Planetary tidal locking causing asymetrical water distributionHow much water would remain at the poles of these planets?How can I catch an asteroid?Proxima Centauri and tidally locked planetsWhere on a tidally locked planet with a 25 °C maximum is the 0 °C isotherm?Tidal forces of tidally locked moon orbiting a gas giantWhat would wind currents and water cycle look like on a tidally locked planet?What's the longest plausible orbital period for a habitable planet with a 3:2 spin-orbit resonance?Could canals solve H G Wells Martians water shortage problems?Could these planetary circumstances occur?Is this model possible? Fast axial precession + tidal locking

Proving by induction of n. Is this correct until this point?

Is exact Kanji stroke length important?

Reply ‘no position’ while the job posting is still there (‘HiWi’ position in Germany)

Identify a stage play about a VR experience in which participants are encouraged to simulate performing horrific activities

What is the term when two people sing in harmony, but they aren't singing the same notes?

What is the opposite of 'gravitas'?

Taylor series of product of two functions

What was required to accept "troll"?

Does "Dominei" mean something?

I2C signal and power over long range (10meter cable)

Greatest common substring

How do I repair my stair bannister?

A known event to a history junkie

Golf game boilerplate

Visiting the UK as unmarried couple

How will losing mobility of one hand affect my career as a programmer?

Invariance of results when scaling explanatory variables in logistic regression, is there a proof?

Can I use my Chinese passport to enter China after I acquired another citizenship?

What is the oldest known work of fiction?

Lightning Web Component - do I need to track changes for every single input field in a form

Adding empty element to declared container without declaring type of element

Calculating the number of days between 2 dates in Excel

Would it be legal for a US State to ban exports of a natural resource?

Female=gender counterpart?



Planetary tidal locking causing asymetrical water distribution


How much water would remain at the poles of these planets?How can I catch an asteroid?Proxima Centauri and tidally locked planetsWhere on a tidally locked planet with a 25 °C maximum is the 0 °C isotherm?Tidal forces of tidally locked moon orbiting a gas giantWhat would wind currents and water cycle look like on a tidally locked planet?What's the longest plausible orbital period for a habitable planet with a 3:2 spin-orbit resonance?Could canals solve H G Wells Martians water shortage problems?Could these planetary circumstances occur?Is this model possible? Fast axial precession + tidal locking













4












$begingroup$


Imagine a planet of roughly the same size as Earth with the same amount of land, the same atmosphere and the same proportion of water (other planetary parameters may vary from Earth like) that has suddenly become gravitational locked so that one side always faces the sun.



Is there any scenario in which after a sufficiently long time large tracts of the ocean bed on the side facing the sun would be exposed to the atmosphere and all of the planets water would end up locked up in ice on the dark side? If so what special conditions would allow it and if not what processes would prevent this from happening?










share|improve this question









$endgroup$











  • $begingroup$
    Cold trap (astronomy).
    $endgroup$
    – AlexP
    Mar 16 at 18:07










  • $begingroup$
    physicsforums.com/threads/brown-dwarf-habitable-zones.875002 if you use a brown-dwarf in a binary star system to produce the tidal lock, it might be a place to start, maybe try placing the browndwarf+earth outside the habitable zone of the parent star. Though as the linked post suggests you'd likely find a great deal of 'rubble' close to the brown dwarf which, even if your planet had cleared it's own orbit, would help mitigate against any potential winds.
    $endgroup$
    – Giu Piete
    Mar 16 at 20:58











  • $begingroup$
    It seems to e that tidal locking is not the ONLY system that causes one side to always face 'in'. On the other hand, these systems would already have pre-ordained the distribution of water and land mass, and even atmosphere, such that the planet would have to have been custom built in the first place.
    $endgroup$
    – Justin Thyme
    Mar 17 at 15:07















4












$begingroup$


Imagine a planet of roughly the same size as Earth with the same amount of land, the same atmosphere and the same proportion of water (other planetary parameters may vary from Earth like) that has suddenly become gravitational locked so that one side always faces the sun.



