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How to solve this trig equation , $tan^-1(x) = 1 / tan (x)$?


Solve trigonometric equation $tantheta + sectheta =2cos theta$Find all solutions of the equation $tan x = 2 + tan3x$How to solve this trig. equation?Solving for x in a trig equationIf the quadratic equation $x^2+(2-tantheta)x-(1+tantheta)=0$ has two integral roots,How to solve this Trigonometric equation $tan^2theta + sec(2theta)=1$?Solve the equation $tan(2x) = 1+tan(x)$Solving a trig equation using subsitutionWhy is $tan(theta)$ the reciprocal of $tan(90 - theta)$?How do I solve this trigonometric function equation?













0












$begingroup$


Given the equation $$tan^-1(x) = frac1tan(x),quad xin[0,2pi],$$ find the value/values of $x$.



I tried to take $tan (x)$ for the both sides but the equation had more complicated !










share|cite|improve this question









New contributor




Mohammad Alshareef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
    $endgroup$
    – user
    Mar 11 at 20:56






  • 1




    $begingroup$
    I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
    $endgroup$
    – herb steinberg
    Mar 11 at 20:59










  • $begingroup$
    Where is this coming from ?
    $endgroup$
    – Yves Daoust
    Mar 11 at 21:01










  • $begingroup$
    tan−1(x) = arctan (x)
    $endgroup$
    – Mohammad Alshareef
    Mar 11 at 21:04










  • $begingroup$
    I wrote it , And it has solutions , but i don't know how to find them handly .
    $endgroup$
    – Mohammad Alshareef
    Mar 11 at 21:05















0












$begingroup$


Given the equation $$tan^-1(x) = frac1tan(x),quad xin[0,2pi],$$ find the value/values of $x$.



I tried to take $tan (x)$ for the both sides but the equation had more complicated !










share|cite|improve this question









New contributor




Mohammad Alshareef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
    $endgroup$
    – user
    Mar 11 at 20:56






  • 1




    $begingroup$
    I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
    $endgroup$
    – herb steinberg
    Mar 11 at 20:59










  • $begingroup$
    Where is this coming from ?
    $endgroup$
    – Yves Daoust
    Mar 11 at 21:01










  • $begingroup$
    tan−1(x) = arctan (x)
    $endgroup$
    – Mohammad Alshareef
    Mar 11 at 21:04










  • $begingroup$
    I wrote it , And it has solutions , but i don't know how to find them handly .
    $endgroup$
    – Mohammad Alshareef
    Mar 11 at 21:05













0












0








0





$begingroup$


Given the equation $$tan^-1(x) = frac1tan(x),quad xin[0,2pi],$$ find the value/values of $x$.



I tried to take $tan (x)$ for the both sides but the equation had more complicated !










share|cite|improve this question









New contributor




Mohammad Alshareef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Given the equation $$tan^-1(x) = frac1tan(x),quad xin[0,2pi],$$ find the value/values of $x$.



I tried to take $tan (x)$ for the both sides but the equation had more complicated !







trigonometry






share|cite|improve this question









New contributor




Mohammad Alshareef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




Mohammad Alshareef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited Mar 11 at 20:58









user

5,36211030




5,36211030






New contributor




Mohammad Alshareef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked Mar 11 at 20:53









Mohammad AlshareefMohammad Alshareef

81




81




New contributor




Mohammad Alshareef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Mohammad Alshareef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Mohammad Alshareef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
    $endgroup$
    – user
    Mar 11 at 20:56






  • 1




    $begingroup$
    I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
    $endgroup$
    – herb steinberg
    Mar 11 at 20:59










  • $begingroup$
    Where is this coming from ?
    $endgroup$
    – Yves Daoust
    Mar 11 at 21:01










  • $begingroup$
    tan−1(x) = arctan (x)
    $endgroup$
    – Mohammad Alshareef
    Mar 11 at 21:04










  • $begingroup$
    I wrote it , And it has solutions , but i don't know how to find them handly .
    $endgroup$
    – Mohammad Alshareef
    Mar 11 at 21:05
















  • $begingroup$
    What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
    $endgroup$
    – user
    Mar 11 at 20:56






  • 1




    $begingroup$
    I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
    $endgroup$
    – herb steinberg
    Mar 11 at 20:59










