If a ray r emanating from an exterior point of triangle ABC intersects side AB at any point between A and B, then r also intersects side AC or side BC [duplicate]Justify each step in the following proof of Proposition 3.9 (a). I like to know if I'm in the right track and I'm also missing a few of themGiven triangle ABC, if D is an interior pt and E is an exterior pt, segment DE intersects triangle ABC?Finding the Perimiter of a right Triangle given an interior angle bisector and exterior angle bisectorQuestion about proof regarding a triangle and a line.Given a point origin, find ray that intersects two linesProve In Equilateral Triangle $ABC$ $AM$ and $AN$ are equalProve that ray CE intersects $triangle ABC$ at a point $D$ on $AB$ and that $D$ must lie strictly between $A$ and $B$.Justify each step in the following proof of Proposition 3.9 (a). I like to know if I'm in the right track and I'm also missing a few of themGeometry: Construct a rectangle with area equal to a given triangle and with one side equal to a given segment.Given a triangle $ABC$, make it a point $D$ on the side $AB$.Prove that if a ray has its endpoint on a line, where the ray is not on the line, then the points of the ray are on the same side of the line.
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If a ray r emanating from an exterior point of triangle ABC intersects side AB at any point between A and B, then r also intersects side AC or side BC [duplicate]
Justify each step in the following proof of Proposition 3.9 (a). I like to know if I'm in the right track and I'm also missing a few of themGiven triangle ABC, if D is an interior pt and E is an exterior pt, segment DE intersects triangle ABC?Finding the Perimiter of a right Triangle given an interior angle bisector and exterior angle bisectorQuestion about proof regarding a triangle and a line.Given a point origin, find ray that intersects two linesProve In Equilateral Triangle $ABC$ $AM$ and $AN$ are equalProve that ray CE intersects $triangle ABC$ at a point $D$ on $AB$ and that $D$ must lie strictly between $A$ and $B$.Justify each step in the following proof of Proposition 3.9 (a). I like to know if I'm in the right track and I'm also missing a few of themGeometry: Construct a rectangle with area equal to a given triangle and with one side equal to a given segment.Given a triangle $ABC$, make it a point $D$ on the side $AB$.Prove that if a ray has its endpoint on a line, where the ray is not on the line, then the points of the ray are on the same side of the line.
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This question is an exact duplicate of:
Justify each step in the following proof of Proposition 3.9 (a). I like to know if I'm in the right track and I'm also missing a few of them
1 answer
Prove Proposition 3.9:
If a ray r emanating from an exterior point of triangle $ABC$ intersects side $AB$ at any point between $A$ and $B$, then $r$ also intersects side $AC$ or side $BC$.
Can someone help me finish this proof I started
By the hypothesis, let $DE$ be a ray emanating from an exterior point $D$ of triangle $ABC$ where the ray $DE$ intersects $AB$ at point $E$ such that $A*E*B$.
By pachs theorem, the line DE either intersects $AC$ or $BC$.
3.Suppose $DE$ intersects $AC$ at point $M$ where $M$ is not equal to $A$
Then by the definition of line segment, either $M=C$, or $D*M*E$
geometry euclidean-geometry education math-history
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marked as duplicate by Lee David Chung Lin, Leucippus, Lord Shark the Unknown, Vinyl_cape_jawa, uniquesolution Mar 16 at 9:57
This question was marked as an exact duplicate of an existing question.
add a comment |
$begingroup$
This question is an exact duplicate of:
Justify each step in the following proof of Proposition 3.9 (a). I like to know if I'm in the right track and I'm also missing a few of them
1 answer
Prove Proposition 3.9:
If a ray r emanating from an exterior point of triangle $ABC$ intersects side $AB$ at any point between $A$ and $B$, then $r$ also intersects side $AC$ or side $BC$.
Can someone help me finish this proof I started
By the hypothesis, let $DE$ be a ray emanating from an exterior point $D$ of triangle $ABC$ where the ray $DE$ intersects $AB$ at point $E$ such that $A*E*B$.
