A question about the homotopy. The 2019 Stack Overflow Developer Survey Results Are InA little question about homotopy equivalenceHomotopy equivalence an retractionsHomotopy for the complement when slightly thickening a subspace of $ℝ^n$Homology and Homotopy in the Plane IIQuestion about homotopic functions and homotopy classesProve that there is only one homotopy class of continuous functions from $X$ to $D$Homotopy 'diagrams' for Klein bottle and projective planeTwo questions about homotopy of pathsHomotopy ExerciseFree Homotopy of Loops

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A question about the homotopy.



The 2019 Stack Overflow Developer Survey Results Are InA little question about homotopy equivalenceHomotopy equivalence an retractionsHomotopy for the complement when slightly thickening a subspace of $ℝ^n$Homology and Homotopy in the Plane IIQuestion about homotopic functions and homotopy classesProve that there is only one homotopy class of continuous functions from $X$ to $D$Homotopy 'diagrams' for Klein bottle and projective planeTwo questions about homotopy of pathsHomotopy ExerciseFree Homotopy of Loops










0












$begingroup$


Recently, I learned the definition of homotopy, and had a question. In all continuous curves(in complex plane) with $a$ as the starting point and $b$ as the end point, if the two curves are homotopic are regarded as the same curve, how many such curves are there?



I would be very happy if someone could answer my question, since this is my first question.



Thank you very much!










share|cite|improve this question











$endgroup$
















    0












    $begingroup$


    Recently, I learned the definition of homotopy, and had a question. In all continuous curves(in complex plane) with $a$ as the starting point and $b$ as the end point, if the two curves are homotopic are regarded as the same curve, how many such curves are there?



    I would be very happy if someone could answer my question, since this is my first question.



    Thank you very much!










    share|cite|improve this question











    $endgroup$














      0












      0








      0





      $begingroup$


      Recently, I learned the definition of homotopy, and had a question. In all continuous curves(in complex plane) with $a$ as the starting point and $b$ as the end point, if the two curves are homotopic are regarded as the same curve, how many such curves are there?



      I would be very happy if someone could answer my question, since this is my first question.



      Thank you very much!










      share|cite|improve this question











      $endgroup$




      Recently, I learned the definition of homotopy, and had a question. In all continuous curves(in complex plane) with $a$ as the starting point and $b$ as the end point, if the two curves are homotopic are regarded as the same curve, how many such curves are there?



      I would be very happy if someone could answer my question, since this is my first question.



      Thank you very much!







      general-topology algebraic-topology homotopy-theory






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 23 at 4:58









      Thomas Shelby

      4,7362727




      4,7362727










      asked Mar 23 at 4:12









      Junjie YaoJunjie Yao

      1




      1




















          1 Answer
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          1












          $begingroup$

          There would be only one curve. Suppose $f$ and $g$ are two paths with the same initial and final points. Then define $H:Itimes Ito Bbb C$ by $H(x,t)=(1-t)f(x)+tg(x)$, where $I=[0,1]$. Clearly, $H(x,0)=f(x), H(x,1)=g(x), H(0,t)=f(0)=g(0), H(1,t)=f(1)=g(1)$. Can you check the continuity of $H$?






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            The above hint actually proves a stronger notion, called the path homotopy. Actually, any two continuous maps from a space $X$ to $Bbb C$ are homotopic.
            $endgroup$
            – Thomas Shelby
            Mar 23 at 5:03











          Your Answer





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          $begingroup$

          There would be only one curve. Suppose $f$ and $g$ are two paths with the same initial and final points. Then define $H:Itimes Ito Bbb C$ by $H(x,t)=(1-t)f(x)+tg(x)$, where $I=[0,1]$. Clearly, $H(x,0)=f(x), H(x,1)=g(x), H(0,t)=f(0)=g(0), H(1,t)=f(1)=g(1)$. Can you check the continuity of $H$?






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            The above hint actually proves a stronger notion, called the path homotopy. Actually, any two continuous maps from a space $X$ to $Bbb C$ are homotopic.
            $endgroup$
            – Thomas Shelby
            Mar 23 at 5:03















          1












          $begingroup$

          There would be only one curve. Suppose $f$ and $g$ are two paths with the same initial and final points. Then define $H:Itimes Ito Bbb C$ by $H(x,t)=(1-t)f(x)+tg(x)$, where $I=[0,1]$. Clearly, $H(x,0)=f(x), H(x,1)=g(x), H(0,t)=f(0)=g(0), H(1,t)=f(1)=g(1)$. Can you check the continuity of $H$?






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            The above hint actually proves a stronger notion, called the path homotopy. Actually, any two continuous maps from a space $X$ to $Bbb C$ are homotopic.
            $endgroup$
            – Thomas Shelby
            Mar 23 at 5:03













          1












          1








          1





          $begingroup$

          There would be only one curve. Suppose $f$ and $g$ are two paths with the same initial and final points. Then define $H:Itimes Ito Bbb C$ by $H(x,t)=(1-t)f(x)+tg(x)$, where $I=[0,1]$. Clearly, $H(x,0)=f(x), H(x,1)=g(x), H(0,t)=f(0)=g(0), H(1,t)=f(1)=g(1)$. Can you check the continuity of $H$?






          share|cite|improve this answer









          $endgroup$



          There would be only one curve. Suppose $f$ and $g$ are two paths with the same initial and final points. Then define $H:Itimes Ito Bbb C$ by $H(x,t)=(1-t)f(x)+tg(x)$, where $I=[0,1]$. Clearly, $H(x,0)=f(x), H(x,1)=g(x), H(0,t)=f(0)=g(0), H(1,t)=f(1)=g(1)$. Can you check the continuity of $H$?







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Mar 23 at 4:50









          Thomas ShelbyThomas Shelby

          4,7362727




          4,7362727











          • $begingroup$
            The above hint actually proves a stronger notion, called the path homotopy. Actually, any two continuous maps from a space $X$ to $Bbb C$ are homotopic.
            $endgroup$
            – Thomas Shelby
            Mar 23 at 5:03
















          • $begingroup$
            The above hint actually proves a stronger notion, called the path homotopy. Actually, any two continuous maps from a space $X$ to $Bbb C$ are homotopic.
            $endgroup$
            – Thomas Shelby
            Mar 23 at 5:03















          $begingroup$
          The above hint actually proves a stronger notion, called the path homotopy. Actually, any two continuous maps from a space $X$ to $Bbb C$ are homotopic.
          $endgroup$
          – Thomas Shelby
          Mar 23 at 5:03




          $begingroup$
          The above hint actually proves a stronger notion, called the path homotopy. Actually, any two continuous maps from a space $X$ to $Bbb C$ are homotopic.
          $endgroup$
          – Thomas Shelby
          Mar 23 at 5:03

















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