Fourier Transform for triangular wave Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Derive Fourier transform of sinc functionFourier transform of $f(x)=exp(-|x|)operatornamesgn(x)$fourier transform of sinc functionHow to develop the Fourier Transform in my mind now that I know the Fourier Seires?Fast fourier transform and nyquist frequencyFourier transform of divergent function.A more elegant way to find the Fourier transformHow can I find the Fourier transform of constant value like $1$.Fourier Transform of triangle function 𝑥(𝑡)=Δ((t-1)/2)Hints to Fourier analysis problem
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Fourier Transform for triangular wave
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Derive Fourier transform of sinc functionFourier transform of $f(x)=exp(-|x|)operatornamesgn(x)$fourier transform of sinc functionHow to develop the Fourier Transform in my mind now that I know the Fourier Seires?Fast fourier transform and nyquist frequencyFourier transform of divergent function.A more elegant way to find the Fourier transformHow can I find the Fourier transform of constant value like $1$.Fourier Transform of triangle function 𝑥(𝑡)=Δ((t-1)/2)Hints to Fourier analysis problem
$begingroup$
Could someone tell me if I've worked this out right? I'm unsure of the process, especially the final parts where I convert it to a sinc function.
Please let me know if I've made mistakes anywhere else too.
fourier-analysis triangles integral-transforms
$endgroup$
add a comment |
$begingroup$
Could someone tell me if I've worked this out right? I'm unsure of the process, especially the final parts where I convert it to a sinc function.
Please let me know if I've made mistakes anywhere else too.
fourier-analysis triangles integral-transforms
$endgroup$
add a comment |
$begingroup$
Could someone tell me if I've worked this out right? I'm unsure of the process, especially the final parts where I convert it to a sinc function.
Please let me know if I've made mistakes anywhere else too.
fourier-analysis triangles integral-transforms
$endgroup$
Could someone tell me if I've worked this out right? I'm unsure of the process, especially the final parts where I convert it to a sinc function.
Please let me know if I've made mistakes anywhere else too.
fourier-analysis triangles integral-transforms
fourier-analysis triangles integral-transforms
edited Mar 27 at 18:59
Glorfindel
3,41381930
3,41381930
asked Mar 4 '14 at 18:03
user2802349user2802349
2416
2416
add a comment |
add a comment |
1 Answer
1
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oldest
votes
$begingroup$
The mistake on the last step:
$$
frac6sqrt2pi left[ frac sin^2frac3omega2frac3omega^22 right]
=
frac6sqrt2pi left[ frac sin^2frac3omega2frac23left(frac3omega2right)^2 right]
=
frac9sqrt2pi left[ frac sinfrac3omega2frac3omega2 right]^2
=
frac9sqrt2pi rm sinc^2frac3omega2
$$
$endgroup$
$begingroup$
Thanks so much. I was unsure about how sinc's worked with they were squared. Does the solution look right to you for a triangle wave of this kind? :(
$endgroup$
– user2802349
Mar 4 '14 at 18:20
$begingroup$
The answer is correct now.
$endgroup$
– bcp
Mar 4 '14 at 18:27
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The mistake on the last step:
$$
frac6sqrt2pi left[ frac sin^2frac3omega2frac3omega^22 right]
=
frac6sqrt2pi left[ frac sin^2frac3omega2frac23left(frac3omega2right)^2 right]
=
frac9sqrt2pi left[ frac sinfrac3omega2frac3omega2 right]^2
=
frac9sqrt2pi rm sinc^2frac3omega2
$$
$endgroup$
$begingroup$
Thanks so much. I was unsure about how sinc's worked with they were squared. Does the solution look right to you for a triangle wave of this kind? :(
$endgroup$
– user2802349
Mar 4 '14 at 18:20
$begingroup$
The answer is correct now.
$endgroup$
– bcp
Mar 4 '14 at 18:27
add a comment |
$begingroup$
The mistake on the last step:
$$
frac6sqrt2pi left[ frac sin^2frac3omega2frac3omega^22 right]
=
frac6sqrt2pi left[ frac sin^2frac3omega2frac23left(frac3omega2right)^2 right]
=
frac9sqrt2pi left[ frac sinfrac3omega2frac3omega2 right]^2
=
frac9sqrt2pi rm sinc^2frac3omega2
$$
$endgroup$
$begingroup$
Thanks so much. I was unsure about how sinc's worked with they were squared. Does the solution look right to you for a triangle wave of this kind? :(
$endgroup$
– user2802349
Mar 4 '14 at 18:20
$begingroup$
The answer is correct now.
$endgroup$
– bcp
Mar 4 '14 at 18:27
add a comment |
$begingroup$
The mistake on the last step:
$$
frac6sqrt2pi left[ frac sin^2frac3omega2frac3omega^22 right]
=
frac6sqrt2pi left[ frac sin^2frac3omega2frac23left(frac3omega2right)^2 right]
=
frac9sqrt2pi left[ frac sinfrac3omega2frac3omega2 right]^2
=
frac9sqrt2pi rm sinc^2frac3omega2
$$
$endgroup$
The mistake on the last step:
$$
frac6sqrt2pi left[ frac sin^2frac3omega2frac3omega^22 right]
=
frac6sqrt2pi left[ frac sin^2frac3omega2frac23left(frac3omega2right)^2 right]
=
frac9sqrt2pi left[ frac sinfrac3omega2frac3omega2 right]^2
=
frac9sqrt2pi rm sinc^2frac3omega2
$$
answered Mar 4 '14 at 18:09
bcpbcp
304112
304112
$begingroup$
Thanks so much. I was unsure about how sinc's worked with they were squared. Does the solution look right to you for a triangle wave of this kind? :(
$endgroup$
– user2802349
Mar 4 '14 at 18:20
$begingroup$
The answer is correct now.
$endgroup$
– bcp
Mar 4 '14 at 18:27
add a comment |
$begingroup$
Thanks so much. I was unsure about how sinc's worked with they were squared. Does the solution look right to you for a triangle wave of this kind? :(
$endgroup$
– user2802349
Mar 4 '14 at 18:20
$begingroup$
The answer is correct now.
$endgroup$
– bcp
Mar 4 '14 at 18:27
$begingroup$
Thanks so much. I was unsure about how sinc's worked with they were squared. Does the solution look right to you for a triangle wave of this kind? :(
$endgroup$
– user2802349
Mar 4 '14 at 18:20
$begingroup$
Thanks so much. I was unsure about how sinc's worked with they were squared. Does the solution look right to you for a triangle wave of this kind? :(
$endgroup$
– user2802349
Mar 4 '14 at 18:20
$begingroup$
The answer is correct now.
$endgroup$
– bcp
Mar 4 '14 at 18:27
$begingroup$
The answer is correct now.
$endgroup$
– bcp
Mar 4 '14 at 18:27
add a comment |
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