By pachs theorem, the line DE either intersects $AC$ or $BC$.
3.Suppose $DE$ intersects $AC$ at point $M$ where $M$ is not equal to $A$
Then by the definition of line segment, either $M=C$, or $D*M*E$
geometry euclidean-geometry education math-history
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marked as duplicate by Lee David Chung Lin, Leucippus, Lord Shark the Unknown, Vinyl_cape_jawa, uniquesolution Mar 16 at 9:57
This question was marked as an exact duplicate of an existing question.
1
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Please change the title of your question - proposition 3.9a is not something people will know.
$endgroup$
– Piotr Benedysiuk
Mar 15 at 17:18
add a comment |
$begingroup$
This question is an exact duplicate of:
Justify each step in the following proof of Proposition 3.9 (a). I like to know if I'm in the right track and I'm also missing a few of them
1 answer
Prove Proposition 3.9:
If a ray r emanating from an exterior point of triangle $ABC$ intersects side $AB$ at any point between $A$ and $B$, then $r$ also intersects side $AC$ or side $BC$.
Can someone help me finish this proof I started
By the hypothesis, let $DE$ be a ray emanating from an exterior point $D$ of triangle $ABC$ where the ray $DE$ intersects $AB$ at point $E$ such that $A*E*B$.
By pachs theorem, the line DE either intersects $AC$ or $BC$.
3.Suppose $DE$ intersects $AC$ at point $M$ where $M$ is not equal to $A$
Then by the definition of line segment, either $M=C$, or $D*M*E$
geometry euclidean-geometry education math-history
$endgroup$
This question is an exact duplicate of:
Justify each step in the following proof of Proposition 3.9 (a). I like to know if I'm in the right track and I'm also missing a few of them
1 answer
Prove Proposition 3.9:
If a ray r emanating from an exterior point of triangle $ABC$ intersects side $AB$ at any point between $A$ and $B$, then $r$ also intersects side $AC$ or side $BC$.
Can someone help me finish this proof I started
By the hypothesis, let $DE$ be a ray emanating from an exterior point $D$ of triangle $ABC$ where the ray $DE$ intersects $AB$ at point $E$ such that $A*E*B$.
By pachs theorem, the line DE either intersects $AC$ or $BC$.
3.Suppose $DE$ intersects $AC$ at point $M$ where $M$ is not equal to $A$
Then by the definition of line segment, either $M=C$, or $D*M*E$
This question is an exact duplicate of:
Justify each step in the following proof of Proposition 3.9 (a). I like to know if I'm in the right track and I'm also missing a few of them
1 answer
geometry euclidean-geometry education math-history
geometry euclidean-geometry education math-history
edited Mar 15 at 17:45
Math1234
asked Mar 15 at 17:05
Math1234Math1234
63
63
marked as duplicate by Lee David Chung Lin, Leucippus, Lord Shark the Unknown, Vinyl_cape_jawa, uniquesolution Mar 16 at 9:57
This question was marked as an exact duplicate of an existing question.
marked as duplicate by Lee David Chung Lin, Leucippus, Lord Shark the Unknown, Vinyl_cape_jawa, uniquesolution Mar 16 at 9:57
This question was marked as an exact duplicate of an existing question.
1
$begingroup$
Please change the title of your question - proposition 3.9a is not something people will know.
$endgroup$
– Piotr Benedysiuk
Mar 15 at 17:18
add a comment |
1
$begingroup$
Please change the title of your question - proposition 3.9a is not something people will know.
$endgroup$
– Piotr Benedysiuk
Mar 15 at 17:18
1
1
$begingroup$
Please change the title of your question - proposition 3.9a is not something people will know.
$endgroup$
– Piotr Benedysiuk
Mar 15 at 17:18
$begingroup$
Please change the title of your question - proposition 3.9a is not something people will know.
