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Remove specific words in a string


What is the difference between String and string in C#?How do I iterate over the words of a string?How do I read / convert an InputStream into a String in Java?Extract filename and extension in BashHow to replace all occurrences of a string in JavaScriptHow to check whether a string contains a substring in JavaScript?Does Python have a string 'contains' substring method?How do I check if a string contains a specific word?How do I convert a String to an int in Java?Why is char[] preferred over String for passwords?






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7















Given a string = "test20190906.pdf", how can I get only "test.pdf" such that it removes the date from the string by using string.replace or remove ?



Considering the format will always be filename + date + .extension.










share|improve this question



















  • 2





    Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.

    – Sibgha
    Mar 21 at 10:52






  • 3





    Is it just the date you want to remove or all numbers?

    – Popeye
    Mar 21 at 10:55











  • Will extension always be .pdf?

    – Piro
    Mar 21 at 12:54











  • @Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?

    – Nicholas K
    Mar 26 at 4:23

















7















Given a string = "test20190906.pdf", how can I get only "test.pdf" such that it removes the date from the string by using string.replace or remove ?



Considering the format will always be filename + date + .extension.










share|improve this question



















  • 2





    Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.

    – Sibgha
    Mar 21 at 10:52






  • 3





    Is it just the date you want to remove or all numbers?

    – Popeye
    Mar 21 at 10:55











  • Will extension always be .pdf?

    – Piro
    Mar 21 at 12:54











  • @Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?

    – Nicholas K
    Mar 26 at 4:23













7












7








7


1






Given a string = "test20190906.pdf", how can I get only "test.pdf" such that it removes the date from the string by using string.replace or remove ?



Considering the format will always be filename + date + .extension.










share|improve this question
















Given a string = "test20190906.pdf", how can I get only "test.pdf" such that it removes the date from the string by using string.replace or remove ?



Considering the format will always be filename + date + .extension.







java string






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 21 at 11:29







Viper629

















asked Mar 21 at 10:44









Viper629Viper629

505




505







  • 2





    Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.

    – Sibgha
    Mar 21 at 10:52






  • 3





    Is it just the date you want to remove or all numbers?

    – Popeye
    Mar 21 at 10:55











  • Will extension always be .pdf?

    – Piro
    Mar 21 at 12:54











  • @Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?

    – Nicholas K
    Mar 26 at 4:23












  • 2





    Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.

    – Sibgha
    Mar 21 at 10:52






  • 3





    Is it just the date you want to remove or all numbers?

    – Popeye
    Mar 21 at 10:55











  • Will extension always be .pdf?

    – Piro
    Mar 21 at 12:54











  • @Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?

    – Nicholas K
    Mar 26 at 4:23







2




2





Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.

– Sibgha
Mar 21 at 10:52





Consider mentioning the exact format of the date/time in the file name. That will help produce better solutions.

– Sibgha
Mar 21 at 10:52




3




3





Is it just the date you want to remove or all numbers?

– Popeye
Mar 21 at 10:55





Is it just the date you want to remove or all numbers?

– Popeye
Mar 21 at 10:55













Will extension always be .pdf?

– Piro
Mar 21 at 12:54





Will extension always be .pdf?

– Piro
Mar 21 at 12:54













@Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?

– Nicholas K
Mar 26 at 4:23





@Viper629 - Did any answer work for you? If yes do consider accepting/upvoting them. What should I do when someone answers my question?

– Nicholas K
Mar 26 at 4:23












9 Answers
9






active

oldest

votes


















4














There are a lot of good answers, but I want present one more. It'll work if filename contains digits not only in date part. I assume that date is always appears before extension and has fixed length.



s.replaceAll("\d8\.pdf", ".pdf");


And if the file extension varies then you could do some additional work:



public static String removeDate(String s) 
final String extension = s.substring(s.lastIndexOf("."));
final String pattern = "\d8\" + extension;

return s.replaceAll(pattern, extension);


public static void main(String args[])

System.out.println(removeDate("test20190101.pdf"));
System.out.println(removeDate("123123test20190101.txt"));
System.out.println(removeDate("123te11st20190101.csv"));



This can be done with the regexp only, but at the cost of readability.






share|improve this answer




















  • 2





    Should escape the dot too: "\d8\.pdf"

    – zwol
    Mar 21 at 13:18


















10














You can use a regex to remove consecutive digits that resemble a date in any format provided the filename is appended immediately by the date.



