Is every 3-dimensional Poincaré complex a 3-dimensional topological variety?Poincare duality in group (co)homologyHomotopy groups of compact topological manifoldPath or One-Dimensional ManifoldOrientability of space with only even dimensional cells.Do manifolds have the homotopy type of finite-dimensional CW-complexes?Axiomatic descrption of Poincaré polynomialQuestion about (topological) orientation of an $n$-dimensional manifoldTheorem about Poincaré algebraInduced isomorphism by Homotopy equivalenceAlexander duality on (co)chain levelsingular cohomology and Poincaré duality

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Is every 3-dimensional Poincaré complex a 3-dimensional topological variety?


Poincare duality in group (co)homologyHomotopy groups of compact topological manifoldPath or One-Dimensional ManifoldOrientability of space with only even dimensional cells.Do manifolds have the homotopy type of finite-dimensional CW-complexes?Axiomatic descrption of Poincaré polynomialQuestion about (topological) orientation of an $n$-dimensional manifoldTheorem about Poincaré algebraInduced isomorphism by Homotopy equivalenceAlexander duality on (co)chain levelsingular cohomology and Poincaré duality













0












$begingroup$


I have this question, if every 3-dimensional Poincaré complex is a 3-dimensional topological manifold?



Definition (Poincaré complex)
$X$ is a n-dimensional Poincaré complex if $X$ have the same homotopy type of a finite CW complex with a homomorphism $$ w: pi_1 (X) rightarrow mathbbZ/2 $$ and $M in H_n (X;mathbbZ[w])$, such that
$$H^ast (X;mathbbZ[w]) rightarrow ^frown [M] H_n-s(X;mathbbZ[w])$$ is a isomorphism.










share|cite|improve this question









New contributor




Erick David Luna Núñez is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 1




    $begingroup$
    By "any" do you mean "every"? And what is a "topological variety"? Do you mean "a topological manifold"?
    $endgroup$
    – Moishe Kohan
    Mar 11 at 21:31






  • 2




    $begingroup$
    Welcome to Math.SE. Please review How to Ask. Especially when asking about topics from advanced subjects, Readers will reasonably expect that you give more context about the problem you want help with. Bare problem statements are often ambiguous as to where you found difficulty in approaching them, and in this way it can convey the impression that an assigned exercise is being "passed through" without the thought necessary to digest its meaning.
    $endgroup$
    – hardmath
    Mar 11 at 22:16






  • 1




    $begingroup$
    BTW, I am quite sure that the question is not an "assigned exercise", but it is poorly worded. Suggested reading: amazon.com/Elliptic-Structures-3-Manifolds-Mathematical-Society/… which contains an answer to what I think your question is.
    $endgroup$
    – Moishe Kohan
    Mar 11 at 22:46















0












$begingroup$


I have this question, if every 3-dimensional Poincaré complex is a 3-dimensional topological manifold?



Definition (Poincaré complex)
$X$ is a n-dimensional Poincaré complex if $X$ have the same homotopy type of a finite CW complex with a homomorphism $$ w: pi_1 (X) rightarrow mathbbZ/2 $$ and $M in H_n (X;mathbbZ[w])$, such that
$$H^ast (X;mathbbZ[w]) rightarrow ^frown [M] H_n-s(X;mathbbZ[w])$$ is a isomorphism.










share|cite|improve this question









New contributor




Erick David Luna Núñez is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 1




    $begingroup$
    By "any" do you mean "every"? And what is a "topological variety"? Do you mean "a topological manifold"?
    $endgroup$
    – Moishe Kohan
    Mar 11 at 21:31






  • 2




    $begingroup$
    Welcome to Math.SE. Please review How to Ask. Especially when asking about topics from advanced subjects, Readers will reasonably expect that you give more context about the problem you want help with. Bare problem statements are often ambiguous as to where you found difficulty in approaching them, and in this way it can convey the impression that an assigned exercise is being "passed through" without the thought necessary to digest its meaning.
    $endgroup$
    – hardmath
    Mar 11 at 22:16






  • 1




    $begingroup$
    BTW, I am quite sure that the question is not an "assigned exercise", but it is poorly worded. Suggested reading: amazon.com/Elliptic-Structures-3-Manifolds-Mathematical-Society/… which contains an answer to what I think your question is.
    $endgroup$
    – Moishe Kohan
    Mar 11 at 22:46













0












0








0





$begingroup$


I have this question, if every 3-dimensional Poincaré complex is a 3-dimensional topological manifold?



