Embed a weighted projective space into an unweighted projective space.Terminology for weighted projective spacesIn the Proj construction, are the homogeneuos prime ideals determined up to an element in the base ring?Projective variety defined by a non-radical ideal.Weighted projective space and $mathrmProj$Isomorphism (?) of polynomial rings with different gradings and their ProjClosed points in projective space correspond to which homogenous prime ideals in $k[x_0,…,x_n]$Morphism of projective schemes not induced by maps of graded rings, Vakil's 16.4 GWhat would an infinite dimensional projective space look like as a scheme?Projective Space over an algebraically closed fieldAffine charts are dense in projective space

Is there a single word describing earning money through any means?

How do I color the graph in datavisualization?

If a character has darkvision, can they see through an area of nonmagical darkness filled with lightly obscuring gas?

Do Legal Documents Require Signing In Standard Pen Colors?

A social experiment. What is the worst that can happen?

Why did the HMS Bounty go back to a time when whales are already rare?

Biological Blimps: Propulsion

The Staircase of Paint

Are the IPv6 address space and IPv4 address space completely disjoint?

Has any country ever had 2 former presidents in jail simultaneously?

How could a planet have erratic days?

What should you do if you miss a job interview (deliberately)?

Is it safe to use olive oil to clean the ear wax?

How can Trident be so inexpensive? Will it orbit Triton or just do a (slow) flyby?

What should you do when eye contact makes your subordinate uncomfortable?

Where did Heinlein say "Once you get to Earth orbit, you're halfway to anywhere in the Solar System"?

Calculating Wattage for Resistor in High Frequency Application?

Is there a working SACD iso player for Ubuntu?

Create all possible words using a set or letters

Non-trope happy ending?

Why should universal income be universal?

How can "mimic phobia" be cured or prevented?

How to implement a feedback to keep the DC gain at zero for this conceptual passive filter?

Creature in Shazam mid-credits scene?



Embed a weighted projective space into an unweighted projective space.


Terminology for weighted projective spacesIn the Proj construction, are the homogeneuos prime ideals determined up to an element in the base ring?Projective variety defined by a non-radical ideal.Weighted projective space and $mathrmProj$Isomorphism (?) of polynomial rings with different gradings and their ProjClosed points in projective space correspond to which homogenous prime ideals in $k[x_0,…,x_n]$Morphism of projective schemes not induced by maps of graded rings, Vakil's 16.4 GWhat would an infinite dimensional projective space look like as a scheme?Projective Space over an algebraically closed fieldAffine charts are dense in projective space













2












$begingroup$


To show is the following.




Let $X = P(a_0,dotsc,a_n)$, $a_i geq 1$ be a weighted projective space (that is $X = operatornameProj k[x_0,dotsc,x_n]$, where $operatornamedeg x_i = a_i$).
Then there exists an $N$ and a closed embedding $X to mathbb P^N_k$ ($mathbb P^N_k = operatornameProj k[y_0,dotsc,y_N]$, where $operatornamedegy_i = 1$).




I can't find a surjective ring morphism between the graded rings (there doesn't really exist one, right?). Is the embedding some kind of Veronese-like map?










share|cite|improve this question









$endgroup$
















    2












    $begingroup$


    To show is the following.




    Let $X = P(a_0,dotsc,a_n)$, $a_i geq 1$ be a weighted projective space (that is $X = operatornameProj k[x_0,dotsc,x_n]$, where $operatornamedeg x_i = a_i$).
    Then there exists an $N$ and a closed embedding $X to mathbb P^N_k$ ($mathbb P^N_k = operatornameProj k[y_0,dotsc,y_N]$, where $operatornamedegy_i = 1$).




    I can't find a surjective ring morphism between the graded rings (there doesn't really exist one, right?). Is the embedding some kind of Veronese-like map?










    share|cite|improve this question









    $endgroup$














      2












      2








      2





      $begingroup$


      To show is the following.




      Let $X = P(a_0,dotsc,a_n)$, $a_i geq 1$ be a weighted projective space (that is $X = operatornameProj k[x_0,dotsc,x_n]$, where $operatornamedeg x_i = a_i$).
      Then there exists an $N$ and a closed embedding $X to mathbb P^N_k$ ($mathbb P^N_k = operatornameProj k[y_0,dotsc,y_N]$, where $operatornamedegy_i = 1$).




