Simple formula for the dimension of weight spaces of Verma module?irreducible highest weight modulesProperties of the longest element in a Weyl groupHow to use Weyl dimension formula?Weight spaces of Verma modulesInducing highest weight modulesDimension of a weight space which is of weight $0$.How to find the multiplicity of weight in a Verma module?Composition series for Verma modules.finding high weight vector in Verma moduleThe relation between Weyl character formula and Frobenius characteristic map
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Simple formula for the dimension of weight spaces of Verma module?
irreducible highest weight modulesProperties of the longest element in a Weyl groupHow to use Weyl dimension formula?Weight spaces of Verma modulesInducing highest weight modulesDimension of a weight space which is of weight $0$.How to find the multiplicity of weight in a Verma module?Composition series for Verma modules.finding high weight vector in Verma moduleThe relation between Weyl character formula and Frobenius characteristic map
$begingroup$
Let $mathfrakg$ be a simple Lie algebra (e.g. $mathfraksl_n$), and let $M_lambda$ be the Verma module with highest weight $lambda$.
Is there a simple formula for $dim (M_lambda)_mu$, where $(M_lambda)_mu$ denotes the weight space with weight $mu$? Of course Weyl character formula gives me the generating function, but I am looking for a closed form formula for $dim (M_lambda)_mu$.
Edit : Apparently this is called the Kostant partition function.
representation-theory lie-algebras verma-modules
$endgroup$
add a comment |
$begingroup$
Let $mathfrakg$ be a simple Lie algebra (e.g. $mathfraksl_n$), and let $M_lambda$ be the Verma module with highest weight $lambda$.
Is there a simple formula for $dim (M_lambda)_mu$, where $(M_lambda)_mu$ denotes the weight space with weight $mu$? Of course Weyl character formula gives me the generating function, but I am looking for a closed form formula for $dim (M_lambda)_mu$.
Edit : Apparently this is called the Kostant partition function.
representation-theory lie-algebras verma-modules
$endgroup$
$begingroup$
Which formulation of Weyl's character formula do you mean? I recall it usually being given directly, rather than via a generating function.
$endgroup$
– Tobias Kildetoft
Mar 18 at 17:01
$begingroup$
@TobiasKildetoft For instance, if you expand $1/Delta(z)$ into a power series where $Delta(z)$ is a Weyl denominator, the coefficients of this series are the certain dimensions that I want.
$endgroup$
– Henry
Mar 19 at 19:35
$begingroup$
As you write in your edit, it's the Kostant partition function: the number of ways to write $lambda-mu$ as a non-negative integer linear combination of positive roots. You won't get a better formula than that in general.
$endgroup$
– Stephen
Mar 20 at 22:54
$begingroup$
@Stephen But isn't Kostant partition function piecewise polynomial? If an explicit form of the piecewise polynomial is known for, say, $A_n$, then that would be helpful.
$endgroup$
– Henry
Mar 20 at 23:18
add a comment |
$begingroup$
Let $mathfrakg$ be a simple Lie algebra (e.g. $mathfraksl_n$), and let $M_lambda$ be the Verma module with highest weight $lambda$.
Is there a simple formula for $dim (M_lambda)_mu$, where $(M_lambda)_mu$ denotes the weight space with weight $mu$? Of course Weyl character formula gives me the generating function, but I am looking for a closed form formula for $dim (M_lambda)_mu$.
Edit : Apparently this is called the Kostant partition function.
representation-theory lie-algebras verma-modules
$endgroup$
Let $mathfrakg$ be a simple Lie algebra (e.g. $mathfraksl_n$), and let $M_lambda$ be the Verma module with highest weight $lambda$.
Is there a simple formula for $dim (M_lambda)_mu$, where $(M_lambda)_mu$ denotes the weight space with weight $mu$? Of course Weyl character formula gives me the generating function, but I am looking for a closed form formula for $dim (M_lambda)_mu$.
Edit : Apparently this is called the Kostant partition function.
representation-theory lie-algebras verma-modules
representation-theory lie-algebras verma-modules
edited Mar 21 at 6:21
Saad
20.2k92352
20.2k92352
asked Mar 17 at 22:26
HenryHenry
1,731726
1,731726
$begingroup$
Which formulation of Weyl's character formula do you mean? I recall it usually being given directly, rather than via a generating function.
$endgroup$
– Tobias Kildetoft
Mar 18 at 17:01
$begingroup$
@TobiasKildetoft For instance, if you expand $1/Delta(z)$ into a power series where $Delta(z)$ is a Weyl denominator, the coefficients of this series are the certain dimensions that I want.