Definition (Poincaré complex)
$X$ is a n-dimensional Poincaré complex if $X$ have the same homotopy type of a finite CW complex with a homomorphism $$ w: pi_1 (X) rightarrow mathbbZ/2 $$ and $M in H_n (X;mathbbZ[w])$, such that
$$H^ast (X;mathbbZ[w]) rightarrow ^frown [M] H_n-s(X;mathbbZ[w])$$ is a isomorphism.










share|cite|improve this question









New contributor




Erick David Luna Núñez is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I have this question, if every 3-dimensional Poincaré complex is a 3-dimensional topological manifold?



Definition (Poincaré complex)
$X$ is a n-dimensional Poincaré complex if $X$ have the same homotopy type of a finite CW complex with a homomorphism $$ w: pi_1 (X) rightarrow mathbbZ/2 $$ and $M in H_n (X;mathbbZ[w])$, such that
$$H^ast (X;mathbbZ[w]) rightarrow ^frown [M] H_n-s(X;mathbbZ[w])$$ is a isomorphism.







algebraic-topology differential-topology homology-cohomology low-dimensional-topology poincare-duality






share|cite|improve this question









New contributor




Erick David Luna Núñez is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




Erick David Luna Núñez is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited Mar 12 at 21:27







Erick David Luna Núñez













New contributor




Erick David Luna Núñez is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Mar 11 at 19:18









Erick David Luna NúñezErick David Luna Núñez

11




11




New contributor




Erick David Luna Núñez is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Erick David Luna Núñez is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Erick David Luna Núñez is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 1




    $begingroup$
    By "any" do you mean "every"? And what is a "topological variety"? Do you mean "a topological manifold"?
    $endgroup$
    – Moishe Kohan
    Mar 11 at 21:31






  • 2




    $begingroup$
    Welcome to Math.SE. Please review How to Ask. Especially when asking about topics from advanced subjects, Readers will reasonably expect that you give more context about the problem you want help with. Bare problem statements are often ambiguous as to where you found difficulty in approaching them, and in this way it can convey the impression that an assigned exercise is being "passed through" without the thought necessary to digest its meaning.
    $endgroup$
    – hardmath
    Mar 11 at 22:16






  • 1




    $begingroup$
    BTW, I am quite sure that the question is not an "assigned exercise", but it is poorly worded. Suggested reading: amazon.com/Elliptic-Structures-3-Manifolds-Mathematical-Society/… which contains an answer to what I think your question is.
    $endgroup$
    – Moishe Kohan
    Mar 11 at 22:46












  • 1




    $begingroup$
    By "any" do you mean "every"? And what is a "topological variety"? Do you mean "a topological manifold"?
    $endgroup$
    – Moishe Kohan
    Mar 11 at 21:31






  • 2




    $begingroup$
    Welcome to Math.SE. Please review How to Ask. Especially when asking about topics from advanced subjects, Readers will reasonably expect that you give more context about the problem you want help with. Bare problem statements are often ambiguous as to where you found difficulty in approaching them, and in this way it can convey the impression that an assigned exercise is being "passed through" without the thought necessary to digest its meaning.
    $endgroup$
    – hardmath
    Mar 11 at 22:16






  • 1




    $begingroup$
    BTW, I am quite sure that the question is not an "assigned exercise", but it is poorly worded. Suggested reading: amazon.com/Elliptic-Structures-3-Manifolds-Mathematical-Society/… which contains an answer to what I think your question is.
    $endgroup$
    – Moishe Kohan
    Mar 11 at 22:46







1




1




$begingroup$
By "any" do you mean "every"? And what is a "topological variety"? Do you mean "a topological manifold"?
$endgroup$
– Moishe Kohan
Mar 11 at 21:31




$begingroup$
By "any" do you mean "every"? And what is a "topological variety"? Do you mean "a topological manifold"?
$endgroup$
– Moishe Kohan
Mar 11 at 21:31




2




2




$begingroup$
Welcome to Math.SE. Please review How to Ask. Especially when asking about topics from advanced subjects, Readers will reasonably expect that you give more context about the problem you want help with. Bare problem statements are often ambiguous as to where you found difficulty in approaching them, and in this way it can convey the impression that an assigned exercise is being "passed through" without the thought necessary to digest its meaning.
$endgroup$
– hardmath
Mar 11 at 22:16




$begingroup$
Welcome to Math.SE. Please review How to Ask. Especially when asking about topics from advanced subjects, Readers will reasonably expect that you give more context about the problem you want help with. Bare problem statements are often ambiguous as to where you found difficulty in approaching them, and in this way it can convey the impression that an assigned exercise is being "passed through" without the thought necessary to digest its meaning.
$endgroup$
– hardmath
Mar 11 at 22:16




