Why is positive definiteness required for a global minimum to exist? The 2019 Stack Overflow Developer Survey Results Are Inhessian matrix not positive definite at a minimum?Positive definiteness of matrix?Does existence of global minimum imply coercivity?Coerciveness and Positive definiteness relation?Why (x'Ay)^2 <=(x'Ax)(y'Ay), when A is positive definite?minimum eigenvalue of the Hadamard product of positive semi-definite matricesPositive definiteness of matrix A.Minimum eigenvalue of sums of positive semi-definite matricesGlobal minimum of $f(x)=langle Ax,x rangle +2 langle x,b rangle+c$Positive definiteness of “sub-matrices”

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Why is positive definiteness required for a global minimum to exist?



The 2019 Stack Overflow Developer Survey Results Are Inhessian matrix not positive definite at a minimum?Positive definiteness of matrix?Does existence of global minimum imply coercivity?Coerciveness and Positive definiteness relation?Why (x'Ay)^2 <=(x'Ax)(y'Ay), when A is positive definite?minimum eigenvalue of the Hadamard product of positive semi-definite matricesPositive definiteness of matrix A.Minimum eigenvalue of sums of positive semi-definite matricesGlobal minimum of $f(x)=langle Ax,x rangle +2 langle x,b rangle+c$Positive definiteness of “sub-matrices”










0












$begingroup$


When we optimize



$$min x'Ax$$



why does matrix $A$ need to be positive definite in order to have a global minimum?










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    It is not required. If $A=0$ then there is a global minimum. You need positive semi definite. Otherwise there is a direction in which you can produce values that are unbounded below.
    $endgroup$
    – copper.hat
    Mar 23 at 3:15











  • $begingroup$
    @copper.hat what is the requirement to have a unique solution?
    $endgroup$
    – JOHN
    Mar 23 at 3:19










  • $begingroup$
    Can you guess? Where is the derivative (of a convex function) zero?
    $endgroup$
    – copper.hat
    Mar 23 at 3:19











  • $begingroup$
    @copper.hat you would want $Ax=0$ has a solution, so the det𝐀 != 0. and second derivative to be negative. I don't know how could A be expressed to meet this.
    $endgroup$
    – JOHN
    Mar 23 at 3:28










  • $begingroup$
    What is the second derivative of $x mapsto x'Ax$??
    $endgroup$
    – copper.hat
    Mar 23 at 3:29















0












$begingroup$


When we optimize



$$min x'Ax$$



why does matrix $A$ need to be positive definite in order to have a global minimum?










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    It is not required. If $A=0$ then there is a global minimum. You need positive semi definite. Otherwise there is a direction in which you can produce values that are unbounded below.
    $endgroup$
    – copper.hat
    Mar 23 at 3:15











  • $begingroup$
    @copper.hat what is the requirement to have a unique solution?
    $endgroup$
    – JOHN
    Mar 23 at 3:19










  • $begingroup$
    Can you guess? Where is the derivative (of a convex function) zero?
    $endgroup$
    – copper.hat
    Mar 23 at 3:19











  • $begingroup$
    @copper.hat you would want $Ax=0$ has a solution, so the det𝐀 != 0. and second derivative to be negative. I don't know how could A be expressed to meet this.
    $endgroup$
    – JOHN
    Mar 23 at 3:28










  • $begingroup$
    What is the second derivative of $x mapsto x'Ax$??
    $endgroup$
    – copper.hat
    Mar 23 at 3:29













0












0








0





$begingroup$


When we optimize



$$min x'Ax$$



why does matrix $A$ need to be positive definite in order to have a global minimum?










share|cite|improve this question











$endgroup$




When we optimize



$$min x'Ax$$



why does matrix $A$ need to be positive definite in order to have a global minimum?







matrices optimization convex-optimization positive-definite quadratic-programming






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 23 at 9:22









Rodrigo de Azevedo

13.2k41962




13.2k41962










asked Mar 23 at 3:13









JOHNJOHN

183




183







  • 1




    $begingroup$
    It is not required. If $A=0$ then there is a global minimum. You need positive semi definite. Otherwise there is a direction in which you can produce values that are unbounded below.
    $endgroup$
    – copper.hat
    Mar 23 at 3:15











  • $begingroup$
    @copper.hat what is the requirement to have a unique solution?
    $endgroup$
    – JOHN
    Mar 23 at 3:19










  • $begingroup$
    Can you guess? Where is the derivative (of a convex function) zero?
    $endgroup$
    – copper.hat
    Mar 23 at 3:19











  • $begingroup$
    @copper.hat you would want $Ax=0$ has a solution, so the det𝐀 != 0. and second derivative to be negative. I don't know how could A be expressed to meet this.
    $endgroup$
    – JOHN
    Mar 23 at 3:28










  • $begingroup$
    What is the second derivative of $x mapsto x'Ax$??
    $endgroup$
    – copper.hat
    Mar 23 at 3:29












  • 1




    $begingroup$
    It is not required. If $A=0$ then there is a global minimum. You need positive semi definite. Otherwise there is a direction in which you can produce values that are unbounded below.
    $endgroup$
    – copper.hat
    Mar 23 at 3:15











  • $begingroup$
    @copper.hat what is the requirement to have a unique solution?
    $endgroup$
    – JOHN
    Mar 23 at 3:19










  • $begingroup$
    Can you guess? Where is the derivative (of a convex function) zero?
    $endgroup$
    – copper.hat
    Mar 23 at 3:19











  • $begingroup$
    @copper.hat you would want $Ax=0$ has a solution, so the det𝐀 != 0. and second derivative to be negative. I don't know how could A be expressed to meet this.
    $endgroup$
    – JOHN
    Mar 23 at 3:28










  • $begingroup$
    What is the second derivative of $x mapsto x'Ax$??
    $endgroup$
    – copper.hat
    Mar 23 at 3:29







1




1




$begingroup$
It is not required. If $A=0$ then there is a global minimum. You need positive semi definite. Otherwise there is a direction in which you can produce values that are unbounded below.
$endgroup$
– copper.hat
Mar 23 at 3:15





$begingroup$
It is not required. If $A=0$ then there is a global minimum. You need positive semi definite. Otherwise there is a direction in which you can produce values that are unbounded below.
$endgroup$
– copper.hat
Mar 23 at 3:15













$begingroup$
@copper.hat what is the requirement to have a unique solution?
$endgroup$
– JOHN
Mar 23 at 3:19




$begingroup$
@copper.hat what is the requirement to have a unique solution?
$endgroup$
– JOHN
Mar 23 at 3:19












$begingroup$
Can you guess? Where is the derivative (of a convex function) zero?
$endgroup$
– copper.hat
Mar 23 at 3:19





$begingroup$
Can you guess? Where is the derivative (of a convex function) zero?
$endgroup$
– copper.hat
Mar 23 at 3:19













$begingroup$
@copper.hat you would want $Ax=0$ has a solution, so the det𝐀 != 0. and second derivative to be negative. I don't know how could A be expressed to meet this.
$endgroup$
– JOHN
Mar 23 at 3:28




$begingroup$
@copper.hat you would want $Ax=0$ has a solution, so the det𝐀 != 0. and second derivative to be negative. I don't know how could A be expressed to meet this.
$endgroup$
– JOHN
Mar 23 at 3:28












$begingroup$
What is the second derivative of $x mapsto x'Ax$??
$endgroup$
– copper.hat
Mar 23 at 3:29




$begingroup$
What is the second derivative of $x mapsto x'Ax$??
$endgroup$
– copper.hat
Mar 23 at 3:29










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