Pencil and fundamental groupFundamental group of the torusProof of the existence of Lefschetz Pencils.A “trivial” implication I don't understand.Fundamental group of two Moebius bands identified on boundary circlesConnecting fundamental groups and group actionsDetails for calculating the fundamental group of mapping torusFundamental group of the $T^1 cup D^2$Van Kampen Theorem shows $pi_1(S^1 vee S^1)cong mathbbZ * mathbbZ$ and $pi_1(S^n) cong left1right$ for $ngeq 2$.Induced homomorphism between fundamental groupsThe fundamental group of the Lattice - (R x Z) U (Z x R)
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Pencil and fundamental group
Fundamental group of the torusProof of the existence of Lefschetz Pencils.A “trivial” implication I don't understand.Fundamental group of two Moebius bands identified on boundary circlesConnecting fundamental groups and group actionsDetails for calculating the fundamental group of mapping torusFundamental group of the $T^1 cup D^2$Van Kampen Theorem shows $pi_1(S^1 vee S^1)cong mathbbZ * mathbbZ$ and $pi_1(S^n) cong left1right$ for $ngeq 2$.Induced homomorphism between fundamental groupsThe fundamental group of the Lattice - (R x Z) U (Z x R)
$begingroup$
Let $f_i(x,y,z)$ be a homogeneous polynomial of degree $i$. Then for pencil $C_a,b=a(f_2)^3+b(f_3)^2$, we have a map $phi:mathbbCP^2setminus Bto mathbbCP^1$, where $B$ is the base locus of pencil $C_a,b$, and the map is given by $[x,y,z]mapsto [a,b]=[(f_3)^2(x,y,z):(f_2)^3(x,y,z)]$.
Let $C$ be the union $phi^−1(1,0)cup phi^−1(0,1)cupphi^−1 (1,1)$ and let $L$ be a line containing only smooth points of $C$ and transversal to $C$.
Then how to see the map: $pi_1(Lsetminus Lcap C)topi_1(mathbbCP^2setminus C)$ induced by inclusion is surjective? Moreover, how to compute these two fundamental groups?
I guess we can use Lefschetz hyperplane theorem to deduce the surjection. But can't go further .
algebraic-geometry algebraic-topology projective-space fundamental-groups
$endgroup$
add a comment |
$begingroup$
Let $f_i(x,y,z)$ be a homogeneous polynomial of degree $i$. Then for pencil $C_a,b=a(f_2)^3+b(f_3)^2$, we have a map $phi:mathbbCP^2setminus Bto mathbbCP^1$, where $B$ is the base locus of pencil $C_a,b$, and the map is given by $[x,y,z]mapsto [a,b]=[(f_3)^2(x,y,z):(f_2)^3(x,y,z)]$.
Let $C$ be the union $phi^−1(1,0)cup phi^−1(0,1)cupphi^−1 (1,1)$ and let $L$ be a line containing only smooth points of $C$ and transversal to $C$.
Then how to see the map: $pi_1(Lsetminus Lcap C)topi_1(mathbbCP^2setminus C)$ induced by inclusion is surjective? Moreover, how to compute these two fundamental groups?
I guess we can use Lefschetz hyperplane theorem to deduce the surjection. But can't go further .
algebraic-geometry algebraic-topology projective-space fundamental-groups
$endgroup$
$begingroup$
I should also say that it can be very complicated to describe the fundamental group of $mathbbCP^2 setminus C$ where $C$ is an algebraic curve if $C$ is singular, the group will depend on the precise singularities that the curve (it is still not completely understood). However, if $C$ is a degree $d$ smooth curve in $mathbbCP^2$ then $pi_1(mathbbCP^2 setminus C) cong mathbbZ_d$
$endgroup$
– Nick L
2 days ago
$begingroup$
@NickL $f_3$ has degree $3$, and $f_3^2$ has degree $6$
$endgroup$
– 6666
2 days ago
$begingroup$
I see, I will delete my first comment.
$endgroup$
– Nick L
2 days ago
add a comment |
$begingroup$
Let $f_i(x,y,z)$ be a homogeneous polynomial of degree $i$. Then for pencil $C_a,b=a(f_2)^3+b(f_3)^2$, we have a map $phi:mathbbCP^2setminus Bto mathbbCP^1$, where $B$ is the base locus of pencil $C_a,b$, and the map is given by $[x,y,z]mapsto [a,b]=[(f_3)^2(x,y,z):(f_2)^3(x,y,z)]$.
Let $C$ be the union $phi^−1(1,0)cup phi^−1(0,1)cupphi^−1 (1,1)$ and let $L$ be a line containing only smooth points of $C$ and transversal to $C$.
Then how to see the map: $pi_1(Lsetminus Lcap C)topi_1(mathbbCP^2setminus C)$ induced by inclusion is surjective? Moreover, how to compute these two fundamental groups?
