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Max possible area, of a rectangle shape where one side is a half circle. circumference of 100m


Area between a semicircle and a 45° lineWhat shape do we get when we shear an ellipse? And more generally, do affine transformations always map conic sections to conic sections?'Concentric' parabolas — two parabolas that have a constant vector distanceincreasing area of circle,square &rectangleSplitting area of composite shape in half and finding length of fenceTo optimize fenced area in a semi-ellipse, what a/b should I choose?Find max possible area of square and circleMax area of rectangle in an ellipseArea of Rectangle and circleA flower in a hexagon













0












$begingroup$


A picture of the shape!



I recently took a maths test where one of the questions was just unsolvable for me. I'm going to try to make it as clear as possible, to not create confusion.



The question looks like this:



"A rectangle shape, which has one of it's sides replaced by a half circle (see picture above.) has a circumference of 100 meters.



What is the maximum possible area of this shape?"



The test was about quadratic equations, parabolas, and their graphs.



How would you solve this kind of question? I would really appreciate all help I could get!










share|cite|improve this question









$endgroup$
















    0












    $begingroup$


    A picture of the shape!



    I recently took a maths test where one of the questions was just unsolvable for me. I'm going to try to make it as clear as possible, to not create confusion.



    The question looks like this:



    "A rectangle shape, which has one of it's sides replaced by a half circle (see picture above.) has a circumference of 100 meters.



    What is the maximum possible area of this shape?"



    The test was about quadratic equations, parabolas, and their graphs.



    How would you solve this kind of question? I would really appreciate all help I could get!










    share|cite|improve this question









    $endgroup$














      0












      0








      0





      $begingroup$


      A picture of the shape!



      I recently took a maths test where one of the questions was just unsolvable for me. I'm going to try to make it as clear as possible, to not create confusion.



      The question looks like this:



      "A rectangle shape, which has one of it's sides replaced by a half circle (see picture above.) has a circumference of 100 meters.



      What is the maximum possible area of this shape?"



      The test was about quadratic equations, parabolas, and their graphs.



      How would you solve this kind of question? I would really appreciate all help I could get!










      share|cite|improve this question









      $endgroup$




      A picture of the shape!



      I recently took a maths test where one of the questions was just unsolvable for me. I'm going to try to make it as clear as possible, to not create confusion.



      The question looks like this:



      "A rectangle shape, which has one of it's sides replaced by a half circle (see picture above.) has a circumference of 100 meters.



      What is the maximum possible area of this shape?"



      The test was about quadratic equations, parabolas, and their graphs.



      How would you solve this kind of question? I would really appreciate all help I could get!







      quadratics conic-sections area






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Mar 21 at 14:43









      Haupta2Haupta2

      1




      1




















          1 Answer
          1






          active

          oldest

          votes


















          0












          $begingroup$

          Let the sidelength of the rectangle be $x$ respectively $y$, then the area is given by
          $$A=xy-fracpi y^28$$ and the perimeter is given by $$p=2x+y+fracpi y2$$
          Can you proceed now?






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            I'm sorry if i wasn't clear enough with the question. In a similar problem, with a normal rectangle with the perimeter of 100. I would label the sides X and (50-X) respectively. The area would then be = X(50-X). which would give me something like: ax^2 + bx + c = y Is this sort of equation possible with this problem?
            $endgroup$
            – Haupta2
            Mar 21 at 15:12











          • $begingroup$
            But you must subtract the area of the half circle
            $endgroup$
            – Dr. Sonnhard Graubner
            Mar 21 at 15:14











          Your Answer





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          1 Answer
          1






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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0












          $begingroup$

          Let the sidelength of the rectangle be $x$ respectively $y$, then the area is given by
          $$A=xy-fracpi y^28$$ and the perimeter is given by $$p=2x+y+fracpi y2$$
          Can you proceed now?






