Is equipotent $sim$ relation? The Next CEO of Stack OverflowIs there a name for this type of binary relation?The equivalence relation $(z_1, n_1)sim(z_2, n_2) :Leftrightarrow z_1 cdot n_2 = z_2 cdot n_1$Define a relation $sim$ on ℕ by $asim b$ if $ab$ is a perfect squareProving a relation on Z×(Z-0) is an equivalence relationWhy is the definition of relation as set of ordered pairs incomplete?Correctness of relation definition constructed from partition setDefine a relation on a subset with conditionsHomo and Isomorphism for Setsis the equipotent relation an equivalence relation?If $Asim B$(both dedekind infinite), is it then that $Asim Bcup x$
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Is equipotent $sim$ relation?
The Next CEO of Stack OverflowIs there a name for this type of binary relation?The equivalence relation $(z_1, n_1)sim(z_2, n_2) :Leftrightarrow z_1 cdot n_2 = z_2 cdot n_1$Define a relation $sim$ on ℕ by $asim b$ if $ab$ is a perfect squareProving a relation on Z×(Z-0) is an equivalence relationWhy is the definition of relation as set of ordered pairs incomplete?Correctness of relation definition constructed from partition setDefine a relation on a subset with conditionsHomo and Isomorphism for Setsis the equipotent relation an equivalence relation?If $Asim B$(both dedekind infinite), is it then that $Asim Bcup x$
$begingroup$
Problem: $sim$ is the mark for bijection between two set. Let $A$, $B$, $C$ be sets. Then$$A sim A\Asim B Rightarrow Bsim A\(Asim B land Bsim C )Rightarrow Asim C$$
I know that is not a relation because it is define on set that contains all set which is not set. But my professor told that if I write like this it is OK.
Let $A,B,Csubset U$ where $U$ is some universal set. Then$$A sim A\Asim B Rightarrow Bsim A\(Asim B land Bsim C )Rightarrow Asim C$$
Because I define relation $sim$ on $P(U) × P(U)$ Is this correct?
elementary-set-theory relations
$endgroup$
add a comment |
$begingroup$
Problem: $sim$ is the mark for bijection between two set. Let $A$, $B$, $C$ be sets. Then$$A sim A\Asim B Rightarrow Bsim A\(Asim B land Bsim C )Rightarrow Asim C$$
I know that is not a relation because it is define on set that contains all set which is not set. But my professor told that if I write like this it is OK.
Let $A,B,Csubset U$ where $U$ is some universal set. Then$$A sim A\Asim B Rightarrow Bsim A\(Asim B land Bsim C )Rightarrow Asim C$$
Because I define relation $sim$ on $P(U) × P(U)$ Is this correct?
elementary-set-theory relations
$endgroup$
$begingroup$
Yes, that's correct.
$endgroup$
– Floris Claassens
Mar 19 at 11:38
$begingroup$
It is a relation on $wp(U)$ or equivalently a subset of $wp(U)timeswp(U)$.
$endgroup$
– drhab
Mar 19 at 11:41
add a comment |
$begingroup$
Problem: $sim$ is the mark for bijection between two set. Let $A$, $B$, $C$ be sets. Then$$A sim A\Asim B Rightarrow Bsim A\(Asim B land Bsim C )Rightarrow Asim C$$
I know that is not a relation because it is define on set that contains all set which is not set. But my professor told that if I write like this it is OK.
Let $A,B,Csubset U$ where $U$ is some universal set. Then$$A sim A\Asim B Rightarrow Bsim A\(Asim B land Bsim C )Rightarrow Asim C$$
Because I define relation $sim$ on $P(U) × P(U)$ Is this correct?
elementary-set-theory relations
$endgroup$
Problem: $sim$ is the mark for bijection between two set. Let $A$, $B$, $C$ be sets. Then$$A sim A\Asim B Rightarrow Bsim A\(Asim B land Bsim C )Rightarrow Asim C$$
I know that is not a relation because it is define on set that contains all set which is not set. But my professor told that if I write like this it is OK.
Let $A,B,Csubset U$ where $U$ is some universal set. Then$$A sim A\Asim B Rightarrow Bsim A\(Asim B land Bsim C )Rightarrow Asim C$$
Because I define relation $sim$ on $P(U) × P(U)$ Is this correct?
elementary-set-theory relations
elementary-set-theory relations
edited Mar 19 at 11:43
Saad
20.3k92352
20.3k92352
asked Mar 19 at 11:34
josfjosf
286317
286317
$begingroup$
Yes, that's correct.
$endgroup$
– Floris Claassens
Mar 19 at 11:38
$begingroup$
It is a relation on $wp(U)$ or equivalently a subset of $wp(U)timeswp(U)$.
$endgroup$
– drhab
Mar 19 at 11:41
add a comment |
$begingroup$
Yes, that's correct.
$endgroup$
– Floris Claassens
Mar 19 at 11:38
$begingroup$
It is a relation on $wp(U)$ or equivalently a subset of $wp(U)timeswp(U)$.
$endgroup$
– drhab
Mar 19 at 11:41
$begingroup$
Yes, that's correct.
$endgroup$
– Floris Claassens
Mar 19 at 11:38
$begingroup$
Yes, that's correct.
$endgroup$
– Floris Claassens
Mar 19 at 11:38
$begingroup$
It is a relation on $wp(U)$ or equivalently a subset of $wp(U)timeswp(U)$.
$endgroup$
– drhab
Mar 19 at 11:41
$begingroup$
It is a relation on $wp(U)$ or equivalently a subset of $wp(U)timeswp(U)$.
$endgroup$
– drhab
Mar 19 at 11:41
add a comment |
0
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$begingroup$
Yes, that's correct.
$endgroup$
– Floris Claassens
Mar 19 at 11:38
$begingroup$
It is a relation on $wp(U)$ or equivalently a subset of $wp(U)timeswp(U)$.
$endgroup$
– drhab
Mar 19 at 11:41