$endgroup$
– Piotr Benedysiuk
Mar 15 at 17:18
add a comment |
1 Answer
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Then by the definition of line segment, either $M=C$, or $D*M*E$
This step is not correct/justified.
Up to that point your proof is correct. In fact, the only thing you need to conclude the proof is that $D*E*M$ or $D*M*E$. Since these points are distinct, you may assume the contrary i.e. $E*D*M$, and show that $D$ is an interior point of a triangle which contradicts the assumption. To do this, prove that $D$ belongs to all three halfplanes which determine the interior of a triangle.
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How exactly would you prove D is in the interior? What would the layout of it be? I'm confused how to show how EDM means that D in the interior.
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– Math1234
Mar 21 at 3:48
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Then by the definition of line segment, either $M=C$, or $D*M*E$
This step is not correct/justified.
Up to that point your proof is correct. In fact, the only thing you need to conclude the proof is that $D*E*M$ or $D*M*E$. Since these points are distinct, you may assume the contrary i.e. $E*D*M$, and show that $D$ is an interior point of a triangle which contradicts the assumption. To do this, prove that $D$ belongs to all three halfplanes which determine the interior of a triangle.
$endgroup$
$begingroup$
How exactly would you prove D is in the interior? What would the layout of it be? I'm confused how to show how EDM means that D in the interior.
$endgroup$
– Math1234
Mar 21 at 3:48
add a comment |
$begingroup$
Then by the definition of line segment, either $M=C$, or $D*M*E$
This step is not correct/justified.
Up to that point your proof is correct. In fact, the only thing you need to conclude the proof is that $D*E*M$ or $D*M*E$. Since these points are distinct, you may assume the contrary i.e. $E*D*M$, and show that $D$ is an interior point of a triangle which contradicts the assumption. To do this, prove that $D$ belongs to all three halfplanes which determine the interior of a triangle.
$endgroup$
$begingroup$
How exactly would you prove D is in the interior? What would the layout of it be? I'm confused how to show how EDM means that D in the interior.
$endgroup$
– Math1234
Mar 21 at 3:48
add a comment |
$begingroup$
Then by the definition of line segment, either $M=C$, or $D*M*E$
This step is not correct/justified.
Up to that point your proof is correct. In fact, the only thing you need to conclude the proof is that $D*E*M$ or $D*M*E$. Since these points are distinct, you may assume the contrary i.e. $E*D*M$, and show that $D$ is an interior point of a triangle which contradicts the assumption. To do this, prove that $D$ belongs to all three halfplanes which determine the interior of a triangle.
$endgroup$
Then by the definition of line segment, either $M=C$, or $D*M*E$
This step is not correct/justified.
Up to that point your proof is correct. In fact, the only thing you need to conclude the proof is that $D*E*M$ or $D*M*E$. Since these points are distinct, you may assume the contrary i.e. $E*D*M$, and show that $D$ is an interior point of a triangle which contradicts the assumption. To do this, prove that $D$ belongs to all three halfplanes which determine the interior of a triangle.
answered Mar 15 at 19:13
KulistyKulisty
419216
419216
$begingroup$
How exactly would you prove D is in the interior? What would the layout of it be? I'm confused how to show how EDM means that D in the interior.
$endgroup$
– Math1234
Mar 21 at 3:48
add a comment |
$begingroup$
How exactly would you prove D is in the interior? What would the layout of it be? I'm confused how to show how EDM means that D in the interior.
$endgroup$
– Math1234
Mar 21 at 3:48
$begingroup$
How exactly would you prove D is in the interior? What would the layout of it be? I'm confused how to show how EDM means that D in the interior.
$endgroup$
– Math1234
Mar 21 at 3:48
$begingroup$
How exactly would you prove D is in the interior? What would the layout of it be? I'm confused how to show how EDM means that D in the interior.
$endgroup$
– Math1234
Mar 21 at 3:48
add a comment |
1
$begingroup$
Please change the title of your question - proposition 3.9a is not something people will know.
$endgroup$
– Piotr Benedysiuk
Mar 15 at 17:18