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            I'm sorry if i wasn't clear enough with the question. In a similar problem, with a normal rectangle with the perimeter of 100. I would label the sides X and (50-X) respectively. The area would then be = X(50-X). which would give me something like: ax^2 + bx + c = y Is this sort of equation possible with this problem?
            $endgroup$
            – Haupta2
            Mar 21 at 15:12











          • $begingroup$
            But you must subtract the area of the half circle
            $endgroup$
            – Dr. Sonnhard Graubner
            Mar 21 at 15:14















          0












          $begingroup$

          Let the sidelength of the rectangle be $x$ respectively $y$, then the area is given by
          $$A=xy-fracpi y^28$$ and the perimeter is given by $$p=2x+y+fracpi y2$$
          Can you proceed now?






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            I'm sorry if i wasn't clear enough with the question. In a similar problem, with a normal rectangle with the perimeter of 100. I would label the sides X and (50-X) respectively. The area would then be = X(50-X). which would give me something like: ax^2 + bx + c = y Is this sort of equation possible with this problem?
            $endgroup$
            – Haupta2
            Mar 21 at 15:12











          • $begingroup$
            But you must subtract the area of the half circle
            $endgroup$
            – Dr. Sonnhard Graubner
            Mar 21 at 15:14













          0












          0








          0





          $begingroup$

          Let the sidelength of the rectangle be $x$ respectively $y$, then the area is given by
          $$A=xy-fracpi y^28$$ and the perimeter is given by $$p=2x+y+fracpi y2$$
          Can you proceed now?






          share|cite|improve this answer









          $endgroup$



          Let the sidelength of the rectangle be $x$ respectively $y$, then the area is given by
          $$A=xy-fracpi y^28$$ and the perimeter is given by $$p=2x+y+fracpi y2$$
          Can you proceed now?







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Mar 21 at 14:56









          Dr. Sonnhard GraubnerDr. Sonnhard Graubner

          78.4k42867




          78.4k42867











          • $begingroup$
            I'm sorry if i wasn't clear enough with the question. In a similar problem, with a normal rectangle with the perimeter of 100. I would label the sides X and (50-X) respectively. The area would then be = X(50-X). which would give me something like: ax^2 + bx + c = y Is this sort of equation possible with this problem?
            $endgroup$
            – Haupta2
            Mar 21 at 15:12











          • $begingroup$
            But you must subtract the area of the half circle
            $endgroup$
            – Dr. Sonnhard Graubner
            Mar 21 at 15:14
















          • $begingroup$
            I'm sorry if i wasn't clear enough with the question. In a similar problem, with a normal rectangle with the perimeter of 100. I would label the sides X and (50-X) respectively. The area would then be = X(50-X). which would give me something like: ax^2 + bx + c = y Is this sort of equation possible with this problem?
            $endgroup$
            – Haupta2
            Mar 21 at 15:12











          • $begingroup$
            But you must subtract the area of the half circle
            $endgroup$
            – Dr. Sonnhard Graubner
            Mar 21 at 15:14















          $begingroup$
          I'm sorry if i wasn't clear enough with the question. In a similar problem, with a normal rectangle with the perimeter of 100. I would label the sides X and (50-X) respectively. The area would then be = X(50-X). which would give me something like: ax^2 + bx + c = y Is this sort of equation possible with this problem?
          $endgroup$
          – Haupta2
          Mar 21 at 15:12





          $begingroup$
          I'm sorry if i wasn't clear enough with the question. In a similar problem, with a normal rectangle with the perimeter of 100. I would label the sides X and (50-X) respectively. The area would then be = X(50-X). which would give me something like: ax^2 + bx + c = y Is this sort of equation possible with this problem?
          $endgroup$
          – Haupta2
          Mar 21 at 15:12













          $begingroup$
          But you must subtract the area of the half circle
          $endgroup$
          – Dr. Sonnhard Graubner
          Mar 21 at 15:14




          $begingroup$
          But you must subtract the area of the half circle
          $endgroup$
          – Dr. Sonnhard Graubner
          Mar 21 at 15:14

















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