Is there any scenario in which after a sufficiently long time large tracts of the ocean bed on the side facing the sun would be exposed to the atmosphere and all of the planets water would end up locked up in ice on the dark side? If so what special conditions would allow it and if not what processes would prevent this from happening?










share|improve this question









$endgroup$











  • $begingroup$
    Cold trap (astronomy).
    $endgroup$
    – AlexP
    Mar 16 at 18:07










  • $begingroup$
    physicsforums.com/threads/brown-dwarf-habitable-zones.875002 if you use a brown-dwarf in a binary star system to produce the tidal lock, it might be a place to start, maybe try placing the browndwarf+earth outside the habitable zone of the parent star. Though as the linked post suggests you'd likely find a great deal of 'rubble' close to the brown dwarf which, even if your planet had cleared it's own orbit, would help mitigate against any potential winds.
    $endgroup$
    – Giu Piete
    Mar 16 at 20:58











  • $begingroup$
    It seems to e that tidal locking is not the ONLY system that causes one side to always face 'in'. On the other hand, these systems would already have pre-ordained the distribution of water and land mass, and even atmosphere, such that the planet would have to have been custom built in the first place.
    $endgroup$
    – Justin Thyme
    Mar 17 at 15:07













4












4








4


1



$begingroup$


Imagine a planet of roughly the same size as Earth with the same amount of land, the same atmosphere and the same proportion of water (other planetary parameters may vary from Earth like) that has suddenly become gravitational locked so that one side always faces the sun.



Is there any scenario in which after a sufficiently long time large tracts of the ocean bed on the side facing the sun would be exposed to the atmosphere and all of the planets water would end up locked up in ice on the dark side? If so what special conditions would allow it and if not what processes would prevent this from happening?










share|improve this question









$endgroup$




Imagine a planet of roughly the same size as Earth with the same amount of land, the same atmosphere and the same proportion of water (other planetary parameters may vary from Earth like) that has suddenly become gravitational locked so that one side always faces the sun.



Is there any scenario in which after a sufficiently long time large tracts of the ocean bed on the side facing the sun would be exposed to the atmosphere and all of the planets water would end up locked up in ice on the dark side? If so what special conditions would allow it and if not what processes would prevent this from happening?







science-based planets environment climate






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 16 at 17:59









SlartySlarty

11.3k42664




11.3k42664











  • $begingroup$
    Cold trap (astronomy).
    $endgroup$
    – AlexP
    Mar 16 at 18:07










  • $begingroup$
    physicsforums.com/threads/brown-dwarf-habitable-zones.875002 if you use a brown-dwarf in a binary star system to produce the tidal lock, it might be a place to start, maybe try placing the browndwarf+earth outside the habitable zone of the parent star. Though as the linked post suggests you'd likely find a great deal of 'rubble' close to the brown dwarf which, even if your planet had cleared it's own orbit, would help mitigate against any potential winds.
    $endgroup$
    – Giu Piete
    Mar 16 at 20:58











  • $begingroup$
    It seems to e that tidal locking is not the ONLY system that causes one side to always face 'in'. On the other hand, these systems would already have pre-ordained the distribution of water and land mass, and even atmosphere, such that the planet would have to have been custom built in the first place.
    $endgroup$
    – Justin Thyme
    Mar 17 at 15:07
















  • $begingroup$
    Cold trap (astronomy).
    $endgroup$
    – AlexP
    Mar 16 at 18:07










  • $begingroup$
    physicsforums.com/threads/brown-dwarf-habitable-zones.875002 if you use a brown-dwarf in a binary star system to produce the tidal lock, it might be a place to start, maybe try placing the browndwarf+earth outside the habitable zone of the parent star. Though as the linked post suggests you'd likely find a great deal of 'rubble' close to the brown dwarf which, even if your planet had cleared it's own orbit, would help mitigate against any potential winds.
    $endgroup$
    – Giu Piete
    Mar 16 at 20:58











  • $begingroup$
    It seems to e that tidal locking is not the ONLY system that causes one side to always face 'in'. On the other hand, these systems would already have pre-ordained the distribution of water and land mass, and even atmosphere, such that the planet would have to have been custom built in the first place.
    $endgroup$
    – Justin Thyme
    Mar 17 at 15:07















$begingroup$
Cold trap (astronomy).
$endgroup$
– AlexP
Mar 16 at 18:07




$begingroup$
Cold trap (astronomy).
$endgroup$
– AlexP
Mar 16 at 18:07












$begingroup$
physicsforums.com/threads/brown-dwarf-habitable-zones.875002 if you use a brown-dwarf in a binary star system to produce the tidal lock, it might be a place to start, maybe try placing the browndwarf+earth outside the habitable zone of the parent star. Though as the linked post suggests you'd likely find a great deal of 'rubble' close to the brown dwarf which, even if your planet had cleared it's own orbit, would help mitigate against any potential winds.
$endgroup$
– Giu Piete
Mar 16 at 20:58