1




1




$begingroup$
BTW, I am quite sure that the question is not an "assigned exercise", but it is poorly worded. Suggested reading: amazon.com/Elliptic-Structures-3-Manifolds-Mathematical-Society/… which contains an answer to what I think your question is.
$endgroup$
– Moishe Kohan
Mar 11 at 22:46




$begingroup$
BTW, I am quite sure that the question is not an "assigned exercise", but it is poorly worded. Suggested reading: amazon.com/Elliptic-Structures-3-Manifolds-Mathematical-Society/… which contains an answer to what I think your question is.
$endgroup$
– Moishe Kohan
Mar 11 at 22:46










1 Answer
1






active

oldest

votes


















1












$begingroup$

First of all, you can always modify an $n$-dimensional closed (oriented if you prefer) connected $n$-dimensional manifold to make it into a finite CW $n$-dimensional Poincare complex which is not a manifold: Just attach a 1-cell to it along a vertex of this cell. This does not change the homotopy type, hence, keeps the space $X$ a Poincare complex, but $X$ is clearly not a manifold. Thus, a meaningful question to ask is:




Is every $n$-dimensional finite Poincare complex homotopy-equivalent to an $n$-dimensional manifold?




In dimension 2, it is a nontrivial theorem due to Bieri, Linnell and Muller that the question has positive answer. In dimension 3 the answer is negative, an example is due to C.B. Thomas, it is somewhere in his book:



Elliptic Structures on 3-Manifolds, Cambridge University Press, 1986.



In fact, he had this example already in 1977 modulo the Smale Conjecture which was proven by Hatcher in 1983.



It is a famous open problem (due to C.T.C. Wall) if every finite aspherical n-dimensional Poincare complex is homotopy equivalent to an n-dimensional manifold, $nge 3$. From what I know, the question is expected to have positive answer in dimension 3 and negative answer in (sufficiently) higher dimensions. Already in dimension 3 this problem is notoriously difficult.



Two more papers to read:



C.T.C Wall, Poincare duality in dimension 3, 2004.



J. Klein, Poincare duality spaces, In: Surveys on surgery theory, Vol. 1, 135–165,
Ann. of Math. Stud., 145, Princeton Univ. Press, Princeton, NJ, 2000.



See also my answer here.






share|cite|improve this answer











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    $begingroup$

    First of all, you can always modify an $n$-dimensional closed (oriented if you prefer) connected $n$-dimensional manifold to make it into a finite CW $n$-dimensional Poincare complex which is not a manifold: Just attach a 1-cell to it along a vertex of this cell. This does not change the homotopy type, hence, keeps the space $X$ a Poincare complex, but $X$ is clearly not a manifold. Thus, a meaningful question to ask is:




    Is every $n$-dimensional finite Poincare complex homotopy-equivalent to an $n$-dimensional manifold?




    In dimension 2, it is a nontrivial theorem due to Bieri, Linnell and Muller that the question has positive answer. In dimension 3 the answer is negative, an example is due to C.B. Thomas, it is somewhere in his book:



    Elliptic Structures on 3-Manifolds, Cambridge University Press, 1986.



    In fact, he had this example already in 1977 modulo the Smale Conjecture which was proven by Hatcher in 1983.



    It is a famous open problem (due to C.T.C. Wall) if every finite aspherical n-dimensional Poincare complex is homotopy equivalent to an n-dimensional manifold, $nge 3$. From what I know, the question is expected to have positive answer in dimension 3 and negative answer in (sufficiently) higher dimensions. Already in dimension 3 this problem is notoriously difficult.



    Two more papers to read:



    C.T.C Wall, Poincare duality in dimension 3, 2004.



    J. Klein, Poincare duality spaces, In: Surveys on surgery theory, Vol. 1, 135–165,
    Ann. of Math. Stud., 145, Princeton Univ. Press, Princeton, NJ, 2000.



    See also my answer here.






    share|cite|improve this answer











    $endgroup$

















      1












      $begingroup$

      First of all, you can always modify an $n$-dimensional closed (oriented if you prefer) connected $n$-dimensional manifold to make it into a finite CW $n$-dimensional Poincare complex which is not a manifold: Just attach a 1-cell to it along a vertex of this cell. This does not change the homotopy type, hence, keeps the space $X$ a Poincare complex, but $X$ is clearly not a manifold. Thus, a meaningful question to ask is:




      Is every $n$-dimensional finite Poincare complex homotopy-equivalent to an $n$-dimensional manifold?




      In dimension 2, it is a nontrivial theorem due to Bieri, Linnell and Muller that the question has positive answer. In dimension 3 the answer is negative, an example is due to C.B. Thomas, it is somewhere in his book:



      Elliptic Structures on 3-Manifolds, Cambridge University Press, 1986.