$endgroup$
– Henry
Mar 19 at 19:35
$begingroup$
As you write in your edit, it's the Kostant partition function: the number of ways to write $lambda-mu$ as a non-negative integer linear combination of positive roots. You won't get a better formula than that in general.
$endgroup$
– Stephen
Mar 20 at 22:54
$begingroup$
@Stephen But isn't Kostant partition function piecewise polynomial? If an explicit form of the piecewise polynomial is known for, say, $A_n$, then that would be helpful.
$endgroup$
– Henry
Mar 20 at 23:18
add a comment |
$begingroup$
Which formulation of Weyl's character formula do you mean? I recall it usually being given directly, rather than via a generating function.
$endgroup$
– Tobias Kildetoft
Mar 18 at 17:01
$begingroup$
@TobiasKildetoft For instance, if you expand $1/Delta(z)$ into a power series where $Delta(z)$ is a Weyl denominator, the coefficients of this series are the certain dimensions that I want.
$endgroup$
– Henry
Mar 19 at 19:35
$begingroup$
As you write in your edit, it's the Kostant partition function: the number of ways to write $lambda-mu$ as a non-negative integer linear combination of positive roots. You won't get a better formula than that in general.
$endgroup$
– Stephen
Mar 20 at 22:54
$begingroup$
@Stephen But isn't Kostant partition function piecewise polynomial? If an explicit form of the piecewise polynomial is known for, say, $A_n$, then that would be helpful.
$endgroup$
– Henry
Mar 20 at 23:18
$begingroup$
Which formulation of Weyl's character formula do you mean? I recall it usually being given directly, rather than via a generating function.
$endgroup$
– Tobias Kildetoft
Mar 18 at 17:01
$begingroup$
Which formulation of Weyl's character formula do you mean? I recall it usually being given directly, rather than via a generating function.
$endgroup$
– Tobias Kildetoft
Mar 18 at 17:01
$begingroup$
@TobiasKildetoft For instance, if you expand $1/Delta(z)$ into a power series where $Delta(z)$ is a Weyl denominator, the coefficients of this series are the certain dimensions that I want.
$endgroup$
– Henry
Mar 19 at 19:35
$begingroup$
@TobiasKildetoft For instance, if you expand $1/Delta(z)$ into a power series where $Delta(z)$ is a Weyl denominator, the coefficients of this series are the certain dimensions that I want.
$endgroup$
– Henry
Mar 19 at 19:35
$begingroup$
As you write in your edit, it's the Kostant partition function: the number of ways to write $lambda-mu$ as a non-negative integer linear combination of positive roots. You won't get a better formula than that in general.
$endgroup$
– Stephen
Mar 20 at 22:54
$begingroup$
As you write in your edit, it's the Kostant partition function: the number of ways to write $lambda-mu$ as a non-negative integer linear combination of positive roots. You won't get a better formula than that in general.
$endgroup$
– Stephen
Mar 20 at 22:54
$begingroup$
@Stephen But isn't Kostant partition function piecewise polynomial? If an explicit form of the piecewise polynomial is known for, say, $A_n$, then that would be helpful.
$endgroup$
– Henry
Mar 20 at 23:18
$begingroup$
@Stephen But isn't Kostant partition function piecewise polynomial? If an explicit form of the piecewise polynomial is known for, say, $A_n$, then that would be helpful.
$endgroup$
– Henry
Mar 20 at 23:18
add a comment |
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$begingroup$
Which formulation of Weyl's character formula do you mean? I recall it usually being given directly, rather than via a generating function.
$endgroup$
– Tobias Kildetoft
Mar 18 at 17:01
$begingroup$
@TobiasKildetoft For instance, if you expand $1/Delta(z)$ into a power series where $Delta(z)$ is a Weyl denominator, the coefficients of this series are the certain dimensions that I want.
$endgroup$
– Henry
Mar 19 at 19:35
$begingroup$
As you write in your edit, it's the Kostant partition function: the number of ways to write $lambda-mu$ as a non-negative integer linear combination of positive roots. You won't get a better formula than that in general.
$endgroup$
– Stephen
Mar 20 at 22:54
$begingroup$
@Stephen But isn't Kostant partition function piecewise polynomial? If an explicit form of the piecewise polynomial is known for, say, $A_n$, then that would be helpful.
$endgroup$
– Henry
Mar 20 at 23:18