"test20190906.pdf".replaceAll("[0-9]8\.", "."));





share|improve this answer




















  • 1





    What if you did something like "test20190906.pdf".replaceAll("[0-9]8\.", ".") because if there is any reason a file may have a number at then end other than the date (ie JavaFinalYear5<date>.txt then you may want to preserve the number 5. This way you can just select the date, and no other numbers.

    – KGlasier
    Mar 21 at 20:39











  • @KGlasier : Yeah your suggestion was much better. Thanks.

    – Nicholas K
    Mar 22 at 6:46


















5














I see previous answers and that answers does not work if you got other numbers in file name for example: 01_test20190913.pdf



In that case solution will be



String file = "01_test20190913.pdf";
System.out.println(file.substring(0, file.length() - 12)+".pdf");


here i take the first part of string without last 12 characters and add ".pdf"






share|improve this answer
































    1














    Assuming the date contains only numbers, you can use regex to replace numbers, e.g.:



    String fileNameWithDate = "test20190906.pdf";
    String fileName = fileNameWithDate.replaceAll("[0-9]+", ""));
    System.out.println(fileName);





    share|improve this answer




















    • 1





      he want to remove just a date, not all numbers

      – pavelbere
      Mar 21 at 10:51


















    1














    If the format of date is "yyyyMMdd" then I suggest go for the simplest solution as also given by @pavelbere. But this solution also assumes that the date always appends in the end of the filename.



    String file = "test20190906.pdf"; 
    String fileName = file.substring(0, file.length() - 12)+".pdf";





    share|improve this answer























    • But this solution also assumes that the date always appends in the end of the filename.

      – Sibgha
      Mar 21 at 11:05



















    0














    If you want to remove the dates only from the String then you can take a look on the solution (Assuming the date will come just before the .pdf) :



     String fileNameWithDate = "te3st320190906.pdf";

    StringBuilder sb = new StringBuilder(fileNameWithDate).replace(fileNameWithDate.indexOf(".pdf") - 8,
    fileNameWithDate.indexOf(".pdf"), "");
    System.out.println(sb.toString());


    Output:



    te3st3.pdf





    share|improve this answer

























    • What if the file name is test112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing .replaceAll("[0-9]+", "") in the end?

      – Nicholas K
      Mar 21 at 10:59












    • Sorry I forgot to put that I have the assumption that date will come just before the .pdf .

      – Amit Bera
      Mar 21 at 11:01


















    0














    string name = "test20190906.pdf"
    name.replaceAll("[0-9]","");





    share|improve this answer






























      0














      My approach would be to remove all numbers which are 8 digits long and are next to the last dot and replace them with a dot using the regex: (d8)(?!.*d.).



      String filename = "filename12345678.pdf";
      filename = filename.replaceAll("(\d8)(?!.*\d\.)\.", ".");


      You can see this being used and an explanation of what it does here.



      If the date can be different lengths then replace the 8 with a *, this enables the date to be any length.






      share|improve this answer
































        0














        An answer that doesn't use Regex:
        For filename as the original string:



        l = filename.split('.')
        l[-2] = l[-2][:-8]
        output = '.'.join(l)


        This uses the fact that the last '.' will always precede the extension, so the 8 characters prior to this will be dates. As long as we remove those, and put the '.' back in, we have the filename regardless of extension, regardless of characters preceding it, without using Regular Expressions.






        share|improve this answer























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          9 Answers
          9






          active

          oldest

          votes








          9 Answers
          9






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          4














          There are a lot of good answers, but I want present one more. It'll work if filename contains digits not only in date part. I assume that date is always appears before extension and has fixed length.



          s.replaceAll("\d8\.pdf", ".pdf");


          And if the file extension varies then you could do some additional work:



          public static String removeDate(String s) 
          final String extension = s.substring(s.lastIndexOf("."));
          final String pattern = "\d8\" + extension;

          return s.replaceAll(pattern, extension);


          public static void main(String args[])

