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Given a set of numbers, find the majority group (non equal numbers)
The Next CEO of Stack OverflowCalculating Percent Variance Of Dates?How do I calculate a confidence interval with a description that on average one group is less than another?Statistical Test for Two Group MeansHow to calculate continous variance of given set of functions?How can I get the covariance just given the variance?Variance of first 30 odd numbersFind the expectations of the largest and smallest order statistics $X_(n)$ and $X_(1)$ respectively. Uniform distributionFind the critical value in Tukey's HSDFind the average spacing between an array of numbersGiven arbitrary set if each member map randomly to a different set injectively, is the k smallest number of the new set representative of the old set?
$begingroup$
Suppose the given set is $0.01,0.2,4,0.3$ then the result should be $1,2,4$ respectively, this means finding the largest (at least $n/2 + 1)$ group with the smallest variance.
My problem is how to classify such groups so I could calculate the variance?
statistics
edited Mar 20 at 5:01
YuiTo Cheng
2,1862937
asked Mar 19 at 12:23
user9275053user9275053
1
$endgroup$
add a comment |
$begingroup$
Suppose the given set is $0.01,0.2,4,0.3$ then the result should be $1,2,4$ respectively, this means finding the largest (at least $n/2 + 1)$ group with the smallest variance.
My problem is how to classify such groups so I could calculate the variance?
statistics
edited Mar 20 at 5:01
YuiTo Cheng
2,1862937
asked Mar 19 at 12:23
user9275053user9275053
1
$endgroup$
add a comment |
$begingroup$
Suppose the given set is $0.01,0.2,4,0.3$ then the result should be $1,2,4$ respectively, this means finding the largest (at least $n/2 + 1)$ group with the smallest variance.
My problem is how to classify such groups so I could calculate the variance?
statistics
edited Mar 20 at 5:01
YuiTo Cheng
2,1862937
asked Mar 19 at 12:23
user9275053user9275053
1
$endgroup$
Suppose the given set is $0.01,0.2,4,0.3$ then the result should be $1,2,4$ respectively, this means finding the largest (at least $n/2 + 1)$ group with the smallest variance.
My problem is how to classify such groups so I could calculate the variance?
statistics
statistics
edited Mar 20 at 5:01
YuiTo Cheng
2,1862937
asked Mar 19 at 12:23
user9275053user9275053
1
edited Mar 20 at 5:01
YuiTo Cheng
2,1862937
asked Mar 19 at 12:23
user9275053user9275053
1
edited Mar 20 at 5:01
YuiTo Cheng
2,1862937
edited Mar 20 at 5:01
YuiTo Cheng
2,1862937
edited Mar 20 at 5:01
YuiTo Cheng
2,1862937
2,1862937
asked Mar 19 at 12:23
user9275053user9275053
1
asked Mar 19 at 12:23
user9275053user9275053
1
asked Mar 19 at 12:23
user9275053user9275053
1
1
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
For a set of $m$ numbers $a_j$, the variance is
$$ frac1m sum_j a_j^2 - frac1m^2left(sum_j a_jright)^2 $$
If you have $n$ numbers $a_1, ldots, a_n$, sorted in increasing or decreasing order, and you want a subset of size $m$ with least possible variance, it's easy to see that you'll want to take
$a_k, ldots, a_k+m-1$ for some $k$. So there are not too many cases to try.
answered Mar 19 at 12:38
Robert IsraelRobert Israel
330k23218473
$endgroup$
add a comment |
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1 Answer
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$begingroup$
For a set of $m$ numbers $a_j$, the variance is
$$ frac1m sum_j a_j^2 - frac1m^2left(sum_j a_jright)^2 $$
If you have $n$ numbers $a_1, ldots, a_n$, sorted in increasing or decreasing order, and you want a subset of size $m$ with least possible variance, it's easy to see that you'll want to take
$a_k, ldots, a_k+m-1$ for some $k$. So there are not too many cases to try.
answered Mar 19 at 12:38
Robert IsraelRobert Israel
330k23218473
$endgroup$
add a comment |
$begingroup$
For a set of $m$ numbers $a_j$, the variance is
$$ frac1m sum_j a_j^2 - frac1m^2left(sum_j a_jright)^2 $$
If you have $n$ numbers $a_1, ldots, a_n$, sorted in increasing or decreasing order, and you want a subset of size $m$ with least possible variance, it's easy to see that you'll want to take
$a_k, ldots, a_k+m-1$ for some $k$. So there are not too many cases to try.
answered Mar 19 at 12:38
Robert IsraelRobert Israel
330k23218473
$endgroup$
add a comment |
$begingroup$
For a set of $m$ numbers $a_j$, the variance is
$$ frac1m sum_j a_j^2 - frac1m^2left(sum_j a_jright)^2 $$
If you have $n$ numbers $a_1, ldots, a_n$, sorted in increasing or decreasing order, and you want a subset of size $m$ with least possible variance, it's easy to see that you'll want to take
$a_k, ldots, a_k+m-1$ for some $k$. So there are not too many cases to try.
answered Mar 19 at 12:38
Robert IsraelRobert Israel
330k23218473
$endgroup$
For a set of $m$ numbers $a_j$, the variance is
$$ frac1m sum_j a_j^2 - frac1m^2left(sum_j a_jright)^2 $$
If you have $n$ numbers $a_1, ldots, a_n$, sorted in increasing or decreasing order, and you want a subset of size $m$ with least possible variance, it's easy to see that you'll want to take
$a_k, ldots, a_k+m-1$ for some $k$. So there are not too many cases to try.
answered Mar 19 at 12:38
Robert IsraelRobert Israel
330k23218473
answered Mar 19 at 12:38
Robert IsraelRobert Israel
330k23218473
answered Mar 19 at 12:38
Robert IsraelRobert Israel
330k23218473
answered Mar 19 at 12:38
Robert IsraelRobert Israel
330k23218473
330k23218473
add a comment |
add a comment |
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