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Solve symbolic Sylvester-like equation in MATLAB or MAPLE


Differentiation of a parametric function using MATLAB or MapleSolving symbolic linear equations with mapleTurning Matrix Equation into a Sylvester EquationSolving integral equation in matlabSolve intregal equation using MATLABWorking with Maple toolbox for MatlabSolving a Sylvester equation - Won't give me the right answer in MATLABNonlinear Sylvester-like equationEquation of two Matlab function filesUsing MATLAB to solve Poisson matrix equation













0












$begingroup$


I'm looking for a way to solve a symbolic Sylvester-like equation in MATLAB or MAPLE (or any other available tool). In particular, I have the following equation,



$$AX+XA=B$$



where, $A$ has some parameters in it, e.g.,



$$A=beginbmatrixa+1 & 2\3 & 1endbmatrix$$



$B$ is known and I want to solve for $X$ as a function of $a$.










share|cite|improve this question











$endgroup$











  • $begingroup$
    Matlab has now a "sylvester" function uk.mathworks.com/help/matlab/ref/sylvester.html
    $endgroup$
    – Jean Marie
    Mar 11 at 21:41










  • $begingroup$
    Why not use vectorization?
    $endgroup$
    – Rodrigo de Azevedo
    Mar 11 at 21:45










  • $begingroup$
    @JeanMarie Yes, but the input arguments must be numeric arrays.
    $endgroup$
    – Mohammad
    Mar 11 at 21:46










  • $begingroup$
    @RodrigodeAzevedo Can you please describe more?
    $endgroup$
    – Mohammad
    Mar 11 at 21:46










  • $begingroup$
    Vectorization converts the matrix equation into a system of $4$ linear equations in $4$ unknowns, which is easy to solve symbolically. In MATLAB, use kron for the Kronecker product and reshape for the vectorization and un-vectorization.
    $endgroup$
    – Rodrigo de Azevedo
    Mar 11 at 21:48
















0












$begingroup$


I'm looking for a way to solve a symbolic Sylvester-like equation in MATLAB or MAPLE (or any other available tool). In particular, I have the following equation,



$$AX+XA=B$$



where, $A$ has some parameters in it, e.g.,



$$A=beginbmatrixa+1 & 2\3 & 1endbmatrix$$



$B$ is known and I want to solve for $X$ as a function of $a$.










share|cite|improve this question











$endgroup$











  • $begingroup$
    Matlab has now a "sylvester" function uk.mathworks.com/help/matlab/ref/sylvester.html
    $endgroup$
    – Jean Marie
    Mar 11 at 21:41










  • $begingroup$
    Why not use vectorization?
    $endgroup$
    – Rodrigo de Azevedo
    Mar 11 at 21:45










  • $begingroup$
    @JeanMarie Yes, but the input arguments must be numeric arrays.
    $endgroup$
    – Mohammad
    Mar 11 at 21:46










  • $begingroup$
    @RodrigodeAzevedo Can you please describe more?
    $endgroup$
    – Mohammad
    Mar 11 at 21:46










  • $begingroup$
    Vectorization converts the matrix equation into a system of $4$ linear equations in $4$ unknowns, which is easy to solve symbolically. In MATLAB, use kron for the Kronecker product and reshape for the vectorization and un-vectorization.
    $endgroup$
    – Rodrigo de Azevedo
    Mar 11 at 21:48














0












0








0





$begingroup$


I'm looking for a way to solve a symbolic Sylvester-like equation in MATLAB or MAPLE (or any other available tool). In particular, I have the following equation,



$$AX+XA=B$$



where, $A$ has some parameters in it, e.g.,



$$A=beginbmatrixa+1 & 2\3 & 1endbmatrix$$



$B$ is known and I want to solve for $X$ as a function of $a$.










