Pipe-fitting problem 3D The Next CEO of Stack OverflowFinding $ csc theta $ given $ cot theta $Functional inverse of $sinthetasqrttantheta$$sin(2arccos(x))$, please help me understand how to do these kind of problems.Proving:$tan(20^circ)cdot tan(30^circ) cdot tan(40^circ)=tan(10^circ)$Compound angle formulasHelp needed verifying a trigonometric identityHow to Simplify $-frac14sinfrac x4 + fracsqrt34cosfrac x4 = 0$?Triangular sides$ frac5cos^2x = 7tan x + 3 $Solution to trig simultaneous equations
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Pipe-fitting problem 3D
The Next CEO of Stack OverflowFinding $ csc theta $ given $ cot theta $Functional inverse of $sinthetasqrttantheta$$sin(2arccos(x))$, please help me understand how to do these kind of problems.Proving:$tan(20^circ)cdot tan(30^circ) cdot tan(40^circ)=tan(10^circ)$Compound angle formulasHelp needed verifying a trigonometric identityHow to Simplify $-frac14sinfrac x4 + fracsqrt34cosfrac x4 = 0$?Triangular sides$ frac5cos^2x = 7tan x + 3 $Solution to trig simultaneous equations
$begingroup$
I have a 3D pipe-fitting problem for which I was able to write the following equations:
$$
y = tan (a)sqrtx^2 + z^2\
z = tan (b)sqrtx^2 + y^2\
y = sin (a)sqrtx^2 + y^2 + z^2\
z = sin (b)sqrtx^2 + y^2 + z^2
$$
$x > 0$ and known; $y$ and $z ge 0$; $0 < a$, $b < 90º$
what choices for $a$ and $b$ will minimize $y + z$?
if $a$ and $b$ are constrained to $45º$, $22.5º$ or $11.25º$, what choices minimize $y + z$?
I tried rearranging and combining these equations, and I got:
$$
y = fracx sin(a)sqrtcos^2(a) - sin^2(b)\
z = fracx sin(b)sqrtcos^2(b) - sin^2(a)
$$
But these equations behave strangely: as $a$ and $b$ go to $0$, $y$ and $z$ go to $0$; and in my problem, that means the pipes never meet.
Here is the physical problem: I have a vertical pipe, and a pipe aligned on the $z$-axis, separated by a fixed horizontal distance $x$. The length of the pipes can be varied. I need to connect the ends with one pipe and $2$ fittings from $0º$ to $90º$.
There is an easy solution with one $45º$ fitting, and one $90º$ fitting, but I am trying to avoid it.
So, did I model the problem correctly? Were my reduced equations correct? I am also having trouble seeing which variables are independent. Any help would be appreciated.
trigonometry 3d
$endgroup$
add a comment |
$begingroup$
I have a 3D pipe-fitting problem for which I was able to write the following equations:
$$
y = tan (a)sqrtx^2 + z^2\
z = tan (b)sqrtx^2 + y^2\
y = sin (a)sqrtx^2 + y^2 + z^2\
z = sin (b)sqrtx^2 + y^2 + z^2
$$
$x > 0$ and known; $y$ and $z ge 0$; $0 < a$, $b < 90º$
what choices for $a$ and $b$ will minimize $y + z$?
if $a$ and $b$ are constrained to $45º$, $22.5º$ or $11.25º$, what choices minimize $y + z$?
I tried rearranging and combining these equations, and I got:
$$
y = fracx sin(a)sqrtcos^2(a) - sin^2(b)\
z = fracx sin(b)sqrtcos^2(b) - sin^2(a)
$$
But these equations behave strangely: as $a$ and $b$ go to $0$, $y$ and $z$ go to $0$; and in my problem, that means the pipes never meet.
Here is the physical problem: I have a vertical pipe, and a pipe aligned on the $z$-axis, separated by a fixed horizontal distance $x$. The length of the pipes can be varied. I need to connect the ends with one pipe and $2$ fittings from $0º$ to $90º$.
There is an easy solution with one $45º$ fitting, and one $90º$ fitting, but I am trying to avoid it.
So, did I model the problem correctly? Were my reduced equations correct? I am also having trouble seeing which variables are independent. Any help would be appreciated.
trigonometry 3d
$endgroup$
add a comment |
$begingroup$
I have a 3D pipe-fitting problem for which I was able to write the following equations:
$$
y = tan (a)sqrtx^2 + z^2\
z = tan (b)sqrtx^2 + y^2\
y = sin (a)sqrtx^2 + y^2 + z^2\
z = sin (b)sqrtx^2 + y^2 + z^2
$$
$x > 0$ and known; $y$ and $z ge 0$; $0 < a$, $b < 90º$
what choices for $a$ and $b$ will minimize $y + z$?
if $a$ and $b$ are constrained to $45º$, $22.5º$ or $11.25º$, what choices minimize $y + z$?
