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Clarification on Term Order of an Infinitesimal



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Determine the order of an infinitesimal.What is the order of an infinitesimal?Taylor series with functions as parameters (as opposed to variables)Calculus of Variations statement of a Singular Value Decomposition?What methods are available for this optimization problem?Derivative of an Infinitesimal?How should the Calculus of Variations deal with $delta(t-t_0)$ variations?Find the curve which together with $gamma$ encloses the greatest area.Where does Jacobi's accessory equation come from?Lie's theorem about infinitesimal rigid motions and riemannian manifolds curvatureUniqueness in Bernstein's theorem of calculus of variationsVariation of Lagrangian with infinitesimal transformation of time and position variables










0












$begingroup$


I've seen several questions posted on this, namely



  1. What is the order of an infinitesimal?


  2. Determine the order of an infinitesimal.


I'm asking this question because I've seen it pop up in variational calculus and want to make sure the answers in the above posts apply.



e.g. Gelfand & Fomin's Calculus of Variations states (Section 3.2, pg. 11), for



$$
beginalign
Delta J[h] &= J[y+h] - J[y] \
&=varphi [h] + epsilon lVert h rVert,
endalign
$$



that "the linear functional $varphi [h]$ which differs from $Delta J[h]$ by an infinitesimal of order higher than 1 relative to $lVert h rVert$, is called the [first] variation of $J[y]$ and is denoted by $delta J[h]$".



This kind of terminology appears more than once.



Question



Is the order of an infinitesimal, $epsilon$, its integer power, $n$, such that



$$
epsilon^n
$$



is an nth-order infinitesimal, with the only difference between orders of infinitesimals being how fast they converge to $0$?



(This definition being purely due to Cauchy, explained in his text, the English annotated version of which is given here:



http://users.uoa.gr/~spapast/TomeasDidaktikhs/Caychy/CauchyCoursdAnalyseAnAnnotatedTranslationSourcesandStudiesintheHistoryofMathematicsandPhysicalSciences.pdf))










share|cite|improve this question









$endgroup$
















    0












    $begingroup$


    I've seen several questions posted on this, namely



    1. What is the order of an infinitesimal?


    2. Determine the order of an infinitesimal.


    I'm asking this question because I've seen it pop up in variational calculus and want to make sure the answers in the above posts apply.



    e.g. Gelfand & Fomin's Calculus of Variations states (Section 3.2, pg. 11), for



    $$
    beginalign
    Delta J[h] &= J[y+h] - J[y] \
    &=varphi [h] + epsilon lVert h rVert,
    endalign
    $$



    that "the linear functional $varphi [h]$ which differs from $Delta J[h]$ by an infinitesimal of order higher than 1 relative to $lVert h rVert$, is called the [first] variation of $J[y]$ and is denoted by $delta J[h]$".



    This kind of terminology appears more than once.



    Question



    Is the order of an infinitesimal, $epsilon$, its integer power, $n$, such that



    $$
    epsilon^n
    $$



    is an nth-order infinitesimal, with the only difference between orders of infinitesimals being how fast they converge to $0$?



    (This definition being purely due to Cauchy, explained in his text, the English annotated version of which is given here:



    http://users.uoa.gr/~spapast/TomeasDidaktikhs/Caychy/CauchyCoursdAnalyseAnAnnotatedTranslationSourcesandStudiesintheHistoryofMathematicsandPhysicalSciences.pdf))










    share|cite|improve this question









    $endgroup$














      0












      0








      0





      $begingroup$


      I've seen several questions posted on this, namely



      1. What is the order of an infinitesimal?


      2. Determine the order of an infinitesimal.


      I'm asking this question because I've seen it pop up in variational calculus and want to make sure the answers in the above posts apply.



      e.g. Gelfand & Fomin's Calculus of Variations states (Section 3.2, pg. 11), for



      $$
      beginalign
      Delta J[h] &= J[y+h] - J[y] \
      &=varphi [h] + epsilon lVert h rVert,
      endalign
      $$



      that "the linear functional $varphi [h]$ which differs from $Delta J[h]$ by an infinitesimal of order higher than 1 relative to $lVert h rVert$, is called the [first] variation of $J[y]$ and is denoted by $delta J[h]$".



      This kind of terminology appears more than once.



      Question



      Is the order of an infinitesimal, $epsilon$, its integer power, $n$, such that



      $$
      epsilon^n
      $$



      is an nth-order infinitesimal, with the only difference between orders of infinitesimals being how fast they converge to $0$?



      (This definition being purely due to Cauchy, explained in his text, the English annotated version of which is given here:



      http://users.uoa.gr/~spapast/TomeasDidaktikhs/Caychy/CauchyCoursdAnalyseAnAnnotatedTranslationSourcesandStudiesintheHistoryofMathematicsandPhysicalSciences.pdf))










      share|cite|improve this question









      $endgroup$




      I've seen several questions posted on this, namely



      1. What is the order of an infinitesimal?


      2. Determine the order of an infinitesimal.


      I'm asking this question because I've seen it pop up in variational calculus and want to make sure the answers in the above posts apply.



      e.g. Gelfand & Fomin's Calculus of Variations states (Section 3.2, pg. 11), for



      $$
      beginalign
      Delta J[h] &= J[y+h] - J[y] \
      &=varphi [h] + epsilon lVert h rVert,
      endalign
      $$



      that "the linear functional $varphi [h]$ which differs from $Delta J[h]$ by an infinitesimal of order higher than 1 relative to $lVert h rVert$, is called the [first] variation of $J[y]$ and is denoted by $delta J[h]$".



      This kind of terminology appears more than once.



      Question



      Is the order of an infinitesimal, $epsilon$, its integer power, $n$, such that



      $$
      epsilon^n
      $$



      is an nth-order infinitesimal, with the only difference between orders of infinitesimals being how fast they converge to $0$?



      (This definition being purely due to Cauchy, explained in his text, the English annotated version of which is given here:



      http://users.uoa.gr/~spapast/TomeasDidaktikhs/Caychy/CauchyCoursdAnalyseAnAnnotatedTranslationSourcesandStudiesintheHistoryofMathematicsandPhysicalSciences.pdf))







      calculus-of-variations






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Mar 27 at 20:25









      A. HendryA. Hendry

      346




      346




















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          0












          $begingroup$

          Yes, the order of an infinitesimal is its integer power. The rate at which in converges to 0 is proportional to its order.






          share|cite|improve this answer









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            0












            $begingroup$

            Yes, the order of an infinitesimal is its integer power. The rate at which in converges to 0 is proportional to its order.






            share|cite|improve this answer









            $endgroup$

















              0












              $begingroup$

              Yes, the order of an infinitesimal is its integer power. The rate at which in converges to 0 is proportional to its order.






              share|cite|improve this answer









              $endgroup$















                0












                0








                0





                $begingroup$

                Yes, the order of an infinitesimal is its integer power. The rate at which in converges to 0 is proportional to its order.






                share|cite|improve this answer









                $endgroup$



                Yes, the order of an infinitesimal is its integer power. The rate at which in converges to 0 is proportional to its order.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Apr 1 at 12:23









                A. HendryA. Hendry

                346




                346



























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