hard calculus distribution in probability The Next CEO of Stack OverflowProbability distribution for the sum of two variables (binomial and uniform) - Specify distributionFind a specific probability distributionDistribution of arcsin of a uniform random variableBeckmann distributionProve that two processes have the same lawPolar transformation of a probability distribution functionProbability that $sintheta cosphi < 0.999772$Proving normal distribution in Box MullerProbability density function of $X$ with a uniform distribution on a unit sphereDistribution of $|sin(Theta)|$ if $Theta$ is uniform on $(0,2pi)$ and arcsine distribution
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hard calculus distribution in probability
The Next CEO of Stack OverflowProbability distribution for the sum of two variables (binomial and uniform) - Specify distributionFind a specific probability distributionDistribution of arcsin of a uniform random variableBeckmann distributionProve that two processes have the same lawPolar transformation of a probability distribution functionProbability that $sintheta cosphi < 0.999772$Proving normal distribution in Box MullerProbability density function of $X$ with a uniform distribution on a unit sphereDistribution of $|sin(Theta)|$ if $Theta$ is uniform on $(0,2pi)$ and arcsine distribution
$begingroup$
Let $theta sim U(0,2pi)$, $phi = cot^-1fraccostheta + hsintheta$, $0 < h leq 1$, please prove that $phi sim U(0, pi)$.
probability probability-distributions
edited Mar 19 at 12:06
Mostafa Ayaz
18.2k31040
asked Mar 19 at 12:03
ZFZouZFZou
11
$endgroup$
add a comment |
$begingroup$
Let $theta sim U(0,2pi)$, $phi = cot^-1fraccostheta + hsintheta$, $0 < h leq 1$, please prove that $phi sim U(0, pi)$.
probability probability-distributions
edited Mar 19 at 12:06
Mostafa Ayaz
18.2k31040
asked Mar 19 at 12:03
ZFZouZFZou
11
$endgroup$
1
$begingroup$
Use the title to tell what the problem is about, no more no less. The "hard" adjective is relative and useless.
$endgroup$
– leonbloy
Mar 19 at 12:07
1
$begingroup$
Have you tried drawing the graph of $phi$ as a function of $theta$ (e.g. for $h = 1/2$)?
$endgroup$
– Vincent
Mar 19 at 12:26
add a comment |
$begingroup$
Let $theta sim U(0,2pi)$, $phi = cot^-1fraccostheta + hsintheta$, $0 < h leq 1$, please prove that $phi sim U(0, pi)$.
probability probability-distributions
edited Mar 19 at 12:06
Mostafa Ayaz
18.2k31040
asked Mar 19 at 12:03
ZFZouZFZou
11
$endgroup$
Let $theta sim U(0,2pi)$, $phi = cot^-1fraccostheta + hsintheta$, $0 < h leq 1$, please prove that $phi sim U(0, pi)$.
probability probability-distributions
probability probability-distributions
edited Mar 19 at 12:06
Mostafa Ayaz
18.2k31040
asked Mar 19 at 12:03
ZFZouZFZou
11
edited Mar 19 at 12:06
Mostafa Ayaz
18.2k31040
asked Mar 19 at 12:03
ZFZouZFZou
11
edited Mar 19 at 12:06
Mostafa Ayaz
18.2k31040
edited Mar 19 at 12:06
Mostafa Ayaz
18.2k31040
edited Mar 19 at 12:06
Mostafa Ayaz
18.2k31040
18.2k31040
asked Mar 19 at 12:03
ZFZouZFZou
11
asked Mar 19 at 12:03
ZFZouZFZou
11
asked Mar 19 at 12:03
ZFZouZFZou
11
11
1
$begingroup$
Use the title to tell what the problem is about, no more no less. The "hard" adjective is relative and useless.
$endgroup$
– leonbloy
Mar 19 at 12:07
1
$begingroup$
Have you tried drawing the graph of $phi$ as a function of $theta$ (e.g. for $h = 1/2$)?
$endgroup$
– Vincent
Mar 19 at 12:26
add a comment |
1
$begingroup$
Use the title to tell what the problem is about, no more no less. The "hard" adjective is relative and useless.
$endgroup$
– leonbloy
Mar 19 at 12:07
1
$begingroup$
Have you tried drawing the graph of $phi$ as a function of $theta$ (e.g. for $h = 1/2$)?
$endgroup$
– Vincent
Mar 19 at 12:26
1
1
$begingroup$
Use the title to tell what the problem is about, no more no less. The "hard" adjective is relative and useless.
$endgroup$
– leonbloy
Mar 19 at 12:07
$begingroup$
Use the title to tell what the problem is about, no more no less. The "hard" adjective is relative and useless.
$endgroup$
– leonbloy
Mar 19 at 12:07
1
1
$begingroup$
Have you tried drawing the graph of $phi$ as a function of $theta$ (e.g. for $h = 1/2$)?
$endgroup$
– Vincent
Mar 19 at 12:26
$begingroup$
Have you tried drawing the graph of $phi$ as a function of $theta$ (e.g. for $h = 1/2$)?
$endgroup$
– Vincent
Mar 19 at 12:26
add a comment |
0
active
oldest
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1
$begingroup$
Use the title to tell what the problem is about, no more no less. The "hard" adjective is relative and useless.
$endgroup$
– leonbloy
Mar 19 at 12:07
1
$begingroup$
Have you tried drawing the graph of $phi$ as a function of $theta$ (e.g. for $h = 1/2$)?
$endgroup$
– Vincent
Mar 19 at 12:26