      I can't find a surjective ring morphism between the graded rings (there doesn't really exist one, right?). Is the embedding some kind of Veronese-like map?










      share|cite|improve this question









      $endgroup$




      To show is the following.




      Let $X = P(a_0,dotsc,a_n)$, $a_i geq 1$ be a weighted projective space (that is $X = operatornameProj k[x_0,dotsc,x_n]$, where $operatornamedeg x_i = a_i$).
      Then there exists an $N$ and a closed embedding $X to mathbb P^N_k$ ($mathbb P^N_k = operatornameProj k[y_0,dotsc,y_N]$, where $operatornamedegy_i = 1$).




      I can't find a surjective ring morphism between the graded rings (there doesn't really exist one, right?). Is the embedding some kind of Veronese-like map?







      algebraic-geometry projective-space graded-rings projective-schemes






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Mar 15 at 18:49









      BerberBerber

      909




      909




















          1 Answer
          1






          active

          oldest

          votes


















          2












          $begingroup$

          There is a very ampleness condition due to Delorme in [Del75a]. You can also look at [BR86] for an English reference. We have changed the dimension $n$ in your notation to an $r$ to closer match the notation in these references.



          We start with some definitions.



          Definition [Del75a, Def. 2.1; BR86, Defs. 4B.1, 4B.2, and 4B.3]. We let $m_J := operatornamelcma_i mid i in J$ for every non-empty subset $J subseteq 0,1,ldots,r$, and let $m := m_1,2,ldots,r$. Now set
          $$G := begincases
          -a_r & textif $r = 0$, and\
          displaystyle-sum_i=0^r a_i + frac1rsum_2 le nu le r+1 binomr-1nu-2^-1 sum_lvert J rvert = nu m_J & textotherwise.
          endcases$$

          We then say that an integer $n ge 0$ satisfies condition $D(n)$ if one of the following equivalent conditions hold:



          • Given a relation $sum_i = 0^r B_ia_i = n + km$ with $k in mathbfZ_>0$ and $B_i in mathbfZ_ge0$ for every $i$, there exist $b_i in mathbfZ_ge0$ with $B_i ge b_i$ for every $i$, such that $sum_i = 0^r b_ia_i=km$.


          • Every monomial $prod_i=0^r x_i^B_i$ of degree $n+km$ is divisible by a monomial $prod_i=0^r x_i^b_i$ of degree $km$.


          We then define $F$ to be the smallest integer such that $n > F$ implies $D(n)$ holds. We also define $E$ to be the smallest integer such that $n > E$ implies $D(mn)$ holds. Note that $mE le F$.



          One can then show that $F$ is finite and $F le G$ [Del75a, Prop. 2.2; BR86, Prop. 4B.5]. The proof is a double induction on $k$ and $r$, and boils down to the pigeon-hole principle.



          With notation as above, we then have the following:



          Theorem [Del75a, Prop. 2.3; BR86, Thm. 4B.7]. Let $X = mathbfP(a_0,a_1,ldots,a_r)$ be a weighted projective space over a commutative ring $A$, where $a_i ge 1$ for every $1$. With notation as above, we have the following:



          1. $mathcalO_X(m)$ is an ample invertible sheaf.


          2. If $n > F$, then the sheaf $mathcalO_X(n)$ is globally generated.


          3. If $n > 0$ and $n > E$, then the sheaf $mathcalO_X(nm)$ is very ample.


          We prove (3), since this is what you are interested in. For every $p in mathbfZ_>0$, the condition $D(mn)$ implies that every monomial of degree $pmn = (p-1)mn + mn$ in $A[x_0,x_1,ldots,x_r]$ is divisible by a monomial of degree $(p-1)mn$. Thus, the $mn$th Veronese subring $A[x_0,x_1,ldots,x_r]^(mn)$ of $A[x_0,x_1,ldots,x_r]$ is generated in degree $1$ over $A$.