$begingroup$
physicsforums.com/threads/brown-dwarf-habitable-zones.875002 if you use a brown-dwarf in a binary star system to produce the tidal lock, it might be a place to start, maybe try placing the browndwarf+earth outside the habitable zone of the parent star. Though as the linked post suggests you'd likely find a great deal of 'rubble' close to the brown dwarf which, even if your planet had cleared it's own orbit, would help mitigate against any potential winds.
$endgroup$
– Giu Piete
Mar 16 at 20:58













$begingroup$
It seems to e that tidal locking is not the ONLY system that causes one side to always face 'in'. On the other hand, these systems would already have pre-ordained the distribution of water and land mass, and even atmosphere, such that the planet would have to have been custom built in the first place.
$endgroup$
– Justin Thyme
Mar 17 at 15:07




$begingroup$
It seems to e that tidal locking is not the ONLY system that causes one side to always face 'in'. On the other hand, these systems would already have pre-ordained the distribution of water and land mass, and even atmosphere, such that the planet would have to have been custom built in the first place.
$endgroup$
– Justin Thyme
Mar 17 at 15:07










2 Answers
2






active

oldest

votes


















7












$begingroup$

Researchers have modeled this very question



See their Figure 1:



Figure 1. Diagram showing amount of water for three different types of planets.



Apparently there are 3 relevant variables: less water, less geothermal heat flux, and more night-side continental area will increase the effect. Geothermal heat flux is how fast heat from the planet's core reaches the surface.



According to them, if earth became tidally locked, roughly half of the oceans would freeze. If you want to increase the effect with the same amount of water, simply change the other two variables: continents are more concentrated and end up on the night side, and they don't get much heat from the core.



And Now the Part Where I Ruin Your Day



However if the tidal locking is natural, this scenario has big problems. In order to move the habitable zone close enough to the star for tidal locking, it has to be a small red dwarf star. While long lived, young red dwarfs throw lots of huge magnetic and radiation flare tantrums. For a planet's atmosphere to not get blasted off during puberty, it has to have a very strong magnetic field -- think a fast or a huge electric generator. But unfortunately, tidally locked planets spin very slowly. That means you need a larger super-earth type planet to generate that field. You might be able to roll with that, but the kicker is that your powerful magnetic generator also makes a ton more geothermal heat to melt your ice. Maybe the planet's core is lined with space shuttle thermal tiles?



But Wait, It Gets Worse



A comment on another answer indicated a bigger question, about the ice cap swinging toward the sun. Unfortunately that's a no-go. Apart from the fact that surface water is only about 0.02% of the earth's mass, tidal forces relative to the center of the earth are actually away as well as toward:



Relative Tidal Directions



In the left picture, imagine subtracting the center average arrow from the outside arrows to get the effect from earth's perspective. It's not quite as much on the backside, but the icecap still won't be interested in wandering past those side parts. Sorry pal.






share|improve this answer









$endgroup$








  • 1




    $begingroup$
    If a pear shaped object was orbiting the sun which end would face the sun?
    $endgroup$
    – Slarty
    Mar 16 at 23:02










  • $begingroup$
    I'm pretty sure that if the pointy end settles at a local maximum of gravitational force, it will not move to the global maximum unless perturbed.
    $endgroup$
    – BoomChuck
    Mar 17 at 12:47



















1












$begingroup$

Yes -- this scenario is definitely possible. Climate models for tidally-locked planets find that for planets with relatively thin atmospheres with modest amounts of water, it can indeed all be trapped on the dark side of the planet as ice (technical references here and here).



