $$sum_ifrac12y_i^2-P_ix_i+Ksum_j< icos(x_i-x_j),$$ if you know a derivative-free method to do that.
    $endgroup$
    – LutzL
    Mar 11 at 12:08










  • $begingroup$
    What's wrong with checking eigenvalues numerically? You can find analytical expression for derivatives using any symbolic engine, plug in equilibrium coordinates and find eigenvalues quite reliably. Another crudest way to check stability is just to pick a random point quite close to the equilibrium and integrate trajectory for a moderate amount of time. If it is a saddle, most likely you won't pick a point from its stable manifold and trajectory abruptly goes somewhere else, not to the equilibrium. P.S. Kuramoto with an inertia? :)
    $endgroup$
    – Evgeny
    Mar 11 at 12:29










  • $begingroup$
    Will that work? Picking a 'random' point nearby in 2n dimensional space? Wouldn't it by chance be a direction which exhibits 'directional' stability while others are unstable? And yes! It is indeed Kuramoto with inertia :-)
    $endgroup$
    – Fabric
    2 days ago















$begingroup$
You could test if it is a local minimum of the energy function $$sum_ifrac12y_i^2-P_ix_i+Ksum_j< icos(x_i-x_j),$$ if you know a derivative-free method to do that.
$endgroup$
– LutzL
Mar 11 at 12:08




$begingroup$
You could test if it is a local minimum of the energy function $$sum_ifrac12y_i^2-P_ix_i+Ksum_j< icos(x_i-x_j),$$ if you know a derivative-free method to do that.
$endgroup$
– LutzL
Mar 11 at 12:08












$begingroup$
What's wrong with checking eigenvalues numerically? You can find analytical expression for derivatives using any symbolic engine, plug in equilibrium coordinates and find eigenvalues quite reliably. Another crudest way to check stability is just to pick a random point quite close to the equilibrium and integrate trajectory for a moderate amount of time. If it is a saddle, most likely you won't pick a point from its stable manifold and trajectory abruptly goes somewhere else, not to the equilibrium. P.S. Kuramoto with an inertia? :)
$endgroup$
– Evgeny
Mar 11 at 12:29




$begingroup$
What's wrong with checking eigenvalues numerically? You can find analytical expression for derivatives using any symbolic engine, plug in equilibrium coordinates and find eigenvalues quite reliably. Another crudest way to check stability is just to pick a random point quite close to the equilibrium and integrate trajectory for a moderate amount of time. If it is a saddle, most likely you won't pick a point from its stable manifold and trajectory abruptly goes somewhere else, not to the equilibrium. P.S. Kuramoto with an inertia? :)
$endgroup$
– Evgeny
Mar 11 at 12:29












$begingroup$
Will that work? Picking a 'random' point nearby in 2n dimensional space? Wouldn't it by chance be a direction which exhibits 'directional' stability while others are unstable? And yes! It is indeed Kuramoto with inertia :-)
$endgroup$
– Fabric
2 days ago




$begingroup$
Will that work? Picking a 'random' point nearby in 2n dimensional space? Wouldn't it by chance be a direction which exhibits 'directional' stability while others are unstable? And yes! It is indeed Kuramoto with inertia :-)
$endgroup$
– Fabric
2 days ago










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