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Remove specific words in a string
What is the difference between String and string in C#?How do I iterate over the words of a string?How do I read / convert an InputStream into a String in Java?Extract filename and extension in BashHow to replace all occurrences of a string in JavaScriptHow to check whether a string contains a substring in JavaScript?Does Python have a string 'contains' substring method?How do I check if a string contains a specific word?How do I convert a String to an int in Java?Why is char[] preferred over String for passwords?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
Given a string = "test20190906.pdf", how can I get only "test.pdf" such that it removes the date from the string by using string.replace or remove ?
Considering the format will always be filename + date + .extension.
java string
add a comment |
Given a string = "test20190906.pdf", how can I get only "test.pdf" such that it removes the date from the string by using string.replace or remove ?
Considering the format will always be filename + date + .extension.
java string
2
Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.
– Sibgha
Mar 21 at 10:52
3
Is it just the date you want to remove or all numbers?
– Popeye
Mar 21 at 10:55
Will extension always be .pdf?
– Piro
Mar 21 at 12:54
@Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?
– Nicholas K
Mar 26 at 4:23
add a comment |
Given a string = "test20190906.pdf", how can I get only "test.pdf" such that it removes the date from the string by using string.replace or remove ?
Considering the format will always be filename + date + .extension.
java string
Given a string = "test20190906.pdf", how can I get only "test.pdf" such that it removes the date from the string by using string.replace or remove ?
Considering the format will always be filename + date + .extension.
java string
java string
edited Mar 21 at 11:29
Viper629
asked Mar 21 at 10:44
Viper629Viper629
505
505
2
Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.
– Sibgha
Mar 21 at 10:52
3
Is it just the date you want to remove or all numbers?
– Popeye
Mar 21 at 10:55
Will extension always be .pdf?
– Piro
Mar 21 at 12:54
@Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?
– Nicholas K
Mar 26 at 4:23
add a comment |
2
Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.
– Sibgha
Mar 21 at 10:52
3
Is it just the date you want to remove or all numbers?
– Popeye
Mar 21 at 10:55
Will extension always be .pdf?
– Piro
Mar 21 at 12:54
@Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?
– Nicholas K
Mar 26 at 4:23
2
2
Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.
– Sibgha
Mar 21 at 10:52
Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.
– Sibgha
Mar 21 at 10:52
3
3
Is it just the date you want to remove or all numbers?
– Popeye
Mar 21 at 10:55
Is it just the date you want to remove or all numbers?
– Popeye
Mar 21 at 10:55
Will extension always be .pdf?
– Piro
Mar 21 at 12:54
Will extension always be .pdf?
– Piro
Mar 21 at 12:54
@Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?
– Nicholas K
Mar 26 at 4:23
@Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?
– Nicholas K
Mar 26 at 4:23
add a comment |
9 Answers
9
active
oldest
votes
There are a lot of good answers, but I want present one more. It'll work if filename contains digits not only in date part. I assume that date is always appears before extension and has fixed length.
s.replaceAll("\d8\.pdf", ".pdf");
And if the file extension varies then you could do some additional work:
public static String removeDate(String s)
final String extension = s.substring(s.lastIndexOf("."));
final String pattern = "\d8\" + extension;
return s.replaceAll(pattern, extension);
public static void main(String args[])
System.out.println(removeDate("test20190101.pdf"));
System.out.println(removeDate("123123test20190101.txt"));
System.out.println(removeDate("123te11st20190101.csv"));
This can be done with the regexp only, but at the cost of readability.
2
Should escape the dot too:"\d8\.pdf"
– zwol
Mar 21 at 13:18
add a comment |
You can use a regex to remove consecutive digits that resemble a date in any format provided the filename is appended immediately by the date.
"test20190906.pdf".replaceAll("[0-9]8\.", "."));
1
What if you did something like"test20190906.pdf".replaceAll("[0-9]8\.", ".")because if there is any reason a file may have a number at then end other than the date (ieJavaFinalYear5<date>.txtthen you may want to preserve the number5. This way you can just select the date, and no other numbers.
– KGlasier
Mar 21 at 20:39
@KGlasier : Yeah your suggestion was much better. Thanks.