          System.out.println(removeDate("test20190101.pdf"));
          System.out.println(removeDate("123123test20190101.txt"));
          System.out.println(removeDate("123te11st20190101.csv"));



          This can be done with the regexp only, but at the cost of readability.






          share|improve this answer




















          • 2





            Should escape the dot too: "\d8\.pdf"

            – zwol
            Mar 21 at 13:18















          4














          There are a lot of good answers, but I want present one more. It'll work if filename contains digits not only in date part. I assume that date is always appears before extension and has fixed length.



          s.replaceAll("\d8\.pdf", ".pdf");


          And if the file extension varies then you could do some additional work:



          public static String removeDate(String s) 
          final String extension = s.substring(s.lastIndexOf("."));
          final String pattern = "\d8\" + extension;

          return s.replaceAll(pattern, extension);


          public static void main(String args[])

          System.out.println(removeDate("test20190101.pdf"));
          System.out.println(removeDate("123123test20190101.txt"));
          System.out.println(removeDate("123te11st20190101.csv"));



          This can be done with the regexp only, but at the cost of readability.






          share|improve this answer




















          • 2





            Should escape the dot too: "\d8\.pdf"

            – zwol
            Mar 21 at 13:18













          4












          4








          4







          There are a lot of good answers, but I want present one more. It'll work if filename contains digits not only in date part. I assume that date is always appears before extension and has fixed length.



          s.replaceAll("\d8\.pdf", ".pdf");


          And if the file extension varies then you could do some additional work:



          public static String removeDate(String s) 
          final String extension = s.substring(s.lastIndexOf("."));
          final String pattern = "\d8\" + extension;

          return s.replaceAll(pattern, extension);


          public static void main(String args[])

          System.out.println(removeDate("test20190101.pdf"));
          System.out.println(removeDate("123123test20190101.txt"));
          System.out.println(removeDate("123te11st20190101.csv"));



          This can be done with the regexp only, but at the cost of readability.






          share|improve this answer















          There are a lot of good answers, but I want present one more. It'll work if filename contains digits not only in date part. I assume that date is always appears before extension and has fixed length.



          s.replaceAll("\d8\.pdf", ".pdf");


          And if the file extension varies then you could do some additional work:



          public static String removeDate(String s) 
          final String extension = s.substring(s.lastIndexOf("."));
          final String pattern = "\d8\" + extension;

          return s.replaceAll(pattern, extension);


          public static void main(String args[])

          System.out.println(removeDate("test20190101.pdf"));
          System.out.println(removeDate("123123test20190101.txt"));
          System.out.println(removeDate("123te11st20190101.csv"));



          This can be done with the regexp only, but at the cost of readability.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 22 at 3:21

























          answered Mar 21 at 10:57









          Mikhail IlinykhMikhail Ilinykh

          578210




          578210







          • 2





            Should escape the dot too: "\d8\.pdf"

            – zwol
            Mar 21 at 13:18












          • 2





            Should escape the dot too: "\d8\.pdf"

            – zwol
            Mar 21 at 13:18







          2




          2





          Should escape the dot too: "\d8\.pdf"

          – zwol
          Mar 21 at 13:18





          Should escape the dot too: "\d8\.pdf"

          – zwol
          Mar 21 at 13:18













          10














          You can use a regex to remove consecutive digits that resemble a date in any format provided the filename is appended immediately by the date.



          "test20190906.pdf".replaceAll("[0-9]8\.", "."));





          share|improve this answer




















          • 1





            What if you did something like "test20190906.pdf".replaceAll("[0-9]8\.", ".") because if there is any reason a file may have a number at then end other than the date (ie JavaFinalYear5<date>.txt then you may want to preserve the number 5. This way you can just select the date, and no other numbers.

            – KGlasier
            Mar 21 at 20:39











          • @KGlasier : Yeah your suggestion was much better. Thanks.

            – Nicholas K
            Mar 22 at 6:46















          10














          You can use a regex to remove consecutive digits that resemble a date in any format provided the filename is appended immediately by the date.



          "test20190906.pdf".replaceAll("[0-9]8\.", "."));





          share|improve this answer




















          • 1





            What if you did something like "test20190906.pdf".replaceAll("[0-9]8\.", ".") because if there is any reason a file may have a number at then end other than the date (ie JavaFinalYear5<date>.txt then you may want to preserve the number 5. This way you can just select the date, and no other numbers.