With a bit more water or a bit thicker atmosphere you can have an Eyeball planet with enough water that the zone of permanent sunset/sunrise (what I called the "ring of life") can be quite pleasant. See here for an explanation of that type of hot Eyeball planet. There also exist cold Eyeball planets with lots of water (see here). A good candidate for an Eyeball planet is Proxima b.






share|improve this answer









$endgroup$












  • $begingroup$
    My concern would be for a planet with as much water as Earth that the huge ice build-up on the dark side would eventually destabilise the tidal locking causing the planet to "flip around" so the massive ice bulge faces the sun.
    $endgroup$
    – Slarty
    Mar 16 at 18:32






  • 1




    $begingroup$
    @Slarty Tide pulls the near side in and the far side out, so it seems to me that such an asymmetry would reinforce the locking.
    $endgroup$
    – Anton Sherwood
    Mar 16 at 20:37










Your Answer





StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "579"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fworldbuilding.stackexchange.com%2fquestions%2f141644%2fplanetary-tidal-locking-causing-asymetrical-water-distribution%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









7












$begingroup$

Researchers have modeled this very question



See their Figure 1:



Figure 1. Diagram showing amount of water for three different types of planets.



Apparently there are 3 relevant variables: less water, less geothermal heat flux, and more night-side continental area will increase the effect. Geothermal heat flux is how fast heat from the planet's core reaches the surface.



According to them, if earth became tidally locked, roughly half of the oceans would freeze. If you want to increase the effect with the same amount of water, simply change the other two variables: continents are more concentrated and end up on the night side, and they don't get much heat from the core.



And Now the Part Where I Ruin Your Day



However if the tidal locking is natural, this scenario has big problems. In order to move the habitable zone close enough to the star for tidal locking, it has to be a small red dwarf star. While long lived, young red dwarfs throw lots of huge magnetic and radiation flare tantrums. For a planet's atmosphere to not get blasted off during puberty, it has to have a very strong magnetic field -- think a fast or a huge electric generator. But unfortunately, tidally locked planets spin very slowly. That means you need a larger super-earth type planet to generate that field. You might be able to roll with that, but the kicker is that your powerful magnetic generator also makes a ton more geothermal heat to melt your ice. Maybe the planet's core is lined with space shuttle thermal tiles?



But Wait, It Gets Worse



A comment on another answer indicated a bigger question, about the ice cap swinging toward the sun. Unfortunately that's a no-go. Apart from the fact that surface water is only about 0.02% of the earth's mass, tidal forces relative to the center of the earth are actually away as well as toward:



Relative Tidal Directions



In the left picture, imagine subtracting the center average arrow from the outside arrows to get the effect from earth's perspective. It's not quite as much on the backside, but the icecap still won't be interested in wandering past those side parts. Sorry pal.






share|improve this answer









$endgroup$








  • 1




    $begingroup$
    If a pear shaped object was orbiting the sun which end would face the sun?
    $endgroup$
    – Slarty
    Mar 16 at 23:02










  • $begingroup$
    I'm pretty sure that if the pointy end settles at a local maximum of gravitational force, it will not move to the global maximum unless perturbed.
    $endgroup$
    – BoomChuck
    Mar 17 at 12:47
















7












$begingroup$

Researchers have modeled this very question



See their Figure 1:



Figure 1. Diagram showing amount of water for three different types of planets.



Apparently there are 3 relevant variables: less water, less geothermal heat flux, and more night-side continental area will increase the effect. Geothermal heat flux is how fast heat from the planet's core reaches the surface.



According to them, if earth became tidally locked, roughly half of the oceans would freeze. If you want to increase the effect with the same amount of water, simply change the other two variables: continents are more concentrated and end up on the night side, and they don't get much heat from the core.



And Now the Part Where I Ruin Your Day



However if the tidal locking is natural, this scenario has big problems. In order to move the habitable zone close enough to the star for tidal locking, it has to be a small red dwarf star. While long lived, young red dwarfs throw lots of huge magnetic and radiation flare tantrums. For a planet's atmosphere to not get blasted off during puberty, it has to have a very strong magnetic field -- think a fast or a huge electric generator. But unfortunately, tidally locked planets spin very slowly. That means you need a larger super-earth type planet to generate that field. You might be able to roll with that, but the kicker is that your powerful magnetic generator also makes a ton more geothermal heat to melt your ice. Maybe the planet's core is lined with space shuttle thermal tiles?