– Nicholas K
Mar 22 at 6:46
add a comment |
I see previous answers and that answers does not work if you got other numbers in file name for example: 01_test20190913.pdf
In that case solution will be
String file = "01_test20190913.pdf";
System.out.println(file.substring(0, file.length() - 12)+".pdf");
here i take the first part of string without last 12 characters and add ".pdf"
add a comment |
Assuming the date contains only numbers, you can use regex to replace numbers, e.g.:
String fileNameWithDate = "test20190906.pdf";
String fileName = fileNameWithDate.replaceAll("[0-9]+", ""));
System.out.println(fileName);
1
he want to remove just a date, not all numbers
– pavelbere
Mar 21 at 10:51
add a comment |
If the format of date is "yyyyMMdd" then I suggest go for the simplest solution as also given by @pavelbere. But this solution also assumes that the date always appends in the end of the filename.
String file = "test20190906.pdf";
String fileName = file.substring(0, file.length() - 12)+".pdf";
But this solution also assumes that the date always appends in the end of the filename.
– Sibgha
Mar 21 at 11:05
add a comment |
If you want to remove the dates only from the String then you can take a look on the solution (Assuming the date will come just before the .pdf) :
String fileNameWithDate = "te3st320190906.pdf";
StringBuilder sb = new StringBuilder(fileNameWithDate).replace(fileNameWithDate.indexOf(".pdf") - 8,
fileNameWithDate.indexOf(".pdf"), "");
System.out.println(sb.toString());
Output:
te3st3.pdf
What if the file name istest112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing.replaceAll("[0-9]+", "")in the end?
– Nicholas K
Mar 21 at 10:59
Sorry I forgot to put that I have the assumption that date will come just before the.pdf.
– Amit Bera
Mar 21 at 11:01
add a comment |
string name = "test20190906.pdf"
name.replaceAll("[0-9]","");
add a comment |
My approach would be to remove all numbers which are 8 digits long and are next to the last dot and replace them with a dot using the regex: (d8)(?!.*d.).
String filename = "filename12345678.pdf";
filename = filename.replaceAll("(\d8)(?!.*\d\.)\.", ".");
You can see this being used and an explanation of what it does here.
If the date can be different lengths then replace the 8 with a *, this enables the date to be any length.
add a comment |
An answer that doesn't use Regex:
For filename as the original string:
l = filename.split('.')
l[-2] = l[-2][:-8]
output = '.'.join(l)
This uses the fact that the last '.' will always precede the extension, so the 8 characters prior to this will be dates. As long as we remove those, and put the '.' back in, we have the filename regardless of extension, regardless of characters preceding it, without using Regular Expressions.
add a comment |
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9 Answers
9
active
oldest
votes
9 Answers
9
active
oldest
votes
active
oldest
votes
active
oldest
votes
There are a lot of good answers, but I want present one more. It'll work if filename contains digits not only in date part. I assume that date is always appears before extension and has fixed length.
s.replaceAll("\d8\.pdf", ".pdf");
And if the file extension varies then you could do some additional work:
public static String removeDate(String s)
final String extension = s.substring(s.lastIndexOf("."));
final String pattern = "\d8\" + extension;
return s.replaceAll(pattern, extension);
public static void main(String args[])
System.out.println(removeDate("test20190101.pdf"));
System.out.println(removeDate("123123test20190101.txt"));
System.out.println(removeDate("123te11st20190101.csv"));
This can be done with the regexp only, but at the cost of readability.
2
Should escape the dot too:"\d8\.pdf"
– zwol
Mar 21 at 13:18
add a comment |
There are a lot of good answers, but I want present one more. It'll work if filename contains digits not only in date part. I assume that date is always appears before extension and has fixed length.
s.replaceAll("\d8\.pdf", ".pdf");
And if the file extension varies then you could do some additional work:
public static String removeDate(String s)
final String extension = s.substring(s.lastIndexOf("."));
final String pattern = "\d8\" + extension;
return s.replaceAll(pattern, extension);
public static void main(String args[])
System.out.println(removeDate("test20190101.pdf"));
System.out.println(removeDate("123123test20190101.txt"));
System.out.println(removeDate("123te11st20190101.csv"));
This can be done with the regexp only, but at the cost of readability.