          You can therefore embed $X$ into $mathbfP^N_A$, where $N$ is the number of generators of $A[x_0,x_1,ldots,x_r]_mn$, by
          $$X = operatornameProjbigl(A[x_0,x_1,ldots,x_r]bigr) simeq operatornameProjbigl(A[x_0,x_1,ldots,x_r]^(mn)bigr) hookrightarrow mathbfP^N_A.$$
          Unraveling the definitions given above, we note that in particular, setting
          $$n = biggllfloorfrac1mGbiggrrfloor+1$$
          works.



          References



          [BR86] Mauro Beltrametti and Lorenzo Robbiano, "Introduction to the theory of weighted projective spaces," Exposition. Math. 4 (1986), no. 2, 111–162. mr: 879909.



          [Del75a] Charles Delorme, "Espaces projectifs anisotropes," Bull. Soc. Math. France 103 (1975), no. 2, 203–223. doi: 10.24033/bsmf.1802. mr: 404277.



          [Del75b] Charles Delorme, "Erratum: 'Espaces projectifs anisotropes'," Bull. Soc. Math. France 103 (1975), no. 4, 510. doi: 10.24033/bsmf.1812. mr: 404278.






          share|cite|improve this answer











          $endgroup$












            Your Answer





            StackExchange.ifUsing("editor", function ()
            return StackExchange.using("mathjaxEditing", function ()
            StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
            StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
            );
            );
            , "mathjax-editing");

            StackExchange.ready(function()
            var channelOptions =
            tags: "".split(" "),
            id: "69"
            ;
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function()
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled)
            StackExchange.using("snippets", function()
            createEditor();
            );

            else
            createEditor();

            );

            function createEditor()
            StackExchange.prepareEditor(
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader:
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            ,
            noCode: true, onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            );



            );













            draft saved

            draft discarded


















            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3149666%2fembed-a-weighted-projective-space-into-an-unweighted-projective-space%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2












            $begingroup$

            There is a very ampleness condition due to Delorme in [Del75a]. You can also look at [BR86] for an English reference. We have changed the dimension $n$ in your notation to an $r$ to closer match the notation in these references.



            We start with some definitions.



            Definition [Del75a, Def. 2.1; BR86, Defs. 4B.1, 4B.2, and 4B.3]. We let $m_J := operatornamelcma_i mid i in J$ for every non-empty subset $J subseteq 0,1,ldots,r$, and let $m := m_1,2,ldots,r$. Now set
            $$G := begincases
            -a_r & textif $r = 0$, and\
            displaystyle-sum_i=0^r a_i + frac1rsum_2 le nu le r+1 binomr-1nu-2^-1 sum_lvert J rvert = nu m_J & textotherwise.
            endcases$$

            We then say that an integer $n ge 0$ satisfies condition $D(n)$ if one of the following equivalent conditions hold:



            • Given a relation $sum_i = 0^r B_ia_i = n + km$ with $k in mathbfZ_>0$ and $B_i in mathbfZ_ge0$ for every $i$, there exist $b_i in mathbfZ_ge0$ with $B_i ge b_i$ for every $i$, such that $sum_i = 0^r b_ia_i=km$.


            • Every monomial $prod_i=0^r x_i^B_i$ of degree $n+km$ is divisible by a monomial $prod_i=0^r x_i^b_i$ of degree $km$.


            We then define $F$ to be the smallest integer such that $n > F$ implies $D(n)$ holds. We also define $E$ to be the smallest integer such that $n > E$ implies $D(mn)$ holds. Note that $mE le F$.



            One can then show that $F$ is finite and $F le G$ [Del75a, Prop. 2.2; BR86, Prop. 4B.5]. The proof is a double induction on $k$ and $r$, and boils down to the pigeon-hole principle.



            With notation as above, we then have the following:



            Theorem [Del75a, Prop. 2.3; BR86, Thm. 4B.7]. Let $X = mathbfP(a_0,a_1,ldots,a_r)$ be a weighted projective space over a commutative ring $A$, where $a_i ge 1$ for every $1$. With notation as above, we have the following:



            1. $mathcalO_X(m)$ is an ample invertible sheaf.