But Wait, It Gets Worse



A comment on another answer indicated a bigger question, about the ice cap swinging toward the sun. Unfortunately that's a no-go. Apart from the fact that surface water is only about 0.02% of the earth's mass, tidal forces relative to the center of the earth are actually away as well as toward:



Relative Tidal Directions



In the left picture, imagine subtracting the center average arrow from the outside arrows to get the effect from earth's perspective. It's not quite as much on the backside, but the icecap still won't be interested in wandering past those side parts. Sorry pal.






share|improve this answer









$endgroup$








  • 1




    $begingroup$
    If a pear shaped object was orbiting the sun which end would face the sun?
    $endgroup$
    – Slarty
    Mar 16 at 23:02










  • $begingroup$
    I'm pretty sure that if the pointy end settles at a local maximum of gravitational force, it will not move to the global maximum unless perturbed.
    $endgroup$
    – BoomChuck
    Mar 17 at 12:47














7












7








7





$begingroup$

Researchers have modeled this very question



See their Figure 1:



Figure 1. Diagram showing amount of water for three different types of planets.



Apparently there are 3 relevant variables: less water, less geothermal heat flux, and more night-side continental area will increase the effect. Geothermal heat flux is how fast heat from the planet's core reaches the surface.



According to them, if earth became tidally locked, roughly half of the oceans would freeze. If you want to increase the effect with the same amount of water, simply change the other two variables: continents are more concentrated and end up on the night side, and they don't get much heat from the core.



And Now the Part Where I Ruin Your Day



However if the tidal locking is natural, this scenario has big problems. In order to move the habitable zone close enough to the star for tidal locking, it has to be a small red dwarf star. While long lived, young red dwarfs throw lots of huge magnetic and radiation flare tantrums. For a planet's atmosphere to not get blasted off during puberty, it has to have a very strong magnetic field -- think a fast or a huge electric generator. But unfortunately, tidally locked planets spin very slowly. That means you need a larger super-earth type planet to generate that field. You might be able to roll with that, but the kicker is that your powerful magnetic generator also makes a ton more geothermal heat to melt your ice. Maybe the planet's core is lined with space shuttle thermal tiles?



But Wait, It Gets Worse



A comment on another answer indicated a bigger question, about the ice cap swinging toward the sun. Unfortunately that's a no-go. Apart from the fact that surface water is only about 0.02% of the earth's mass, tidal forces relative to the center of the earth are actually away as well as toward:



Relative Tidal Directions



In the left picture, imagine subtracting the center average arrow from the outside arrows to get the effect from earth's perspective. It's not quite as much on the backside, but the icecap still won't be interested in wandering past those side parts. Sorry pal.






share|improve this answer









$endgroup$



Researchers have modeled this very question



See their Figure 1:



Figure 1. Diagram showing amount of water for three different types of planets.



Apparently there are 3 relevant variables: less water, less geothermal heat flux, and more night-side continental area will increase the effect. Geothermal heat flux is how fast heat from the planet's core reaches the surface.



According to them, if earth became tidally locked, roughly half of the oceans would freeze. If you want to increase the effect with the same amount of water, simply change the other two variables: continents are more concentrated and end up on the night side, and they don't get much heat from the core.



And Now the Part Where I Ruin Your Day



However if the tidal locking is natural, this scenario has big problems. In order to move the habitable zone close enough to the star for tidal locking, it has to be a small red dwarf star. While long lived, young red dwarfs throw lots of huge magnetic and radiation flare tantrums. For a planet's atmosphere to not get blasted off during puberty, it has to have a very strong magnetic field -- think a fast or a huge electric generator. But unfortunately, tidally locked planets spin very slowly. That means you need a larger super-earth type planet to generate that field. You might be able to roll with that, but the kicker is that your powerful magnetic generator also makes a ton more geothermal heat to melt your ice. Maybe the planet's core is lined with space shuttle thermal tiles?



But Wait, It Gets Worse



A comment on another answer indicated a bigger question, about the ice cap swinging toward the sun. Unfortunately that's a no-go. Apart from the fact that surface water is only about 0.02% of the earth's mass, tidal forces relative to the center of the earth are actually away as well as toward:



Relative Tidal Directions



In the left picture, imagine subtracting the center average arrow from the outside arrows to get the effect from earth's perspective. It's not quite as much on the backside, but the icecap still won't be interested in wandering past those side parts. Sorry pal.