share|cite|improve this question











$endgroup$




I'm looking for a way to solve a symbolic Sylvester-like equation in MATLAB or MAPLE (or any other available tool). In particular, I have the following equation,



$$AX+XA=B$$



where, $A$ has some parameters in it, e.g.,



$$A=beginbmatrixa+1 & 2\3 & 1endbmatrix$$



$B$ is known and I want to solve for $X$ as a function of $a$.







matrix-equations matlab maple sylvester-equation






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 11 at 21:44









Rodrigo de Azevedo

13k41960




13k41960










asked Mar 11 at 21:09









MohammadMohammad

206




206











  • $begingroup$
    Matlab has now a "sylvester" function uk.mathworks.com/help/matlab/ref/sylvester.html
    $endgroup$
    – Jean Marie
    Mar 11 at 21:41










  • $begingroup$
    Why not use vectorization?
    $endgroup$
    – Rodrigo de Azevedo
    Mar 11 at 21:45










  • $begingroup$
    @JeanMarie Yes, but the input arguments must be numeric arrays.
    $endgroup$
    – Mohammad
    Mar 11 at 21:46










  • $begingroup$
    @RodrigodeAzevedo Can you please describe more?
    $endgroup$
    – Mohammad
    Mar 11 at 21:46










  • $begingroup$
    Vectorization converts the matrix equation into a system of $4$ linear equations in $4$ unknowns, which is easy to solve symbolically. In MATLAB, use kron for the Kronecker product and reshape for the vectorization and un-vectorization.
    $endgroup$
    – Rodrigo de Azevedo
    Mar 11 at 21:48

















  • $begingroup$
    Matlab has now a "sylvester" function uk.mathworks.com/help/matlab/ref/sylvester.html
    $endgroup$
    – Jean Marie
    Mar 11 at 21:41










  • $begingroup$
    Why not use vectorization?
    $endgroup$
    – Rodrigo de Azevedo
    Mar 11 at 21:45










  • $begingroup$
    @JeanMarie Yes, but the input arguments must be numeric arrays.
    $endgroup$
    – Mohammad
    Mar 11 at 21:46










  • $begingroup$
    @RodrigodeAzevedo Can you please describe more?
    $endgroup$
    – Mohammad
    Mar 11 at 21:46










  • $begingroup$
    Vectorization converts the matrix equation into a system of $4$ linear equations in $4$ unknowns, which is easy to solve symbolically. In MATLAB, use kron for the Kronecker product and reshape for the vectorization and un-vectorization.
    $endgroup$
    – Rodrigo de Azevedo
    Mar 11 at 21:48
















$begingroup$
Matlab has now a "sylvester" function uk.mathworks.com/help/matlab/ref/sylvester.html
$endgroup$
– Jean Marie
Mar 11 at 21:41




$begingroup$
Matlab has now a "sylvester" function uk.mathworks.com/help/matlab/ref/sylvester.html
$endgroup$
– Jean Marie
Mar 11 at 21:41












$begingroup$
Why not use vectorization?
$endgroup$
– Rodrigo de Azevedo
Mar 11 at 21:45




$begingroup$
Why not use vectorization?
$endgroup$
– Rodrigo de Azevedo
Mar 11 at 21:45












$begingroup$
@JeanMarie Yes, but the input arguments must be numeric arrays.
$endgroup$
– Mohammad
Mar 11 at 21:46




$begingroup$
@JeanMarie Yes, but the input arguments must be numeric arrays.
$endgroup$
– Mohammad
Mar 11 at 21:46












$begingroup$
@RodrigodeAzevedo Can you please describe more?
$endgroup$
– Mohammad
Mar 11 at 21:46




$begingroup$
@RodrigodeAzevedo Can you please describe more?
$endgroup$
– Mohammad
Mar 11 at 21:46












$begingroup$
Vectorization converts the matrix equation into a system of $4$ linear equations in $4$ unknowns, which is easy to solve symbolically. In MATLAB, use kron for the Kronecker product and reshape for the vectorization and un-vectorization.
$endgroup$
– Rodrigo de Azevedo
Mar 11 at 21:48





