Covariance of centred random vairablesCovariance and Random VariablesConditional Covariance of Functions of Random VariablesRandom Variables and covarianceCovariance with transformations of random variablesCovariance inequality for $n$ exchangeable random variablescovariance of random variablesCompute covariance of dependent random variablesMinimal Covariance of random variables.Covariance of independent random variables.Covariance of Marshall-Olkin random variables

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Covariance of centred random vairables


Covariance and Random VariablesConditional Covariance of Functions of Random VariablesRandom Variables and covarianceCovariance with transformations of random variablesCovariance inequality for $n$ exchangeable random variablescovariance of random variablesCompute covariance of dependent random variablesMinimal Covariance of random variables.Covariance of independent random variables.Covariance of Marshall-Olkin random variables













0












$begingroup$


Let $X$ and $Y$ be two random variables, with $mathbbE(X)=mathbbE(Y)=0$.



Is it true that $mathbbE(XY)=0$ ? In other word, is it true that cov$(X,Y)=0$ ?










share|cite|improve this question









$endgroup$
















    0












    $begingroup$


    Let $X$ and $Y$ be two random variables, with $mathbbE(X)=mathbbE(Y)=0$.



    Is it true that $mathbbE(XY)=0$ ? In other word, is it true that cov$(X,Y)=0$ ?










    share|cite|improve this question









    $endgroup$














      0












      0








      0





      $begingroup$


      Let $X$ and $Y$ be two random variables, with $mathbbE(X)=mathbbE(Y)=0$.



      Is it true that $mathbbE(XY)=0$ ? In other word, is it true that cov$(X,Y)=0$ ?










      share|cite|improve this question









      $endgroup$




      Let $X$ and $Y$ be two random variables, with $mathbbE(X)=mathbbE(Y)=0$.



      Is it true that $mathbbE(XY)=0$ ? In other word, is it true that cov$(X,Y)=0$ ?







      probability probability-theory expected-value






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Mar 15 at 17:20









      C.S.C.S.

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      235




















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          1












          $begingroup$

          It is not true.



          Consider $$P(-1,-1)=P(1,1)=frac12$$



          Then $E(X)=0=E(Y)$ but $E(XY)=1$.






          share|cite|improve this answer









          $endgroup$












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            1












            $begingroup$

            It is not true.



            Consider $$P(-1,-1)=P(1,1)=frac12$$



            Then $E(X)=0=E(Y)$ but $E(XY)=1$.






            share|cite|improve this answer









            $endgroup$

















              1












              $begingroup$

              It is not true.



              Consider $$P(-1,-1)=P(1,1)=frac12$$



              Then $E(X)=0=E(Y)$ but $E(XY)=1$.






              share|cite|improve this answer









              $endgroup$















                1












                1








                1





                $begingroup$

                It is not true.



                Consider $$P(-1,-1)=P(1,1)=frac12$$



                Then $E(X)=0=E(Y)$ but $E(XY)=1$.






                share|cite|improve this answer









                $endgroup$



                It is not true.



                Consider $$P(-1,-1)=P(1,1)=frac12$$



                Then $E(X)=0=E(Y)$ but $E(XY)=1$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Mar 15 at 17:24









                Siong Thye GohSiong Thye Goh

                103k1468119




                103k1468119



























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