How to solve this trig equation , $tan^-1(x) = 1 / tan (x)$?Solve trigonometric equation $tantheta + sectheta =2cos theta$Find all solutions of the equation $tan x = 2 + tan3x$How to solve this trig. equation?Solving for x in a trig equationIf the quadratic equation $x^2+(2-tantheta)x-(1+tantheta)=0$ has two integral roots,How to solve this Trigonometric equation $tan^2theta + sec(2theta)=1$?Solve the equation $tan(2x) = 1+tan(x)$Solving a trig equation using subsitutionWhy is $tan(theta)$ the reciprocal of $tan(90 - theta)$?How do I solve this trigonometric function equation?
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How to solve this trig equation , $tan^-1(x) = 1 / tan (x)$?
Solve trigonometric equation $tantheta + sectheta =2cos theta$Find all solutions of the equation $tan x = 2 + tan3x$How to solve this trig. equation?Solving for x in a trig equationIf the quadratic equation $x^2+(2-tantheta)x-(1+tantheta)=0$ has two integral roots,How to solve this Trigonometric equation $tan^2theta + sec(2theta)=1$?Solve the equation $tan(2x) = 1+tan(x)$Solving a trig equation using subsitutionWhy is $tan(theta)$ the reciprocal of $tan(90 - theta)$?How do I solve this trigonometric function equation?
$begingroup$
Given the equation $$tan^-1(x) = frac1tan(x),quad xin[0,2pi],$$ find the value/values of $x$.
I tried to take $tan (x)$ for the both sides but the equation had more complicated !
trigonometry
New contributor
$endgroup$
add a comment |
$begingroup$
Given the equation $$tan^-1(x) = frac1tan(x),quad xin[0,2pi],$$ find the value/values of $x$.
I tried to take $tan (x)$ for the both sides but the equation had more complicated !
trigonometry
New contributor
$endgroup$
$begingroup$
What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
$endgroup$
– user
Mar 11 at 20:56
1
$begingroup$
I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
$endgroup$
– herb steinberg
Mar 11 at 20:59
$begingroup$
Where is this coming from ?
$endgroup$
– Yves Daoust
Mar 11 at 21:01
$begingroup$
tan−1(x) = arctan (x)
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:04
$begingroup$
I wrote it , And it has solutions , but i don't know how to find them handly .
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:05
add a comment |
$begingroup$
Given the equation $$tan^-1(x) = frac1tan(x),quad xin[0,2pi],$$ find the value/values of $x$.
I tried to take $tan (x)$ for the both sides but the equation had more complicated !
trigonometry
New contributor
$endgroup$
Given the equation $$tan^-1(x) = frac1tan(x),quad xin[0,2pi],$$ find the value/values of $x$.
I tried to take $tan (x)$ for the both sides but the equation had more complicated !
trigonometry
trigonometry
New contributor
New contributor
edited Mar 11 at 20:58
user
5,36211030
5,36211030
New contributor
asked Mar 11 at 20:53
Mohammad AlshareefMohammad Alshareef
81
81
New contributor
New contributor
$begingroup$
What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
$endgroup$
– user
Mar 11 at 20:56
1
$begingroup$
I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
$endgroup$
– herb steinberg
Mar 11 at 20:59
$begingroup$
Where is this coming from ?
$endgroup$
– Yves Daoust
Mar 11 at 21:01
$begingroup$
tan−1(x) = arctan (x)
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:04
$begingroup$
I wrote it , And it has solutions , but i don't know how to find them handly .
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:05
add a comment |
$begingroup$
What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
$endgroup$
– user
Mar 11 at 20:56
1
$begingroup$
I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
$endgroup$
– herb steinberg
Mar 11 at 20:59
$begingroup$
Where is this coming from ?
$endgroup$
– Yves Daoust
Mar 11 at 21:01
$begingroup$
tan−1(x) = arctan (x)
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:04
$begingroup$
I wrote it , And it has solutions , but i don't know how to find them handly .