            – KGlasier
            Mar 21 at 20:39











          • @KGlasier : Yeah your suggestion was much better. Thanks.

            – Nicholas K
            Mar 22 at 6:46













          10












          10








          10







          You can use a regex to remove consecutive digits that resemble a date in any format provided the filename is appended immediately by the date.



          "test20190906.pdf".replaceAll("[0-9]8\.", "."));





          share|improve this answer















          You can use a regex to remove consecutive digits that resemble a date in any format provided the filename is appended immediately by the date.



          "test20190906.pdf".replaceAll("[0-9]8\.", "."));






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 22 at 6:44

























          answered Mar 21 at 10:46









          Nicholas KNicholas K

          8,47271739




          8,47271739







          • 1





            What if you did something like "test20190906.pdf".replaceAll("[0-9]8\.", ".") because if there is any reason a file may have a number at then end other than the date (ie JavaFinalYear5<date>.txt then you may want to preserve the number 5. This way you can just select the date, and no other numbers.

            – KGlasier
            Mar 21 at 20:39











          • @KGlasier : Yeah your suggestion was much better. Thanks.

            – Nicholas K
            Mar 22 at 6:46












          • 1





            What if you did something like "test20190906.pdf".replaceAll("[0-9]8\.", ".") because if there is any reason a file may have a number at then end other than the date (ie JavaFinalYear5<date>.txt then you may want to preserve the number 5. This way you can just select the date, and no other numbers.

            – KGlasier
            Mar 21 at 20:39











          • @KGlasier : Yeah your suggestion was much better. Thanks.

            – Nicholas K
            Mar 22 at 6:46







          1




          1





          What if you did something like "test20190906.pdf".replaceAll("[0-9]8\.", ".") because if there is any reason a file may have a number at then end other than the date (ie JavaFinalYear5<date>.txt then you may want to preserve the number 5. This way you can just select the date, and no other numbers.

          – KGlasier
          Mar 21 at 20:39





          What if you did something like "test20190906.pdf".replaceAll("[0-9]8\.", ".") because if there is any reason a file may have a number at then end other than the date (ie JavaFinalYear5<date>.txt then you may want to preserve the number 5. This way you can just select the date, and no other numbers.

          – KGlasier
          Mar 21 at 20:39













          @KGlasier : Yeah your suggestion was much better. Thanks.

          – Nicholas K
          Mar 22 at 6:46





          @KGlasier : Yeah your suggestion was much better. Thanks.

          – Nicholas K
          Mar 22 at 6:46











          5














          I see previous answers and that answers does not work if you got other numbers in file name for example: 01_test20190913.pdf



          In that case solution will be



          String file = "01_test20190913.pdf";
          System.out.println(file.substring(0, file.length() - 12)+".pdf");


          here i take the first part of string without last 12 characters and add ".pdf"






          share|improve this answer





























            5














            I see previous answers and that answers does not work if you got other numbers in file name for example: 01_test20190913.pdf



            In that case solution will be



            String file = "01_test20190913.pdf";
            System.out.println(file.substring(0, file.length() - 12)+".pdf");


            here i take the first part of string without last 12 characters and add ".pdf"






            share|improve this answer



























              5












              5








              5







              I see previous answers and that answers does not work if you got other numbers in file name for example: 01_test20190913.pdf



              In that case solution will be



              String file = "01_test20190913.pdf";
              System.out.println(file.substring(0, file.length() - 12)+".pdf");


              here i take the first part of string without last 12 characters and add ".pdf"






              share|improve this answer















              I see previous answers and that answers does not work if you got other numbers in file name for example: 01_test20190913.pdf



              In that case solution will be



              String file = "01_test20190913.pdf";
              System.out.println(file.substring(0, file.length() - 12)+".pdf");


              here i take the first part of string without last 12 characters and add ".pdf"







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Mar 21 at 16:57

























              answered Mar 21 at 10:49









              pavelberepavelbere

              454110




              454110





















                  1














                  Assuming the date contains only numbers, you can use regex to replace numbers, e.g.:



                  String fileNameWithDate = "test20190906.pdf";
                  String fileName = fileNameWithDate.replaceAll("[0-9]+", ""));
                  System.out.println(fileName);





                  share|improve this answer




















                  • 1





                    he want to remove just a date, not all numbers

                    – pavelbere
                    Mar 21 at 10:51















                  1














                  Assuming the date contains only numbers, you can use regex to replace numbers, e.g.:



                  String fileNameWithDate = "test20190906.pdf";
                  String fileName = fileNameWithDate.replaceAll("[0-9]+", ""));
                  System.out.println(fileName);





                  share|improve this answer




















                  • 1





                    he want to remove just a date, not all numbers

                    – pavelbere
                    Mar 21 at 10:51













                  1












                  1








                  1







                  Assuming the date contains only numbers, you can use regex to replace numbers, e.g.:



                  String fileNameWithDate = "test20190906.pdf";
                  String fileName = fileNameWithDate.replaceAll("[0-9]+", ""));
                  System.out.println(fileName);





                  share|improve this answer















                  Assuming the date contains only numbers, you can use regex to replace numbers, e.g.:



                  String fileNameWithDate = "test20190906.pdf";
                  String fileName = fileNameWithDate.replaceAll("[0-9]+", ""));
                  System.out.println(fileName);






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Mar 21 at 10:52

























                  answered Mar 21 at 10:46









                  Darshan MehtaDarshan Mehta

                  23.6k32955




                  23.6k32955







                  • 1





                    he want to remove just a date, not all numbers

                    – pavelbere
                    Mar 21 at 10:51












                  • 1





                    he want to remove just a date, not all numbers

                    – pavelbere
                    Mar 21 at 10:51







                  1




                  1





                  he want to remove just a date, not all numbers

                  – pavelbere
                  Mar 21 at 10:51





                  he want to remove just a date, not all numbers

                  – pavelbere
                  Mar 21 at 10:51











                  1














                  If the format of date is "yyyyMMdd" then I suggest go for the simplest solution as also given by @pavelbere. But this solution also assumes that the date always appends in the end of the filename.



                  String file = "test20190906.pdf"; 
                  String fileName = file.substring(0, file.length() - 12)+".pdf";





                  share|improve this answer























                  • But this solution also assumes that the date always appends in the end of the filename.

                    – Sibgha
                    Mar 21 at 11:05
















                  1














                  If the format of date is "yyyyMMdd" then I suggest go for the simplest solution as also given by @pavelbere. But this solution also assumes that the date always appends in the end of the filename.



                  String file = "test20190906.pdf"; 
                  String fileName = file.substring(0, file.length() - 12)+".pdf";





                  share|improve this answer























                  • But this solution also assumes that the date always appends in the end of the filename.

                    – Sibgha
                    Mar 21 at 11:05














                  1












                  1








                  1







                  If the format of date is "yyyyMMdd" then I suggest go for the simplest solution as also given by @pavelbere. But this solution also assumes that the date always appends in the end of the filename.



                  String file = "test20190906.pdf"; 
                  String fileName = file.substring(0, file.length() - 12)+".pdf";





                  share|improve this answer













                  If the format of date is "yyyyMMdd" then I suggest go for the simplest solution as also given by @pavelbere. But this solution also assumes that the date always appends in the end of the filename.



                  String file = "test20190906.pdf"; 
                  String fileName = file.substring(0, file.length() - 12)+".pdf";






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 21 at 10:57









                  SibghaSibgha

                  1587




                  1587












                  • But this solution also assumes that the date always appends in the end of the filename.

                    – Sibgha
                    Mar 21 at 11:05


















                  • But this solution also assumes that the date always appends in the end of the filename.

                    – Sibgha
                    Mar 21 at 11:05

















                  But this solution also assumes that the date always appends in the end of the filename.

                  – Sibgha
                  Mar 21 at 11:05






                  But this solution also assumes that the date always appends in the end of the filename.