2
Should escape the dot too:"\d8\.pdf"
– zwol
Mar 21 at 13:18
add a comment |
There are a lot of good answers, but I want present one more. It'll work if filename contains digits not only in date part. I assume that date is always appears before extension and has fixed length.
s.replaceAll("\d8\.pdf", ".pdf");
And if the file extension varies then you could do some additional work:
public static String removeDate(String s)
final String extension = s.substring(s.lastIndexOf("."));
final String pattern = "\d8\" + extension;
return s.replaceAll(pattern, extension);
public static void main(String args[])
System.out.println(removeDate("test20190101.pdf"));
System.out.println(removeDate("123123test20190101.txt"));
System.out.println(removeDate("123te11st20190101.csv"));
This can be done with the regexp only, but at the cost of readability.
There are a lot of good answers, but I want present one more. It'll work if filename contains digits not only in date part. I assume that date is always appears before extension and has fixed length.
s.replaceAll("\d8\.pdf", ".pdf");
And if the file extension varies then you could do some additional work:
public static String removeDate(String s)
final String extension = s.substring(s.lastIndexOf("."));
final String pattern = "\d8\" + extension;
return s.replaceAll(pattern, extension);
public static void main(String args[])
System.out.println(removeDate("test20190101.pdf"));
System.out.println(removeDate("123123test20190101.txt"));
System.out.println(removeDate("123te11st20190101.csv"));
This can be done with the regexp only, but at the cost of readability.
edited Mar 22 at 3:21
answered Mar 21 at 10:57
Mikhail IlinykhMikhail Ilinykh
578210
578210
2
Should escape the dot too:"\d8\.pdf"
– zwol
Mar 21 at 13:18
add a comment |
2
Should escape the dot too:"\d8\.pdf"
– zwol
Mar 21 at 13:18
2
2
Should escape the dot too:
"\d8\.pdf"– zwol
Mar 21 at 13:18
Should escape the dot too:
"\d8\.pdf"– zwol
Mar 21 at 13:18
add a comment |
You can use a regex to remove consecutive digits that resemble a date in any format provided the filename is appended immediately by the date.
"test20190906.pdf".replaceAll("[0-9]8\.", "."));
1
What if you did something like"test20190906.pdf".replaceAll("[0-9]8\.", ".")because if there is any reason a file may have a number at then end other than the date (ieJavaFinalYear5<date>.txtthen you may want to preserve the number5. This way you can just select the date, and no other numbers.
– KGlasier
Mar 21 at 20:39
@KGlasier : Yeah your suggestion was much better. Thanks.
– Nicholas K
Mar 22 at 6:46
add a comment |
You can use a regex to remove consecutive digits that resemble a date in any format provided the filename is appended immediately by the date.
"test20190906.pdf".replaceAll("[0-9]8\.", "."));
1
What if you did something like"test20190906.pdf".replaceAll("[0-9]8\.", ".")because if there is any reason a file may have a number at then end other than the date (ieJavaFinalYear5<date>.txtthen you may want to preserve the number5. This way you can just select the date, and no other numbers.
– KGlasier
Mar 21 at 20:39
@KGlasier : Yeah your suggestion was much better. Thanks.
– Nicholas K
Mar 22 at 6:46
add a comment |
You can use a regex to remove consecutive digits that resemble a date in any format provided the filename is appended immediately by the date.
"test20190906.pdf".replaceAll("[0-9]8\.", "."));
You can use a regex to remove consecutive digits that resemble a date in any format provided the filename is appended immediately by the date.
"test20190906.pdf".replaceAll("[0-9]8\.", "."));
edited Mar 22 at 6:44
answered Mar 21 at 10:46
Nicholas KNicholas K
8,47271739
8,47271739
1
What if you did something like"test20190906.pdf".replaceAll("[0-9]8\.", ".")because if there is any reason a file may have a number at then end other than the date (ieJavaFinalYear5<date>.txtthen you may want to preserve the number5. This way you can just select the date, and no other numbers.
– KGlasier
Mar 21 at 20:39
@KGlasier : Yeah your suggestion was much better. Thanks.
– Nicholas K
Mar 22 at 6:46
add a comment |
1
What if you did something like"test20190906.pdf".replaceAll("[0-9]8\.", ".")because if there is any reason a file may have a number at then end other than the date (ieJavaFinalYear5<date>.txtthen you may want to preserve the number5. This way you can just select the date, and no other numbers.
– KGlasier
Mar 21 at 20:39
@KGlasier : Yeah your suggestion was much better. Thanks.