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 16 at 20:35









BoomChuckBoomChuck

2,2771415




2,2771415







  • 1




    $begingroup$
    If a pear shaped object was orbiting the sun which end would face the sun?
    $endgroup$
    – Slarty
    Mar 16 at 23:02










  • $begingroup$
    I'm pretty sure that if the pointy end settles at a local maximum of gravitational force, it will not move to the global maximum unless perturbed.
    $endgroup$
    – BoomChuck
    Mar 17 at 12:47













  • 1




    $begingroup$
    If a pear shaped object was orbiting the sun which end would face the sun?
    $endgroup$
    – Slarty
    Mar 16 at 23:02










  • $begingroup$
    I'm pretty sure that if the pointy end settles at a local maximum of gravitational force, it will not move to the global maximum unless perturbed.
    $endgroup$
    – BoomChuck
    Mar 17 at 12:47








1




1




$begingroup$
If a pear shaped object was orbiting the sun which end would face the sun?
$endgroup$
– Slarty
Mar 16 at 23:02




$begingroup$
If a pear shaped object was orbiting the sun which end would face the sun?
$endgroup$
– Slarty
Mar 16 at 23:02












$begingroup$
I'm pretty sure that if the pointy end settles at a local maximum of gravitational force, it will not move to the global maximum unless perturbed.
$endgroup$
– BoomChuck
Mar 17 at 12:47





$begingroup$
I'm pretty sure that if the pointy end settles at a local maximum of gravitational force, it will not move to the global maximum unless perturbed.
$endgroup$
– BoomChuck
Mar 17 at 12:47












1












$begingroup$

Yes -- this scenario is definitely possible. Climate models for tidally-locked planets find that for planets with relatively thin atmospheres with modest amounts of water, it can indeed all be trapped on the dark side of the planet as ice (technical references here and here).



With a bit more water or a bit thicker atmosphere you can have an Eyeball planet with enough water that the zone of permanent sunset/sunrise (what I called the "ring of life") can be quite pleasant. See here for an explanation of that type of hot Eyeball planet. There also exist cold Eyeball planets with lots of water (see here). A good candidate for an Eyeball planet is Proxima b.






share|improve this answer









$endgroup$












  • $begingroup$
    My concern would be for a planet with as much water as Earth that the huge ice build-up on the dark side would eventually destabilise the tidal locking causing the planet to "flip around" so the massive ice bulge faces the sun.
    $endgroup$
    – Slarty
    Mar 16 at 18:32






  • 1




    $begingroup$
    @Slarty Tide pulls the near side in and the far side out, so it seems to me that such an asymmetry would reinforce the locking.
    $endgroup$
    – Anton Sherwood
    Mar 16 at 20:37















1












$begingroup$

Yes -- this scenario is definitely possible. Climate models for tidally-locked planets find that for planets with relatively thin atmospheres with modest amounts of water, it can indeed all be trapped on the dark side of the planet as ice (technical references here and here).



With a bit more water or a bit thicker atmosphere you can have an Eyeball planet with enough water that the zone of permanent sunset/sunrise (what I called the "ring of life") can be quite pleasant. See here for an explanation of that type of hot Eyeball planet. There also exist cold Eyeball planets with lots of water (see here). A good candidate for an Eyeball planet is Proxima b.






share|improve this answer









$endgroup$












  • $begingroup$
    My concern would be for a planet with as much water as Earth that the huge ice build-up on the dark side would eventually destabilise the tidal locking causing the planet to "flip around" so the massive ice bulge faces the sun.
    $endgroup$
    – Slarty
    Mar 16 at 18:32






  • 1




    $begingroup$
    @Slarty Tide pulls the near side in and the far side out, so it seems to me that such an asymmetry would reinforce the locking.
    $endgroup$
    – Anton Sherwood
    Mar 16 at 20:37













1












1








1





$begingroup$

Yes -- this scenario is definitely possible. Climate models for tidally-locked planets find that for planets with relatively thin atmospheres with modest amounts of water, it can indeed all be trapped on the dark side of the planet as ice (technical references here and here).



With a bit more water or a bit thicker atmosphere you can have an Eyeball planet with enough water that the zone of permanent sunset/sunrise (what I called the "ring of life") can be quite pleasant. See here for an explanation of that type of hot Eyeball planet. There also exist cold Eyeball planets with lots of water (see here). A good candidate for an Eyeball planet is Proxima b.






share|improve this answer









$endgroup$



Yes -- this scenario is definitely possible. Climate models for tidally-locked planets find that for planets with relatively thin atmospheres with modest amounts of water, it can indeed all be trapped on the dark side of the planet as ice (technical references here and here).