                  – Sibgha
                  Mar 21 at 11:05












                  0














                  If you want to remove the dates only from the String then you can take a look on the solution (Assuming the date will come just before the .pdf) :



                   String fileNameWithDate = "te3st320190906.pdf";

                  StringBuilder sb = new StringBuilder(fileNameWithDate).replace(fileNameWithDate.indexOf(".pdf") - 8,
                  fileNameWithDate.indexOf(".pdf"), "");
                  System.out.println(sb.toString());


                  Output:



                  te3st3.pdf





                  share|improve this answer

























                  • What if the file name is test112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing .replaceAll("[0-9]+", "") in the end?

                    – Nicholas K
                    Mar 21 at 10:59












                  • Sorry I forgot to put that I have the assumption that date will come just before the .pdf .

                    – Amit Bera
                    Mar 21 at 11:01















                  0














                  If you want to remove the dates only from the String then you can take a look on the solution (Assuming the date will come just before the .pdf) :



                   String fileNameWithDate = "te3st320190906.pdf";

                  StringBuilder sb = new StringBuilder(fileNameWithDate).replace(fileNameWithDate.indexOf(".pdf") - 8,
                  fileNameWithDate.indexOf(".pdf"), "");
                  System.out.println(sb.toString());


                  Output:



                  te3st3.pdf





                  share|improve this answer

























                  • What if the file name is test112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing .replaceAll("[0-9]+", "") in the end?

                    – Nicholas K
                    Mar 21 at 10:59












                  • Sorry I forgot to put that I have the assumption that date will come just before the .pdf .

                    – Amit Bera
                    Mar 21 at 11:01













                  0












                  0








                  0







                  If you want to remove the dates only from the String then you can take a look on the solution (Assuming the date will come just before the .pdf) :



                   String fileNameWithDate = "te3st320190906.pdf";

                  StringBuilder sb = new StringBuilder(fileNameWithDate).replace(fileNameWithDate.indexOf(".pdf") - 8,
                  fileNameWithDate.indexOf(".pdf"), "");
                  System.out.println(sb.toString());


                  Output:



                  te3st3.pdf





                  share|improve this answer















                  If you want to remove the dates only from the String then you can take a look on the solution (Assuming the date will come just before the .pdf) :



                   String fileNameWithDate = "te3st320190906.pdf";

                  StringBuilder sb = new StringBuilder(fileNameWithDate).replace(fileNameWithDate.indexOf(".pdf") - 8,
                  fileNameWithDate.indexOf(".pdf"), "");
                  System.out.println(sb.toString());


                  Output:



                  te3st3.pdf






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Mar 21 at 11:02

























                  answered Mar 21 at 10:54









                  Amit BeraAmit Bera

                  4,2411630




                  4,2411630












                  • What if the file name is test112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing .replaceAll("[0-9]+", "") in the end?

                    – Nicholas K
                    Mar 21 at 10:59












                  • Sorry I forgot to put that I have the assumption that date will come just before the .pdf .

                    – Amit Bera
                    Mar 21 at 11:01

















                  • What if the file name is test112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing .replaceAll("[0-9]+", "") in the end?

                    – Nicholas K
                    Mar 21 at 10:59












                  • Sorry I forgot to put that I have the assumption that date will come just before the .pdf .

                    – Amit Bera
                    Mar 21 at 11:01
















                  What if the file name is test112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing .replaceAll("[0-9]+", "") in the end?

                  – Nicholas K
                  Mar 21 at 10:59






                  What if the file name is test112019090611.pdf? Also, what is the point of all the StringBuilder etc... when you end up doing .replaceAll("[0-9]+", "") in the end?

                  – Nicholas K
                  Mar 21 at 10:59














                  Sorry I forgot to put that I have the assumption that date will come just before the .pdf .

                  – Amit Bera
                  Mar 21 at 11:01





                  Sorry I forgot to put that I have the assumption that date will come just before the .pdf .

                  – Amit Bera
                  Mar 21 at 11:01











                  0














                  string name = "test20190906.pdf"
                  name.replaceAll("[0-9]","");





                  share|improve this answer



























                    0














                    string name = "test20190906.pdf"
                    name.replaceAll("[0-9]","");





                    share|improve this answer

























                      0












                      0








                      0







                      string name = "test20190906.pdf"
                      name.replaceAll("[0-9]","");





                      share|improve this answer













                      string name = "test20190906.pdf"
                      name.replaceAll("[0-9]","");






                      share|improve this answer












                      share|improve this answer



                      share|improve this answer










                      answered Mar 21 at 11:13









                      pamithapamitha

                      3715




                      3715





















                          0














                          My approach would be to remove all numbers which are 8 digits long and are next to the last dot and replace them with a dot using the regex: (d8)(?!.*d.).