$begingroup$
Vectorization converts the matrix equation into a system of $4$ linear equations in $4$ unknowns, which is easy to solve symbolically. In MATLAB, use kron for the Kronecker product and reshape for the vectorization and un-vectorization.
$endgroup$
– Rodrigo de Azevedo
Mar 11 at 21:48











1 Answer
1






active

oldest

votes


















2












$begingroup$

You could write the Sylvester equation as a linear system:
beginequation
(I_2 otimes A + A^T otimes I_2) mathrmvec X = mathrmvec B
endequation

which you can then solve for $mathrmvecX$:
beginalign
mathrmvecX
& = (I_2 otimes A + A^T otimes I_2)^-1 mathrmvec B \
& = fracmathrmadj (I_2 otimes A + A^T otimes I_2)mathrmdet (I_2 otimes A + A^T otimes I_2) mathrmvec B
endalign

and finally reshape back to a 2 by 2 matrix.






share|cite|improve this answer











$endgroup$












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    1 Answer
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    oldest

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    1 Answer
    1






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    active

    oldest

    votes






    active

    oldest

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    2












    $begingroup$

    You could write the Sylvester equation as a linear system:
    beginequation
    (I_2 otimes A + A^T otimes I_2) mathrmvec X = mathrmvec B
    endequation

    which you can then solve for $mathrmvecX$:
    beginalign
    mathrmvecX
    & = (I_2 otimes A + A^T otimes I_2)^-1 mathrmvec B \
    & = fracmathrmadj (I_2 otimes A + A^T otimes I_2)mathrmdet (I_2 otimes A + A^T otimes I_2) mathrmvec B
    endalign

    and finally reshape back to a 2 by 2 matrix.






    share|cite|improve this answer











    $endgroup$

















      2












      $begingroup$

      You could write the Sylvester equation as a linear system:
      beginequation
      (I_2 otimes A + A^T otimes I_2) mathrmvec X = mathrmvec B
      endequation

      which you can then solve for $mathrmvecX$:
      beginalign
      mathrmvecX
      & = (I_2 otimes A + A^T otimes I_2)^-1 mathrmvec B \
      & = fracmathrmadj (I_2 otimes A + A^T otimes I_2)mathrmdet (I_2 otimes A + A^T otimes I_2) mathrmvec B
      endalign

      and finally reshape back to a 2 by 2 matrix.






      share|cite|improve this answer











      $endgroup$















        2












        2








        2





        $begingroup$

        You could write the Sylvester equation as a linear system:
        beginequation
        (I_2 otimes A + A^T otimes I_2) mathrmvec X = mathrmvec B
        endequation

        which you can then solve for $mathrmvecX$:
        beginalign
        mathrmvecX
        & = (I_2 otimes A + A^T otimes I_2)^-1 mathrmvec B \
        & = fracmathrmadj (I_2 otimes A + A^T otimes I_2)mathrmdet (I_2 otimes A + A^T otimes I_2) mathrmvec B
        endalign

        and finally reshape back to a 2 by 2 matrix.






        share|cite|improve this answer











        $endgroup$



        You could write the Sylvester equation as a linear system:
        beginequation
        (I_2 otimes A + A^T otimes I_2) mathrmvec X = mathrmvec B
        endequation

        which you can then solve for $mathrmvecX$:
        beginalign
        mathrmvecX
        & = (I_2 otimes A + A^T otimes I_2)^-1 mathrmvec B \
        & = fracmathrmadj (I_2 otimes A + A^T otimes I_2)mathrmdet (I_2 otimes A + A^T otimes I_2) mathrmvec B
        endalign

        and finally reshape back to a 2 by 2 matrix.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Mar 12 at 21:49

























        answered Mar 11 at 21:50









        Koen TielsKoen Tiels

        1706




        1706



























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