With a bit more water or a bit thicker atmosphere you can have an Eyeball planet with enough water that the zone of permanent sunset/sunrise (what I called the "ring of life") can be quite pleasant. See here for an explanation of that type of hot Eyeball planet. There also exist cold Eyeball planets with lots of water (see here). A good candidate for an Eyeball planet is Proxima b.







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 16 at 18:21









Sean RaymondSean Raymond

3,071721




3,071721











  • $begingroup$
    My concern would be for a planet with as much water as Earth that the huge ice build-up on the dark side would eventually destabilise the tidal locking causing the planet to "flip around" so the massive ice bulge faces the sun.
    $endgroup$
    – Slarty
    Mar 16 at 18:32






  • 1




    $begingroup$
    @Slarty Tide pulls the near side in and the far side out, so it seems to me that such an asymmetry would reinforce the locking.
    $endgroup$
    – Anton Sherwood
    Mar 16 at 20:37
















  • $begingroup$
    My concern would be for a planet with as much water as Earth that the huge ice build-up on the dark side would eventually destabilise the tidal locking causing the planet to "flip around" so the massive ice bulge faces the sun.
    $endgroup$
    – Slarty
    Mar 16 at 18:32






  • 1




    $begingroup$
    @Slarty Tide pulls the near side in and the far side out, so it seems to me that such an asymmetry would reinforce the locking.
    $endgroup$
    – Anton Sherwood
    Mar 16 at 20:37















$begingroup$
My concern would be for a planet with as much water as Earth that the huge ice build-up on the dark side would eventually destabilise the tidal locking causing the planet to "flip around" so the massive ice bulge faces the sun.
$endgroup$
– Slarty
Mar 16 at 18:32




$begingroup$
My concern would be for a planet with as much water as Earth that the huge ice build-up on the dark side would eventually destabilise the tidal locking causing the planet to "flip around" so the massive ice bulge faces the sun.
$endgroup$
– Slarty
Mar 16 at 18:32




1




1




$begingroup$
@Slarty Tide pulls the near side in and the far side out, so it seems to me that such an asymmetry would reinforce the locking.
$endgroup$
– Anton Sherwood
Mar 16 at 20:37




$begingroup$
@Slarty Tide pulls the near side in and the far side out, so it seems to me that such an asymmetry would reinforce the locking.
$endgroup$
– Anton Sherwood
Mar 16 at 20:37

















draft saved

draft discarded
















































Thanks for contributing an answer to Worldbuilding Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fworldbuilding.stackexchange.com%2fquestions%2f141644%2fplanetary-tidal-locking-causing-asymetrical-water-distribution%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Lowndes Grove History Architecture References Navigation menu32°48′6″N 79°57′58″W / 32.80167°N 79.96611°W / 32.80167; -79.9661132°48′6″N 79°57′58″W / 32.80167°N 79.96611°W / 32.80167; -79.9661178002500"National Register Information System"Historic houses of South Carolina"Lowndes Grove""+32° 48' 6.00", −79° 57' 58.00""Lowndes Grove, Charleston County (260 St. Margaret St., Charleston)""Lowndes Grove"The Charleston ExpositionIt Happened in South Carolina"Lowndes Grove (House), Saint Margaret Street & Sixth Avenue, Charleston, Charleston County, SC(Photographs)"Plantations of the Carolina Low Countrye

random experiment with two different functions on unit interval Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Random variable and probability space notionsRandom Walk with EdgesFinding functions where the increase over a random interval is Poisson distributedNumber of days until dayCan an observed event in fact be of zero probability?Unit random processmodels of coins and uniform distributionHow to get the number of successes given $n$ trials , probability $P$ and a random variable $X$Absorbing Markov chain in a computer. Is “almost every” turned into always convergence in computer executions?Stopped random walk is not uniformly integrable

How should I support this large drywall patch? Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?How do I cover large gaps in drywall?How do I keep drywall around a patch from crumbling?Can I glue a second layer of drywall?How to patch long strip on drywall?Large drywall patch: how to avoid bulging seams?Drywall Mesh Patch vs. Bulge? To remove or not to remove?How to fix this drywall job?Prep drywall before backsplashWhat's the best way to fix this horrible drywall patch job?Drywall patching using 3M Patch Plus Primer