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How can I solve this series of 8 equations with 4 variables?



The Next CEO of Stack OverflowHelp explain method to solve two equations in two unknowns where one of the variables has a square termHow to solve these simultaneous equations using any better way?How do I Solve this Seemingly Simple Set of Four Equations with Four Unknowns?How to use elimination to solve a system of equations with 3 variablesIs this possible to solve through algebra?How to solve a system of equations with variables multiplied to each other?Linear system: 3 variables, 2 equations w/o all variablesHow can I solve this non-linear system of equations?Is there a symbol for assigning an equation to a letterFind the area using simultaneous equations










0












$begingroup$


I have this series of equations and I would like to find a generic formula for S;



When;

p = 0, c = 0 and e = 0, S = 0
p = 0, c = 1 and e = 0, S = 5/7
p = 0, c = 0 and e = 1, S = 1/7
p = 0, c = 1 and e = 1, S = 6/7
p = 1, c = 1 and e = 1, S = 1
p = 1, c = 1 and e = 0, S = 4/7
p = 1, c = 0 and e = 1, S = 3/7
p = 1, c = 0 and e = 0, S = 2/7


I know when solving simultaneous equations that I need to eliminate a variable and substitute but I feel like I have too many equations here.










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    I do not see equations.
    $endgroup$
    – Claude Leibovici
    Mar 19 at 10:26






  • 2




    $begingroup$
    well is $s$ a linear function of the other $3$? then yeah you can find inconsistency by the 6th equation.
    $endgroup$
    – orange
    Mar 19 at 10:32






  • 1




    $begingroup$
    Referring to @orange's comment, if you look at most of the equations, you would first guess that $S = frac17(2p+5c+e)$, but then there are two equations (out of the eight) for which this fails ...
    $endgroup$
    – Matti P.
    Mar 19 at 10:36







  • 1




    $begingroup$
    @MattiP. yes. So there might be a non linear factor
    $endgroup$
    – orange
    Mar 19 at 10:39






  • 2




    $begingroup$
    Can you tell us about where the equations came from ? It might be that it would be more useful to fit an approximate solution, than to find an exact one.
    $endgroup$
    – Simon
    Mar 19 at 10:41















0












$begingroup$


I have this series of equations and I would like to find a generic formula for S;



When;

p = 0, c = 0 and e = 0, S = 0
p = 0, c = 1 and e = 0, S = 5/7
p = 0, c = 0 and e = 1, S = 1/7
p = 0, c = 1 and e = 1, S = 6/7
p = 1, c = 1 and e = 1, S = 1
p = 1, c = 1 and e = 0, S = 4/7
p = 1, c = 0 and e = 1, S = 3/7
p = 1, c = 0 and e = 0, S = 2/7


I know when solving simultaneous equations that I need to eliminate a variable and substitute but I feel like I have too many equations here.










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    I do not see equations.
    $endgroup$
    – Claude Leibovici
    Mar 19 at 10:26






  • 2




    $begingroup$
    well is $s$ a linear function of the other $3$? then yeah you can find inconsistency by the 6th equation.
    $endgroup$
    – orange
    Mar 19 at 10:32






  • 1




    $begingroup$
    Referring to @orange's comment, if you look at most of the equations, you would first guess that $S = frac17(2p+5c+e)$, but then there are two equations (out of the eight) for which this fails ...
    $endgroup$
    – Matti P.
    Mar 19 at 10:36







  • 1




    $begingroup$
    @MattiP. yes. So there might be a non linear factor
    $endgroup$
    – orange
    Mar 19 at 10:39






  • 2




    $begingroup$
    Can you tell us about where the equations came from ? It might be that it would be more useful to fit an approximate solution, than to find an exact one.
    $endgroup$
    – Simon
    Mar 19 at 10:41













0












0








0


1



$begingroup$


I have this series of equations and I would like to find a generic formula for S;



When;

p = 0, c = 0 and e = 0, S = 0
p = 0, c = 1 and e = 0, S = 5/7
p = 0, c = 0 and e = 1, S = 1/7
p = 0, c = 1 and e = 1, S = 6/7
p = 1, c = 1 and e = 1, S = 1
p = 1, c = 1 and e = 0, S = 4/7
p = 1, c = 0 and e = 1, S = 3/7
p = 1, c = 0 and e = 0, S = 2/7


I know when solving simultaneous equations that I need to eliminate a variable and substitute but I feel like I have too many equations here.










