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$AcapLambda$ polynomially convex in $Lambda$


How do I compute this Holomorphically Convex Hull?How to prove that $H(S_1cap S_2)subset H(S_1) cap H(S_2)$ and $H(S_1 cup S_2) supset H(S_1) cup H(S_2)$Derivative sets $A'$Proving that $overlineoverlineE_1 setminus E_2 setminus E_2 = overlineE_1 setminus E_2$ in a topological spaceholomorphically convex hull$A cup B$ is not connected, when $A$ and $B$ are connected, $A cap B = varnothing$ and satisfy CAdherence and closed setsIntuition behind holomorphic convexity$A,B$ subsets of euclidean space, $A$ convex, $B$ path connected and closure of $A$ has a point in common with $B$What about Union of connected sets?













0












$begingroup$


Let $ASubsetBbb C^n$ polynomially convex, that is its convex hull
$$
widehat A:=zinBbb C^n;:;
$$

coincides with $A$.



Consider then $LambdasubsetBbb C^n$ such that $LambdasimeqBbb C$ (say, for example $Lambda=Bbb Ce_1$, where $e_1=(1,0,dots)inBbb C^n$).



How can I prove that $AcapLambda$ is polynomially convex in $Lambda$? How can one deduce from this that $Lambdasetminus A$ is connected?



EDIT: Could this a particular case of the following statemen?




$A,BSubsetBbb C^n$ polynomially convex $Rightarrow$ $Acup B$ p.c.











share|cite|improve this question











$endgroup$
















    0












    $begingroup$


    Let $ASubsetBbb C^n$ polynomially convex, that is its convex hull
    $$
    widehat A:=zinBbb C^n;:;
    $$

    coincides with $A$.



    Consider then $LambdasubsetBbb C^n$ such that $LambdasimeqBbb C$ (say, for example $Lambda=Bbb Ce_1$, where $e_1=(1,0,dots)inBbb C^n$).



    How can I prove that $AcapLambda$ is polynomially convex in $Lambda$? How can one deduce from this that $Lambdasetminus A$ is connected?



    EDIT: Could this a particular case of the following statemen?




    $A,BSubsetBbb C^n$ polynomially convex $Rightarrow$ $Acup B$ p.c.











    share|cite|improve this question











    $endgroup$














      0












      0








      0





      $begingroup$


      Let $ASubsetBbb C^n$ polynomially convex, that is its convex hull
      $$
      widehat A:=zinBbb C^n;:;
      $$

      coincides with $A$.



      Consider then $LambdasubsetBbb C^n$ such that $LambdasimeqBbb C$ (say, for example $Lambda=Bbb Ce_1$, where $e_1=(1,0,dots)inBbb C^n$).



      How can I prove that $AcapLambda$ is polynomially convex in $Lambda$? How can one deduce from this that $Lambdasetminus A$ is connected?



      EDIT: Could this a particular case of the following statemen?




      $A,BSubsetBbb C^n$ polynomially convex $Rightarrow$ $Acup B$ p.c.











      share|cite|improve this question











      $endgroup$




      Let $ASubsetBbb C^n$ polynomially convex, that is its convex hull
      $$
      widehat A:=zinBbb C^n;:;
      $$

      coincides with $A$.



      Consider then $LambdasubsetBbb C^n$ such that $LambdasimeqBbb C$ (say, for example $Lambda=Bbb Ce_1$, where $e_1=(1,0,dots)inBbb C^n$).



      How can I prove that $AcapLambda$ is polynomially convex in $Lambda$? How can one deduce from this that $Lambdasetminus A$ is connected?



      EDIT: Could this a particular case of the following statemen?




      $A,BSubsetBbb C^n$ polynomially convex $Rightarrow$ $Acup B$ p.c.








      general-topology complex-analysis several-complex-variables






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 23 at 11:24







      Joe

















      asked Mar 21 at 14:24









      JoeJoe

      7,23921229




      7,23921229




















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