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how to set variables in mathematica

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1

$begingroup$

I have this optimization problem that Mathematica solves correctly:

NMinimize[x0^2 + x1^2 + x2^2, x0 - x1 + 2.0 x2 == 1.0,
x0 + x1* + x2 == 0.0, x0, x1, x2]

0.17748, x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

My problem is I want x0, x1 and x2 to have these values from here on and I dont know how to do (set) this. For example, if i try to plot

Plot[x0 + x1*x + x2*x^2,x,-1,1]

it gives me an empty plot because it does not know what x0, x1,and x2 are.

Thanks for your help.

S

symbolic-computation

share|cite|improve this question

asked Oct 14 '13 at 15:28

user89699user89699

563

$endgroup$

add a comment | 

1

$begingroup$

I have this optimization problem that Mathematica solves correctly:

NMinimize[x0^2 + x1^2 + x2^2, x0 - x1 + 2.0 x2 == 1.0,
x0 + x1* + x2 == 0.0, x0, x1, x2]

0.17748, x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

My problem is I want x0, x1 and x2 to have these values from here on and I dont know how to do (set) this. For example, if i try to plot

Plot[x0 + x1*x + x2*x^2,x,-1,1]

it gives me an empty plot because it does not know what x0, x1,and x2 are.

Thanks for your help.

S

symbolic-computation

share|cite|improve this question

asked Oct 14 '13 at 15:28

user89699user89699

563

$endgroup$

add a comment | 

$begingroup$

I have this optimization problem that Mathematica solves correctly:

NMinimize[x0^2 + x1^2 + x2^2, x0 - x1 + 2.0 x2 == 1.0,
x0 + x1* + x2 == 0.0, x0, x1, x2]

0.17748, x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

My problem is I want x0, x1 and x2 to have these values from here on and I dont know how to do (set) this. For example, if i try to plot

Plot[x0 + x1*x + x2*x^2,x,-1,1]

it gives me an empty plot because it does not know what x0, x1,and x2 are.

Thanks for your help.

S

symbolic-computation

share|cite|improve this question

asked Oct 14 '13 at 15:28

user89699user89699

563

$endgroup$

share|cite|improve this question

asked Oct 14 '13 at 15:28

user89699user89699

563

share|cite|improve this question

asked Oct 14 '13 at 15:28

user89699user89699

563

asked Oct 14 '13 at 15:28

user89699user89699

563

asked Oct 14 '13 at 15:28

user89699user89699

563

1 Answer
1

active

oldest

votes

1

$begingroup$

Give your solution a name, such as sol:

sol = NMinimize[x0^2 + x1^2 + x2^2, x0 - x1 + 2.0 x2 == 1.0, 
 x0 + x1*+x2 == 0.0, x0, x1, x2]

0.17748, x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

You want to grab the second part of this solution namely sol[[2]]:

sol[[2]]

x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

and substitute those values into your expression:

expr = x0 + x1*x + x2*x^2 /. sol[[2]];

Plot[expr, x, -1, 1] 

_{(source: tri.org.au)}

I want x0, x1 and x2 to have these values from here on

Although it is certainly possible to globally set x0 = blah, and x1 = bleh, ... you will quickly find yourself in trouble if you do so. It is a much better approach generally to leave x0, x1 and x2 as global unassigned variables, and to then create a special expression like expr above with these numeric values replaced, rather than globally setting the values of x0, x1, and x2.

share|cite|improve this answer

edited Mar 12 at 18:22

Glorfindel

3,42981830

answered Oct 14 '13 at 15:35

wolfieswolfies

4,2392923

$endgroup$

add a comment | 

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1

$begingroup$

Give your solution a name, such as sol:

sol = NMinimize[x0^2 + x1^2 + x2^2, x0 - x1 + 2.0 x2 == 1.0, 
 x0 + x1*+x2 == 0.0, x0, x1, x2]

