$AcapLambda$ polynomially convex in $Lambda$How do I compute this Holomorphically Convex Hull?How to prove that $H(S_1cap S_2)subset H(S_1) cap H(S_2)$ and $H(S_1 cup S_2) supset H(S_1) cup H(S_2)$Derivative sets $A'$Proving that $overlineoverlineE_1 setminus E_2 setminus E_2 = overlineE_1 setminus E_2$ in a topological spaceholomorphically convex hull$A cup B$ is not connected, when $A$ and $B$ are connected, $A cap B = varnothing$ and satisfy CAdherence and closed setsIntuition behind holomorphic convexity$A,B$ subsets of euclidean space, $A$ convex, $B$ path connected and closure of $A$ has a point in common with $B$What about Union of connected sets?
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$AcapLambda$ polynomially convex in $Lambda$
How do I compute this Holomorphically Convex Hull?How to prove that $H(S_1cap S_2)subset H(S_1) cap H(S_2)$ and $H(S_1 cup S_2) supset H(S_1) cup H(S_2)$Derivative sets $A'$Proving that $overlineoverlineE_1 setminus E_2 setminus E_2 = overlineE_1 setminus E_2$ in a topological spaceholomorphically convex hull$A cup B$ is not connected, when $A$ and $B$ are connected, $A cap B = varnothing$ and satisfy CAdherence and closed setsIntuition behind holomorphic convexity$A,B$ subsets of euclidean space, $A$ convex, $B$ path connected and closure of $A$ has a point in common with $B$What about Union of connected sets?
$begingroup$
Let $ASubsetBbb C^n$ polynomially convex, that is its convex hull
$$
widehat A:=zinBbb C^n;:;
$$
coincides with $A$.
Consider then $LambdasubsetBbb C^n$ such that $LambdasimeqBbb C$ (say, for example $Lambda=Bbb Ce_1$, where $e_1=(1,0,dots)inBbb C^n$).
How can I prove that $AcapLambda$ is polynomially convex in $Lambda$? How can one deduce from this that $Lambdasetminus A$ is connected?
EDIT: Could this a particular case of the following statemen?
$A,BSubsetBbb C^n$ polynomially convex $Rightarrow$ $Acup B$ p.c.
general-topology complex-analysis several-complex-variables
$endgroup$
add a comment |
$begingroup$
Let $ASubsetBbb C^n$ polynomially convex, that is its convex hull
$$
widehat A:=zinBbb C^n;:;
$$
coincides with $A$.
Consider then $LambdasubsetBbb C^n$ such that $LambdasimeqBbb C$ (say, for example $Lambda=Bbb Ce_1$, where $e_1=(1,0,dots)inBbb C^n$).
How can I prove that $AcapLambda$ is polynomially convex in $Lambda$? How can one deduce from this that $Lambdasetminus A$ is connected?
EDIT: Could this a particular case of the following statemen?
$A,BSubsetBbb C^n$ polynomially convex $Rightarrow$ $Acup B$ p.c.
general-topology complex-analysis several-complex-variables
$endgroup$
add a comment |
$begingroup$
Let $ASubsetBbb C^n$ polynomially convex, that is its convex hull
$$
widehat A:=zinBbb C^n;:;
$$
coincides with $A$.
Consider then $LambdasubsetBbb C^n$ such that $LambdasimeqBbb C$ (say, for example $Lambda=Bbb Ce_1$, where $e_1=(1,0,dots)inBbb C^n$).
How can I prove that $AcapLambda$ is polynomially convex in $Lambda$? How can one deduce from this that $Lambdasetminus A$ is connected?
EDIT: Could this a particular case of the following statemen?
$A,BSubsetBbb C^n$ polynomially convex $Rightarrow$ $Acup B$ p.c.
general-topology complex-analysis several-complex-variables
$endgroup$
Let $ASubsetBbb C^n$ polynomially convex, that is its convex hull
$$
widehat A:=zinBbb C^n;:;
$$
coincides with $A$.
Consider then $LambdasubsetBbb C^n$ such that $LambdasimeqBbb C$ (say, for example $Lambda=Bbb Ce_1$, where $e_1=(1,0,dots)inBbb C^n$).
How can I prove that $AcapLambda$ is polynomially convex in $Lambda$? How can one deduce from this that $Lambdasetminus A$ is connected?
EDIT: Could this a particular case of the following statemen?
$A,BSubsetBbb C^n$ polynomially convex $Rightarrow$ $Acup B$ p.c.
general-topology complex-analysis several-complex-variables
general-topology complex-analysis several-complex-variables
edited Mar 23 at 11:24
Joe
asked Mar 21 at 14:24
JoeJoe
7,23921229
7,23921229
add a comment |
add a comment |
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