– Nicholas K
Mar 22 at 6:46
1
1
What if you did something like
"test20190906.pdf".replaceAll("[0-9]8\.", ".") because if there is any reason a file may have a number at then end other than the date (ie JavaFinalYear5<date>.txt then you may want to preserve the number 5. This way you can just select the date, and no other numbers.– KGlasier
Mar 21 at 20:39
What if you did something like
"test20190906.pdf".replaceAll("[0-9]8\.", ".") because if there is any reason a file may have a number at then end other than the date (ie JavaFinalYear5<date>.txt then you may want to preserve the number 5. This way you can just select the date, and no other numbers.– KGlasier
Mar 21 at 20:39
@KGlasier : Yeah your suggestion was much better. Thanks.
– Nicholas K
Mar 22 at 6:46
@KGlasier : Yeah your suggestion was much better. Thanks.
– Nicholas K
Mar 22 at 6:46
add a comment |
I see previous answers and that answers does not work if you got other numbers in file name for example: 01_test20190913.pdf
In that case solution will be
String file = "01_test20190913.pdf";
System.out.println(file.substring(0, file.length() - 12)+".pdf");
here i take the first part of string without last 12 characters and add ".pdf"
add a comment |
I see previous answers and that answers does not work if you got other numbers in file name for example: 01_test20190913.pdf
In that case solution will be
String file = "01_test20190913.pdf";
System.out.println(file.substring(0, file.length() - 12)+".pdf");
here i take the first part of string without last 12 characters and add ".pdf"
add a comment |
I see previous answers and that answers does not work if you got other numbers in file name for example: 01_test20190913.pdf
In that case solution will be
String file = "01_test20190913.pdf";
System.out.println(file.substring(0, file.length() - 12)+".pdf");
here i take the first part of string without last 12 characters and add ".pdf"
I see previous answers and that answers does not work if you got other numbers in file name for example: 01_test20190913.pdf
In that case solution will be
String file = "01_test20190913.pdf";
System.out.println(file.substring(0, file.length() - 12)+".pdf");
here i take the first part of string without last 12 characters and add ".pdf"
edited Mar 21 at 16:57
answered Mar 21 at 10:49
pavelberepavelbere
454110
454110
add a comment |
add a comment |
Assuming the date contains only numbers, you can use regex to replace numbers, e.g.:
String fileNameWithDate = "test20190906.pdf";
String fileName = fileNameWithDate.replaceAll("[0-9]+", ""));
System.out.println(fileName);
1
he want to remove just a date, not all numbers
– pavelbere
Mar 21 at 10:51
add a comment |
Assuming the date contains only numbers, you can use regex to replace numbers, e.g.:
String fileNameWithDate = "test20190906.pdf";
String fileName = fileNameWithDate.replaceAll("[0-9]+", ""));
System.out.println(fileName);
1
he want to remove just a date, not all numbers
– pavelbere
Mar 21 at 10:51
add a comment |
Assuming the date contains only numbers, you can use regex to replace numbers, e.g.:
String fileNameWithDate = "test20190906.pdf";
String fileName = fileNameWithDate.replaceAll("[0-9]+", ""));
System.out.println(fileName);
Assuming the date contains only numbers, you can use regex to replace numbers, e.g.:
String fileNameWithDate = "test20190906.pdf";
String fileName = fileNameWithDate.replaceAll("[0-9]+", ""));
System.out.println(fileName);
edited Mar 21 at 10:52
answered Mar 21 at 10:46
Darshan MehtaDarshan Mehta
23.6k32955
23.6k32955
1
he want to remove just a date, not all numbers
– pavelbere
Mar 21 at 10:51
add a comment |
1
he want to remove just a date, not all numbers
– pavelbere
Mar 21 at 10:51
1
1
he want to remove just a date, not all numbers
– pavelbere
Mar 21 at 10:51
he want to remove just a date, not all numbers
– pavelbere
Mar 21 at 10:51
add a comment |
If the format of date is "yyyyMMdd" then I suggest go for the simplest solution as also given by @pavelbere. But this solution also assumes that the date always appends in the end of the filename.
String file = "test20190906.pdf";
String fileName = file.substring(0, file.length() - 12)+".pdf";
But this solution also assumes that the date always appends in the end of the filename.
– Sibgha
Mar 21 at 11:05
add a comment |
If the format of date is "yyyyMMdd" then I suggest go for the simplest solution as also given by @pavelbere. But this solution also assumes that the date always appends in the end of the filename.