            2. If $n > F$, then the sheaf $mathcalO_X(n)$ is globally generated.


            3. If $n > 0$ and $n > E$, then the sheaf $mathcalO_X(nm)$ is very ample.


            We prove (3), since this is what you are interested in. For every $p in mathbfZ_>0$, the condition $D(mn)$ implies that every monomial of degree $pmn = (p-1)mn + mn$ in $A[x_0,x_1,ldots,x_r]$ is divisible by a monomial of degree $(p-1)mn$. Thus, the $mn$th Veronese subring $A[x_0,x_1,ldots,x_r]^(mn)$ of $A[x_0,x_1,ldots,x_r]$ is generated in degree $1$ over $A$.



            You can therefore embed $X$ into $mathbfP^N_A$, where $N$ is the number of generators of $A[x_0,x_1,ldots,x_r]_mn$, by
            $$X = operatornameProjbigl(A[x_0,x_1,ldots,x_r]bigr) simeq operatornameProjbigl(A[x_0,x_1,ldots,x_r]^(mn)bigr) hookrightarrow mathbfP^N_A.$$
            Unraveling the definitions given above, we note that in particular, setting
            $$n = biggllfloorfrac1mGbiggrrfloor+1$$
            works.



            References



            [BR86] Mauro Beltrametti and Lorenzo Robbiano, "Introduction to the theory of weighted projective spaces," Exposition. Math. 4 (1986), no. 2, 111–162. mr: 879909.



            [Del75a] Charles Delorme, "Espaces projectifs anisotropes," Bull. Soc. Math. France 103 (1975), no. 2, 203–223. doi: 10.24033/bsmf.1802. mr: 404277.



            [Del75b] Charles Delorme, "Erratum: 'Espaces projectifs anisotropes'," Bull. Soc. Math. France 103 (1975), no. 4, 510. doi: 10.24033/bsmf.1812. mr: 404278.






            share|cite|improve this answer











            $endgroup$

















              2












              $begingroup$

              There is a very ampleness condition due to Delorme in [Del75a]. You can also look at [BR86] for an English reference. We have changed the dimension $n$ in your notation to an $r$ to closer match the notation in these references.



              We start with some definitions.



              Definition [Del75a, Def. 2.1; BR86, Defs. 4B.1, 4B.2, and 4B.3]. We let $m_J := operatornamelcma_i mid i in J$ for every non-empty subset $J subseteq 0,1,ldots,r$, and let $m := m_1,2,ldots,r$. Now set
              $$G := begincases
              -a_r & textif $r = 0$, and\
              displaystyle-sum_i=0^r a_i + frac1rsum_2 le nu le r+1 binomr-1nu-2^-1 sum_lvert J rvert = nu m_J & textotherwise.
              endcases$$

              We then say that an integer $n ge 0$ satisfies condition $D(n)$ if one of the following equivalent conditions hold:



              • Given a relation $sum_i = 0^r B_ia_i = n + km$ with $k in mathbfZ_>0$ and $B_i in mathbfZ_ge0$ for every $i$, there exist $b_i in mathbfZ_ge0$ with $B_i ge b_i$ for every $i$, such that $sum_i = 0^r b_ia_i=km$.


              • Every monomial $prod_i=0^r x_i^B_i$ of degree $n+km$ is divisible by a monomial $prod_i=0^r x_i^b_i$ of degree $km$.


              We then define $F$ to be the smallest integer such that $n > F$ implies $D(n)$ holds. We also define $E$ to be the smallest integer such that $n > E$ implies $D(mn)$ holds. Note that $mE le F$.



              One can then show that $F$ is finite and $F le G$ [Del75a, Prop. 2.2; BR86, Prop. 4B.5]. The proof is a double induction on $k$ and $r$, and boils down to the pigeon-hole principle.



              With notation as above, we then have the following:



              Theorem [Del75a, Prop. 2.3; BR86, Thm. 4B.7]. Let $X = mathbfP(a_0,a_1,ldots,a_r)$ be a weighted projective space over a commutative ring $A$, where $a_i ge 1$ for every $1$. With notation as above, we have the following:



              1. $mathcalO_X(m)$ is an ample invertible sheaf.