share|cite|improve this question









$endgroup$




I have this series of equations and I would like to find a generic formula for S;



When;

p = 0, c = 0 and e = 0, S = 0
p = 0, c = 1 and e = 0, S = 5/7
p = 0, c = 0 and e = 1, S = 1/7
p = 0, c = 1 and e = 1, S = 6/7
p = 1, c = 1 and e = 1, S = 1
p = 1, c = 1 and e = 0, S = 4/7
p = 1, c = 0 and e = 1, S = 3/7
p = 1, c = 0 and e = 0, S = 2/7


I know when solving simultaneous equations that I need to eliminate a variable and substitute but I feel like I have too many equations here.







systems-of-equations






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 19 at 10:25









TaylrlTaylrl

1034




1034







  • 1




    $begingroup$
    I do not see equations.
    $endgroup$
    – Claude Leibovici
    Mar 19 at 10:26






  • 2




    $begingroup$
    well is $s$ a linear function of the other $3$? then yeah you can find inconsistency by the 6th equation.
    $endgroup$
    – orange
    Mar 19 at 10:32






  • 1




    $begingroup$
    Referring to @orange's comment, if you look at most of the equations, you would first guess that $S = frac17(2p+5c+e)$, but then there are two equations (out of the eight) for which this fails ...
    $endgroup$
    – Matti P.
    Mar 19 at 10:36







  • 1




    $begingroup$
    @MattiP. yes. So there might be a non linear factor
    $endgroup$
    – orange
    Mar 19 at 10:39






  • 2




    $begingroup$
    Can you tell us about where the equations came from ? It might be that it would be more useful to fit an approximate solution, than to find an exact one.
    $endgroup$
    – Simon
    Mar 19 at 10:41












  • 1




    $begingroup$
    I do not see equations.
    $endgroup$
    – Claude Leibovici
    Mar 19 at 10:26






  • 2




    $begingroup$
    well is $s$ a linear function of the other $3$? then yeah you can find inconsistency by the 6th equation.
    $endgroup$
    – orange
    Mar 19 at 10:32






  • 1




    $begingroup$
    Referring to @orange's comment, if you look at most of the equations, you would first guess that $S = frac17(2p+5c+e)$, but then there are two equations (out of the eight) for which this fails ...
    $endgroup$
    – Matti P.
    Mar 19 at 10:36







  • 1




    $begingroup$
    @MattiP. yes. So there might be a non linear factor
    $endgroup$
    – orange
    Mar 19 at 10:39






  • 2




    $begingroup$
    Can you tell us about where the equations came from ? It might be that it would be more useful to fit an approximate solution, than to find an exact one.
    $endgroup$
    – Simon
    Mar 19 at 10:41







1




1




$begingroup$
I do not see equations.
$endgroup$
– Claude Leibovici
Mar 19 at 10:26




$begingroup$
I do not see equations.
$endgroup$
– Claude Leibovici
Mar 19 at 10:26




2




2




$begingroup$
well is $s$ a linear function of the other $3$? then yeah you can find inconsistency by the 6th equation.
$endgroup$
– orange
Mar 19 at 10:32




$begingroup$
well is $s$ a linear function of the other $3$? then yeah you can find inconsistency by the 6th equation.
$endgroup$
– orange
Mar 19 at 10:32




1




1




$begingroup$
Referring to @orange's comment, if you look at most of the equations, you would first guess that $S = frac17(2p+5c+e)$, but then there are two equations (out of the eight) for which this fails ...
$endgroup$
– Matti P.
Mar 19 at 10:36





$begingroup$
Referring to @orange's comment, if you look at most of the equations, you would first guess that $S = frac17(2p+5c+e)$, but then there are two equations (out of the eight) for which this fails ...
$endgroup$
– Matti P.
Mar 19 at 10:36





1




1




$begingroup$
@MattiP. yes. So there might be a non linear factor
$endgroup$
– orange
Mar 19 at 10:39




$begingroup$
@MattiP. yes. So there might be a non linear factor
$endgroup$
– orange
Mar 19 at 10:39




2




2




$begingroup$
Can you tell us about where the equations came from ? It might be that it would be more useful to fit an approximate solution, than to find an exact one.
$endgroup$
– Simon
Mar 19 at 10:41




$begingroup$
Can you tell us about where the equations came from ? It might be that it would be more useful to fit an approximate solution, than to find an exact one.
$endgroup$
– Simon
Mar 19 at 10:41










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