                          String filename = "filename12345678.pdf";
                          filename = filename.replaceAll("(\d8)(?!.*\d\.)\.", ".");


                          You can see this being used and an explanation of what it does here.



                          If the date can be different lengths then replace the 8 with a *, this enables the date to be any length.






                          share|improve this answer





























                            0














                            My approach would be to remove all numbers which are 8 digits long and are next to the last dot and replace them with a dot using the regex: (d8)(?!.*d.).



                            String filename = "filename12345678.pdf";
                            filename = filename.replaceAll("(\d8)(?!.*\d\.)\.", ".");


                            You can see this being used and an explanation of what it does here.



                            If the date can be different lengths then replace the 8 with a *, this enables the date to be any length.






                            share|improve this answer



























                              0












                              0








                              0







                              My approach would be to remove all numbers which are 8 digits long and are next to the last dot and replace them with a dot using the regex: (d8)(?!.*d.).



                              String filename = "filename12345678.pdf";
                              filename = filename.replaceAll("(\d8)(?!.*\d\.)\.", ".");


                              You can see this being used and an explanation of what it does here.



                              If the date can be different lengths then replace the 8 with a *, this enables the date to be any length.






                              share|improve this answer















                              My approach would be to remove all numbers which are 8 digits long and are next to the last dot and replace them with a dot using the regex: (d8)(?!.*d.).



                              String filename = "filename12345678.pdf";
                              filename = filename.replaceAll("(\d8)(?!.*\d\.)\.", ".");


                              You can see this being used and an explanation of what it does here.



                              If the date can be different lengths then replace the 8 with a *, this enables the date to be any length.







                              share|improve this answer














                              share|improve this answer



                              share|improve this answer








                              edited Mar 21 at 11:44

























                              answered Mar 21 at 11:39









                              Toby SmithToby Smith

                              4231715




                              4231715





















                                  0














                                  An answer that doesn't use Regex:
                                  For filename as the original string:



                                  l = filename.split('.')
                                  l[-2] = l[-2][:-8]
                                  output = '.'.join(l)


                                  This uses the fact that the last '.' will always precede the extension, so the 8 characters prior to this will be dates. As long as we remove those, and put the '.' back in, we have the filename regardless of extension, regardless of characters preceding it, without using Regular Expressions.






                                  share|improve this answer



























                                    0














                                    An answer that doesn't use Regex:
                                    For filename as the original string:



                                    l = filename.split('.')
                                    l[-2] = l[-2][:-8]
                                    output = '.'.join(l)


                                    This uses the fact that the last '.' will always precede the extension, so the 8 characters prior to this will be dates. As long as we remove those, and put the '.' back in, we have the filename regardless of extension, regardless of characters preceding it, without using Regular Expressions.






                                    share|improve this answer

























                                      0












                                      0








                                      0







                                      An answer that doesn't use Regex:
                                      For filename as the original string:



                                      l = filename.split('.')
                                      l[-2] = l[-2][:-8]
                                      output = '.'.join(l)


                                      This uses the fact that the last '.' will always precede the extension, so the 8 characters prior to this will be dates. As long as we remove those, and put the '.' back in, we have the filename regardless of extension, regardless of characters preceding it, without using Regular Expressions.






                                      share|improve this answer













                                      An answer that doesn't use Regex:
                                      For filename as the original string:



                                      l = filename.split('.')
                                      l[-2] = l[-2][:-8]
                                      output = '.'.join(l)


                                      This uses the fact that the last '.' will always precede the extension, so the 8 characters prior to this will be dates. As long as we remove those, and put the '.' back in, we have the filename regardless of extension, regardless of characters preceding it, without using Regular Expressions.







                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered Mar 21 at 15:24









                                      Jim EisenbergJim Eisenberg

                                      17118




                                      17118



























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