              2. If $n > F$, then the sheaf $mathcalO_X(n)$ is globally generated.


              3. If $n > 0$ and $n > E$, then the sheaf $mathcalO_X(nm)$ is very ample.


              We prove (3), since this is what you are interested in. For every $p in mathbfZ_>0$, the condition $D(mn)$ implies that every monomial of degree $pmn = (p-1)mn + mn$ in $A[x_0,x_1,ldots,x_r]$ is divisible by a monomial of degree $(p-1)mn$. Thus, the $mn$th Veronese subring $A[x_0,x_1,ldots,x_r]^(mn)$ of $A[x_0,x_1,ldots,x_r]$ is generated in degree $1$ over $A$.



              You can therefore embed $X$ into $mathbfP^N_A$, where $N$ is the number of generators of $A[x_0,x_1,ldots,x_r]_mn$, by
              $$X = operatornameProjbigl(A[x_0,x_1,ldots,x_r]bigr) simeq operatornameProjbigl(A[x_0,x_1,ldots,x_r]^(mn)bigr) hookrightarrow mathbfP^N_A.$$
              Unraveling the definitions given above, we note that in particular, setting
              $$n = biggllfloorfrac1mGbiggrrfloor+1$$
              works.



              References



              [BR86] Mauro Beltrametti and Lorenzo Robbiano, "Introduction to the theory of weighted projective spaces," Exposition. Math. 4 (1986), no. 2, 111–162. mr: 879909.



              [Del75a] Charles Delorme, "Espaces projectifs anisotropes," Bull. Soc. Math. France 103 (1975), no. 2, 203–223. doi: 10.24033/bsmf.1802. mr: 404277.



              [Del75b] Charles Delorme, "Erratum: 'Espaces projectifs anisotropes'," Bull. Soc. Math. France 103 (1975), no. 4, 510. doi: 10.24033/bsmf.1812. mr: 404278.






              share|cite|improve this answer











              $endgroup$















                2












                2








                2





                $begingroup$

                There is a very ampleness condition due to Delorme in [Del75a]. You can also look at [BR86] for an English reference. We have changed the dimension $n$ in your notation to an $r$ to closer match the notation in these references.



                We start with some definitions.



                Definition [Del75a, Def. 2.1; BR86, Defs. 4B.1, 4B.2, and 4B.3]. We let $m_J := operatornamelcma_i mid i in J$ for every non-empty subset $J subseteq 0,1,ldots,r$, and let $m := m_1,2,ldots,r$. Now set
                $$G := begincases
                -a_r & textif $r = 0$, and\
                displaystyle-sum_i=0^r a_i + frac1rsum_2 le nu le r+1 binomr-1nu-2^-1 sum_lvert J rvert = nu m_J & textotherwise.
                endcases$$

                We then say that an integer $n ge 0$ satisfies condition $D(n)$ if one of the following equivalent conditions hold:



                • Given a relation $sum_i = 0^r B_ia_i = n + km$ with $k in mathbfZ_>0$ and $B_i in mathbfZ_ge0$ for every $i$, there exist $b_i in mathbfZ_ge0$ with $B_i ge b_i$ for every $i$, such that $sum_i = 0^r b_ia_i=km$.


                • Every monomial $prod_i=0^r x_i^B_i$ of degree $n+km$ is divisible by a monomial $prod_i=0^r x_i^b_i$ of degree $km$.


                We then define $F$ to be the smallest integer such that $n > F$ implies $D(n)$ holds. We also define $E$ to be the smallest integer such that $n > E$ implies $D(mn)$ holds. Note that $mE le F$.



                One can then show that $F$ is finite and $F le G$ [Del75a, Prop. 2.2; BR86, Prop. 4B.5]. The proof is a double induction on $k$ and $r$, and boils down to the pigeon-hole principle.



                With notation as above, we then have the following:



                Theorem [Del75a, Prop. 2.3; BR86, Thm. 4B.7]. Let $X = mathbfP(a_0,a_1,ldots,a_r)$ be a weighted projective space over a commutative ring $A$, where $a_i ge 1$ for every $1$. With notation as above, we have the following:



                1. $mathcalO_X(m)$ is an ample invertible sheaf.