String file = "test20190906.pdf";
String fileName = file.substring(0, file.length() - 12)+".pdf";
But this solution also assumes that the date always appends in the end of the filename.
– Sibgha
Mar 21 at 11:05
add a comment |
If the format of date is "yyyyMMdd" then I suggest go for the simplest solution as also given by @pavelbere. But this solution also assumes that the date always appends in the end of the filename.
String file = "test20190906.pdf";
String fileName = file.substring(0, file.length() - 12)+".pdf";
If the format of date is "yyyyMMdd" then I suggest go for the simplest solution as also given by @pavelbere. But this solution also assumes that the date always appends in the end of the filename.
String file = "test20190906.pdf";
String fileName = file.substring(0, file.length() - 12)+".pdf";
answered Mar 21 at 10:57
SibghaSibgha
1587
1587
But this solution also assumes that the date always appends in the end of the filename.
– Sibgha
Mar 21 at 11:05
add a comment |
But this solution also assumes that the date always appends in the end of the filename.
– Sibgha
Mar 21 at 11:05
But this solution also assumes that the date always appends in the end of the filename.– Sibgha
Mar 21 at 11:05
But this solution also assumes that the date always appends in the end of the filename.– Sibgha
Mar 21 at 11:05
add a comment |
If you want to remove the dates only from the String then you can take a look on the solution (Assuming the date will come just before the .pdf) :
String fileNameWithDate = "te3st320190906.pdf";
StringBuilder sb = new StringBuilder(fileNameWithDate).replace(fileNameWithDate.indexOf(".pdf") - 8,
fileNameWithDate.indexOf(".pdf"), "");
System.out.println(sb.toString());
Output:
te3st3.pdf
What if the file name istest112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing.replaceAll("[0-9]+", "")in the end?
– Nicholas K
Mar 21 at 10:59
Sorry I forgot to put that I have the assumption that date will come just before the.pdf.
– Amit Bera
Mar 21 at 11:01
add a comment |
If you want to remove the dates only from the String then you can take a look on the solution (Assuming the date will come just before the .pdf) :
String fileNameWithDate = "te3st320190906.pdf";
StringBuilder sb = new StringBuilder(fileNameWithDate).replace(fileNameWithDate.indexOf(".pdf") - 8,
fileNameWithDate.indexOf(".pdf"), "");
System.out.println(sb.toString());
Output:
te3st3.pdf
What if the file name istest112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing.replaceAll("[0-9]+", "")in the end?
– Nicholas K
Mar 21 at 10:59
Sorry I forgot to put that I have the assumption that date will come just before the.pdf.
– Amit Bera
Mar 21 at 11:01
add a comment |
If you want to remove the dates only from the String then you can take a look on the solution (Assuming the date will come just before the .pdf) :
String fileNameWithDate = "te3st320190906.pdf";
StringBuilder sb = new StringBuilder(fileNameWithDate).replace(fileNameWithDate.indexOf(".pdf") - 8,
fileNameWithDate.indexOf(".pdf"), "");
System.out.println(sb.toString());
Output:
te3st3.pdf
If you want to remove the dates only from the String then you can take a look on the solution (Assuming the date will come just before the .pdf) :
String fileNameWithDate = "te3st320190906.pdf";
StringBuilder sb = new StringBuilder(fileNameWithDate).replace(fileNameWithDate.indexOf(".pdf") - 8,
fileNameWithDate.indexOf(".pdf"), "");
System.out.println(sb.toString());
Output:
te3st3.pdf
edited Mar 21 at 11:02
answered Mar 21 at 10:54
Amit BeraAmit Bera
4,2411630
4,2411630
What if the file name istest112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing.replaceAll("[0-9]+", "")in the end?
– Nicholas K
Mar 21 at 10:59
Sorry I forgot to put that I have the assumption that date will come just before the.pdf.
– Amit Bera
Mar 21 at 11:01
add a comment |
What if the file name istest112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing.replaceAll("[0-9]+", "")in the end?
– Nicholas K
Mar 21 at 10:59
Sorry I forgot to put that I have the assumption that date will come just before the.pdf.