      In fact, he had this example already in 1977 modulo the Smale Conjecture which was proven by Hatcher in 1983.



      It is a famous open problem (due to C.T.C. Wall) if every finite aspherical n-dimensional Poincare complex is homotopy equivalent to an n-dimensional manifold, $nge 3$. From what I know, the question is expected to have positive answer in dimension 3 and negative answer in (sufficiently) higher dimensions. Already in dimension 3 this problem is notoriously difficult.



      Two more papers to read:



      C.T.C Wall, Poincare duality in dimension 3, 2004.



      J. Klein, Poincare duality spaces, In: Surveys on surgery theory, Vol. 1, 135–165,
      Ann. of Math. Stud., 145, Princeton Univ. Press, Princeton, NJ, 2000.



      See also my answer here.






      share|cite|improve this answer











      $endgroup$















        1












        1








        1





        $begingroup$

        First of all, you can always modify an $n$-dimensional closed (oriented if you prefer) connected $n$-dimensional manifold to make it into a finite CW $n$-dimensional Poincare complex which is not a manifold: Just attach a 1-cell to it along a vertex of this cell. This does not change the homotopy type, hence, keeps the space $X$ a Poincare complex, but $X$ is clearly not a manifold. Thus, a meaningful question to ask is:




        Is every $n$-dimensional finite Poincare complex homotopy-equivalent to an $n$-dimensional manifold?




        In dimension 2, it is a nontrivial theorem due to Bieri, Linnell and Muller that the question has positive answer. In dimension 3 the answer is negative, an example is due to C.B. Thomas, it is somewhere in his book:



        Elliptic Structures on 3-Manifolds, Cambridge University Press, 1986.



        In fact, he had this example already in 1977 modulo the Smale Conjecture which was proven by Hatcher in 1983.



        It is a famous open problem (due to C.T.C. Wall) if every finite aspherical n-dimensional Poincare complex is homotopy equivalent to an n-dimensional manifold, $nge 3$. From what I know, the question is expected to have positive answer in dimension 3 and negative answer in (sufficiently) higher dimensions. Already in dimension 3 this problem is notoriously difficult.



        Two more papers to read:



        C.T.C Wall, Poincare duality in dimension 3, 2004.



        J. Klein, Poincare duality spaces, In: Surveys on surgery theory, Vol. 1, 135–165,
        Ann. of Math. Stud., 145, Princeton Univ. Press, Princeton, NJ, 2000.



        See also my answer here.






        share|cite|improve this answer











        $endgroup$



        First of all, you can always modify an $n$-dimensional closed (oriented if you prefer) connected $n$-dimensional manifold to make it into a finite CW $n$-dimensional Poincare complex which is not a manifold: Just attach a 1-cell to it along a vertex of this cell. This does not change the homotopy type, hence, keeps the space $X$ a Poincare complex, but $X$ is clearly not a manifold. Thus, a meaningful question to ask is:




        Is every $n$-dimensional finite Poincare complex homotopy-equivalent to an $n$-dimensional manifold?




        In dimension 2, it is a nontrivial theorem due to Bieri, Linnell and Muller that the question has positive answer. In dimension 3 the answer is negative, an example is due to C.B. Thomas, it is somewhere in his book:



        Elliptic Structures on 3-Manifolds, Cambridge University Press, 1986.



        In fact, he had this example already in 1977 modulo the Smale Conjecture which was proven by Hatcher in 1983.



        It is a famous open problem (due to C.T.C. Wall) if every finite aspherical n-dimensional Poincare complex is homotopy equivalent to an n-dimensional manifold, $nge 3$. From what I know, the question is expected to have positive answer in dimension 3 and negative answer in (sufficiently) higher dimensions. Already in dimension 3 this problem is notoriously difficult.



        Two more papers to read:



        C.T.C Wall, Poincare duality in dimension 3, 2004.



        J. Klein, Poincare duality spaces, In: Surveys on surgery theory, Vol. 1, 135–165,
        Ann. of Math. Stud., 145, Princeton Univ. Press, Princeton, NJ, 2000.



        See also my answer here.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited yesterday

























        answered yesterday









        Moishe KohanMoishe Kohan

        48k344110




        48k344110




















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            Erick David Luna Núñez is a new contributor. Be nice, and check out our Code of Conduct.












            Erick David Luna Núñez is a new contributor. Be nice, and check out our Code of Conduct.











            Erick David Luna Núñez is a new contributor. Be nice, and check out our Code of Conduct.














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