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:05
$begingroup$
What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
$endgroup$
– user
Mar 11 at 20:56
$begingroup$
What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
$endgroup$
– user
Mar 11 at 20:56
1
1
$begingroup$
I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
$endgroup$
– herb steinberg
Mar 11 at 20:59
$begingroup$
I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
$endgroup$
– herb steinberg
Mar 11 at 20:59
$begingroup$
Where is this coming from ?
$endgroup$
– Yves Daoust
Mar 11 at 21:01
$begingroup$
Where is this coming from ?
$endgroup$
– Yves Daoust
Mar 11 at 21:01
$begingroup$
tan−1(x) = arctan (x)
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:04
$begingroup$
tan−1(x) = arctan (x)
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:04
$begingroup$
I wrote it , And it has solutions , but i don't know how to find them handly .
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:05
$begingroup$
I wrote it , And it has solutions , but i don't know how to find them handly .
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:05
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
I believe you will not be able to find exact solutions, only numerical. However, as you note, it does have solutions, it has $2n$ solutions in every interval of the form $[-n pi, n pi]$.
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$begingroup$
In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
$endgroup$
– user
Mar 11 at 21:39
add a comment |
$begingroup$
There are two solutions in the given interval and you can find them only numerically.
$endgroup$
add a comment |
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2 Answers
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2 Answers
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$begingroup$
I believe you will not be able to find exact solutions, only numerical. However, as you note, it does have solutions, it has $2n$ solutions in every interval of the form $[-n pi, n pi]$.
$endgroup$
$begingroup$
In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
$endgroup$
– user
Mar 11 at 21:39
add a comment |
$begingroup$
I believe you will not be able to find exact solutions, only numerical. However, as you note, it does have solutions, it has $2n$ solutions in every interval of the form $[-n pi, n pi]$.
$endgroup$
$begingroup$
In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
$endgroup$
– user
Mar 11 at 21:39
add a comment |
$begingroup$
I believe you will not be able to find exact solutions, only numerical. However, as you note, it does have solutions, it has $2n$ solutions in every interval of the form $[-n pi, n pi]$.
$endgroup$
I believe you will not be able to find exact solutions, only numerical. However, as you note, it does have solutions, it has $2n$ solutions in every interval of the form $[-n pi, n pi]$.
answered Mar 11 at 21:23
PierreCarrePierreCarre
1,480211
1,480211
$begingroup$
In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
$endgroup$
– user
Mar 11 at 21:39
add a comment |
$begingroup$
In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
$endgroup$
– user
Mar 11 at 21:39
$begingroup$
In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
$endgroup$
– user
Mar 11 at 21:39
$begingroup$
In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
$endgroup$
– user
Mar 11 at 21:39
add a comment |
$begingroup$
There are two solutions in the given interval and you can find them only numerically.
$endgroup$
add a comment |
$begingroup$
There are two solutions in the given interval and you can find them only numerically.
$endgroup$
add a comment |
$begingroup$
There are two solutions in the given interval and you can find them only numerically.
$endgroup$
There are two solutions in the given interval and you can find them only numerically.
answered Mar 12 at 8:08
OldboyOldboy
8,77611037
8,77611037
add a comment |
add a comment |
Mohammad Alshareef is a new contributor. Be nice, and check out our Code of Conduct.
Mohammad Alshareef is a new contributor. Be nice, and check out our Code of Conduct.
Mohammad Alshareef is a new contributor. Be nice, and check out our Code of Conduct.
Mohammad Alshareef is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
$endgroup$
– user
Mar 11 at 20:56
1
$begingroup$
I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
$endgroup$
– herb steinberg
Mar 11 at 20:59
$begingroup$
Where is this coming from ?
$endgroup$
– Yves Daoust
Mar 11 at 21:01
$begingroup$
tan−1(x) = arctan (x)
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:04
$begingroup$
I wrote it , And it has solutions , but i don't know how to find them handly .
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:05