                2. If $n > F$, then the sheaf $mathcalO_X(n)$ is globally generated.


                3. If $n > 0$ and $n > E$, then the sheaf $mathcalO_X(nm)$ is very ample.


                We prove (3), since this is what you are interested in. For every $p in mathbfZ_>0$, the condition $D(mn)$ implies that every monomial of degree $pmn = (p-1)mn + mn$ in $A[x_0,x_1,ldots,x_r]$ is divisible by a monomial of degree $(p-1)mn$. Thus, the $mn$th Veronese subring $A[x_0,x_1,ldots,x_r]^(mn)$ of $A[x_0,x_1,ldots,x_r]$ is generated in degree $1$ over $A$.



                You can therefore embed $X$ into $mathbfP^N_A$, where $N$ is the number of generators of $A[x_0,x_1,ldots,x_r]_mn$, by
                $$X = operatornameProjbigl(A[x_0,x_1,ldots,x_r]bigr) simeq operatornameProjbigl(A[x_0,x_1,ldots,x_r]^(mn)bigr) hookrightarrow mathbfP^N_A.$$
                Unraveling the definitions given above, we note that in particular, setting
                $$n = biggllfloorfrac1mGbiggrrfloor+1$$
                works.



                References



                [BR86] Mauro Beltrametti and Lorenzo Robbiano, "Introduction to the theory of weighted projective spaces," Exposition. Math. 4 (1986), no. 2, 111–162. mr: 879909.



                [Del75a] Charles Delorme, "Espaces projectifs anisotropes," Bull. Soc. Math. France 103 (1975), no. 2, 203–223. doi: 10.24033/bsmf.1802. mr: 404277.



                [Del75b] Charles Delorme, "Erratum: 'Espaces projectifs anisotropes'," Bull. Soc. Math. France 103 (1975), no. 4, 510. doi: 10.24033/bsmf.1812. mr: 404278.






                share|cite|improve this answer











                $endgroup$



                There is a very ampleness condition due to Delorme in [Del75a]. You can also look at [BR86] for an English reference. We have changed the dimension $n$ in your notation to an $r$ to closer match the notation in these references.



                We start with some definitions.



                Definition [Del75a, Def. 2.1; BR86, Defs. 4B.1, 4B.2, and 4B.3]. We let $m_J := operatornamelcma_i mid i in J$ for every non-empty subset $J subseteq 0,1,ldots,r$, and let $m := m_1,2,ldots,r$. Now set
                $$G := begincases
                -a_r & textif $r = 0$, and\
                displaystyle-sum_i=0^r a_i + frac1rsum_2 le nu le r+1 binomr-1nu-2^-1 sum_lvert J rvert = nu m_J & textotherwise.
                endcases$$

                We then say that an integer $n ge 0$ satisfies condition $D(n)$ if one of the following equivalent conditions hold:



                • Given a relation $sum_i = 0^r B_ia_i = n + km$ with $k in mathbfZ_>0$ and $B_i in mathbfZ_ge0$ for every $i$, there exist $b_i in mathbfZ_ge0$ with $B_i ge b_i$ for every $i$, such that $sum_i = 0^r b_ia_i=km$.


                • Every monomial $prod_i=0^r x_i^B_i$ of degree $n+km$ is divisible by a monomial $prod_i=0^r x_i^b_i$ of degree $km$.


                We then define $F$ to be the smallest integer such that $n > F$ implies $D(n)$ holds. We also define $E$ to be the smallest integer such that $n > E$ implies $D(mn)$ holds. Note that $mE le F$.



                One can then show that $F$ is finite and $F le G$ [Del75a, Prop. 2.2; BR86, Prop. 4B.5]. The proof is a double induction on $k$ and $r$, and boils down to the pigeon-hole principle.



                With notation as above, we then have the following:



                Theorem [Del75a, Prop. 2.3; BR86, Thm. 4B.7]. Let $X = mathbfP(a_0,a_1,ldots,a_r)$ be a weighted projective space over a commutative ring $A$, where $a_i ge 1$ for every $1$. With notation as above, we have the following:



                1. $mathcalO_X(m)$ is an ample invertible sheaf.