  • $begingroup$
    Where is this coming from ?
    $endgroup$
    – Yves Daoust
    Mar 11 at 21:01










  • $begingroup$
    tan−1(x) = arctan (x)
    $endgroup$
    – Mohammad Alshareef
    Mar 11 at 21:04










  • $begingroup$
    I wrote it , And it has solutions , but i don't know how to find them handly .
    $endgroup$
    – Mohammad Alshareef
    Mar 11 at 21:05















$begingroup$
What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
$endgroup$
– user
Mar 11 at 20:56




$begingroup$
What is $tan ^-1x $? Is it $arctan (x) $ or $1/tan (x) $?
$endgroup$
– user
Mar 11 at 20:56




1




1




$begingroup$
I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
$endgroup$
– herb steinberg
Mar 11 at 20:59




$begingroup$
I doubt if yu can find an analytic solution. Graphing can get you approximations, which can be refined by Newton's method.
$endgroup$
– herb steinberg
Mar 11 at 20:59












$begingroup$
Where is this coming from ?
$endgroup$
– Yves Daoust
Mar 11 at 21:01




$begingroup$
Where is this coming from ?
$endgroup$
– Yves Daoust
Mar 11 at 21:01












$begingroup$
tan−1(x) = arctan (x)
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:04




$begingroup$
tan−1(x) = arctan (x)
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:04












$begingroup$
I wrote it , And it has solutions , but i don't know how to find them handly .
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:05




$begingroup$
I wrote it , And it has solutions , but i don't know how to find them handly .
$endgroup$
– Mohammad Alshareef
Mar 11 at 21:05










2 Answers
2






active

oldest

votes


















0












$begingroup$

I believe you will not be able to find exact solutions, only numerical. However, as you note, it does have solutions, it has $2n$ solutions in every interval of the form $[-n pi, n pi]$.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
    $endgroup$
    – user
    Mar 11 at 21:39



















0












$begingroup$

There are two solutions in the given interval and you can find them only numerically.



enter image description here






share|cite|improve this answer









$endgroup$












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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0












    $begingroup$

    I believe you will not be able to find exact solutions, only numerical. However, as you note, it does have solutions, it has $2n$ solutions in every interval of the form $[-n pi, n pi]$.






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
      $endgroup$
      – user
      Mar 11 at 21:39
















    0












    $begingroup$

    I believe you will not be able to find exact solutions, only numerical. However, as you note, it does have solutions, it has $2n$ solutions in every interval of the form $[-n pi, n pi]$.






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
      $endgroup$
      – user
      Mar 11 at 21:39














    0












    0








    0





    $begingroup$

    I believe you will not be able to find exact solutions, only numerical. However, as you note, it does have solutions, it has $2n$ solutions in every interval of the form $[-n pi, n pi]$.






    share|cite|improve this answer









    $endgroup$



    I believe you will not be able to find exact solutions, only numerical. However, as you note, it does have solutions, it has $2n$ solutions in every interval of the form $[-n pi, n pi]$.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered Mar 11 at 21:23









    PierreCarrePierreCarre

    1,480211




    1,480211











    • $begingroup$
      In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
      $endgroup$
      – user
      Mar 11 at 21:39

















    • $begingroup$
      In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
      $endgroup$
      – user
      Mar 11 at 21:39
















    $begingroup$
    In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
    $endgroup$
    – user
    Mar 11 at 21:39





    $begingroup$
    In fact, there is a single solution for each $[kpi, (k+1)pi]$ interval. Moreover, if $x $ is a solution, $-x $ is a solution as well.
    $endgroup$
    – user
    Mar 11 at 21:39












    0












    $begingroup$

    There are two solutions in the given interval and you can find them only numerically.



    enter image description here






    share|cite|improve this answer









    $endgroup$

















      0












      $begingroup$

      There are two solutions in the given interval and you can find them only numerically.



      enter image description here






      share|cite|improve this answer









      $endgroup$















        0












        0








        0





        $begingroup$

        There are two solutions in the given interval and you can find them only numerically.



        enter image description here






        share|cite|improve this answer









        $endgroup$



        There are two solutions in the given interval and you can find them only numerically.



        enter image description here







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Mar 12 at 8:08









        OldboyOldboy

        8,77611037




        8,77611037




















            Mohammad Alshareef is a new contributor. Be nice, and check out our Code of Conduct.









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