I tried rearranging and combining these equations, and I got:
$$
y = fracx sin(a)sqrtcos^2(a) - sin^2(b)\
z = fracx sin(b)sqrtcos^2(b) - sin^2(a)
$$
But these equations behave strangely: as $a$ and $b$ go to $0$, $y$ and $z$ go to $0$; and in my problem, that means the pipes never meet.
Here is the physical problem: I have a vertical pipe, and a pipe aligned on the $z$-axis, separated by a fixed horizontal distance $x$. The length of the pipes can be varied. I need to connect the ends with one pipe and $2$ fittings from $0º$ to $90º$.
There is an easy solution with one $45º$ fitting, and one $90º$ fitting, but I am trying to avoid it.
So, did I model the problem correctly? Were my reduced equations correct? I am also having trouble seeing which variables are independent. Any help would be appreciated.
trigonometry 3d
$endgroup$
I have a 3D pipe-fitting problem for which I was able to write the following equations:
$$
y = tan (a)sqrtx^2 + z^2\
z = tan (b)sqrtx^2 + y^2\
y = sin (a)sqrtx^2 + y^2 + z^2\
z = sin (b)sqrtx^2 + y^2 + z^2
$$
$x > 0$ and known; $y$ and $z ge 0$; $0 < a$, $b < 90º$
what choices for $a$ and $b$ will minimize $y + z$?
if $a$ and $b$ are constrained to $45º$, $22.5º$ or $11.25º$, what choices minimize $y + z$?
I tried rearranging and combining these equations, and I got:
$$
y = fracx sin(a)sqrtcos^2(a) - sin^2(b)\
z = fracx sin(b)sqrtcos^2(b) - sin^2(a)
$$
But these equations behave strangely: as $a$ and $b$ go to $0$, $y$ and $z$ go to $0$; and in my problem, that means the pipes never meet.
Here is the physical problem: I have a vertical pipe, and a pipe aligned on the $z$-axis, separated by a fixed horizontal distance $x$. The length of the pipes can be varied. I need to connect the ends with one pipe and $2$ fittings from $0º$ to $90º$.
There is an easy solution with one $45º$ fitting, and one $90º$ fitting, but I am trying to avoid it.
So, did I model the problem correctly? Were my reduced equations correct? I am also having trouble seeing which variables are independent. Any help would be appreciated.
trigonometry 3d
trigonometry 3d
edited Feb 12 '14 at 0:57
Michael Afrides
asked Feb 10 '14 at 22:20
Michael AfridesMichael Afrides
112
112
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$begingroup$
Please look at my blog at forexsg.wordpress.com/2014/06/19/solution-for-3d-pipe-fitting-connection-vertical-wye-tee-and-elbow-or-another-wye-tee/
I descirbed my solution there. /_a and /_b cannot go to zero at the same time. When a is increasing b is decreasing. They are inverse of each other. There are more variables than the equations can define. Two equations cannot define 5 variables. Even with two know angles you need to define at least one other distance x,y or z . So you have to fix two angles and one of the distances x y or z .
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$begingroup$
Please look at my blog at forexsg.wordpress.com/2014/06/19/solution-for-3d-pipe-fitting-connection-vertical-wye-tee-and-elbow-or-another-wye-tee/
I descirbed my solution there. /_a and /_b cannot go to zero at the same time. When a is increasing b is decreasing. They are inverse of each other. There are more variables than the equations can define. Two equations cannot define 5 variables. Even with two know angles you need to define at least one other distance x,y or z . So you have to fix two angles and one of the distances x y or z .
$endgroup$
add a comment |
$begingroup$
Please look at my blog at forexsg.wordpress.com/2014/06/19/solution-for-3d-pipe-fitting-connection-vertical-wye-tee-and-elbow-or-another-wye-tee/
I descirbed my solution there. /_a and /_b cannot go to zero at the same time. When a is increasing b is decreasing. They are inverse of each other. There are more variables than the equations can define. Two equations cannot define 5 variables. Even with two know angles you need to define at least one other distance x,y or z . So you have to fix two angles and one of the distances x y or z .
$endgroup$
add a comment |
$begingroup$
Please look at my blog at forexsg.wordpress.com/2014/06/19/solution-for-3d-pipe-fitting-connection-vertical-wye-tee-and-elbow-or-another-wye-tee/
I descirbed my solution there. /_a and /_b cannot go to zero at the same time. When a is increasing b is decreasing. They are inverse of each other. There are more variables than the equations can define. Two equations cannot define 5 variables. Even with two know angles you need to define at least one other distance x,y or z . So you have to fix two angles and one of the distances x y or z .
$endgroup$
Please look at my blog at forexsg.wordpress.com/2014/06/19/solution-for-3d-pipe-fitting-connection-vertical-wye-tee-and-elbow-or-another-wye-tee/
I descirbed my solution there. /_a and /_b cannot go to zero at the same time. When a is increasing b is decreasing. They are inverse of each other. There are more variables than the equations can define. Two equations cannot define 5 variables. Even with two know angles you need to define at least one other distance x,y or z . So you have to fix two angles and one of the distances x y or z .
answered Jun 21 '14 at 6:49
user159320user159320
1
1
add a comment |
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