                2. If $n > F$, then the sheaf $mathcalO_X(n)$ is globally generated.


                3. If $n > 0$ and $n > E$, then the sheaf $mathcalO_X(nm)$ is very ample.


                We prove (3), since this is what you are interested in. For every $p in mathbfZ_>0$, the condition $D(mn)$ implies that every monomial of degree $pmn = (p-1)mn + mn$ in $A[x_0,x_1,ldots,x_r]$ is divisible by a monomial of degree $(p-1)mn$. Thus, the $mn$th Veronese subring $A[x_0,x_1,ldots,x_r]^(mn)$ of $A[x_0,x_1,ldots,x_r]$ is generated in degree $1$ over $A$.



                You can therefore embed $X$ into $mathbfP^N_A$, where $N$ is the number of generators of $A[x_0,x_1,ldots,x_r]_mn$, by
                $$X = operatornameProjbigl(A[x_0,x_1,ldots,x_r]bigr) simeq operatornameProjbigl(A[x_0,x_1,ldots,x_r]^(mn)bigr) hookrightarrow mathbfP^N_A.$$
                Unraveling the definitions given above, we note that in particular, setting
                $$n = biggllfloorfrac1mGbiggrrfloor+1$$
                works.



                References



                [BR86] Mauro Beltrametti and Lorenzo Robbiano, "Introduction to the theory of weighted projective spaces," Exposition. Math. 4 (1986), no. 2, 111–162. mr: 879909.



                [Del75a] Charles Delorme, "Espaces projectifs anisotropes," Bull. Soc. Math. France 103 (1975), no. 2, 203–223. doi: 10.24033/bsmf.1802. mr: 404277.



                [Del75b] Charles Delorme, "Erratum: 'Espaces projectifs anisotropes'," Bull. Soc. Math. France 103 (1975), no. 4, 510. doi: 10.24033/bsmf.1812. mr: 404278.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Mar 18 at 18:46

























                answered Mar 17 at 22:28









                Takumi MurayamaTakumi Murayama

                6,39611646




                6,39611646



























                    draft saved

                    draft discarded
















































                    Thanks for contributing an answer to Mathematics Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid


                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.

                    Use MathJax to format equations. MathJax reference.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function ()
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3149666%2fembed-a-weighted-projective-space-into-an-unweighted-projective-space%23new-answer', 'question_page');

                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    How should I support this large drywall patch? Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?How do I cover large gaps in drywall?How do I keep drywall around a patch from crumbling?Can I glue a second layer of drywall?How to patch long strip on drywall?Large drywall patch: how to avoid bulging seams?Drywall Mesh Patch vs. Bulge? To remove or not to remove?How to fix this drywall job?Prep drywall before backsplashWhat's the best way to fix this horrible drywall patch job?Drywall patching using 3M Patch Plus Primer

                    random experiment with two different functions on unit interval Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Random variable and probability space notionsRandom Walk with EdgesFinding functions where the increase over a random interval is Poisson distributedNumber of days until dayCan an observed event in fact be of zero probability?Unit random processmodels of coins and uniform distributionHow to get the number of successes given $n$ trials , probability $P$ and a random variable $X$Absorbing Markov chain in a computer. Is “almost every” turned into always convergence in computer executions?Stopped random walk is not uniformly integrable

                    Lowndes Grove History Architecture References Navigation menu32°48′6″N 79°57′58″W / 32.80167°N 79.96611°W / 32.80167; -79.9661132°48′6″N 79°57′58″W / 32.80167°N 79.96611°W / 32.80167; -79.9661178002500"National Register Information System"Historic houses of South Carolina"Lowndes Grove""+32° 48' 6.00", −79° 57' 58.00""Lowndes Grove, Charleston County (260 St. Margaret St., Charleston)""Lowndes Grove"The Charleston ExpositionIt Happened in South Carolina"Lowndes Grove (House), Saint Margaret Street & Sixth Avenue, Charleston, Charleston County, SC(Photographs)"Plantations of the Carolina Low Countrye