– Amit Bera
Mar 21 at 11:01
What if the file name is
test112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing .replaceAll("[0-9]+", "") in the end?– Nicholas K
Mar 21 at 10:59
What if the file name is
test112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing .replaceAll("[0-9]+", "") in the end?– Nicholas K
Mar 21 at 10:59
Sorry I forgot to put that I have the assumption that date will come just before the
.pdf .– Amit Bera
Mar 21 at 11:01
Sorry I forgot to put that I have the assumption that date will come just before the
.pdf .– Amit Bera
Mar 21 at 11:01
add a comment |
string name = "test20190906.pdf"
name.replaceAll("[0-9]","");
add a comment |
string name = "test20190906.pdf"
name.replaceAll("[0-9]","");
add a comment |
string name = "test20190906.pdf"
name.replaceAll("[0-9]","");
string name = "test20190906.pdf"
name.replaceAll("[0-9]","");
answered Mar 21 at 11:13
pamithapamitha
3715
3715
add a comment |
add a comment |
My approach would be to remove all numbers which are 8 digits long and are next to the last dot and replace them with a dot using the regex: (d8)(?!.*d.).
String filename = "filename12345678.pdf";
filename = filename.replaceAll("(\d8)(?!.*\d\.)\.", ".");
You can see this being used and an explanation of what it does here.
If the date can be different lengths then replace the 8 with a *, this enables the date to be any length.
add a comment |
My approach would be to remove all numbers which are 8 digits long and are next to the last dot and replace them with a dot using the regex: (d8)(?!.*d.).
String filename = "filename12345678.pdf";
filename = filename.replaceAll("(\d8)(?!.*\d\.)\.", ".");
You can see this being used and an explanation of what it does here.
If the date can be different lengths then replace the 8 with a *, this enables the date to be any length.
add a comment |
My approach would be to remove all numbers which are 8 digits long and are next to the last dot and replace them with a dot using the regex: (d8)(?!.*d.).
String filename = "filename12345678.pdf";
filename = filename.replaceAll("(\d8)(?!.*\d\.)\.", ".");
You can see this being used and an explanation of what it does here.
If the date can be different lengths then replace the 8 with a *, this enables the date to be any length.
My approach would be to remove all numbers which are 8 digits long and are next to the last dot and replace them with a dot using the regex: (d8)(?!.*d.).
String filename = "filename12345678.pdf";
filename = filename.replaceAll("(\d8)(?!.*\d\.)\.", ".");
You can see this being used and an explanation of what it does here.
If the date can be different lengths then replace the 8 with a *, this enables the date to be any length.
edited Mar 21 at 11:44
answered Mar 21 at 11:39
Toby SmithToby Smith
4231715
4231715
add a comment |
add a comment |
An answer that doesn't use Regex:
For filename as the original string:
l = filename.split('.')
l[-2] = l[-2][:-8]
output = '.'.join(l)
This uses the fact that the last '.' will always precede the extension, so the 8 characters prior to this will be dates. As long as we remove those, and put the '.' back in, we have the filename regardless of extension, regardless of characters preceding it, without using Regular Expressions.
add a comment |
An answer that doesn't use Regex:
For filename as the original string:
l = filename.split('.')
l[-2] = l[-2][:-8]
output = '.'.join(l)
This uses the fact that the last '.' will always precede the extension, so the 8 characters prior to this will be dates. As long as we remove those, and put the '.' back in, we have the filename regardless of extension, regardless of characters preceding it, without using Regular Expressions.
add a comment |
An answer that doesn't use Regex:
For filename as the original string:
l = filename.split('.')
l[-2] = l[-2][:-8]
output = '.'.join(l)
This uses the fact that the last '.' will always precede the extension, so the 8 characters prior to this will be dates. As long as we remove those, and put the '.' back in, we have the filename regardless of extension, regardless of characters preceding it, without using Regular Expressions.
An answer that doesn't use Regex:
For filename as the original string:
l = filename.split('.')
l[-2] = l[-2][:-8]
output = '.'.join(l)
This uses the fact that the last '.' will always precede the extension, so the 8 characters prior to this will be dates. As long as we remove those, and put the '.' back in, we have the filename regardless of extension, regardless of characters preceding it, without using Regular Expressions.
answered Mar 21 at 15:24
Jim EisenbergJim Eisenberg
17118
17118
add a comment |
add a comment |
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2
Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.
– Sibgha
Mar 21 at 10:52
3
Is it just the date you want to remove or all numbers?
– Popeye
Mar 21 at 10:55
Will extension always be .pdf?
– Piro
Mar 21 at 12:54
@Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?
– Nicholas K
Mar 26 at 4:23