For $p$ a prime larger than $2k+2$, is it possible that $p^2$ divides $B_2k$? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Which is the greatest possible natural number that divides $(p+3)(p-7)$, where $p$ is a prime number greater than $3$?On the numerators of Bernoulli numbersPrime larger than a twin primeProve that for any natural number $n$ there exists a prime number $p$ greater than $n$Euclid's proof for the existence of infinitely many primeBernoulli number $B_fracp-12$What is the Largest Possible Prime Number? sic The largest possible prime set?Infiniteness of irregular primes $equiv3pmod4$Existence of $m in M subsetneq mathbbN$ such that $p nmid a+bm$, $p$ primeProve that every prime number divides some number in the sequence $ a_n = 2^n+3^n+6^n-1 $
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For $p$ a prime larger than $2k+2$, is it possible that $p^2$ divides $B_2k$?
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Which is the greatest possible natural number that divides $(p+3)(p-7)$, where $p$ is a prime number greater than $3$?On the numerators of Bernoulli numbersPrime larger than a twin primeProve that for any natural number $n$ there exists a prime number $p$ greater than $n$Euclid's proof for the existence of infinitely many primeBernoulli number $B_fracp-12$What is the Largest Possible Prime Number? sic The largest possible prime set?Infiniteness of irregular primes $equiv3pmod4$Existence of $m in M subsetneq mathbbN$ such that $p nmid a+bm$, $p$ primeProve that every prime number divides some number in the sequence $ a_n = 2^n+3^n+6^n-1 $
$begingroup$
One characterization of the irregular primes is as follows:
For an irregular prime $p$, there exists some natural number $kle fracp-32$ such that $p$ divides [the numerator of] $B_2k$ where $B_2k$ is a Bernoulli number.
Question: Is there some prime $p$ for which there exists some natural number $kle fracp-32$, such that $p^2$ divides $B_2k$?
References that provide an answer, or just deal with the question are welcome.
number-theory elementary-number-theory reference-request prime-numbers bernoulli-numbers
$endgroup$
add a comment |
$begingroup$
One characterization of the irregular primes is as follows:
For an irregular prime $p$, there exists some natural number $kle fracp-32$ such that $p$ divides [the numerator of] $B_2k$ where $B_2k$ is a Bernoulli number.
Question: Is there some prime $p$ for which there exists some natural number $kle fracp-32$, such that $p^2$ divides $B_2k$?
References that provide an answer, or just deal with the question are welcome.
number-theory elementary-number-theory reference-request prime-numbers bernoulli-numbers
$endgroup$
add a comment |
$begingroup$
One characterization of the irregular primes is as follows:
For an irregular prime $p$, there exists some natural number $kle fracp-32$ such that $p$ divides [the numerator of] $B_2k$ where $B_2k$ is a Bernoulli number.
Question: Is there some prime $p$ for which there exists some natural number $kle fracp-32$, such that $p^2$ divides $B_2k$?
References that provide an answer, or just deal with the question are welcome.
number-theory elementary-number-theory reference-request prime-numbers bernoulli-numbers
$endgroup$
One characterization of the irregular primes is as follows:
For an irregular prime $p$, there exists some natural number $kle fracp-32$ such that $p$ divides [the numerator of] $B_2k$ where $B_2k$ is a Bernoulli number.
Question: Is there some prime $p$ for which there exists some natural number $kle fracp-32$, such that $p^2$ divides $B_2k$?
References that provide an answer, or just deal with the question are welcome.
number-theory elementary-number-theory reference-request prime-numbers bernoulli-numbers
number-theory elementary-number-theory reference-request prime-numbers bernoulli-numbers
edited Mar 27 at 21:21
J. W. Tanner
5,0551520
5,0551520
asked Mar 27 at 19:51
René GyRené Gy
1,230713
1,230713
add a comment |
add a comment |
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