I guess we can use Lefschetz hyperplane theorem to deduce the surjection. But can't go further .
algebraic-geometry algebraic-topology projective-space fundamental-groups
$endgroup$
Let $f_i(x,y,z)$ be a homogeneous polynomial of degree $i$. Then for pencil $C_a,b=a(f_2)^3+b(f_3)^2$, we have a map $phi:mathbbCP^2setminus Bto mathbbCP^1$, where $B$ is the base locus of pencil $C_a,b$, and the map is given by $[x,y,z]mapsto [a,b]=[(f_3)^2(x,y,z):(f_2)^3(x,y,z)]$.
Let $C$ be the union $phi^−1(1,0)cup phi^−1(0,1)cupphi^−1 (1,1)$ and let $L$ be a line containing only smooth points of $C$ and transversal to $C$.
Then how to see the map: $pi_1(Lsetminus Lcap C)topi_1(mathbbCP^2setminus C)$ induced by inclusion is surjective? Moreover, how to compute these two fundamental groups?
I guess we can use Lefschetz hyperplane theorem to deduce the surjection. But can't go further .
algebraic-geometry algebraic-topology projective-space fundamental-groups
algebraic-geometry algebraic-topology projective-space fundamental-groups
edited Mar 16 at 21:38
6666
asked Mar 16 at 20:56
66666666
1,375621
1,375621
$begingroup$
I should also say that it can be very complicated to describe the fundamental group of $mathbbCP^2 setminus C$ where $C$ is an algebraic curve if $C$ is singular, the group will depend on the precise singularities that the curve (it is still not completely understood). However, if $C$ is a degree $d$ smooth curve in $mathbbCP^2$ then $pi_1(mathbbCP^2 setminus C) cong mathbbZ_d$
$endgroup$
– Nick L
2 days ago
$begingroup$
@NickL $f_3$ has degree $3$, and $f_3^2$ has degree $6$
$endgroup$
– 6666
2 days ago
$begingroup$
I see, I will delete my first comment.
$endgroup$
– Nick L
2 days ago
add a comment |
$begingroup$
I should also say that it can be very complicated to describe the fundamental group of $mathbbCP^2 setminus C$ where $C$ is an algebraic curve if $C$ is singular, the group will depend on the precise singularities that the curve (it is still not completely understood). However, if $C$ is a degree $d$ smooth curve in $mathbbCP^2$ then $pi_1(mathbbCP^2 setminus C) cong mathbbZ_d$
$endgroup$
– Nick L
2 days ago
$begingroup$
@NickL $f_3$ has degree $3$, and $f_3^2$ has degree $6$
$endgroup$
– 6666
2 days ago
$begingroup$
I see, I will delete my first comment.
$endgroup$
– Nick L
2 days ago
$begingroup$
I should also say that it can be very complicated to describe the fundamental group of $mathbbCP^2 setminus C$ where $C$ is an algebraic curve if $C$ is singular, the group will depend on the precise singularities that the curve (it is still not completely understood). However, if $C$ is a degree $d$ smooth curve in $mathbbCP^2$ then $pi_1(mathbbCP^2 setminus C) cong mathbbZ_d$
$endgroup$
– Nick L
2 days ago
$begingroup$
I should also say that it can be very complicated to describe the fundamental group of $mathbbCP^2 setminus C$ where $C$ is an algebraic curve if $C$ is singular, the group will depend on the precise singularities that the curve (it is still not completely understood). However, if $C$ is a degree $d$ smooth curve in $mathbbCP^2$ then $pi_1(mathbbCP^2 setminus C) cong mathbbZ_d$
$endgroup$
– Nick L
2 days ago
$begingroup$
@NickL $f_3$ has degree $3$, and $f_3^2$ has degree $6$
$endgroup$
– 6666
2 days ago
$begingroup$
@NickL $f_3$ has degree $3$, and $f_3^2$ has degree $6$
$endgroup$
– 6666
2 days ago
$begingroup$
I see, I will delete my first comment.
$endgroup$
– Nick L
2 days ago
$begingroup$
I see, I will delete my first comment.
$endgroup$
– Nick L
2 days ago
add a comment |
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$begingroup$
I should also say that it can be very complicated to describe the fundamental group of $mathbbCP^2 setminus C$ where $C$ is an algebraic curve if $C$ is singular, the group will depend on the precise singularities that the curve (it is still not completely understood). However, if $C$ is a degree $d$ smooth curve in $mathbbCP^2$ then $pi_1(mathbbCP^2 setminus C) cong mathbbZ_d$
$endgroup$
– Nick L
2 days ago
$begingroup$
@NickL $f_3$ has degree $3$, and $f_3^2$ has degree $6$
$endgroup$
– 6666
2 days ago
$begingroup$
I see, I will delete my first comment.
$endgroup$
– Nick L
2 days ago