0.17748, x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

You want to grab the second part of this solution namely sol[[2]]:

sol[[2]]

x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

and substitute those values into your expression:

expr = x0 + x1*x + x2*x^2 /. sol[[2]];

Plot[expr, x, -1, 1] 

_{(source: tri.org.au)}

I want x0, x1 and x2 to have these values from here on

Although it is certainly possible to globally set x0 = blah, and x1 = bleh, ... you will quickly find yourself in trouble if you do so. It is a much better approach generally to leave x0, x1 and x2 as global unassigned variables, and to then create a special expression like expr above with these numeric values replaced, rather than globally setting the values of x0, x1, and x2.

share|cite|improve this answer

edited Mar 12 at 18:22

Glorfindel

3,42981830

answered Oct 14 '13 at 15:35

wolfieswolfies

4,2392923

$endgroup$

add a comment | 

1

$begingroup$

Give your solution a name, such as sol:

sol = NMinimize[x0^2 + x1^2 + x2^2, x0 - x1 + 2.0 x2 == 1.0, 
 x0 + x1*+x2 == 0.0, x0, x1, x2]

0.17748, x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

You want to grab the second part of this solution namely sol[[2]]:

sol[[2]]

x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

and substitute those values into your expression:

expr = x0 + x1*x + x2*x^2 /. sol[[2]];

Plot[expr, x, -1, 1] 

_{(source: tri.org.au)}

I want x0, x1 and x2 to have these values from here on

Although it is certainly possible to globally set x0 = blah, and x1 = bleh, ... you will quickly find yourself in trouble if you do so. It is a much better approach generally to leave x0, x1 and x2 as global unassigned variables, and to then create a special expression like expr above with these numeric values replaced, rather than globally setting the values of x0, x1, and x2.

share|cite|improve this answer

edited Mar 12 at 18:22

Glorfindel

3,42981830

answered Oct 14 '13 at 15:35

wolfieswolfies

4,2392923

$endgroup$

add a comment | 

$begingroup$

Give your solution a name, such as sol:

sol = NMinimize[x0^2 + x1^2 + x2^2, x0 - x1 + 2.0 x2 == 1.0, 
 x0 + x1*+x2 == 0.0, x0, x1, x2]

0.17748, x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

You want to grab the second part of this solution namely sol[[2]]:

sol[[2]]

x0 -> 0.0739345, x1 -> -0.205098, x2 -> 0.360484

and substitute those values into your expression:

expr = x0 + x1*x + x2*x^2 /. sol[[2]];

Plot[expr, x, -1, 1] 

_{(source: tri.org.au)}

I want x0, x1 and x2 to have these values from here on

Although it is certainly possible to globally set x0 = blah, and x1 = bleh, ... you will quickly find yourself in trouble if you do so. It is a much better approach generally to leave x0, x1 and x2 as global unassigned variables, and to then create a special expression like expr above with these numeric values replaced, rather than globally setting the values of x0, x1, and x2.

share|cite|improve this answer

edited Mar 12 at 18:22

Glorfindel

3,42981830

answered Oct 14 '13 at 15:35

wolfieswolfies

4,2392923

$endgroup$

sol = NMinimize[x0^2 + x1^2 + x2^2, x0 - x1 + 2.0 x2 == 1.0, 
 x0 + x1*+x2 == 0.0, x0, x1, x2]

sol[[2]]

expr = x0 + x1*x + x2*x^2 /. sol[[2]];

Plot[expr, x, -1, 1] 

share|cite|improve this answer

edited Mar 12 at 18:22

Glorfindel

3,42981830

answered Oct 14 '13 at 15:35

wolfieswolfies

4,2392923

edited Mar 12 at 18:22

Glorfindel

3,42981830

edited Mar 12 at 18:22

Glorfindel

3,42981830

answered Oct 14 '13 at 15:35

wolfieswolfies

4,2392923

answered Oct 14 '13 at 15:35

wolfieswolfies

4,2392923